$selected_offer = $_POST['selected_offer'];
$get_categories = $db->query("SELECT oc_id, oc_name FROM object_category WHERE oc_relate = '".$selected_offer."'");
$json = array();
while ($get_rows = mysql_fetch_array($get_categories, MYSQL_ASSOC)) {
$json[] = $get_rows;
}
echo json_encode($json);
return;
I toke this code from someone else and since I am not familiar with json I am asking here at stackoverflow how can add a function to the oc_name attribute before the json encodes it and still return the same struckture as it is now, like for example:
language($get_rows['oc_name'])
while ($get_rows = mysql_fetch_array($get_categories, MYSQL_ASSOC)) {
$get_rows['oc_name'] = language($get_rows['oc_name']);
$json[] = $get_rows;
}
You can apply your function on the mentioned field before you add the row in your $json array
$json = array();
while ($get_rows = mysql_fetch_array($get_categories, MYSQL_ASSOC)) {
$get_rows['oc_name']=language($get_rows['oc_name']);
$json[] = $get_rows;
}
Related
I have an array populated using an sql statement in the following manner:
$index = 0;
while ($row = sqlsrv_fetch_array($stmt, SQLSRV_FETCH_ASSOC))
{
$bookname[$index] = ($row['Bookname']);
$subjectname[$index] = ($row['SubjectName']);
$index++;
}
When I go to echo json encode the Arrays I get a blank [] when I know it has been populated which is really weird.
Am I doing anything wrong in my context
echo json_encode($Bookname,$SubjectName);
You can use json_encode as like that:
<?php
$index = 0;
$data = array();
while ($row = sqlsrv_fetch_array($stmt, SQLSRV_FETCH_ASSOC))
{
$data[$index]['bookname'] = $row['Bookname'];
$data[$index]['subjectname'] = $row['SubjectName'];
$index++;
}
json_encode($data); // encode your array
?>
Try following:
$index = 0;
$data = array();
while ($row = sqlsrv_fetch_array($stmt, SQLSRV_FETCH_ASSOC))
{
$data['Bookname'][$index] = $row['Bookname']
$data['SubjectName'][$index] = $row['SubjectName'];
$index++;
}
echo json_encode($data);
You have passed two parameter while calling json_encode function. You batter combine two array in one. Then call the json_encode function like json_encode($combinedArray)
I am trying to fetch multiple rows from my database and then encode them with json so I can access them in my Android application. I've successfully encoded an object but I couldn't find a way to do the same with an array. My code looks like:
if ($tag == 'friends') {
$id = $_POST['id'];
$friends = $db->getMyFriends($id);
if ($friends != false) {
// friends found
$result[] = array();
while($row = mysql_fetch_assoc($friends)){
$response[ "error"] = FALSE;
$result[] = array(
$response["friends"]["unique_id"] = $row["unique_id"],
$response["friends"]["name"] = $row["name"],
$response["friends"]["email"] = $row["email"]);
}
echo json_encode($response);
}
The code from getMyFriends($id) I have already tested and it works fine. It returns :
$result = mysql_fetch_array($result);
return $result;
When using a rest client passing the parameters:
Tag: friends
id: $id
this is the json response that I get:
{
"tag": "myfriends",
"error": false
}
, but no actual database data.
If anyone knows what I'm doing wrong, I'd really appreciate it, I've been browsing the internet for hours now.
If getMyFriends already have a $result = mysql_fetch_array($result);you don't need to fetch again.
You could simply:
$friends = $db->getMyFriends($id);
echo json_encode($friends);
But that will only return one friend, if you want all remove $result = mysql_fetch_array($result); from getMyFriends and return the pure mysql_result, then do something like:
$result = array();
while($row = mysql_fetch_assoc($friends)){
array_push($result,$row);
}
echo json_encode($result);
I tried this and it worked.
if($tag=='friends'){
$id = $_REQUEST['id'];
$friends = $db->getMyFriends($id);
if ($friends != false) {
// friends found
$result[] = array();
while($row = mysql_fetch_assoc($friends)){
$response[ "error"] = FALSE;
$result[] = array(
$response["friends"]["unique_id"] = $row["id"],
$response["friends"]["name"] = $row["name"],
$response["friends"]["email"] = $row["email"]
);
}
echo json_encode($result);
}
}
I have the following, and while $data['details'] is being populated OK, there should be three results in $data['tests'], but "tests" isn't showing at all in the JSON result:
{"details":["Clinical result","Signature result"]}
$data = array();
while ($row = mysql_fetch_array($result)) {
$data['details'] = array($row['tests_clinical'], $row['signature']);
foreach($row['lab_test_group_fk'] as $group){
$data['tests'] = array($group);
}
}
echo json_encode($data);
If I change the above to the following then I get only the last record for $row['lab_test_group_fk'], not all three records for that column (hence the foreach loop as above):
while ($row = mysql_fetch_array($result)) {
$data['details'] = array($row['tests_clinical'], $row['signature']);
$data['tests'] = array($row['lab_test_group_fk']);
}
echo json_encode($data);
{"details":["Clinical result","Signature result"],"tests":["21"]}
What am I doing wrong here?
Thanks to Tamil Selvin this was the solution that worked for me:
$data = array();
while ($row = mysql_fetch_array($result)) {
$data['details'] = array($row['tests_clinical'], $row['signature']);
$data['tests'][] = array($row['lab_test_group_fk']);
}
echo json_encode($data);
Which returned:
{"details":["Clinical result","Signature result"],"tests":[["31"],["2"],["21"]]}
Try
$data = array();
while ($row = mysql_fetch_array($result)) {
$data[]['details'] = array($row['tests_clinical'], $row['signature']);
$data[]['tests'] = array($row['lab_test_group_fk']);
}
echo json_encode($data);
or
while ($row = mysql_fetch_array($result)) {
$data[] = array(
'details' => array($row['tests_clinical'], $row['signature']),
'tests' => array($row['lab_test_group_fk'])
);
}
echo json_encode($data);
$data['tests'] = array($group); means reassign $data['tests'] to a new value again.
