How to make json like this from database mysql using php - php

{
"idbarang": "ID-75192864",
"namabarang": "Fruit Tea",
"jenisbarang": "Minuman",
"hargabarang": "6000"
}
i try this
<?php
include 'koneksi.php';
$idbarang = $_GET['id'];
if($idbarang == !null){
$query = mysqli_query($conn, "SELECT * FROM data_barang WHERE id_barang = '$idbarang'");
$result = array();
$i= 0;
while($row = mysqli_fetch_array($query)){
$result[$i]['idbarang'] = $row['id_barang'];
$result[$i]['namabarang'] = $row['nama_barang'];
$result[$i]['jenisbarang'] = $row['jenis_barang'];
$result[$i]['hargabarang'] = $row['harga_barang'];
$i++;
};
echo json_encode($result);
} else {
$query = mysqli_query($conn, "SELECT * FROM data_barang");
$result = array();
$i= 0;
while($row = mysqli_fetch_assoc($query)){
$result[$i]['idbarang'] = $row['id_barang'];
$result[$i]['namabarang'] = $row['nama_barang'];
$result[$i]['jenisbarang'] = $row['jenis_barang'];
$result[$i]['hargabarang'] = $row['harga_barang'];
$i++;
};
echo json_encode($result);
}
?>
and this the result
[
{
"idbarang": "ID-75192864",
"namabarang": "Fruit Tea",
"jenisbarang": "Minuman",
"hargabarang": "6000"
},
{
"idbarang": "ID-96037284",
"namabarang": "Sampoerna",
"jenisbarang": "Rokok",
"hargabarang": "12000"
}
]

I think you are asking why you are always going through the ELSE and never the IF. Thats because of this IF test
if($idbarang == !null){
Instead try
<?php
include 'koneksi.php';
if(!empty($_GET['id'])){
$idbarang = $_GET['id'];
You could also simplify that code quite a lot, and protect it from SQL Injection.
// Do the renaming of column names as part of the query
$sql = 'SELECT id_barang as idbarang, nama_barang as namabarang,
jenis_barang as jenisberang, jenis_barang as hargabarang
FROM data_barang';
if(!empty($_GET['id'])){
// add the WHERE clause on to the base query
$sql .= ' WHERE id_barang = ?';
$stmt = $conn->prepare($sql);
$stmt->bind_param('i', $_GET['id']);
$stmt->execute();
$res = $stmt->get_result();
} else {
$res = $conn->query($sql);
}
// as the renaming is done we can just fetch all the results and convert to a JSON document
$result = $res->fetch_all(MYSQLI_ASSOC);
echo json_encode($result);

Related

How to get value from mssql DB in PHP

Firstly I got the workers name from BIRTHDAYS and then want to get e-mail address from USERS.There is no problem to take workers name's from Table1 but when I try to get the e-mail addresses the db returns me NULL.My DB is mssql.
<?php
include_once("connect.php");
$today = '05.07';
$today1 = $today . "%";
$sql = "SELECT NAME FROM BIRTHDAYS WHERE BIRTH LIKE '$today1' ";
$stmt = sqlsrv_query($conn,$sql);
if($stmt == false){
echo "failed";
}else{
$dizi = array();
while($rows = sqlsrv_fetch_array($stmt,SQLSRV_FETCH_ASSOC))
{
$dizi[] = array('NAME' =>$rows['NAME']);
$newarray = json_encode($dizi,JSON_UNESCAPED_UNICODE);
}
}
foreach(json_decode($newarray) as $nameObj)
{
$nameArr = (array) $nameObj;
$names = reset($nameArr);
mb_convert_case($names, MB_CASE_UPPER, 'UTF-8');
echo $sql2 = "SELECT EMAIL FROM USERS WHERE NAME = '$names' ";
echo "<br>";
$stmt2 = sqlsrv_query($conn,$sql2);
if($stmt2 == false)
{
echo "failed";
}
else
{
$dizi2 = array();
while($rows1 = sqlsrv_fetch_array($stmt2,SQLSRV_FETCH_ASSOC))
{
$dizi1[] = array('EMAIL' =>$rows['EMAIL']);
echo $newarray1 = json_encode($dizi1,JSON_UNESCAPED_UNICODE);
}
}
}
?>
while($rows1 = sqlsrv_fetch_array($stmt2,SQLSRV_FETCH_ASSOC))
{
$dizi1[] = array('EMAIL' =>$rows['EMAIL']);
echo $newarray1 = json_encode($dizi1,JSON_UNESCAPED_UNICODE);
}
you put in $rows1 and would take it from $rows NULL is correct answer :)
take $rows1['EMAIL'] and it would work
and why foreach =?
you can put the statement in while-loop like this:
while ($rows = sqlsrv_fetch_array($stmt, SQLSRV_FETCH_ASSOC)) {
$names = $rows['NAME'];
$sql2 = "SELECT EMAIL FROM USERS WHERE NAME = '$names' ";
echo "<br>";
$stmt2 = sqlsrv_query($conn, $sql2);
if ($stmt2 == false) {
echo "failed";
} else {
$dizi2 = array();
while ($rows1 = sqlsrv_fetch_array($stmt2, SQLSRV_FETCH_ASSOC)) {
$dizi1[] = array('EMAIL' => $rows1['EMAIL']);
echo $newarray1 = json_encode($dizi1, JSON_UNESCAPED_UNICODE);
}
}
}

