I am trying to print json_encode and I get output duplicated. I am certain there is one single record in database and yet it shows the same record data twice in various format. This is it:
[{"0":"Polo","name":"Polo","1":"City ","location":"City ","2":"Manama","city":"Manama"}]
The code behind this is:
$dataArray = array();
while($r = mysql_fetch_array($result))
{
$dataArray[] = $r;
}
print json_encode($dataArray, JSON_UNESCAPED_UNICODE);
Any idea?
This is because the default behavior of mysql_fetch_array() is to return both a column name and index keyed array.
Use mysql_fetch_assoc() or set the second parameter of mysql_fetch_array().
while($r = mysql_fetch_assoc($result)) {
$dataArray[] = $r;
}
You should set another fetch style. It now fetches all columns using both their 0 based index and their name.
This should work as expected:
$dataArray = array();
while($r = mysql_fetch_array($result, MYSQL_ASSOC))
{
$dataArray[] = $r;
}
print json_encode($dataArray, JSON_UNESCAPED_UNICODE);
You're getting this because you can access the results either by name or by column index, but you're serializing the entire thing, so both ways of getting the data are showing up.
try this
//$dataArray = array();
while($r = mysql_fetch_array($result))
{
$dataArray[] = $r;
}
print json_encode($dataArray, JSON_UNESCAPED_UNICODE);
I commented first line. Because you used like that $dataArray[].
Related
I have two different queries which I have to append in same array in form of JSON..
Here is my code from 1st query...
while($row = mysqli_fetch_array($res)) {
array_push($result,array('name'=>$row[0],'photo'=>$row[1],'rollno'=>$row[2],'id'=>$row[3]));
}
Here is my second query push similar as first one.. number of rows is always same as above query
array_push($result,array('status'=>'$status');
After that I'm encoding them like this
echo json_encode(array("result"=>$result));
Here is what I am getting
{"result":[{"name":"Abhishek Singh","photo":"http:\/\/onsitesupport.info\/diary\/photos\/student\/26.png","rollno":"1","id":"26"},
{"status":"status"}]
But I want to result like this
{"result":[{"name":"Abhishek Singh","photo":"http:\/\/onsitesupport.info\/diary\/photos\/student\/26.png","rollno":"1","id":"26","status":"status"}]
I mean status will merge into my every node... how can I achieve this..?
Try the below to add status field to each array:
while($row = mysqli_fetch_array($res)){
array_push($result,array('name'=>$row[0],'photo'=>$row[1],'rollno'=>$row[2],'id'=>$row[3]));
}
$res_row = 0;
while($row2 = mysqli_fetch_array($res2)){
$status = $row2[0]; // status value here
$result[$res_row]['status']=$status;
$res_row++;
}
echo json_encode(array("result"=>$result));
Try this please, using temporary arrays that are merged after all your queries are complete:
// Query 1
while($row = mysqli_fetch_array($res)){
$tmpResults[] = $row;
}
// Query 2
$tmpResult2 = array('status'=>'$status');
// Merge Everything
$final = array_merge($tmpResults, $tmpResult2);
// Encode
$json = json_encode($final, TRUE);
Good luck
Hi I need to add some value-key pair to an array which is the output of mysql query. Below is the code,
$query = "select TITLE,DESCRIPTION from TABLE where ID='1234'";
$result = mysqli_query($conn, $query);
$numrows = mysqli_num_rows($result);
if($numrows>0)
{
while($row = mysqli_fetch_array($result, MYSQLI_ASSOC)) {
$myArray[] = $row;
}
}
echo json_encode($myArray);
Giving me the result like
[{"TITLE":"Special","DESCRIPTION":"This is DESCRIPTION."}]
Now I need to to add an another key-value pair to generate the json output like,
[{"TITLE":"Special","DESCRIPTION":"This is DESCRIPTION.","URL":"imgname.jpg"}]
So I added the code
$myArray["URL"]="imgname.jpg";
echo json_encode($myArray);
But giving me the output like,
{"0":{"TITLE":"Chef Special","DESCRIPTION":"Grilled Salmon and crab."},"URL":"imgname.jpg"}
Is there anything wrong with above code.
check your data with
var_dump($myArray);
and you will find, that it is a 2-dimensional array. you'd have to add your data with
$myArray[0]["URL"] = "imgname.jpg";
If you have to add after encoding it, reverse with:
$a = json_decode($myArray,true)
add a new pair of key, value with $a['URL'] = "imgname.jpg" and then encode again.
I want to show string outside while loop, but it only shows one result.
while($row = $result->fetch_assoc()) {
$myarr = array();
}
echo $myarr;
This shows only one result but I need all the results outside the while loop.
