php dynamically create multi dimensional array

php dynamically create multi dimensional array - php

Try this
After you do this:
$result_mens_senior = mysqli_query($link,$get_mens_senior_query);
$result_mens_inter = mysqli_query($link,$get_mens_inter_query);
$result_ladies= mysqli_query($link, $get_ladies_query);
just do this
while ($standings_men_senior[] = mysqli_fetch_assoc($result_mens_senior)){}
while ($standings_men_inter[] = mysqli_fetch_assoc($result_mens_inter)){}
while ($standings_ladies[] = mysqli_fetch_assoc($result_ladies)){}
Basically all of the posted code should be able to be replaced with:
<?php
$ladies_query = "SELECT `team_name`, `played`, `won`, `drawn`, `lost`, `for`, `against`, `points`
FROM `standings_ladies` order by pos";
$inter_query = "SELECT `team_name`, `played`, `won`, `drawn`, `lost`, `for`, `against`, `points`
FROM `standings_men_inter` order by pos";
$senior_query = "SELECT `team_name`, `played`, `won`, `drawn`, `lost`, `for`, `against`, `points`
FROM `standings_men_senior` order by pos";
$ladies_stmt = mysqli_query($link, $ladies_query) || die ("Couldn't get Ladies"); // reminds me of high school
$inter_stmt = mysqli_query($link, $inter_query) || die ("Couldn't get Inter");
$senior_stmt = mysqli_query($link, $serior_query) || die ("Couldn't get Seniors");
$standings_men_senior = array();
$standings_men_inter = array();
$standings_ladies = array();
while ($row = mysqli_fetch_assoc($senior_stmt)){
$standings_men_senior[] = $row;
}
while ($row = mysqli_fetch_assoc($inter_stmt)){
$standings_men_inter[] = $row;
}
while ($row = mysqli_fetch_assoc($ladies_stmt)){
$standings_ladies[] = $row;
}

Don't try to put everything in a single loop, it significantly reduces your code clarity and will give you little to no gain in performance, there is a term for this and it's called micro-optimization, and you should never do it unless it is really necessary (a bottleneck on a large site).
Now, what I suggest to you is to remake your loop and make it as clear as possible as to how data is manipulated.
The most important thing in your case is to debug, print_r the content of your arrays on every step of the process to check what it contains, from the database to the end of your code, you will find where the problem is.

Related

Display unique results and count duplicate results multi-dimentional array

Here is my multi-dimensional array:
Array
(
[0] => Array
(
[H2H_Id] => T32
[Team1_Id] => T4
[Team1] => Juan Arraya - Max LePivert
[Team2_Id] => T205
[Team2] => Marco Grangeiro - Jeff Morneau
[Winners_Id] => T4
[MatchUps_Id] => M32
)
[1] => Array
(
[H2H_Id] => T39
[Team1_Id] => T205
[Team1] => Marco Grangeiro - Jeff Morneau
[Team2_Id] => T4
[Team2] => Juan Arraya - Max LePivert
[Winners_Id] => T205
[MatchUps_Id] => M32
)
[2] => Array
(
[H2H_Id] => T9
[Team1_Id] => T3
[Team1] => Marco Grangeiro - George Wilkinson
[Team2_Id] => T4
[Team2] => Juan Arraya - Max LePivert
[Winners_Id] => T4
[MatchUps_Id] => M9
)
)
I want the output to be:
Juan Arraya - Max LePivert 1 vs. 1 Marco Grangeiro - Jeff Morneau
Juan Arraya - Max LePivert 1 vs. 0 Marco Grangeiro - George Wilkinson
So basically, I want to display the different match ups separately by using MatchUps_Id and print the names of the teams Team1 and Team2. Based on the Winners_Id I want to add a counter to keep track of the wins per team per match up.
Keep in mind that these results are coming from user inputs which will make the multi-dimensional array different every time I request input from the user passed on by field1 and field2.
This is what I have so far in code:
$query2 = "SELECT HeadToHead.H2HNo H2H_Id, H2HTeam1Id Team1_Id, H2HTeam1 Team1, H2HTeam2Id Team2_Id, H2HTeam2 Team2, WinnersId Winners_Id, MatchUps.MatchUpsNo MatchUps_Id
FROM HeadToHead
JOIN MatchUps ON HeadToHead.MatchUpsNo=MatchUps.MatchUpsNo
WHERE ((H2HTeam1 LIKE '%$field1%' OR H2HTeam2 LIKE '%$field1%') AND (H2HTeam1 LIKE '%$field2%' OR H2HTeam2 LIKE '%$field2%'))";
$result2 = mysql_query($query2);
$num2 = mysql_num_rows($result2);
$arr2 = array();
if($num2 > 0) {
while($row2 = mysql_fetch_assoc($result2)) {
$arr2[] = $row2;
}
}
I get the desired results from the code above.
I think I have done a lot of research on this matter but what I am trying to accomplish seems to be different than what is out there.
Any help is much appreciated.

