Get result from SQL Query - php

I've got a MySQL query based on a database of ship information, this includes a field ship_name and the key ship_id.
I've written a query which uses the current_ship_id of the page, and finds the next ship based on the alphabetical list of ship_names.
This all works fine, HOWEVER, I'm trying to create a link using the below code in the 'IF' statement.
header("Location: shipinfo.php?ship_id=$next_ship_id");
What I don't know how to do is define the variable next_ship_id. I tried the line:
$next_ship_id = ($ship_id);
In theory, I want to get the result of the query $sql (of which I know there is only one result) and find it's ship_id.
How do I do that please?
$sql = " SELECT ship_infomation.ship_id
FROM ship_infomation
INNER JOIN (
SELECT ship_name
FROM ship_infomation
WHERE ship_id = $current_ship_id
) As current_ship
ON ship_infomation.ship_name < current_ship.ship_name
ORDER BY ship_infomation.ship_name ASC
LIMIT 1";
// echo "<br /><br />$sql<br /><br />";
$ships = mysql_query($sql, $ships) or die(mysql_error());
$row_ships = mysql_fetch_assoc($ships);
$totalRows_ships = mysql_num_rows($ships);
$next_ship_id = ($ship_id);
if ($totalRows_ships = 1)
{
header("Location: shipinfo.php?ship_id=$next_ship_id");
}
else
{
// remain on current page
}

For the next ship use:
SELECT ship_id
FROM ship_infomation
WHERE ship_id = (SELECT min(ship_id)
FROM ship_infomation
WHERE ship_id > $current_ship_id)
LIMIT 1
For the previous ship use:
SELECT ship_id
FROM ship_infomation
WHERE ship_id = (SELECT max(ship_id)
FROM ship_infomation
WHERE ship_id < $current_ship_id)
LIMIT 1
And at your code change this:
$ships = mysql_query($sql, $ships) or die(mysql_error());
$row_ships = mysql_fetch_assoc($ships);
$totalRows_ships = mysql_num_rows($ships);
$next_ship_id = ($ship_id);
if ($totalRows_ships = 1)
{
header("Location: shipinfo.php?ship_id=$next_ship_id");
}
else
{
// remain on current page
}
To this:
$ships = mysql_query($sql, $ships) or die(mysql_error());
$row = mysql_fetch_assoc($ships);
$totalRows_ships = mysql_num_rows($ships);
if ($totalRows_ships = 1)
{
header("Location: shipinfo.php?ship_id=" . $row['ship_id']);
}
else
{
// remain on current page
}
For the next and previous, on your code:
$go = isset($_GET['go']) ? $_GET['go'] : 'next';
if ($go == 'next')
$sql = "SELECT ship_id FROM ship_infomation WHERE ship_id = (SELECT min(ship_id) FROM ship_infomation WHERE ship_id > ". mysql_real_escape_string($current_ship_id) . ") LIMIT 1";
else
$sql = "SELECT ship_id FROM ship_infomation WHERE ship_id = (SELECT max(ship_id) FROM ship_infomation WHERE ship_id < ". mysql_real_escape_string($current_ship_id) . ") LIMIT 1";
And on your URL have it like this for the next ship:
http://mysite.com/ships.php?current_ship_id=15&go=next
And like this for the previous:
http://mysite.com/ships.php?current_ship_id=15&go=previous
If the go is not specified it will go to the previous ship by default.
There is no more support for mysql_* functions, they are officially deprecated, no longer maintained and will be removed in the future. You should update your code with PDO or MySQLi to ensure the functionality of your project in the future.

