I have two table Event and EventCategory. I am using zii.widgets.grid.CGridView widget to display all the events in the admin section.
I have created the following relations between tables.
Relation in EventCategory model:
'event' => array(self::HAS_MANY, 'Event', 'category_id'),
Relation in Event model:
'category' => array(self::BELONGS_TO, 'EventCategory', 'category_id'),
The following code I am using to display the Events:
<?php $this->widget('zii.widgets.grid.CGridView', array(
'id'=>'event-grid',
'dataProvider'=>$model->search(),
'filter'=>$model,
'summaryText'=> '',
'columns'=>array(
array('header'=>'Id','name'=>'event_id','filter'=>''),
'event_code',
'category.evntcatm_name',
'event_name',
array(
'class'=>'CButtonColumn',
'htmlOptions'=>array('class'=>'actions aligncenter'),
'deleteButtonImageUrl'=>false,
'updateButtonImageUrl'=>false,
'viewButtonImageUrl'=>false
),
),
)); ?>
'category.evntcatm_name' doesn't display anything. It is just creating the blank column with NO ERROR. What I am missing here.
Please try something like it
$data->category->evntcatm_name
You should use code like this:
'columns' = array(
/*YOUR DATA*/
array(
'name' => 'category_id',
'value' => function($data) {
return !empty($data->category) ? $data->category->evntcatm_name : null;
}),
)
This way can solve your problem with "Trying to get property of non-object". If you see blank cell in grid that means you miss relation (or it doesnt exist, in this way you should check relation condition or database)
Here is a few wild guesses:
Is category.evntcatm_name correctly spelled?
Is there actually data in the evntcatm_name field to begin with?
I know it might sound too simple to miss, but the error almost has to be on that level.
Try finding a category using the primary key and output it's evntcatm_name.
$cat = EventCategory::model()->findByPk(1);
echo $cat->evntcatm_name;
Maybe if you could share your schema for those two tables?
You can use
array(
'header' => 'Category Title',
'value' => '$data->category->evntcatm_name'
),
instead of 'category.evntcatm_name'
The model instance is not object now in the Cgidview:
Try
$data['category']['evntcatm_name'];
Related
I am displaying a CGridView below CDetailView on view.php page for Company model. I have problem in displaying values in CGridView using company details. The company model has an array of CompanyAddresses which is used as CArrayDataProvider for CGridView.
$config = array();
$dataProvider = new CArrayDataProvider($rawData=$model->companyAddresses,$config);
$this->widget('zii.widgets.grid.CGridView', array(
'dataProvider'=>$dataProvider
, 'columns'=>array(
//'id',
array('header'=>'SN.',
//'value'=>'++$row', // may nt work with pagination but the below does work
'value'=>'$this->grid->dataProvider->pagination->currentPage * $this->grid->dataProvider->pagination->pageSize + ($row+1)',
),
'address',
array(
'name'=>'Tehsil',
//'value'=> Utility::getTehsilName(Tehsil::model()->findByPk('tehsil_id')),
'value'=> Utility::getTehsilName($this->loadModel('tehsil_id')),
//'value'=> Tehsil::model()->findByAttributes( array('id' => 'tehsil_id' ) )->name,
),
array(
'name'=>'address_tag_id',
'value'=>AddressTag::model()->findByPk('address_tag_id'),
),
)
));
I am not able to fetch Tehsil_Name from Tehsil Table which has its ID inside CompanyAddress table.
Your using value attribute is wrong, check this:
'value'=>function($data){
return Utility::getTehsilName($data->tehsil_id);
},
value is a php expression that is evaluated to produce the contents of the gridview cell as below
'value' => 'Utility::getTehsilName($this->grid->controller->loadModel($data->tehsil_id))'
If you had used relation chaining to solve this your expression would have been simplified to say:
'value' => '$data->model1->tehsil->name'
where model1 is the middle relation.
I had created a yii Cgridview but how to make custom row in the it. I want to make the custom row whose data is static not related to database?
the problem is similar to below
http://www.yiiframework.com/forum/index.php/topic/47751-insert-first-row-in-cgridview/
insert static first row in cgridview yii
Check this grid row
array(
'name'=>'some_name',
'value'=>'$data->getCountryNameOrStaticStringOrWhatever()',
),
In model
public function getCountryNameOrStaticStringOrWhatever(){
return 'my static content or whatever';
}
you can do it with javascript and jQuery:
add 'afterAjaxUpdate' => 'addStaticRaw', to CGrid config
and register js script:
function addStaticRaw(){
$('#party-ledger-grid tbody tr:first').before("<tr><td>Your static raw blah blah</td></tr>");
}
I was looking for a similar solution and came across this:
$this->widget('zii.widgets.grid.CGridView', array(
'id'=>'something',
'dataProvider'=>$provider,
'columns'=>array(
array(
'name' => 'name',
'header' => 'Name',
'footer' => 'name column for extra row',
),
array(
'name' => 'email',
'header' => 'e-Mail',
'footer' => 'email column for extra row'
),
)
)
Simply fill out the footer elements of each column with the data from you extra row.
It works like a charm!
