loop to populate html table vertically [duplicate] - php

Question

This question already has answers here:
Transposing multidimensional arrays in PHP
(12 answers)
Closed 1 year ago.
I have a mysql query that returns an array of rows. How would i populate my html table using php vertically? there is no limit to how many columns i my HTML table allowed.
My MYSQL query returns about 40 columns per row.
MYSQL row1 => 10|11|12|13|14|15|16|17|18|19
row2 => 20|21|22|23|24|25|26|27|28|29
row3 => 30|31|32|33|34|35|36|37|38|39
HTML output should look like this
10 | 20 | 30
11 | 21 | 31
12 | 22 | 32
13 | 23 | 33
14 | 24 | 34
15 | 25 | 35
16 | 26 | 36
17 | 27 | 37
18 | 28 | 38
19 | 29 | 39
this is my code, and it's displaying nothing.
$values = array();
$sql = "SELECT * FROM `TABLE_NAME` ORDER BY `id` ASC LIMIT 0,12";
$result = $_db->query($sql);
$numrows = $_db->num_rows($result);
$c = 1;
while ($c <= $numrows)
{
$values['col_'.$c] = array();
$c++;
}
$r = 1;
while ($row = $_db->fetch_array($result))
{
$values['col_'.$c][$r] = $row;
$r++;
}
echo "<table border='1'>";
for ($r = 1; $r <= $numrows; $r++)
{
echo "<tr>";
for ($c = 1; $c <= sizeof($values['col_1']); $c++)
{
echo "<td>".$values['col_'.$c][$r]."</td>";
}
echo "</tr>" ;
}
echo "</table>" ;
Any idea what i'm doing wrong? or how to make it simpler? (i think there are too many while loops)

Answer 1

I think what you want is creating the php array from the mysql query, transposing the array (like you would transpose a matrix) and display it.
Transposing an array is a solved problem (transposing multidimentional arrays in php)
For the rest, it is pretty simple ... here is my code:
$res = mysqli_query(...);
$anarr = array();
while ($row = mysqli_fetch_array($res,$result_type=MYSQLI_ASSOC)){
$anarr[] = $row;
}
// here is the transpose part
array_unshift($anarr, null);
$transposedarr = call_user_func_array('array_map', $anarr);
// end of the transpose part
echo '<table>';
foreach ($transposedarr as $r){
echo '<tr>';
foreach ($r as $c){
echo '<td>'.$c.'</td>';
}
echo '</tr>';
}
echo '</table>';
?>

Answer 2

You are assigning only one row in your while loop. Change that with below code:
while ($row = $_db->fetch_assoc($result))
{
$values['col_'.$c][$r] = $row;
$c++;
$r++;
}
Here you are assigning the value to $value['col_1'][$r] and not increasing the value of $c. So at the end it override the values.

Answer 3

You can simplify the problem by just saying
$values[$rowIndex] = $columnArray
So in this case
$values[0] = array( 10, 20, 30 );
$values[1] = array( 11, 21, 31 );
And then loop across each array
echo "<table border='1'>";
foreach( $values as $row )
{
echo "<tr>";
foreach( $row as $columnValue )
{
echo ..whatever..
}
echo "<tr>";
}
echo "</table>" ;
Or something along these lines. I just basically psuedo coded this though, I have no access to php interpreter right now.

Answer 4

//while and foreach loop can do this
<?php
$values = array();
$sql = "SELECT * FROM `TABLE_NAME` ORDER BY `id` ASC LIMIT 0,12";
$result = $_db->query($sql);
$numrows = $_db->num_rows($result);
//check here
if($numrows>0)
{
//1 row
$r = 1;
//column
$c=0;
while ($row = $_db->fetch_assoc($result))
{
//value row column
$values[$r][$c] = $row;
//column == 3
if($c==2)
{
//increase row
$r++;
//reset column
$c = 0;
}else{
$c++;
}
}
echo "<table border='1'>";
//display row and columns
foreach($values as $row)
{
echo "<tr>";
echo "<td>".$values[0]."</td>";
echo "<td>".$values[1]."</td>";
echo "<td>".$values[2]."</td>";
echo "</tr>" ;
}
echo "</table>" ;
}

Answer 5

You can do everything in a single loop. Additionally, at least for your purposes in this example, I don't understand why you're putting everything in an array and then echo, instead of echoing it directly.
e.g. (tested):
$sql = "SELECT * FROM `TABLE_NAME` ORDER BY `id` ASC LIMIT 0,12";
$result = $_db->query($sql);
echo "<table border='1'>";
$tab = array();
while ($row = $result->fetch_row())
{
$tab[] = $row;
}
for( $i = 0, $l = count($tab[$i]); $i < $l; $i++){
echo "<tr>";
for( $j = 0, $m = count($tab); $j < $m; $j++){
echo "<td>".$tab[$j][$i]."</td>";
}
echo "</tr>" ;
}
echo "</table>";
UPDATE: I completely changed my code. I didn't get initially what you needed.
Does this code help you?

Answer 6

This is how I would tackle it. The most difficult part is preparing the structure in which you prepare the table. It uses the following syntax: $somearray[] = $x, which appends $x to array $somearray. implode() concats an array together with a string you define. Last but not least, you were using mysql_fetch_assoc, which returns an associative array (Array( [column1] => "val1" ); etc). You want a numbered array instead for these kind of operations. This can be accomplished with mysql_fetch_array with a second argument of MYSQL_NUM.
$arrayOfRows = Array();
$sql = "SELECT * FROM `TABLE_NAME` ORDER BY `id` ASC LIMIT 0,12";
$result = $_db->query($sql);
$firstrun = true;
while( $row = $_db->fetch_array($result, MYSQL_NUM) ) {
#Setup structure on first run
if( $firstrun ) {
$firstrun = false;
for( $i = 0; $i < count( $row ); $i++ ) {
$arrayOfRows[$i] = Array();
}
}
#Each field in this mysql row needs to be in a different html row
foreach( $row as $k => $v ) {
$arrayOfRows[$k][] = $v;
}
}
#Now simply print it
echo '<table>';
foreach( $arrayOfRows as $k => $row ) {
echo '<tr>';
echo '<td>' . implode( '</td><td>', $row ) . '</td>';
echo '</tr>';
}
echo '</table>';

Answer 7

<?php
$arr = array(array(1,2,3,4,5,6,7,8,9), array(10,11 etc . . .
for($i = 0; $i < 9; ++ $i){
for($x = 0; $x < $num_rows; ++ $x){
echo $arr[$x][$i];
}
echo '<br/>';
}
?>
U may replace 9 with number of columns in tables
I not shure what it this code correct (can't test now), but i think it can help you
Sorry if i do something wrong, i just try to help