You can group the matchups together by 'MatchUps_Id' like this:
foreach ($arr2 as $match) {
// create some short ids to make the next part more readable
$id = $match['MatchUps_Id'];
$t1 = $match['Team1_Id'];
$t2= $match['Team2_Id'];
if (!isset($matchups[$id][$t1]['name'])) {
// initialize if this matchup has not yet been created
$matchups[$id][$t1]['name'] = $match['Team1'];
$matchups[$id][$t2]['name'] = $match['Team2'];
$matchups[$id][$t1]['wins'] = (int) ($match['Winners_Id'] == $match['Team1_Id']);
$matchups[$id][$t2]['wins'] = (int) ($match['Winners_Id'] == $match['Team2_Id']);
} else {
// increment wins if the matchup already exists
$matchups[$id][$t1]['wins'] += $match['Winners_Id'] == $match['Team1_Id'];
$matchups[$id][$t2]['wins'] += $match['Winners_Id'] == $match['Team2_Id'];
}
}
Using $t1 and $t2 as second-level keys allows you to increment the win count for respective teams without needing to know which one is which. The expression $match['Winners_Id'] == $match['Team1_Id'] returns a boolean, which will be implicitly cast to an integer 0 or 1 when used with +=, but must be explicitly cast using (int) when initializing.
After you have grouped your array and counted the wins, you can output the results like this:
foreach ($matchups as $matchup) {
list($a, $b) = array_values($matchup);
echo "$a[name] $a[wins] vs. $b[wins] $b[name]<br>";
}

php mysql check if vendor has 3 low consecutive ratings

Here's one way you can begin approaching this - completely in SQL:
Get the last rating for the vendor. ORDER BY date DESC, limit 1.
Get the second to last rating for the vendor. ORDER BY date DESC, limit 1, OFFSET 1.
Then write a query that does a LEFT join of the first two tables. You will have a dataset that has three columns:
vendor id
last rating
second to last rating
Then you can write an expression that says "if column1 is <3 and column2 < 3, then this new column is true"
You should be able to extend this to three columns relatively easily.

Here is what a came up with to solve this riddle. I think explaining it on here helped as well as Alex also helped as he keyed my brain on using the date. I first started looking at using if statment inside of the query and actually that got my brain out of the box and then it hit me what to do.
It is not perfect and certainly could use some trimming to reduce the code, but i understand it and it seems to work, so that is par for me on this course.
the query...
$sql = "SELECT `rvid`, `ratedate`,`rating` FROM `vendor_ratings_archive` WHERE `rating` <= '3' ORDER BY `ratedate`, `rvid` DESC";
which gives me this
Array
(
[0] => Array
(
[rvid] => 7
[ratedate] => 2016-05-01
[rating] => 2
)
[1] => Array
(
[rvid] => 5
[ratedate] => 2016-05-01
[rating] => 1
)
[2] => Array
(
[rvid] => 5
[ratedate] => 2016-05-01
[rating] => 0
)
[3] => Array
(
[rvid] => 5
[ratedate] => 2016-05-01
[rating] => 3
)
)
notice how vendor (rvid) 5 is grouped together which is an added plus.
next a simple foreach to load a new array
foreach($results as $yield)
{
$rvidarray[] = $yield['rvid'];
}//close foreach
which gives me this
Array
(
[0] => 7
[1] => 5
[2] => 5
[3] => 5
)
then we count the array values to group dups
$rvidcounter = array_count_values($rvidarray);
which results in this
Array(
[7] => 1
[5] => 3
)
so now vender 7 as 1 low score and vendor 5 has 3 low scores and since they were already sorted by date i know that its consecutive. Well it sounds good anyway lol ")
then we create our final array with another foreach
foreach($rvidcounter as $key => $value)
{
//anything 3 or over is your watchlist
if($value > 2)
{
$watchlist[] = $key; //rvid number stored
}
}//close foreach
which gives me this
Array
(
[0] => 5
)
this was all done in a service function. So the final deal is everyone in this array has over 3 consecutive low ratings and then i just use a returned array back in my normal php process file and grab the name of each vender by id and pass that to the html and print out the list.
done...
please feel free to improve on this if you like. I may or may not use it because the above code makes sense to me. Something more complicated may not make sense to me 6 mos from now lol But it would be interesting to see what someone comes up with to shorten the process a bit.
Thanks so much and Happy Coding !!!!!
Dave :)