Related

i have difficulties with the sql part

I posted a code below about my website. In this code i want to update rows in my database, if the user changed the name of the topic on the website's form. Everything is working except the sql part. I mean the part where:"LIMIT 1 OFFSET '$x'" this part of the sql code is not good for some reason, but i don't know why. I tested it in xampp phpmyadmin and it works but here something just wrong.
<?php
$sql = "SELECT topicname, username, created, COUNT(commentid)
FROM user, topic, comment
WHERE topic.topicid = comment.whichtopic
AND user.userid = topic.owner
AND user.username = '" . $_SESSION['user_name '] . "'
GROUP BY topicname ";
$lekerdezes = mysql_query($sql);
$num_rows = mysql_num_rows($lekerdezes); ?>
<?php
if (isset($_POST['delete']))
{
if (!empty($_POST['forumnev']))
{
for ($x = 0; $x < $num_rows; $x++)
{
foreach ($_POST['forumnev'] as $selected)
{
$seged = mysql_query("SELECT created FROM topic WHERE
created IN (SELECT created FROM user, topic, comment WHERE topic.topicid = comment.whichtopic
AND user.userid = topic.owner AND user.username = '" . $_SESSION['user_name '] . "'
GROUP BY topicname ORDER BY created)
LIMIT 1 OFFSET '$x'");
if (!$seged)
{
echo mysql_error();
}
$seged2 = mysql_fetch_array($seged);
$seged2 = $seged2[0];
if (!$seged2)
{
echo mysql_error();
}
$sql = mysql_query("UPDATE topic SET topicname = '$selected' WHERE created = '$seged2'");
}
}
header("Location: topicedit.php");
}
}
?>
Try updating as follows:(Hope your limit: 1 and offset: $x)
$seged = mysql_query("SELECT created FROM topic WHERE created IN (SELECT created
FROM user,topic,comment
WHERE topic.topicid = comment.whichtopic
AND user.userid = topic.owner
AND user.username = '". $_SESSION['user_name'] ."'
GROUP BY topicname
ORDER BY created)
LIMIT $x, 1");