Try $data['tests'][] = array($group); .
You are overwriting existing data of $data. You need some kind of array where you will put all your records. Try this
$data = array();
while ($row = mysql_fetch_array($result)) {
$record = array(); // this creates new record
$record['details'] = array($row['tests_clinical'], $row['signature']);
foreach($row['lab_test_group_fk'] as $group){
$record['tests'] = array($group);
}
$data[] = $record; // this adds record to data
}
echo json_encode($data);
I am attempting to fetch JSON from Instagram according to a number of URL parameters, the JSON is then decoded and then the objects required are then encoded into my own JSON format. Whilst I know this sound a little ridiculous, it is what is required. My only issue here is that for some reason it does not encode each section of JSON, it will only work for one item. The code is as below.
<?php
function instagram($count=16){
$igtoken = $_GET['igtoken'];
$hashtag = $_GET['hashtag'];
$url = 'https://api.instagram.com/v1/tags/'.$hashtag.'/media/recent/?access_token='.$igtoken.'&count='.$count;
$jsonData = json_decode((file_get_contents($url)));
$jsonData = json_decode((file_get_contents($url)));
foreach ($jsonData->data as $key=>$value) {
$response = array();
$response["data"] = array();
$data = array();
$data["createdtime"] = $value->caption->created_time;
$data["username"] = $value->caption->from->username;
$data["profileimage"] = $value->caption->from->profile_picture;
$data["caption"] = $value->caption->text;
$data["postimage"] = $value->images->standard_resolution->url;
array_push($response["data"], $data);
$result = json_encode($response);
}
return $result;
}
echo instagram();
?>
It will work for each section of JSON if I do something like this instead:
$result .= '<li>
'.$value->caption->from->username.'<br/>
'.$value->caption->from->profile_picture.'<br/>
'.$value->caption->text.'<br/>
'.$value->images->standard_resolution->url.'<br/>
'.$value->caption->created_time.'<br/>
</li>';
I feel I have bodged up somewhere with the array, however i'm not entirely sure.
What if we move $response["data"] and $result varia out of foreach?
Have you tried this?
$response = array();
$response["data"] = array();
foreach ($jsonData->data as $key=>$value) {
$data = array();
$data["createdtime"] = $value->caption->created_time;
$data["username"] = $value->caption->from->username;
$data["profileimage"] = $value->caption->from->profile_picture;
$data["caption"] = $value->caption->text;
$data["postimage"] = $value->images->standard_resolution->url;
array_push($response["data"], $data);
}
$result = json_encode($response);
return $result;
I am pulling data from my database and trying to encode into JSON data using json_encode. But to make it easier to read in my android app. I was hopping to format it differently then I am currently doing. Please see bottom encode string example. Any help would be great. Thanks in Advance.
$result = $db->query($query);
while($info = mysql_fetch_array($result))
{
$content[] = $info;
}
$count = count($content);
$result=array();
for($i=0;$i<$count;$i++)
{
$result[id][] = $content[$i]['imageID'];
$result[name][] = $content[$i]['Name'];
$result[thumb][] = $content[$i]['Thumb'];
$result[path][] = $content[$i]['Path'];
}
echo json_encode($result);
{"id":["1","2","3"],"name":["Dragon","fly","bug"],"thumb":["thm_polaroid.jpg","thm_default.jpg","thm_enhanced-buzz-9667-1270841394-4.jpg"],"path":["polaroid.jpg","default.jpg","enhanced-buzz-9667-1270841394-4.jpg"]}
But I am trying to format my array like so when it is encoded by json_encode.
[{"id":"1","name":"Dragon","thumb":"thm_polaroid.jpg","path":"polaroid.jpg"},{"id":"2","name":"Fly","thumb":"thm_default.jpg","path":"default.jpg"},{"id":"3","name":"Bug","thumb":"thm_enhanced-buzz-9667-1270841394-4.jpg","path":"enhanced-buzz-9667-1270841394-4.jpg"}]
Well, there is a problem. This is not valid JSON:
{"image":["1","Dragon","thm_polaroid.jpg","polaroid.jpg"],
"image":["2","fly","thm_default.jpg","default.jpg"]}
A JSON object can only have one value per unique key. This means that your latter image key would clobber the value of the former.
If you are content with this, however:
[["1","Dragon","thm_polaroid.jpg","polaroid.jpg"],
["2","fly","thm_default.jpg","default.jpg"]]
Then you can simply use mysql_fetch_row:
$result = $db->query($query);
while($info = mysql_fetch_row($result))
{
$content[] = $info;
}
echo json_encode($content);
Side Note:
Generally, in PHP, it is best to use foreach( $arr as $val ) (or $arr as $key => $val). for loops should be limited to when they are strictly necessary.
You need to add the iterator $i to the setting array
for($i=0;$i<$count;$i++)
{
$result[$i][id] = $content[$i]['imageID'];
$result[$i][name] = $content[$i]['Name'];
$result[$i][thumb] = $content[$i]['Thumb'];
$result[$i][path] = $content[$i]['Path'];
}
<?
$result = $db->query($query);
while($info = mysql_fetch_array($result))
$content[] = $info;
$result=array();
$count = count($content);
for ($x=0;$x<$count;++$x)
{
$result[$x][] = $content[$x]['imageID'];
$result[$x][] = $content[$x]['Name'];
$result[$x][] = $content[$x]['Thumb'];
$result[$x][] = $content[$x]['Path'];
}
echo json_encode($result);
?>