PHP Cart with Object Oriented PHP - php

I am developing a simple system of sample products with Object Oriented PHP, very simple thing. So far, no problem, but I have to create a button that adds a product code recorded in the database to a form in the sidebar. I do not know to develop a shopping cart with OO PHP, and codes that I find always give error because of the call of the database, or when the data list. I've been thinking of doing for JS, any help?
sorry my bad english

I got it, first I did when I click a link step by GET and the ID Code I need after seto it in a cookie, each cookie with an ID. Then I check if cookie has registered with the IDs. Not the best and most correct, but it works (more or less). Now another problem, I need to click two times to get the result as it passes by id and need to be caught refresh = /
I think it was a bit confusing but it is the maximum that dyslexia allows me to do hehehe
Here I set up the structure with the data I have in my product page:
add
<?php
$cod_get = $_GET['cod'];
setcookie("SITENAME_cod_".$id_get."", $cod_get, time()+3600, "/","", 0);
?>
And here I have a loop checking if cookie with ids, I think it will give problems, but for now I think it works ...
Thank you all.
$produto = new produtos();
$i = 0;
$produto->selecionaTudo($produto);
$produto->selecionaCampos($produto);
while($res = $produto->retornaDados()):
$res->id;
$i++;
$get_cookie = $_COOKIE['SITENAME_cod_'.$res->id.''];
if (isset($get_cookie)) {
echo $get_cookie.', ';
}else{
echo "";
}
endwhile;

Related

How to encrypt product ID in URL

I have a database with just over 800 data.
product table
pid name p_page
1 money money.php
2 gold gold.php
3 .
. .
. .
800 .
I have 2 pages...
product_item.php
<div class="button">
View
</div>`
when you click view the product info is pass to product.php
in here i have
if (isset($_GET['pid'])) {
depending on what product the user clicked on the URL might look like something below but the 44 will change to whatever id
http://www.example.x10.mx/money.php?pid=44
the problem with this, is that money.php have a different layout to the other pages and if I change 44 to 68, the product info will show on the page but the layout will not look good.
My question
what is the best way for me to stop users from being able to change the url.
I want to encrypt all my pid in the url so it will look something like
http://www.example.x10.mx//money.php?sel=the product name here or 4 letters or anything
I just want to take away pid from the url.
Please help me. If you dont understand my question please ask in the comment and try and say what you think you understand.
Edited to show my fetch function
$php = "php/";
$apages = "account/";
$bpages = "booking/";
$gpages = "general/";
$ppages = "product/";
// Global functions
function fetchdir($dir)
{
$protocol = $GLOBALS['protocol'];
$host = $GLOBALS['host'];
($dir == $GLOBALS['apages'] || $dir == $GLOBALS['bpages'] || $dir == $GLOBALS['ppages'] || $dir == $GLOBALS['gpages'] ? $branch = $GLOBALS['pagebranch'] : $branch = $GLOBALS['branch']);
echo $protocol.$host.$branch.$dir;
}
Thanks
p.s. I dont know if this can be done in .htaccess but i think it can be done in php
Some clarification:
I have a url which looks like this
www.example.com/account/product.php?pid=1
the problem with this is that someone can change 1 or any number and if they is a pid in the database with that number it will get the items information and display on the page. Which I don't want to happen because not all product are meant to be display in some pages.
In the papge which i show all my available product. I simple uses a SELECT statement and then echo what I need in some div.
In that page I have a view button.
$stmt = $conn->prepare("SELECT * FROM Product WHERE Type = 'shoes'");
$stmt->execute();
$i = 0;
$rows = $stmt->fetchAll(PDO::FETCH_ASSOC);
foreach ($rows as $row) {
$id = ($row['pid']);
$product_page ($row['dir_page']);
<div class="button" >
<a href = "<?php fetchdir($apages) ?><?echo $product_page?ProdID=<?php echo $id>" > View</a >
</div >
}
Depending on the page that information is getting sent to when you click on view I use Get method
<?php
if (isset($_GET['pid'])) {
// Connect to the MySQL database
dbconnect();
$id = preg_replace('#[^0-9]#i', '', $_GET['pid']);
}
If you notice in my select statement used type to show only the product which type is shoes. I have other types as well, which as their other pages. Now the problem is if i change the pid to any page that doesn't have a type of shoes or if an in the other pages and enter a pid which type is shoes or anything, the information from that page will still render. Which I don't want to happen.
My question
how can i stop users from changing that pid and even if they change it. they will still be on the same page?
The problem isn't having the PID in the URL, it is having the template name in the URL.
Store the template name in the database (you are doing this already), and use that to determine what HTML to wrap the data in instead of putting it (money.php) in the URL.
Move your templates out of the web root (they shouldn't be hit by users directly), have a single index.php and then include() the template based on the data in the database.
You cannot prevent someone from changing the URL or from requesting arbitrary URLs. Your server (i.e. your app) has to decide how to respond to an invalid request. If you don't want to display certain things publicly, flag them as such in your database, test for that flag and simply refuse to output anything if that flag is hit.
Make the server respond negatively if something doesn't fit your conditions; don't expect the user to behave correctly.
Assuming that PID is a autoincrement value, you can still obfuscate it. Add another column in the table that contains a randomly-generated key (using uniqid or some derivative). Then use that key in your URL. You'll get something like: www.example.com/account/product.php?pid=II8GypI6H93Ij. This doesn't guarantee that someone won't find it, but it's good enough in most instances.
Check for allowance in the Database
Depending on your level of programming skills, in the database you could add a field or a relational table that relates the ID of the pages to allowed page templates (I'm guessing you're talking about templates.)
Then in the code you can make it so the page checks this database to see if the page contents are allowed to show. Something like:
$query1 = "SELECT * FROM Product WHERE Type = 'shoes' and allowedTemplate='1'";
This way you won't have to hardcode everything into the code itself. On the backend (if there is a CMS) then you could have checkboxes indicating the relationships to the templates and prefill them by default.
You'll need to make the site so something with that stuff though.
Your other option
You could use clean urls (which used to be better for SEO) to show real words instead of the IDs. Then you can use .htaccess tricks to convert the URIs to their ID counterparts with a dynamic RewriteMap.