Multiple SQL If statements within PHP While loops

I've created a script to run on my database at five minute intervals as a cron job. It's not a well written piece of code, but it's done quickly and should do the job for now.
I'm executing a WHILE loop to execute multiple if statements which in turn have multiple SQL statements within them. Problem is, it's only iterating the WHILE loop once and then stops and i'm not entirely sure why. Code is as below:
<?php
require_once('config.php');
$hashtags = mysql_query("SELECT id, hashtag FROM hashtags WHERE enabled = '1'") or die(mysql_error());
while($row = mysql_fetch_array($hashtags))
{
$hashtag_id = $row['id'];
$hashtag = $row['hashtag'];
//Get id and latest_tweet_id from report log
$latest_report_tweet_id_query = mysql_query("SELECT id, latest_tweet_id FROM reports_log WHERE name = 'post_count' AND hashtag_id = '".$hashtag_id."' LIMIT 1") or die(mysql_error());
if (mysql_num_rows($latest_report_tweet_id_query) == 0) {
$new_report_tweet_id_query = mysql_fetch_array(mysql_query("SELECT tweet_id FROM tweet_tags WHERE tag = '".$hashtag."' ORDER by tweet_id desc LIMIT 1")) or die(mysql_error());
$new_report_tweet_id = $new_report_tweet_id_query['tweet_id'];
$post_count_query = mysql_fetch_array(mysql_query("SELECT count(tweet_id) as tweet_count FROM tweet_tags WHERE tag = '".$hashtag."' AND tweet_id <= '".$new_report_tweet_id."'")) or die(mysql_error());
$post_count = $post_count_query['tweet_count'];
if(mysql_query("INSERT INTO post_count_reports (timestamp, hashtag_id, post_count, latest_tweet_id) VALUES ('".date("Y-m-d H:i:s")."', '".$hashtag_id."', '".$post_count."', '".$new_report_tweet_id."')"))
{
//Get just created id of the report
$report_id_query = mysql_fetch_array(mysql_query("SELECT id FROM post_count_reports WHERE hashtag_id = '".$hashtag_id."' AND latest_tweet_id = '".$new_report_tweet_id."'")) or die(mysql_error());
$report_id = $report_id_query['id'];
if(mysql_query("INSERT INTO reports_log (timestamp, hashtag_id, name, latest_tweet_id, latest_report_id) VALUES ('".date('Y-m-d H:i:s')."', '".$hashtag_id."', 'post_count', '".$new_report_tweet_id."', '".$report_id."')"))
{
echo "Successfully created report! NEW";
}
else {
echo "Failed updating report log! NEW";
}
}
else
{
echo "Failed making report! NEW";
}
}
else {
//Set the latest report id
$latest_report_tweet_id_array = mysql_fetch_array($latest_report_tweet_id_query);
$latest_report_log_id = $latest_report_tweet_id_array['id'];
$latest_report_tweet_id = $latest_report_tweet_id_array['latest_tweet_id'];
//Query to get the latest tweet_id in the database
$new_report_tweet_id_query = mysql_fetch_array(mysql_query("SELECT tweet_id FROM tweet_tags WHERE tag = '".$hashtag."' ORDER by tweet_id desc LIMIT 1")) or die(mysql_error());
$new_report_tweet_id = $new_report_tweet_id_query['tweet_id'];
//Query to get the new post count from database
$new_post_count_query = mysql_fetch_array(mysql_query("SELECT count(tweet_id) as tweet_count FROM tweet_tags WHERE tag = '".$hashtag."' AND tweet_id > '".$latest_report_tweet_id."' AND tweet_id <= '".$new_report_tweet_id."'")) or die(mysql_error());
$new_post_count = $new_post_count_query['tweet_count'];
$old_post_count_query = mysql_fetch_array(mysql_query("SELECT id, post_count FROM post_count_reports ORDER by timestamp desc LIMIT 1")) or die(mysql_error());
$old_post_count = $old_post_count_query['post_count'];
$post_count = $old_post_count + $new_post_count;
if(mysql_query("INSERT INTO post_count_reports (timestamp, hashtag_id, post_count, latest_tweet_id) VALUES ('".date('Y-m-d H:i:s')."', '".$hashtag_id."', '".$post_count."', '".$new_report_tweet_id."')"))
{
//Get just created id of the report
$report_id_query = mysql_fetch_array(mysql_query("SELECT id FROM post_count_reports WHERE hashtag_id = '".$hashtag_id."' AND latest_tweet_id = '".$new_report_tweet_id."' ORDER by timestamp desc LIMIT 1")) or die(mysql_error());
$report_id = $report_id_query['id'];
if(mysql_query("UPDATE reports_log SET id = '".$latest_report_log_id."', timestamp = '".date('Y-m-d H:i:s')."', latest_tweet_id = '".$new_report_tweet_id."', latest_report_id = '".$report_id."' WHERE name = 'post_count'"))
{
echo "Successfully created report!";
}
else {
echo "Failed updating report log!";
}
}
else
{
echo "Failed making report!";
}
}
}
?>
Massive error on my part, turns out whilst there were three hashtags in the hashtags table there were only rows with one of the hashtags in the tweet_tags table. Wasted a few hours on this one.
Moral of the story, always log and check for errors!

