Echo variable which has same name in php join - php

Question

I have a mysql join which is pulling from two tables name product & cart and they're both being pulled from a variable $row_checkout
If i have to echo a certain field, i can normally go $row_checkout['cartid'] and that works fine.
However, i have a coloumn in each table which is called the same 'Status'.
How do i echo from one of the tables? I thought something like $row_checkout['cart.status'] might work but it doesnt appear to?
My database code is as follows:
$colname_checkout = "-1";
if (isset($row_booking['sessionid'])) {
$colname_checkout = (get_magic_quotes_gpc()) ? $row_booking['sessionid'] : addslashes($row_booking['sessionid']);
}
mysql_select_db($database_main, $main);
$query_checkout = sprintf("SELECT * FROM cart, productdatabase WHERE cart.productid = productdatabase.productid AND cart.status != 1 AND cart.status != 0 AND cart.sessionid = '%s' ORDER BY `name` ASC", $colname_checkout);
$checkout = mysql_query($query_checkout, $main) or die(mysql_error());
$row_checkout = mysql_fetch_assoc($checkout);
$totalRows_checkout = mysql_num_rows($checkout);

Answer 1

You can use alias to change a tables field name, to a name that you want.
the cart.status filter, you could make simpler, simpler by asking > 1
SELECT c.status as car_status, pro.status as pro_status
FROM cart as c, productdatabase as pro
WHERE c.productid = pro.productid AND c.status >1 AND c.sessionid = '%s'
ORDER BY `name` ASC", $colname_checkout
Seeing what you get, it will display an associative array with all names and values, that you can use to address the data
while ($row_checkout = mysql_fetch_assoc($checkout)) {
print_r($row_checkout);
}
or specific the fields:
while ($row_checkout = mysql_fetch_assoc($checkout)) {
echo $row_checkout["car_status"];
echo $row_checkout["pro_status"];
}
another comment, the mysql function is not recommended anymore. You could use MySQLi or PDO_MySQL. They are both object oriented and may need a little more time to learn.

Answer 2

Use alias.
Refernce :
http://www.tutorialspoint.com/sql/sql-alias-syntax.htm
$query_checkout =
sprintf("SELECT *,**cart.status AS cart_status, productdatabase.status as
pdb_status** FROM cart, productdatabase WHERE
cart.productid = productdatabase.productid AND
cart.status != 1 AND cart.status != 0
AND cart.sessionid = '%s' ORDER BY `name` ASC", $colname_checkout);