How to make a webpage retain variables from form?

Sorry if I'm duplicating threads here, but I wasn't able to find an answer to this anywhere else on StackOverflow.
Basically what I'm trying to do is make a list in which variables entered in a form by a user can be kept. At the moment, I have the code which makes this possible, and functional, however the variables entered in the form only appear on the list after the user hits submit... As soon as I refresh the page or go to the page from somewhere else, the variables disappear. Is there any way I can stop this from happening?
Edit: here are the codes:
//Page 1
<?php
session_start();
$entries = array(
0 => $_POST['signup_username'],
1 => $_POST['signup_email'],
2 => $_POST['signup_city']);
$entries_unique = array_unique($entries);
$entries_unique_values = array_values($entries_unique);
echo "<a href='Page 2'>Link</a>";
$_SESSION['entries_unique_values'] = $entries_unique_values;
?>
//Page2
<?php
session_start();
$entries_unique_values = $_SESSION['entries_unique_values'];
foreach($entries_unique_values as $key => $value) {
$ValueReplace = $value;
echo "<br /><a href='http://example.com/members/?s=$ValueReplace'>" . $value . "</a><br/>";
}
?>
Your question is really quite vague. the answer depends on how much data you have to store, and fopr how long you need it to exsist.
By variable I assume you mean data the user has entered and that you want to put into a variable.
I also presume that the list of variables is created by php when the form is submitted.
Php will only create the variable list when the form is submitted as php is done entirely on the server, therefore you will not have or see the variables until the form is submitted.
if you wanted to be able to see the list as it is being created you could use javascript then once you have you php variables the javascript list isn't necesary.
each time you request a php page wheather it is the same one or not the server generates a totally new page, meaning all unhardcoded variables from previous pages will be lost unless you continually post the variables around the pages the server will have no memory of them.
You have a few viable options.
) keep passing the user created variables in POST or GET requests so each page has the necesary info to work with. Depending on the situation it might or might not be a good idea. If the data only needs to exsits for one or two pages then it is ok, but bad if you need the data to be accessable from any page on your web.
2.) start a session and store the variables in a session. Good if the data only needs to be around while the user is connected to the site. but will be lost if user close window or after a time.
3.) place a cookie. not a good idea but ok for simple data.
4.) create a mysql database and drop the variable info in there. great for permanent data. this is how i always complex user data.
just a few ideas for you to look into as it is difficult to see what you really mean. good luck.
use PHP session or store variable values in Cookies via JS or using PHP. It would be nice if you show your working codes :)
Your idea is fine, however you just need to add a little condition to your Page 1 that only set your SESSION values when POST is made, that way it will keep the values even if you refresh. Otherwise when you visit the page without a POST those values will be overwritten by blank values, which is what you are seeing now. You can modify it like
<?php
session_start();
if(isset($_POST["signup_username"]))
{
$entries = array(
0 => $_POST['signup_username'],
1 => $_POST['signup_email'],
2 => $_POST['signup_city']);
$entries_unique = array_unique($entries);
$entries_unique_values = array_values($entries_unique);
$_SESSION['entries_unique_values'] = $entries_unique_values;
}
echo "<a href='http://localhost/Calculator/form2.1.php'>Link</a>";
?>
You could use JavaScript and HTML5 local storage.