Pagination Php not working when different sql query conditions are added

Hello I am facing a problem with my pagination system, where if I list results from a mysql table it is working fine, but in case If I add some conditions inside the SQL Query like "AND" this column "AND" other column the script shows the results properly on the first page, when I chooce the second page instead of showing the second portion of results from 26 forward it is starting a new pagination and it is showing everything from the begining without the contions added inside the query. Here is the code of the pagination with the query:
//This gets all the other information from the form
$ciudad=$_POST['ciudad'];
$tipo=$_POST['tipo'];
$con=mysqli_connect();
// Check connection
$sql = "SELECT * FROM cursos WHERE 1";
if (!empty($ciudad)) {
$sql .= " AND ciudad = '$ciudad' ";
}
if (!empty($tipo)) {
$sql .= " AND tipo= '$tipo' ";
}
if (!$result = mysqli_query($con,$sql))
{
die("Error: " . mysqli_error($con));
}
$per_page =25;//define how many games for a page
$count = mysqli_num_rows($result);
$pages = ceil($count/$per_page);
if(!isset($_GET['page']) || $_GET['page']=="") {
$page="1";
} else {
$page=$_GET['page'];
}
$start = ($page - 1) * $per_page;
$sql = "SELECT * FROM cursos WHERE 1 LIMIT $start,$per_page";
?>
This is the code of the generated pages links:
<?php
//Show page links
for ($i = 1; $i <= $pages; $i++)
{?>
<li id="<?php echo $i;?>"><?php echo $i;?></li>
<?php
}
?>
The 2 problems where:
additional filter are not anymore selected in the next page ($_POST will be empty)
instructions related to pagination where calculated AFTER the query (which, obviously, couldn't use theses parameters)
You can either store your extra queries conditions in session, or add it as parameter in the "next page link", or transform your link to a submit form (which is probably the best option)
<li id="<?php echo $i;?>"><?php echo $i;?></li>
If you choose the link solution, don't forget to change your _POST in _GET (or check the second if the first is empty, or use $_REQUEST)
I have to mention your code is not sql injection free and using mysqli_prepare() may worth the time (for security and performances)
EDIT: so, here we go:
sidenotes: using $_REQUEST is not always recommended
And I noticed also you execute your query BEFORE using the pagination system...
//This gets all the other information from the form
$ciudad=$_REQUEST['ciudad'];
$tipo=$_REQUEST['tipo'];
$con=mysqli_connect();
// Check connection
$sql = "SELECT * FROM cursos WHERE 1";
if (!empty($ciudad)) {
$sql .= " AND ciudad = '$ciudad' ";
}
if (!empty($tipo)) {
$sql .= " AND tipo= '$tipo' ";
}
// PAGINATION MOVED UP
$per_page =25;//define how many games for a page
$count = mysqli_num_rows($result);
$pages = ceil($count/$per_page);
if(empty($_GET['page'])) {
$page="1";
} else {
$page=$_GET['page'];
}
$start = ($page - 1) * $per_page;
$sql .= ' LIMIT '.$start.','.$per_page;
if (!$result = mysqli_query($con,$sql))
{
die("Error: " . mysqli_error($con));
}
//Show page links
for ($i = 1; $i <= $pages; $i++)
{?>
<li id="<?php echo $i;?>"><?php echo $i;?></li>
<?php
}
?>
If $ciudad and $tipo both are not empty your query on execution will look like this:
SELECT * FROM cursos WHERE 1 AND ciudad = '$ciudad' ORDER BY id DESC AND tipo= '$tipo' ORDER BY id DESC
It should be like this if i am not mistaken:
SELECT * FROM cursos WHERE 1 AND ciudad = '$ciudad' AND tipo= '$tipo' ORDER BY id DESC
What I would do is change this:
$sql = "SELECT * FROM cursos WHERE 1";
if (!empty($ciudad)) {
$sql .= " AND ciudad = '$ciudad' ORDER BY id DESC ";
}
if (!empty($tipo)) {
$sql .= " AND tipo= '$tipo' ORDER BY id DESC ";
}
too this:
$sql = "SELECT * FROM cursos WHERE 1 ";
if (!empty($ciudad)) {
$sql .= "AND ciudad= '$ciudad' ";
if (!empty($tipo)) {
$sql .= "AND tipo= '$tipo' ";
}
$sql .= "ORDER BY id DESC ";
}
I've also got a link which might help you out with the pagination.
http://www.phpjabbers.com/php--mysql-select-data-and-split-on-pages-php25.html
If city and type are set then your SQL will have two instances of order by... You should add order by after the if statements.

