Ajax not being fired? - php

Question

I'm using the jquery validator plugin, and I'm trying to make my first attempt with AJAX to it.
Right now, I have the following HTML code:
<div class="grid_12" id="info">
</div>
<div class="grid_12">
<div class="block-border">
<div class="block-header">
<h1>Inserir nova página</h1><span></span>
</div>
<form id="formulario" class="block-content form" action="<?=$_SERVER['PHP_SELF'];?>" method="post">
<div class="_100">
<p><label for="textfield">Nome da página</label><input id="page_name" name="textfield" class="required text" type="text" value="" /></p>
</div>
<div class="_100">
<p><label for="textarea">Conteúdo da página</label><textarea id="page_content" name="textarea" class="required uniform" rows="5" cols="40"></textarea></p>
</div>
<div class="block-actions">
<ul class="actions-left">
<li><a class="button red" id="reset-validate-form" href="javascript:void(0);">Limpar</a></li>
</ul>
<ul class="actions-right">
<li><input type="submit" class="button" name="send" value="Inserir"></li>
</ul>
</div>
And my JS code:
<script type="text/javascript">
$().ready(function() {
/*
* Form Validation
*/
$.validator.setDefaults({
submitHandler: function(e) {
$.jGrowl("Ação executada com sucesso.", { theme: 'success' });
$(e).parent().parent().fadeOut();
/*
* Ajax
*/
var mypostrequest=new ajaxRequest();
mypostrequest.onreadystatechange=function(){
if (mypostrequest.readyState==4){
if (mypostrequest.status==200 || window.location.href.indexOf("http")==-1){
document.getElementById("info").innerHTML=mypostrequest.responseText;
}
else{
alert("An error has occured making the request")
}
}
}
var page_name=encodeURIComponent(document.getElementById("page_name").value);
var page_content=encodeURIComponent(document.getElementById("page_content").value);
var parameters="page_name="+page_name+"&page_content="+page_content;
mypostrequest.open("POST", "ajax/inserir_utilizador.php", true);
mypostrequest.setRequestHeader("Content-type", "application/x-www-form-urlencoded");
mypostrequest.send(parameters);
v.resetForm();
v2.resetForm();
v3.resetForm();
return false;
}
});
var v = $("#create-user-form").validate();
jQuery("#reset").click(function() { v.resetForm(); $.jGrowl("User was not created!", { theme: 'error' }); });
var v2 = $("#write-message-form").validate();
jQuery("#reset2").click(function() { v2.resetForm(); $.jGrowl("Message was not sent.", { theme: 'error' }); });
var v3 = $("#create-folder-form").validate();
jQuery("#reset3").click(function() { v3.resetForm(); $.jGrowl("Folder was not created!", { theme: 'error' }); });
var formulario = $("#formulario").validate();
jQuery("#reset-validate-form").click(function() { formulario.resetForm(); $.jGrowl("O formulário foi limpo!", { theme: 'information' }); });
});
I have a div #info without anything in it that I'm trying to put there the result of the ajax.
My ajax file is just trying to echo the POST values:
<?php
$page_name=$_POST["page_name"];
$page_content=$_POST["page_content"];
echo $page_name."<br />";
echo $page_content;
?>
But it really doesn't work. It really doesn't do anything, or if it does, it refreshes the page.
What am I missing?
Regards and thanks!

Answer 1

I recommend you to use $.ajax() or $.post().
It's much easier and your headache will surely go away.
$.ajax({
type: 'POST',
url: 'url to post',
data: data,
success: function(data, status) {
//callback for success
},
error: error, //callback for failure
dataType: "json" //or "html" etc
});
many examples here:
http://api.jquery.com/jQuery.post/
http://api.jquery.com/jQuery.ajax/