Sort result alphabetically - php

Question

function printAll($dirName)
{
if (empty($leid)) { $leid = "1"; }
$root = $_SERVER['DOCUMENT_ROOT'];
$site = $_GET['site'];
$user = $_GET['user'];
$tag = "";
$dirs=array($dirName);
$files=array();
while($dir=array_pop($dirs)){
$handle=opendir($dir);
while($file=readdir($handle)){
if($file!='.' && $file!='..'){
$dest=$dir.'/'.$file;
$userid = str_replace("$root/", "", $dir);
$userid = str_replace("dl/$site","",$userid);
$userid = str_replace("/","",$userid);
if(is_file($dest)){
$files[]=$file;
$titrepost = htmlspecialchars($file);
$downloadlink = "$dest";
$downloadlink = str_replace("$root/", "", $downloadlink);
$za = new ZipArchive();
$za->open($downloadlink);
$leid = $leid + 1;
echo "<br>
<b>File = $file</b><br>
Userid = $userid
<br>";
for( $i = 0; $i < $za->numFiles; $i++ ){
$stat = $za->statIndex( $i );
$toune = basename( $stat['name'] );
echo "$toune <br>";
}
} else {
$dirs[]=$dest;
}
}
}
}
return $files;
}
$site = $_GET['site'];
$currentdir = getcwd();
$source = "$currentdir/dl/$site";
if (!empty($user)) {
$source = "$currentdir/dl/$site/$user";
}
printAll($source);
This script will list all files inside a ZIP archive then echo the name of each files.
Now i'm having some trouble figuring how to sort the files names ($toune) alphabetically
Here's what i tried:
for( $i = 0; $i < $za->numFiles; $i++ ){
$stat = $za->statIndex( $i );
$toune_arr[] = basename( $stat['name'] );
}
asort($toune_arr);
print_r($toune_arr);
But it doesn't work for this code, $toune_arr won't empty after each zip file is listed so each time the script output the filelist it contains the files of the previous zip archives.

Answer 1

Just reset your array in the begining of your function:
function printAll($dirName)
{
$toune_arr = array();
...