I am trying to fetch multiple rows from my database and then encode them with json so I can access them in my Android application. I've successfully encoded an object but I couldn't find a way to do the same with an array. My code looks like:
if ($tag == 'friends') {
$id = $_POST['id'];
$friends = $db->getMyFriends($id);
if ($friends != false) {
// friends found
$result[] = array();
while($row = mysql_fetch_assoc($friends)){
$response[ "error"] = FALSE;
$result[] = array(
$response["friends"]["unique_id"] = $row["unique_id"],
$response["friends"]["name"] = $row["name"],
$response["friends"]["email"] = $row["email"]);
}
echo json_encode($response);
}
The code from getMyFriends($id) I have already tested and it works fine. It returns :
$result = mysql_fetch_array($result);
return $result;
When using a rest client passing the parameters:
Tag: friends
id: $id
this is the json response that I get:
{
"tag": "myfriends",
"error": false
}
, but no actual database data.
If anyone knows what I'm doing wrong, I'd really appreciate it, I've been browsing the internet for hours now.
If getMyFriends already have a $result = mysql_fetch_array($result);you don't need to fetch again.
You could simply:
$friends = $db->getMyFriends($id);
echo json_encode($friends);
But that will only return one friend, if you want all remove $result = mysql_fetch_array($result); from getMyFriends and return the pure mysql_result, then do something like:
$result = array();
while($row = mysql_fetch_assoc($friends)){
array_push($result,$row);
}
echo json_encode($result);
I tried this and it worked.
if($tag=='friends'){
$id = $_REQUEST['id'];
$friends = $db->getMyFriends($id);
if ($friends != false) {
// friends found
$result[] = array();
while($row = mysql_fetch_assoc($friends)){
$response[ "error"] = FALSE;
$result[] = array(
$response["friends"]["unique_id"] = $row["id"],
$response["friends"]["name"] = $row["name"],
$response["friends"]["email"] = $row["email"]
);
}
echo json_encode($result);
}
}
Related
My php server is generating two JSON output
1.] For MySql JSON printing I am using this code.
$sql = "select id ,Title , Meassage from lodhinews";
$result = $conn->query($sql);
$values = array();
if ($result->num_rows > 0) {
// output data of each row
while($row = $result->fetch_assoc()) {
$values['data'][] = array(
'id'=>$row['id'],
'Title'=>$row['Title'],
'Meassage'=>$row['Meassage']
);
}
header('Content-Type: application/json;charset=utf-8');
echo json_encode($values ,JSON_PRETTY_PRINT);
} else {
$values = array(
'error'=>'No results found'
);
}
$conn->close();
?>
2.] For file name printing I am using this code
chdir('./uploads');
foreach(glob('*.*') as $filename){
$data[] = $filename;
}
echo json_encode($data);
?>
both the above code is working fine!
I wanted this both json output combined on one single page
not very complicated ! :)
$merged_array = array();
$merged_array[] = $data;
$merged_array[] = $values;
print json_encode($merged_array,JSON_PRETTY_PRINT);
I have the following, and while $data['details'] is being populated OK, there should be three results in $data['tests'], but "tests" isn't showing at all in the JSON result:
{"details":["Clinical result","Signature result"]}
$data = array();
while ($row = mysql_fetch_array($result)) {
$data['details'] = array($row['tests_clinical'], $row['signature']);
foreach($row['lab_test_group_fk'] as $group){
$data['tests'] = array($group);
}
}
echo json_encode($data);
If I change the above to the following then I get only the last record for $row['lab_test_group_fk'], not all three records for that column (hence the foreach loop as above):
while ($row = mysql_fetch_array($result)) {
$data['details'] = array($row['tests_clinical'], $row['signature']);
$data['tests'] = array($row['lab_test_group_fk']);
}
echo json_encode($data);
{"details":["Clinical result","Signature result"],"tests":["21"]}
What am I doing wrong here?
Thanks to Tamil Selvin this was the solution that worked for me:
$data = array();
while ($row = mysql_fetch_array($result)) {
$data['details'] = array($row['tests_clinical'], $row['signature']);
$data['tests'][] = array($row['lab_test_group_fk']);
}
echo json_encode($data);
Which returned:
{"details":["Clinical result","Signature result"],"tests":[["31"],["2"],["21"]]}
Try
$data = array();
while ($row = mysql_fetch_array($result)) {
$data[]['details'] = array($row['tests_clinical'], $row['signature']);
$data[]['tests'] = array($row['lab_test_group_fk']);
}
echo json_encode($data);
or
while ($row = mysql_fetch_array($result)) {
$data[] = array(
'details' => array($row['tests_clinical'], $row['signature']),
'tests' => array($row['lab_test_group_fk'])
);
}
echo json_encode($data);
$data['tests'] = array($group); means reassign $data['tests'] to a new value again.
Try $data['tests'][] = array($group); .
You are overwriting existing data of $data. You need some kind of array where you will put all your records. Try this
$data = array();
while ($row = mysql_fetch_array($result)) {
$record = array(); // this creates new record
$record['details'] = array($row['tests_clinical'], $row['signature']);
foreach($row['lab_test_group_fk'] as $group){
$record['tests'] = array($group);
}
$data[] = $record; // this adds record to data
}
echo json_encode($data);
In a project, I have to return user_id, user_age from the database and the return format should be like
user object which contains user_id and user_age
average age of users
count of users
the return format should be in JSON format.