You could do it in SQL like that:
SET #rvid = -1;
SELECT DISTINCT rvid FROM
(
SELECT
rvid,
#neg := rating<3, /* 0 or 1 for addition in next line */
#count := IF(#rvid <> rvid , #neg, #count+#neg) AS `count`, /* set or add */
#rvid := rvid /* remember last row */
FROM
testdb.venrate
ORDER BY
rvid, datetime desc
) subq
WHERE count>=3
;
You set a variable to a non existing id. In each chronologically sorted row you check if rating is too low, that results in 1 (too low) or 0 (ok). If rvid is not equal to the last rvid, it means a new vender section is beginning. On begin of section set the value 0 or 1, else add this value. Finally store the current row's rvid for comparison in next row process.
The code above is looking for 3 consecutive low ratings (low means a value less than 3) over all the time.
A small modification checks if all the latest 3 ratings has been equal to or less than 3:
SET #rvid = -1;
SELECT DISTINCT
rvid
FROM
(
SELECT
rvid,
#high_found := rating>3 OR (#rvid = rvid AND #high_found) unflag,
#count := IF(#rvid <> rvid , 1, #count+1) AS `count`,
#rvid := rvid /* remember last row */
FROM
testdb.venrate
ORDER BY
rvid, datetime desc
) subq
WHERE count=3 AND NOT unflag
;

How to take value from First array and generate second array and put the second array in the first array?

I have tried many ways to do this but no luck. I'm trying to take value from First array and generate second array and put the second array in the first array.
The code that I have now, generate the first array, in this array I have column called prereq_id I need to take this value and match it with courses table to bring its information in the courses table course_id=prereq_id. Any help would be highly appreciated
The array output is like this right now
[course_id] => 2
[curriculum_id] => 1
[set_number] => 0
[course_code] => GCIS 516
[course_name] => Data-Centric Concepts and Methods
[credits] => 3
[semester_ava] => 2
[prereq_id] => 10
[set] => 3
php
$result2 = $mysqli->query("SELECT *
FROM curriculumcourses
INNER JOIN courses ON curriculumcourses.course_id = courses.course_id
LEFT JOIN prerequisites ON courses.course_id=prerequisites.course_id
WHERE curriculum_id='$ids' ");
?>
<?php
for ($x = 1; $x <= $mysqli->affected_rows; $x++) {
$rows[] = $result2->fetch_assoc();
}
echo "<pre>";
print_r($rows);
echo "</pre>";
The result I need look like this
[course_id] => 2
[curriculum_id] => 1
[set_number] => 0
[course_code] => GCIS 516
[course_name] => Data-Centric Concepts and Methods
[credits] => 3
[semester_ava] => 2
[prereq_id] => 10
[set] => 3
[course_code] => GCIS 508
[course_name] =>Database Management Systems
[credits] => 3
[semester_ava] => 1

check if a value exist in array from database query

I am trying to build a website that will display the text in multiple languages.
I have a table 'text' with all the languages. If the text does not exist in the chosen language it has to display the default language.
query SELECT * FROM text WHERE TextId = 10
results in
Id TextId LanguageId Text
10 10 1 first name
13 10 2 名前
If I r_print this result I get something like this
Array ( [0] => Array ( [0] => 10 [Id] => 10 [1] => 10 [TextId] => 10 [2] => 1 [LanguageId] => 1 [3] => first name [Text] => first name )
[1] => Array ( [0] => 13 [Id] => 13 [1] => 10 [TextId] => 10 [2] => 2 [LanguageId] => 2 [3] => 名前 [Text] => 名前 ) )
How can I check that LanguageId 2 exist in this array ?
the problem is that it is possible that TextId 2 and Id 2 can also exist in this array.
Is this possible to do with in_array()?