php/mysql with multiple queries

<?php
$query1 = "CREATE VIEW current_rankings AS SELECT * FROM main_table WHERE date = X";
$query2 = "CREATE VIEW previous_rankings AS SELECT rank FROM main_table WHERE date = date_sub('X', INTERVAL 1 MONTH)";
$query3 = "CREATE VIEW final_output AS SELECT current_rankings.player, current_rankings.rank as current_rank LEFT JOIN previous_rankings.rank as prev_rank
ON (current_rankings.player = previous_rankings.player)";
$query4 = "SELECT *, #rank_change = prev_rank - current_rank as rank_change from final_output";
$result = mysql_query($query4) or die(mysql_error());
while($row = mysql_fetch_array($result)) {
echo $row['player']. $row['current_rank']. $row['prev_rank']. $row['rank_change'];
}
?>
All the queries work independently but am really struggling putting all the pieces together in one single result so I can use it with mysql_fetch_array.
I've tried to create views as well as temporary tables but each time it either says table does not exist or return an empty fetch array loop...logic is there but syntax is messed up I think as it's the 1st time I had to deal with multiple queries I need to merge all together. Looking forward to some support. Many thanks.
Thanks to php.net I've come up with a solution : you have to use (mysqli_multi_query($link, $query)) to run multiple concatenated queries.
/* create sql connection*/
$link = mysqli_connect("server", "user", "password", "database");
$query = "SQL STATEMENTS;"; /* first query : Notice the 2 semicolons at the end ! */
$query .= "SQL STATEMENTS;"; /* Notice the dot before = and the 2 semicolons at the end ! */
$query .= "SQL STATEMENTS;"; /* Notice the dot before = and the 2 semicolons at the end ! */
$query .= "SQL STATEMENTS"; /* last query : Notice the dot before = at the end ! */
/* Execute queries */
if (mysqli_multi_query($link, $query)) {
do {
/* store first result set */
if ($result = mysqli_store_result($link)) {
while ($row = mysqli_fetch_array($result))
/* print your results */
{
echo $row['column1'];
echo $row['column2'];
}
mysqli_free_result($result);
}
} while (mysqli_next_result($link));
}
EDIT - The solution above works if you really want to do one big query but it's also possible to execute as many queries as you wish and execute them separately.
$query1 = "Create temporary table A select c1 from t1";
$result1 = mysqli_query($link, $query1) or die(mysqli_error());
$query2 = "select c1 from A";
$result2 = mysqli_query($link, $query2) or die(mysqli_error());
while($row = mysqli_fetch_array($result2)) {
echo $row['c1'];
}
It seems you are not executing $query1 - $query3. You have just skipped to $query4 which won't work if the others have not been executed first.
Also
$query4 = "SELECT *, #rank_change = prev_rank - current_rank as rank_change from final_output";
should probably be
$query4 = "SELECT *, #rank_change := prev_rank - current_rank as rank_change from final_output";
or else the value of rank_change will just be a boolean, true if #rank_change is equal to (prev_rank - current_rank), false if it is not. But do you need #rank_change at all? Will you use it in a subsequent query? Maybe you can remove it altogether.
Even better, you could just combine all the queries into one like this:
SELECT
curr.player,
curr.rank AS current_rank,
#rank_change := prev.rank - curr.rank AS rank_change
FROM
main_table AS curr
LEFT JOIN main_table AS prev
ON curr.player = prev.player
WHERE
curr.date = X
AND prev.date = date_sub('X', INTERVAL 1 MONTH)
You should concatenate them:
<?php
$query = "CREATE VIEW current_rankings AS SELECT * FROM main_table WHERE date = X";
$query .= " CREATE VIEW previous_rankings AS SELECT rank FROM main_table WHERE date = date_sub('X', INTERVAL 1 MONTH)";
$query .= " CREATE VIEW final_output AS SELECT current_rankings.player, current_rankings.rank as current_rank LEFT JOIN previous_rankings.rank as prev_rank
ON (current_rankings.player = previous_rankings.player)";
$query .= " SELECT *, #rank_change = prev_rank - current_rank as rank_change from final_output";
$result = mysql_query($query) or die(mysql_error());
while($row = mysql_fetch_array($result)) {
echo $row['player']. $row['current_rank']. $row['prev_rank']. $row['rank_change'];
}
?>

How can I optimise this mysql/php query?

