I'm trying to run a MYSQL query that will return all services with an id above a particular value. The query works fine when I use a static value as the comparative to 'id' such as:
$query = "SELECT id, name FROM services WHERE id > '14'";
if ($query_run = mysqli_query($link, $query)) {
while ($results = mysqli_fetch_array($query_run)) {
echo $service_id = $results['id'].'<br>';
echo $service_name = $results['name'].'<br>';
}
} else {
echo mysqli_error($link);
}
However if i use a variable like this:
$query = "SELECT id, name FROM services WHERE id > $service_id";
if ($query_run = mysqli_query($link, $query)) {
while ($results = mysqli_fetch_array($query_run)) {
echo $service_id = $results['id'].'<br>';
echo $service_name = $results['name'].'<br>';
}
} else {
echo mysqli_error($link);
}
the query does not return any values
When you hard coded the value you put quotes around it.
Make sure that $service_id is represented as a string.
Try
$query = "SELECT id, name FROM services WHERE id > '$service_id'";
if ($query_run = mysqli_query($link, $query)) {
while ($results = mysqli_fetch_array($query_run)) {
echo $service_id = $results['id'].'<br>';
echo $service_name = $results['name'].'<br>';
}
} else {
echo mysqli_error($link);
}
$query = "SELECT id, name FROM services WHERE id > '".$service_id."'";
Related
{
"idbarang": "ID-75192864",
"namabarang": "Fruit Tea",
"jenisbarang": "Minuman",
"hargabarang": "6000"
}
i try this
<?php
include 'koneksi.php';
$idbarang = $_GET['id'];
if($idbarang == !null){
$query = mysqli_query($conn, "SELECT * FROM data_barang WHERE id_barang = '$idbarang'");
$result = array();
$i= 0;
while($row = mysqli_fetch_array($query)){
$result[$i]['idbarang'] = $row['id_barang'];
$result[$i]['namabarang'] = $row['nama_barang'];
$result[$i]['jenisbarang'] = $row['jenis_barang'];
$result[$i]['hargabarang'] = $row['harga_barang'];
$i++;
};
echo json_encode($result);
} else {
$query = mysqli_query($conn, "SELECT * FROM data_barang");
$result = array();
$i= 0;
while($row = mysqli_fetch_assoc($query)){
$result[$i]['idbarang'] = $row['id_barang'];
$result[$i]['namabarang'] = $row['nama_barang'];
$result[$i]['jenisbarang'] = $row['jenis_barang'];
$result[$i]['hargabarang'] = $row['harga_barang'];
$i++;
};
echo json_encode($result);
}
?>
and this the result
[
{
"idbarang": "ID-75192864",
"namabarang": "Fruit Tea",
"jenisbarang": "Minuman",
"hargabarang": "6000"
},
{
"idbarang": "ID-96037284",
"namabarang": "Sampoerna",
"jenisbarang": "Rokok",
"hargabarang": "12000"
}
]
I think you are asking why you are always going through the ELSE and never the IF. Thats because of this IF test
if($idbarang == !null){
Instead try
<?php
include 'koneksi.php';
if(!empty($_GET['id'])){
$idbarang = $_GET['id'];
You could also simplify that code quite a lot, and protect it from SQL Injection.
// Do the renaming of column names as part of the query
$sql = 'SELECT id_barang as idbarang, nama_barang as namabarang,
jenis_barang as jenisberang, jenis_barang as hargabarang
FROM data_barang';
if(!empty($_GET['id'])){
// add the WHERE clause on to the base query
$sql .= ' WHERE id_barang = ?';
$stmt = $conn->prepare($sql);
$stmt->bind_param('i', $_GET['id']);
$stmt->execute();
$res = $stmt->get_result();
} else {
$res = $conn->query($sql);
}
// as the renaming is done we can just fetch all the results and convert to a JSON document
$result = $res->fetch_all(MYSQLI_ASSOC);
echo json_encode($result);
When Inserting data into SQL it inserts two into rows, and I don't know why.
most probably of the if statement I added after the results you can find it as my comment:
// id_no update
And I used the select query two times to fetch the id and make it an auto-increment thing.
my table:
<?PHP
$query = "SELECT id_no FROM db_name ORDER BY id_no DESC";
$result = mysqli_query($con,$query);
$row = mysqli_fetch_array($result);
$lastid = $row['id_no'];
if(empty($lastid))
{
$number = "SX000001";
}
else
{
$idd = str_replace("SX", "", $lastid);
$id = str_pad($idd + 1, 6, 0, STR_PAD_LEFT);
$number = 'SX'.$id;
}
?>
<?PHP
if(isset($_POST['add_id']))
{
$id_no = mysqli_real_escape_string($con,$_POST['id_no']);
$sql="INSERT INTO `db_name`(`id_no`) VALUES ('$id_no')";
$result=mysqli_query($con,$sql);
// id_no update
if(mysqli_query($con,$sql))
{
$query = "SELECT id_no FROM db_name ORDER BY id_no DESC";
$result = mysqli_query($con,$query);
$row = mysqli_fetch_array($result);
$lastid = $row['id_no'];
if(empty($lastid))
{
$number = "SX000001";
}
else
{
$idd = str_replace("SX", "", $lastid);
$id = str_pad($idd + 1, 6, 0, STR_PAD_LEFT);
$number = 'SX'.$id;
}
}
else
{
echo "Record Faileddd";
}
if($result)
{
$success="Post has been added successfully";
} else
{
$error="Something went wrong!";
}
$id_no = '';
}
?>
You should check if $result is truthy to see if the insertion succeded (without running another query):
$id_no = mysqli_real_escape_string($con,$_POST['id_no']);
$sql="INSERT INTO `db_name`(`id_no`) VALUES ('$id_no')";
$result=mysqli_query($con,$sql);
// id_no update
if($result)
{
...