Fetching record from two table and convert into json

Hi I'm new in PHP and trying to get the below response using php sql but i'm not be able to find the such desire output
[{"Id":1, "name": "India", "Cities":[{"Id":1, "Name":"Mumbai", "country_id":1}, {"Id":2,"Name":"Delhi","country_id":1},
"id":3,"Name":Banglore","country_id":1}, {"Id":2, "Name":"USA", "Cities":[{"Id":6, "Name":"New York", "country_id":2},.....
I have two tables one is country based and other is city based.
I tried
<?php
include_once("config.inc.php");
$sql = "SELECT * FROM country";
$sqlCity = "SELECT * FROM city";
$cityQuery = mysqli_query($conn, $sqlCity);
$sqlQuery = mysqli_query($conn, $sql);
$mainArray = array();
if(mysqli_num_rows($cityQuery) > 0 ){
$cityResponse = array();
while($resCity = mysqli_fetch_assoc($cityQuery)){
$cityResponse[] = $resCity;
}
if(mysqli_num_rows($sqlQuery) > 0 ){
$response = array();
while($res = mysqli_fetch_assoc($sqlQuery)){
$response[] = $res;
}
foreach($cityResponse as $city){
foreach($response as $country){
if($city['country_id'] == $country['id']){
$mainArray = array("Cities" => $city);
}
}
}
echo '{"response": '.json_encode($response).', '.json_encode($mainArray).' "success": true}';
}
}else{
echo '{"response": '.json_encode($response).' "success": false}';
}
?>
currently my response showing
{"response": [{"id":"1","name":"India"},{"id":"2","name":"USA"},{"id":"3","name":"UK"}], {"Cities":{"id":"15","name":"Manchester","country_id":"3"}} "success": true}
For detail code explanation check the inline comments
Modify the SQL query with related column names
The memory you have to take care. By default memory limit in php is 128MB in 5.3
Check the code and let me know the result
<?php
$data = array();
//include your database configuration files
include_once("config.inc.php");
//execute the join query to fetch the result
$sql = "SELECT country.country_id, country.name AS country_name,".
" city.city_id, city.name AS city_name FROM country ".
" JOIN city ON city.country_id=country.country_id ".
" ORDER BY country.country_id ";
//execute query
$sqlQuery = mysqli_query($conn, $sql) or die('error exists on select query');
//check the number of rows count
if(mysqli_num_rows($sqlQuery) > 0 ){
//country id temprory array
$country_id = array();
//loop each result
while($result = mysqli_fetch_assoc($sqlQuery)){
//check the country id is already exist the only push the city entries
if(!in_array($result['country_id'],$country_id)) {
//if the city is for new country then add it to the main container
if(isset($entry) && !empty($entry)) {
array_push($data, $entry);
}
//create entry array
$entry = array();
$entry['Id'] = $result['country_id'];
$entry['name'] = $result['country_name'];
$entry['Cities'] = array();
//create cities array
$city = array();
$city['Id'] = $result['city_id'];
$city['name'] = $result['city_name'];
$city['country_id'] = $result['country_id'];
//append city entry
array_push($entry['Cities'], $city);
$country_id[] = $result['country_id'];
}
else {
//create and append city entry only
$city = array();
$city['Id'] = $result['city_id'];
$city['name'] = $result['city_name'];
$city['country_id'] = $result['country_id'];
array_push($entry['Cities'], $city);
}
}
}
//display and check the expected results
echo json_encode($data);
use like this
<?php
include_once("config.inc.php");
$sql = "SELECT * FROM country";
$sqlCity = "SELECT * FROM city";
$cityQuery = mysqli_query($conn, $sqlCity);
$sqlQuery = mysqli_query($conn, $sql);
$mainArray = array();
if(mysqli_num_rows($cityQuery) > 0 ){
$cityResponse = array();
while($resCity = mysqli_fetch_assoc($cityQuery)){
$cityResponse[] = $resCity;
}
if(mysqli_num_rows($sqlQuery) > 0 ){
$response = array();
while($res = mysqli_fetch_assoc($sqlQuery)){
$response[] = $res;
}
foreach($cityResponse as $city){
foreach($response as $country){
if($city['country_id'] == $country['id']){
$mainArray = array("Cities" => $city);
}
}
}
echo json_encode(array('result'=>'true','Cities'=>$mainArray));
}
}else{
echo json_encode(array('result'=>'false','Cities'=>$response));
}
?>
You can use try this. It actually works for me and it's cool. You can extend to 3 or more tables by editing the code.
try {
$results = array();
$query = "SELECT * FROM country";
$values = array();
$stmt = $datab->prepare($query);
$stmt->execute($values);
while($country = $stmt->fetch(PDO::FETCH_ASSOC)){
$cities = null;
$query2 = "SELECT * FROM city WHERE country_id = ?" ;
$values2 = array($country['id']);
$stmt2 = $datab->prepare($query2);
$stmt2->execute($values2);
$cities = $stmt2->fetchAll();
if($cities){
$country['cities'] = $cities;
} else {
$country['cities'] = '';
}
array_push($results, $country);
}
echo json_encode(array("Countries" => $results));
} catch (PDOException $e) {
throw new Exception($e->getMessage());
}