My page displays an image, and I want to display the previous and next image that is relevant to the current one. At the moment I run the same query 3x and modify the "where" statement with =, >, <.
It works but I feel there must be a better way to do this.
The image id's are not 1,2,3,4,5. and could be 1,2,10,20,21 etc. But if it is much more efficient I am willing to change this.
mysql_select_db("database", $conPro);
$currentid = mysql_real_escape_string($_GET['currentid']);
$query ="SELECT * FROM database WHERE id ='".$currentid."' LIMIT 1 ";
$result = mysql_query($query,$conPro) or die(mysql_error());
$affected_rows = mysql_num_rows($result);
if ($affected_rows==1)
{
$row = mysql_fetch_array($result)or die ('error:' . mysql_error());
$current_id = $row['id'];
$current_header = $row['title'];
$current_description =$row['desc'];
$current_image = "http://".$row['img'];
$current_url = "http://".$row['id']."/".$db_title."/";
$current_thumb = "http://".$row['cloud'];
}
mysql_select_db("database", $conPro);
$query ="SELECT * FROM database WHERE id <'".$currentid."' ORDER BY id DESC LIMIT 1 ";
$result = mysql_query($query,$conPro) or die(mysql_error());
$affected_rows = mysql_num_rows($result);
if ($affected_rows==1)
{
$row = mysql_fetch_array($result)or die ('error:' . mysql_error());
$previous_id = $row['id'];
$previous_header = $row['title'];
$previous_description =$row['desc'];
$previous_image = "http://".$row['img'];
$previous_url = "http://".$row['id']."/".$db_title."/";
$previous_thumb = "http://".$row['cloud'];
}else{
$previous_none = "true"; //no rows found
}
mysql_select_db("database", $conPro);
$query ="SELECT * FROM database WHERE id >'".$currentid."' ORDER BY id ASC LIMIT 1 ";
$result = mysql_query($query,$conPro) or die(mysql_error());
$affected_rows = mysql_num_rows($result);
if ($affected_rows==1)
{
$row = mysql_fetch_array($result)or die ('error:' . mysql_error());
$next_id = $row['id'];
$next_header = $row['title'];
$next_description =$row['desc'];
$next_image = "http://".$row['img'];
$next_url = "http://".$row['id']."/".$db_title."/";
$next_thumb = "http://".$row['cloud'];
}else{
$next_none = "true"; //no rows found
}
mysql_close($conPro);
Thank you for your time
You don't have to do select_db each time. Once you 'select' a db, it stays selected until you select something else.
You can't really get away from doing two separate queries to get the next/previous images, but you can fake it by using a union query:
(SELECT 'next' AS position, ...
FROM yourtable
WHERE (id > $currentid)
ORDER BY id ASC
LIMIT 1)
UNION
(SELECT 'prev' AS position, ...
FROM yourtable
WHERE (id < $currentid)
ORDER BY id DESC
LIMIT 1)
This would return two rows, containing a pseudofield named 'position' which will allow you to easily identify which row is the 'next' record, and which is the 'previous' one. Note that the brackets are required so that the 'order by' clauses apply to the individual queries. Without, mysql will take the order by clause from the last query in the union sequence and apply it to the full union results.
You can get the "previous" one first WHERE id <'".$currentid."' ORDER BY id DESC, and then query for two "above" it: SELECT * FROM database WHERE id >= '".$currentid."' ORDER BY id ASC then it takes only two queries instead of three.

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