}
While creating a group with user ids, I am checking if the entered id exists in database. If it exists, group should be created, if not it should pop out an error.
I am passing array with user ids to a function user_check, but it is not getting checked. Here is my code:
<?php
function user_check($user_id)
{
$u1 = mysqli_query($con, "SELECT uid from users where uid<>'" . $_SESSION['user_id'] . "'");
while ($row = mysqli_fetch_array($u1)) {
$users = $row['uid'];
echo "users" . $users;
$users1 = sort($users);
$users2 = sort($user_id);
printf($users1);
if ($user1 == $user2) {
echo "same";
} else {
echo "not same";
}
}
}
Given a list of user_ids (that you have validated/filtered already) you could write a function something like the following (untested):
function all_users_exist(array $user_ids, Mysqli $con)
{
$result_uids = [];
$ids = implode(',', $user_ids);
$sql = "SELECT uid from users WHERE uid IN ($ids)";
$result = $con->query($sql);
if($result)
while ($row = $result->fetch_array(MYSQLI_ASSOC))
$result_uids[] = $row['uid'];
sort($user_ids);
sort($result_uids);
return $user_ids == $result_uids;
}
I'm inserting into my database id and hours, which is working successfully. However when i insert a new value for an id that has a previous value, the old val isn't replaced by the new, instead they're kept both. I'm trying to update the function with an if/else statement (commented part). But still the same result. The if/else statement must check first if hours (a column in the table) value is empty, if so then perform sql insert, else perform sql update. Any help please?
if (isset($_POST['submit'])) {
$hours = $_POST['Hours'];
$selectid = $_POST['SelectID'];
$sql1 = "INSERT INTO `editedworkhours` (`id`,`H`) VALUES('$selectid','$hours')";
$getResult = mysql_query($sql1);
if (mysql_affected_rows() > 0) {
} else {
}
$tempname = $row['Field'];
$sql2 = "UPDATE editedworkhours SET H ='" . $_GET["hours"] . "' WHERE IDNumber='" . $_GET["selectid"] . "'";
$result2 = mysqli_query($con, $sql2);
if ($con->query($sql2) === TRUE) {
} else {
}
}
echo $menu;
Try this
<?php
if(isset($_POST['submit']))
{
$addedhours = $_POST['AddedHours'];
$selectaf = $_POST['SelectAF'];
$sql1="SELECT * FROM editedworkhours WHERE AFNumber='$selectaf' and AddedWH ='$addedhours'";
$getResult = mysql_query($sql1);
$count = count($getResult);
if(!empty($count) || $count==1)
{
$tempname = $row['Field'];
$sql2 = "UPDATE editedworkhours SET AddedWH ='$addedhours' WHERE AFNumber='$selectaf'";
$result2 = mysql_query($sql2);
if (isset($result2))
{
//Data inserted
}
else
{
//Insert Failed
echo '<script>swal("Error", "Something went wrong error");</script>';
}
echo '<script>swal("Success", "Changes have been saved", "success");</script>';
}
else
{
$sql3 = "INSERT INTO editedworkhours (AFNumber,AddedWH) VALUES('$selectaf','$addedhours')";
$Result = mysql_query($sql3);
if(isset($Result))
{
echo 'Success';
}
else
{
echo 'Failed';
}
}
}
echo $menu;
Hello I'm checking duplicated data from tables. I have a problem that from where data selected. My code is:
$sub_cat = array();
$select = array("core_network","daisy_chain", "rf_bts", "rf_power", "rf_transmission");
$d='0';
for ($i=0;$i<=4;$i++){
$SQL = "SELECT sub_cat FROM (".$select[$i].") WHERE location=('".$id."')";
$result = mysql_query($SQL);
$cs=$d;
if ($result) {
while ($db_field = mysql_fetch_array($result)) {
if(!in_array($db_field['sub_cat'],$sub_cat)) {
$sub_cat[]= $db_field['sub_cat'];
$cs++;
$d=$cs;
$d--;
}
}
}
I need to know that sub_cat selected from which $select[i]. How to find it?
To get the values, do this:
$sub_cat = array();
$select = array("core_network","daisy_chain", "rf_bts", "rf_power", "rf_transmission");
$d='0';
for ($i=0;$i<=4;$i++){
$SQL = "SELECT sub_cat FROM (" . $select[$i] . ") WHERE location=('".$id."')";
$result = mysql_query($SQL); // deprecated - use PDO
$cs = $d;
if ($result) {
while ($db_field = mysql_fetch_array($result)) {
if(!in_array($db_field['sub_cat'], $sub_cat)) {
$table = $select[$i];
$sub_cat[$table][] = $db_field['sub_cat'];
// I have no clue what's going on here in your example:
$cs++;
$d=$cs;
$d--;
}
}
}
}
Then, to retrieve it:
foreach ($sub_cat as $table_name => $values) {
foreach ($values as $row) {
// output values here
}
}