I'm getting foreign key relation based display ids in the gridviews. How to get values instead of ids? Code in my gridview is following:
$criteria->compare('education.UniversityNameid',$this->UniversityName, true);
my gridviews inside code
array(
'name' => 'UniversityName',
'type' => 'raw',
'value'=>'(empty($data->education->UniversityNameid))? "" : Yii::app()->params["currencySymbol"]." ".$data->education->UniversityNameid',
),
You have to set up a relation in your model "University" like this
public function relations() {
// NOTE: you may need to adjust the relation name and the related
// class name for the relations automatically generated below.
return array(
'UniversityName' => array(self::BELONGS_TO, 'University', 'UniversityNameid'),
);
}
thank you can access the Name
$data->education->UniversityName
Set the relation in your model like
'u' => array(self::BELONGS_TO, 'University', 'UniversityNameid'),
and acess it like
'attributes'=>array(
array('name'=>'u.UniversityName',
'label'=>'University',),
),
I want to get the data from two tables. I have used the below code to do so. I am new to Yii, if I am doing it the wrong way, please suggest the right way.
Here is the code of controller:
$dataProvider=new CActiveDataProvider('Users', array(
'criteria'=>array(
'with'=>'leave',
'together'=>true,
'condition'=>'leave.user_id=:user_id',
'params'=>array(':user_id'=>$this->loadModel(Yii::app()->user->getId())->user_id),
),
));
$this->render('admin',array(
'dataProvider'=>$dataProvider,
));
Here is the code of view:
$this->widget('zii.widgets.grid.CGridView', array(
'id'=>'users-grid',
'dataProvider'=>$dataProvider,
'columns'=>array(
array(
'header' => 'Leave Type',
'name'=>'leave_type',
'value'=>'$data->leave->leave_type',
),
'employee_code',
'username',
'password',
array(
'class'=>'CButtonColumn',
),
),
));
My Problem is:
I am joining two tables User and Leave. I want to get the data of users from Leave table as well as the users table. the above code shows me data from user table, when i try to show data from Leave table it throws me following error:
Trying to get property of non-object
UPDATE
Here is my user model relations:
return array(
'leaves' => array(self::HAS_MANY, 'Leaves', 'leave_id'),
'creator' => array(self::BELONGS_TO, 'Users', 'created_by'),
'updator' => array(self::BELONGS_TO, 'Users', 'modified_by'),
'leave' => array(self::HAS_MANY, 'Leaves', 'user_id'),
);
Here is my leave model relations:
return array(
'user' => array(self::BELONGS_TO, 'Users', 'user_id'),
'creator' => array(self::BELONGS_TO, 'Users', 'created_by'),
'updator' => array(self::BELONGS_TO, 'Users', 'modified_by'),
);
You can't display leave relation, because it's a HAS_MANY, I mean, in your $data->leave you have an array of Leave objects.
You should implement implode function, for example:
'value'=> "implode(', ', array_map(function($object) { return $object->leave_type; },
$data->leave))"
BTW, leave relation i think should be a HAS_ONE instead of HAS_MANY, and in this case, you don't need in an implode function in GridView
'value'=>'$data->leave->leave_type', // WRONG
$data->leave = array of objects and you could not access directly leave_type from it. That array was returned from your below relation:
'leave' => array(self::HAS_MANY, 'Leaves', 'user_id'),
I'm not sure the leave type which you want to access and relate it with user. But in this case, the solution is you can add more relation to just access first leave record of user
'singleLeave' => array(self::HAS_ONE, 'Leaves', 'user_id'), // add this line on Model User
And then you can access it properly
'value'=>'$data->singleLeave->leave_type',
Actually, in the first approach, the $data->leave should populate array of Leaves and from there, each Leave record should have to go into child views, and this is the point where you have to go detail
Suppose I have model User which have many to many relation to itself named as friends.
so $user->friends (or $model->friends in view) gives me an array of User objects. I wanted to display the friends as gridview. But CGridView data as dataProvider object. Googling for it found the way to convert array of model objects to dataProvider object as given below.
$this->widget('zii.widgets.grid.CGridView', array(
'id' => 'gridUser',
'dataProvider' => new CArrayDataProvider($model->friends, array()),
));
Now using this I get an error
Property "User.id" is not defined.
UPDATE
public function relations()
{
return array(
'friends' => array(self::MANY_MANY, 'User', 'friendship(user_id, friend_id)'),
);
}
I use two stage building the provider shown below. But I found that it gives you trouble in terms of Pagination. I have not bothered to resolve that problem since am doing other things
$dataProvider = new CArrayDataProvider('User');
$dataProvider->setData($model->friends);
$this->widget('zii.widgets.grid.CGridView', array(
'id' => 'gridUser',
'dataProvider' =>$dataProvider,
));
That being said, your code should work (see the example below from API docs). I suspect there is wrong attribute in your relations than the provided code. Re-check the relation definition if it is ok
From Yii docs:
$rawData=Yii::app()->db->createCommand('SELECT * FROM tbl_user')->queryAll();
// or using: $rawData=User::model()->findAll(); <--this better represents your question
$dataProvider=new CArrayDataProvider($rawData, array(
'id'=>'user',
'sort'=>array(
'attributes'=>array(
'id', 'username', 'email',
),
),
'pagination'=>array(
'pageSize'=>10,
),
));
Got it :) , i can use CActiveDataProvider instead of CArrayDataProvider as given below
$this->widget('zii.widgets.grid.CGridView', array(
'id' => 'gridUser',
'dataProvider' => new CActiveDataProvider('User', array(
'data'=>$model->friends,
)),
//...... columns display list.....
));
Anyways thanks for the reply #Stefano