multiple data queries php ajax mysql not working

<?php
$link = mysql_connect("localhost:8889", "root", "root", "Testdata");
if(!link) {echo "Database connexion not possible"; exit;}
$id = $_GET('testeId');
$jsonData = [];
The first query is working:
$jsonData['table1'] = [];
$sql = "SELECT * FROM registerData WHERE testeId = $id";
if ($result = mysqli_query($link, $sql){
while ($row = mysqli_fetch_assoc($result)) {
$jsonData['table1'][] = $row;
}
}
else {
$jsonData['table1'][] = "Error 1";
}
This second query is not working:
$jsonData['table2'] = [];
$sql = "SELECT * FROM factsData WHERE factsId = $id";
if ($result = mysqli_query($link, $sql){
while ($row = mysqli_fetch_assoc($result)) {
$jsonData['table2'][] = $row;
}
}
else {
$jsonData['table2'][] = "Error 2";
}
mysqli_free_result($result);
echo json_encode($jsonData);
The jsonData string only includes the 1st query:
mysqli_close($link);
The responseText of the ajax request only has data from "table1" array

Can I looping this code in PHP using for or while?

<?php
$query = "SELECT bobot FROM `record_result` WHERE `participantid` = $idParticipant AND `questionid` = 1";
$query1 = "SELECT bobot FROM `record_result` WHERE `participantid` = $idParticipant AND `questionid` = 2";
$comments = mysql_query($query);
$comments1 = mysql_query($query1);
while($row = mysql_fetch_array($comments, MYSQL_ASSOC)) {
$bobot = $row['bobot'];
$bobot = htmlspecialchars($row['bobot'],ENT_QUOTES);
}
while($row = mysql_fetch_array($comments1, MYSQL_ASSOC)) {
$bobot1 = $row['bobot'];
$bobot1 = htmlspecialchars($row['bobot'],ENT_QUOTES);
}
?>
I want to make this code can looping until 10. I hope that there aren't many variable, ex: $query, $query1, $query2, ..., $query10, $comments, $comments1, $comments2, ..., $comments10, $bobot, $bobot1, $bobot2, ..., $bobot10. Someone help me, please ...
You're almost there. But I have to mention that you should start using parameterized queries with prepared statements instead of constructing your queries manually.
$id = 1;
while($id <= 10) {
// construct your query
$query = "SELECT bobot FROM `record_result` WHERE `participantid` = $idParticipant AND `questionid` = $id";
// execute and get results
$comments = mysql_query($query);
// iterate over records in result
while($row = mysql_fetch_array($comments, MYSQL_ASSOC)) {
$bobot = $row['bobot'];
$bobot = htmlspecialchars($row['bobot'],ENT_QUOTES);
}
// increment the id for next cycle through the loop
$id = $id + 1;
}