Updating multiple page elements without refreshing the page using PHP & jQuery

I have a PHP page that uses jQuery to let a user update a particular item without needing to refresh the page. It is an availability update where they can change their availability for an event to Yes, No, or Maybe. Each time they click on the link the appropriate jQuery function is called to send data to a separate PHP file (update_avail.php) and the appropriate data is returned.
Yes
Then when clicked the params are sent to a PHP file which returns back:
No
Then, if clicked again the PHP will return:
Maybe
It all works fine and I'm loving it.
BUT--
I also have a total count at the bottom of the page that is PHP code to count the total number of users that have selected Yes as their availability by simply using:
<?php count($event1_accepted); ?>
How can I make it so that if a user changes their availability it will also update the count without needing to refresh the page?
My thoughts so far are:
$var = 1;
while ($var > 0) {
count($day1_accepted);
$var = 0;
exit;
}
Then add a line to my 'update_avail.php' (which gets sent data from the jQuery function) to make $var = 1
Any help would be great. I would like to stress that my main strength is PHP, not jQuery, so a PHP solution would be preferred, but if necessary I can tackle some simple jQuery.
Thanks!
In the response from update_avail.php return a JSON object with both your replacement html and your new counter value.
Or to keep it simple, if they click "yes" incriment the counter, if they click No or maybe and their previous action wasn't No or Maybe decrease the counter.
Assuming your users are logged into the system I'd recommend having a status field in the user table, perhaps as an enum with "offline", "available", "busy", "unavailable" or something similar and use the query the number of available users whilst updating the users status.
If you were to do this you'd need to include in extend your methods containing session)start() and session_destroy() to change the availability of the user to available / offline respectively
The best way is the one suggested by Scuzzy with some improvements.
In your php, get the count from the database and return a JSON object like:
{ count: 123, html: 'Yes' }
In your page, in the ajax response you get the values and update the elements:
...
success: function(data) {
$("#linkPlaceholder").html(data.html);
$("#countPlaceholder").html(data.count);
}
...

How to show a users last visited pages in wp / buddypress?