I have created user array and encoded to JSON by using the method
json_encode(user);
my code is like this :
while ($row = mysql_fetch_array($result)) {
$user["id"] = $row["id"];
$user["name"] = ucfirst($row["user_name"]);
$user["date"] = $row["date_of_treatment"];
$user["age"] = $row["age_of_user"];
// push single user into final response array
array_push($response, $user);
$count = $count+1;
$sum_of_age = $sum_of_age+$row["age_of_user"];
}
echo json_encode($response);
I have calculated the average age ($sum_of_age/$count) and count of returned users ($count), but I don't know how to return average age and count of users with the same json response.any help will be appreciated.
You can do like this:
$count=0;
$sum_of_age=0;
$response=array();
$response['users']=array();
while ($row = mysql_fetch_array($result)) {
$user["id"] = $row["id"];
$user["name"] = ucfirst($row["user_name"]);
$user["date"] = $row["date_of_treatment"];
$user["age"] = $row["age_of_user"];
// push single user into final response array
array_push($response['users'], $user);
$count = $count+1;
$sum_of_age = $sum_of_age+$row["age_of_user"];
}
$response['count']=$count;
$response['avg']=$sum_of_age/$count;
echo json_encode($response);
You can try this:
$users = array();
$sum_of_age = 0;
$count = 0;
$users = array();
while ($row = mysql_fetch_array($result))
{
$user["id"] = $row["id"];
$user["name"] = ucfirst($row["user_name"]);
$user["date"] = $row["date_of_treatment"];
$user["age"] = $row["age_of_user"];
// push single user into final response array
$users[] = $user;
$count++;
$sum_of_age += (int) $row["age_of_user"];
}
$response = array(
'users' => $users,
'averageAge' => $sum_of_age/$count,
'count' => $count
);
echo json_encode($response);
This should result in the following json response:
{
"users":[
{ "id" : "1", "name" : "John Doe" , "date" : "2014-03-22 15:20" , "age" : 42 },
{...},
...
],
"averageAge": 42,
"count": 1337
}
<?php
$response = array();
while ($row = mysql_fetch_array($result)) {
$user["id"] = $row["id"];
$user["name"] = ucfirst($row["user_name"]);
$user["date"] = $row["date_of_treatment"];
$user["age"] = $row["age_of_user"];
// push single user into final response array
array_push($response, $user);
$count = $count+1;
$sum_of_age = $sum_of_age+$row["age_of_user"];
}
$response["average_age"] = $sum_of_age / $count;
$response["count"] = $count;
echo json_encode($response);
}
This is the answer, thanks #Amal Murali (commented a link), the link you have provided is working.. :-)
$selected_offer = $_POST['selected_offer'];
$get_categories = $db->query("SELECT oc_id, oc_name FROM object_category WHERE oc_relate = '".$selected_offer."'");
$json = array();
while ($get_rows = mysql_fetch_array($get_categories, MYSQL_ASSOC)) {
$json[] = $get_rows;
}
echo json_encode($json);
return;
I toke this code from someone else and since I am not familiar with json I am asking here at stackoverflow how can add a function to the oc_name attribute before the json encodes it and still return the same struckture as it is now, like for example:
language($get_rows['oc_name'])
while ($get_rows = mysql_fetch_array($get_categories, MYSQL_ASSOC)) {
$get_rows['oc_name'] = language($get_rows['oc_name']);
$json[] = $get_rows;
}
You can apply your function on the mentioned field before you add the row in your $json array
$json = array();
while ($get_rows = mysql_fetch_array($get_categories, MYSQL_ASSOC)) {
$get_rows['oc_name']=language($get_rows['oc_name']);
$json[] = $get_rows;
}
I am attempting to fetch JSON from Instagram according to a number of URL parameters, the JSON is then decoded and then the objects required are then encoded into my own JSON format. Whilst I know this sound a little ridiculous, it is what is required. My only issue here is that for some reason it does not encode each section of JSON, it will only work for one item. The code is as below.
<?php
function instagram($count=16){
$igtoken = $_GET['igtoken'];
$hashtag = $_GET['hashtag'];
$url = 'https://api.instagram.com/v1/tags/'.$hashtag.'/media/recent/?access_token='.$igtoken.'&count='.$count;
$jsonData = json_decode((file_get_contents($url)));
$jsonData = json_decode((file_get_contents($url)));
foreach ($jsonData->data as $key=>$value) {
$response = array();
$response["data"] = array();
$data = array();
$data["createdtime"] = $value->caption->created_time;
$data["username"] = $value->caption->from->username;
$data["profileimage"] = $value->caption->from->profile_picture;
$data["caption"] = $value->caption->text;
$data["postimage"] = $value->images->standard_resolution->url;
array_push($response["data"], $data);
$result = json_encode($response);
}
return $result;
}
echo instagram();
?>
It will work for each section of JSON if I do something like this instead:
$result .= '<li>
'.$value->caption->from->username.'<br/>
'.$value->caption->from->profile_picture.'<br/>
'.$value->caption->text.'<br/>
'.$value->images->standard_resolution->url.'<br/>
'.$value->caption->created_time.'<br/>
</li>';
I feel I have bodged up somewhere with the array, however i'm not entirely sure.
What if we move $response["data"] and $result varia out of foreach?
Have you tried this?
$response = array();
$response["data"] = array();
foreach ($jsonData->data as $key=>$value) {
$data = array();
$data["createdtime"] = $value->caption->created_time;
$data["username"] = $value->caption->from->username;
$data["profileimage"] = $value->caption->from->profile_picture;
$data["caption"] = $value->caption->text;
$data["postimage"] = $value->images->standard_resolution->url;
array_push($response["data"], $data);
}
$result = json_encode($response);
return $result;