function call inside a function in php not working

This code is a function calling a function in php. The function call is never called.
function saveSubject(){
$result = mysql_query("select * from term where description='".$_POST['term']."'");
$row = mysql_fetch_array($result, MYSQL_NUM);
global $term;
$term = $row[0];
$x=1;
while(isset($_POST['subCode'.$x])and isset($_POST['subTitle'.$x]) and isset($_POST['subUnit'.$x])){
$code = $_POST['subCode'.$x];
$title = $_POST['subTitle'.$x];
$unit = $_POST['subUnit'.$x];
$query = "INSERT INTO subject(subcode, description, units, termid)
VALUES('".$code."','".$title."',".$unit.",".$term.")";
$result = mysql_query("SELECT * from subject where subcode='".$code."'");
if(mysql_num_rows($result) > 0){
$message = "Subject Code : ".$code;
prompt($message);
}else{
mysql_query($query);
savePre($code, $x);
}
$x++;
}
}
function savePre($code, $y){
$pre = mysql_query("SELECT subject.subcode from subject left join term
on term.termid=subject.termid
left join curriculum on term.termid = curriculum.curriculumid
where term.courseid =".$_POST['course']);
while($row = mysql_fetch_array($pre, MYSQL_NUM)){
$c = $row[0].$y;
if(isset($_POST[$c])){
$result = mysql_query("Select * from pre_requisite where pre_requisites=".$row[0]."and subject=".$code);
if(mysql_num_rows($result) > 0){
$message = "";
}else{
mysql_query("INSERT into pre_requisites(pre_requisite, subject)
values (".$row[0].", ".$code.")");
}
}
}
}
Calling function savePre() in saveSubjec() but the calling is not working. I cannot find out what is wrong. Please help!
Simple...
You code is
$query = "INSERT INTO subject(subcode, description, units, termid)
VALUES('".$code."','".$title."',".$unit.",".$term.")";
$result = mysql_query("SELECT * from subject where subcode='".$code."'");
if(mysql_num_rows($result) > 0)
{
$message = "Subject Code : ".$code;
prompt($message);
}else{
mysql_query($query);
savePre($code, $x);
}
from above code you can imagine that you are inserting record to database and then selecting that record using subcode match where condition so it will always return 1 as output so your else condition will never get execute.
That's the reason why you are not able to call savePre function.
You want to define savePre() function above the saveSubject() function. Use this.
function savePre($code, $y)
{
$pre = mysql_query("SELECT subject.subcode from subject left join term
on term.termid=subject.termid
left join curriculum on term.termid = curriculum.curriculumid
where term.courseid =".$_POST['course']);
while($row = mysql_fetch_array($pre, MYSQL_NUM))
{
$c = $row[0].$y;
if(isset($_POST[$c]))
{
$result = mysql_query("Select * from pre_requisite where pre_requisites=".$row[0]."and subject=".$code);
if(mysql_num_rows($result) > 0){
$message = "";
}else{
mysql_query("INSERT into pre_requisites(pre_requisite, subject)
values (".$row[0].", ".$code.")");
}
}
}
}
function saveSubject()
{
$result = mysql_query("select * from term where description='".$_POST['term']."'");
$row = mysql_fetch_array($result, MYSQL_NUM);
global $term;
$term = $row[0];
$x=1;
while(isset($_POST['subCode'.$x])and isset($_POST['subTitle'.$x]) and isset($_POST['subUnit'.$x]))
{
$code = $_POST['subCode'.$x];
$title = $_POST['subTitle'.$x];
$unit = $_POST['subUnit'.$x];
$result = mysql_query("SELECT * from subject where subcode='".$code."'");
if(mysql_num_rows($result) > 0){
$message = "Subject Code : ".$code;
prompt($message);
}
else
{
$query = "INSERT INTO subject(subcode, description, units, termid)
VALUES('".$code."','".$title."',".$unit.",".$term.")";
mysql_query($query);
savePre($code, $x);
}
$x++;
}
}

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