im trying to figure out how i can show the last 3-5 or so pages within my site a person has visited. I did some searching, and I couldn't find a WP plugin that does so, if anyone knows of one, please point me in that direction :) if not, I'll have to write it from scratch, and thats where i'll need the help.
I've been trying to understand the DB and how it works. I'm assuming that this is where the magic will happen, with PHP, unless there is a javascript option using cookies to do it.
Im open to all ideas :P & Thank you
If i were to code such a plugin, i'd use the session cookies to populate an array via array_unshift() and array_pop(). it'd be as simple as :
$server_url = "http://mydomain.com";
$current_url = $server_url.$_SERVER['PHP_SELF'];
$history_max_url = 5; // change to the number of urls in the history array
//Assign _SESSION array to variable, create one if empty ::: Thanks to Sold Out Activist for the explanation!
$history = (array) $_SESSION['history'];
//Add current url as the latest visit
array_unshift($history, $current_url);
//If history array is full, remove oldest entry
if (count($history) > $history_max_url) {
array_pop($history);
}
//update session variable
$_SESSION['history']=$history;
Now i've coded this on the fly. There might be syntax errors or typos. If such a mistake appears, just put a notice and i'll modify it. The purpose of this answer is mostly to make a proof of concept. You can adapt this to your liking. Please note that i assume that session_start() is already in your code.
Hope it helps.
===============
Hey! Sorry about the late answer, i was out of town for a couple of days! :)
This addon is to answer your request for a print out solution with LI tags
Here's what i'd do :
print "<ol>";
foreach($_SESSION['history'] as $line) {
print "<li>".$line.</li>";
}
print "</ol>";
Simple as that. you should read the foreach loop here : http://www.php.net/manual/en/control-structures.foreach.php
As for the session_start();, put it before you use any $_SESSION variables.
Hope it helped! :)
I'm going to update and translate the code above for WordPress 5+ because the original question has the wordpress tag. Note that you don't need session_start() anywhere.
Here it goes, add the code below to your singular.php template (or single.php + page.php templates, depending on what you need):
/**
* Store last visited ID (WordPress ID)
*/
function so7035465_store_last_id() {
global $post;
$postId = $post->ID; // or get the post ID from your template
$historyMaxUrl = 3; // number of URLs in the history array
$history = (array) $_SESSION['history'];
array_unshift($history, $postId);
if (count($history) > $historyMaxUrl) {
array_pop($history);
}
$_SESSION['history'] = $history;
}
// Display latest viewed posts (or pages) wherever you want
echo '<ul>';
foreach ($_SESSION['history'] as $lastViewedId) {
echo '<li>' . get_permalink($lastViewedId) . '</li>';
}
echo '</ul>';
You can also store latest viewed custom post types (CPT) by placing the so7035465_store_last_id() function in your single-cpt.php template.
You can also add it to a hook or inject it in your template as an action, but that is beyond the scope of this question.

Fetch database information on a new page without using new documents

I'm working on a page where I've listed some entries from a database. Although, because the width of the page is too small to fit more on it (I'm one of those people that wants it to look good on all resolutions), I'm basically only going to be able to fit one row of text on the main page.
So, I've thought of one simple idea - which is to link these database entries to a new page which would contain the information about an entry. The problem is that I actually don't know how to go about doing this. What I can't figure out is how I use the PHP code to link to a new page without using any new documents, but rather just gets information from the database onto a new page. This is probably really basic stuff, but I really can't figure this out. And my explanation was probably a bit complicated.
Here is an example of what I basically want to accomplish:
http://vgmdb.net/db/collection.php?do=browse&ltr=A&field=&perpage=30
They are not using new documents for every user, they are taking it from the database. Which is exactly what I want to do. Again, this is probably a really simple process, but I'm so new to SQL and PHP coding, so go easy on me, heh.
Thanks!
<?php
// if it is a user page requested
if ($_GET['page'] == 'user') {
if (isset($_GET['id']) && is_numeric($_GET['id'])) {
// db call to display user WHERE id = $_GET['id']
$t = mysql_fetch_assoc( SELECT_QUERY );
echo '<h1>' . $t['title'] . '</h1>';
echo '<p>' . $t['text'] . '</p>';
} else {
echo "There isn't such a user".
}
}
// normal page logic goes here
else {
// list entries with links to them
while ($t = mysql_fetch_assoc( SELECT_QUERY )) {
echo '<a href="/index.php?page=user&id='. $t['id'] .'">';
echo $t['title'] . '</a><br />';
}
}
?>
And your links should look like: /index.php?page=user&id=56
Note: You can place your whole user page logic into a new file, like user.php, and include it from the index.php, if it turns out that it it a user page request.
Nisto, it sounds like you have some PHP output issues to contend with first. But the link you included had some code in addition to just a query that allows it to be sorted alphabetically, etc.
This could help you accomplish that task:
www.datatables.net
In a nutshell, you use PHP to dynamically build a table in proper table format. Then you apply datatables via Jquery which will automatically style, sort, filter, and order the table according to the instructions you give it. That's how they get so much data into the screen and page it without reloading the page.
Good luck.
Are you referring to creating pagination links? E.g.:
If so, then try Pagination - what it is and how to do it for a good walkthrough of how to paginate database table rows using PHP.

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