Could you please help me how is this possible?
I am not sure if you want the whole row returned from the query or just a single field.
If its the whole row then try
$myarr = array(); // initialize
while($row = $result->fetch_assoc()) {
$myarr[] = $row;
}
print_r($myarr);
This will give you an array containing n row arrays.
Problem :
You are just assigning the result one after again
$myarr = array();
Here, It means you're assigning the array() again and again, which replaces the old value
Solution / What You should do
1. You can assign it to an Array (Good Approach)
while($row = $result->fetch_assoc()) {
$myarr[] = $row['yourdbitem']; // or $row if you want whole row
}
print_r($myarr);
2. You can concat in each iteration (Bad Approach)
$somevariable = '';
while($row = $result->fetch_assoc()) {
$somevariable .= $row['yourdbitem']; // or $row if you want whole row
}
echo $somevariable
Note :
I have given good and bad approach to updating what you should do and what you should not do :)
I have a simple query with outputs only one column (rows number may change)
SELECT column1 as NUMBER WHERE column1 ...
Output,
NUMBER
1
2
I just want it as an array in PHP with them as comma seperated.
So I did,
$rows = array();
while ($row = mysql_fetch_row($result)) {
$rows[] = $row;
and its working if I echo it with print_r
However because of some reason I cant get the plain values out of this array.
echo $rows[0] gives me the word 'Array'
echo implode(",", $rows); gives me 1Array',Array1
I tried
echo json_encode($rows[0]);
gives me
["1"]
I simply want 1,2
After a lot of different tries I gave up and added group_concat in the sql query. I just want to know what I did wrong.
Thanks.
try this
SELECT GROUP_CONCAT(`column1` SEPARATOR ',') AS number FROM table where....
mysql_fetch_row i returning a single element array. To have your desired output, only select the 1st element:
$rows = array();
while ($row = mysql_fetch_row($result)) {
$rows[] = $row[0];
foreach($rows as $key => $value){
}
should do the trick, with an echo it will output the results as an associative array
just make a simple amendment to your code:
$rows[] = $row;
into:
$rows[] = $row[0];
and use:
implode(", ", $rows[]);
I've got a database with 5 columns and multiple rows. I want to fetch the first 3 rows and echo them as an array. So far I can only get the first row (I'm new to PHP and mysql). Here's my PHP so far:
//==== FETCH DATA
$result = mysql_query("SELECT * FROM $tableName");
$array = mysql_fetch_row($result);
//==== ECHO AS JSON
echo json_encode($array);
Help would be much appreciated.
You need to loop through the results. mysql_fetch_row gets them one at a time.
http://php.net/manual/en/function.mysql-fetch-row.php
The code would end up like:
$jsonData = array();
while ($array = mysql_fetch_row($result)) {
$jsonData[] = $array;
}
echo json_encode($jsonData);
//json_encode()
PLEASE NOTE
The mysql extension is deprecated in PHP 5.5, as stated in the comments you should use mysqli or PDO. You would just substitute mysqli_fetch_row in the code above.
http://www.php.net/manual/en/mysqli-result.fetch-row.php
I do like this while quering an ODBC database connection with PHP 5.5.7, the results will be in JSON format:
$conn = odbc_connect($odbc_name, 'user', 'pass');
$result = odbc_exec($conn, $sql_query);
Fetching results allowing edit on fields:
while( $row = odbc_fetch_array($result) ) {
$json['field_1'] = $row['field_1'];
$json['field_2'] = $row['field_2'];
$json['field_3'] = $row['field_1'] + $row['field_2'];
array_push($response, $json);
}
Or if i do not want to change anything i could simplify like this:
while ($array = odbc_fetch_array($result)) { $response[] = $array; }
What if i want to return the results in JSON format?, easy:
echo json_encode($response, true);
You can change odbc_fetch_array for mysqli_fetch_array to query a MySql db.
According to the PHP Documentation mysql_fetch_row (besides that it's deprecated and you should use mysqli or PDO)
Returns a numerical array that corresponds to the fetched row and moves the internal data pointer ahead.
so you need for example a while loop to fetch all rows:
$rows = array();
while ($row = mysql_fetch_row($result)) {
$rows[] = $row;
}
echo json_encode($rows);
I leave it to you how to only fetch 3 rows :)
You need to put this in some kind of a loop, mysql_fetch_row returns results one at a time.
See example:
http://www.php.net/manual/en/mysqli-result.fetch-row.php#example-1794
$result = mysql_query( "SELECT * FROM $tableName ORDER BY id LIMIT 3");
$json = array();
while($array = mysql_fetch_row($result)){
$json[] = $array;
}
echo json_encode($json);