Must submit form twice - php

Question

I have the following script. It works in jsFiddle
The problem is when I fill in the title AND the text box I have to submit TWICE.
Does someone have an idea of what I'm doing wrong?!
form:
<form id="formid" class="form" method="POST" action="/">
<div>
<label class="title">Title</label>
<div id="titleError"></div>
<input type="text" id="title" name="title" value="">
</div>
<div>
<label class="title">Text</label>
<div id="textError"></div>
<textarea name="text" id="text" rows="14" cols="50"></textarea><br />
</div>
<div>
<input class="btn btn-success" type="submit" id="submitButton" name="submitButton" value="Submit">
</div>
JS:
<script type='text/javascript'>
$(document).ready(function() {
$("#formid").submit( function(event) {
tinyMCE.triggerSave();
var title = $('#title').val();
var text = $('#text').val();
if( title.length === 0 || text.length === 0 ){
if( title.length === 0 ){
$("#titleError").html("<p>Title verplicht</p>");
event.preventDefault();
}
if( text.length === 0 ){
$("#textError").html("<p>Text verplicht</p>");
event.preventDefault();
}
$("html, body").animate({ scrollTop: 0 }, 600);
}
else{
tinyMCE.triggerSave();
/* stop form from submitting normally */
event.preventDefault();
/* Send the data using post */
var posting = $.post( 'http://domain.nl/admin/pages/create', {
title: $('#title').val(),
text: $('#text').val()
});
/* Put the results in the show-content div */
posting.done(function( data ) {
//alert(data);
$.ajax({
url: "<?php echo base_url() ?>/admin/pages",
type: 'GET',
success: function(data) {
$("#show-content").hide().html( data).fadeIn(1500);
}
,
error: function() {
alert("error");
}
});
});
}
});
});
</script>
The solution:
I add this
tinyMCE.triggerSave();
after
$("#formid").submit( function(event) {
and now it works correctly!