Here is a function that can check if LanguageId equals a special value .
function isLanguageIdExists($yourArray , $LanguageId){
$exists=false;
foreach($yourArray as $array){
if(isset($array['LanguageId'])&& $array['LanguageId'] == $LanguageId){
$exists=true;break;
}
}
return $exists;
}
$exist = isLanguageIdExists($yourArray , 2);//return true or false

You can check by isset the key and match the value in php.
$dataArray = array(
0 => array(0 => 10 ,'Id' => 10, 1 => 10, 'TextId' => 10, 2 => 1, 'LanguageId' => 1),1 => array(0 => 10 ,'Id' => 10, 1 => 10, 'TextId' => 10, 2 => 1, 'LanguageId' => 1)
);
foreach($dataArray as $value) {
if(isset($value['LanguageId']) && $value['LanguageId'] == 2) {
echo 'language ID 2 is available';
}
}
Working Demo

After giving this some more thought I came up with a maybe not so elegant solution.
Instead of getting an array back I modified the SQL Query to give one row back with the default language (English) and a user selected language (Japanese).
It uses two left joins. This shows that I received (some) training in SQL but am really not at ease with multidimensional arrays.
Query
def_text = text in default language
usr_text = text in user chosen language
$table01 = "text";
$query="SELECT $table01.TextId,
text_def.Text as def_text,
text_usr.Text as usr_text
FROM $table01
LEFT JOIN $table01 as text_def ON $table01.TextId = text_def.TextId AND text_def.LanguageId = $_SESSION[default_language]
LEFT JOIN $table01 as text_usr ON $table01.TextId = text_usr.TextId AND text_usr.LanguageId = $_SESSION[language]
WHERE $table01.TextId=$mess;";
after getting back the results it is easy to check with isset() or empty() to see if the text is available in the user selected language

How do i get this data in the proper format?

You can fetch fill a multi-dimensional array while fetching the SQL result or split into several SQL commands and therefore build up your array (1st fetching the names, than the products with values of every name).
I do not know which you prefer but as you have a large join splitting the SQL might not be the worst in terms of readability of your code. Performance impact may vary.

Methinks this will do it
<?php
$finalArray = array();
$nameArray = array('Screens', 'Printers', 'Cash Drawers');
foreach ($nameArray as $name) {
while ($row = mysql_fetch_assoc($result)) {
if ($row['name'] == $name) {
if ($row['class_id'] == 1) {
$standard = array('id' => $row['system_step_product_id'], 'price' => $row['cost']);
}
else if ($row['class_id'] == 2) {
$business = array('id' => $row['system_step_product_id'], 'price' => $row['cost']);
}
else if ($row['class_id'] == 3) {
$premium = array('id' => $row['system_step_product_id'], 'price' => $row['cost']);
}
}
}
array_push($finalArray, array('name' => $name, 'standard_product' => $standard, 'business_product' => $business, 'premium_product' => $premium,));
}
?>
Hopefully I got all the column names right.
This is what I tested it off of and I get the correct output http://codepad.org/yjU3gxbB
The only thing you may what to change is creating the name array dynamically
while ($row = mysql_fetch_assoc($result)) {
array_push($nameArray, $row['name']);
}
$nameArray = array_unique($nameArray);
However, PHP doesn't like it when you do a mysql_fetch_assoc twice on the same query. You might want to do another query where you only select the cd.name

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php dynamically create multi dimensional array - php

Related

Display unique results and count duplicate results multi-dimentional array

php mysql check if vendor has 3 low consecutive ratings

How to take value from First array and generate second array and put the second array in the first array?

check if a value exist in array from database query

How do i get this data in the proper format?

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