When I call a script from Javascript
var user = document.getElementById('username').value;
var pass = document.getElementById('password').value;
var conf = document.getElementById('confirm').value;
var code = document.getElementById('code').value;
if(code.length == 0 || pass.length == 0 || user.length == 0 || conf.length == 0) {
alert("Entries empty");
} else if(pass != conf) {
alert("Passwords don't match");
}
window.location = "scripts/changepassword.php?Username="+user+"&Password="+pass+"&Code="+code;
changepassword.php in my scripts folder has the following headings its refreshing the current page and not passing the parameters into the script. any ideas?
it gives me error2.
scripts/changepassword.php
if (isset($_GET['Username']) && isset($_GET['Password'])&& isset($_GET['Code'])) {
...
} else {
$response = array('result'=>"error2");
echo json_encode($response);
echo "hi";
}
the window.location changes the page location (url). If you want to execute the php script without refreshing the page, use AJAX
Related
The code should make a pop up window, asking for confirmation "press ok to confirm the action for user" but it doesn't. i'm all out of ideas.
function friendToggle(type,user,elem){
var conf = confirm("Press OK to confirm the '"+type+"' action for user
<?php echo $u; ?>.");
if(conf != true){
return false;
}
$(elem).innerHTML = 'please wait ...';
var ajax = ajaxObj("POST", "php_parsers/friend_system.php");
ajax.onreadystatechange = function() {
if(ajaxReturn(ajax) == true) {
if(ajax.responseText == "friend_request_sent"){
$(elem).innerHTML = 'OK Friend Request Sent';
} else if(ajax.responseText == "unfriend_ok"){
$(elem).innerHTML = '<button onclick="friendToggle(\'friend\',\'<?php echo $u; ?>\',\'friendBtn\')">Request As Friend</button>';
} else {
alert(ajax.responseText);
$(elem).innerHTML = 'Try again later';
}
}
}
ajax.send("type="+type+"&user="+user);
}
</script>
PHP code:
<?php
$friend_button = '<button disabled>Request As Friend</button>';
$block_button = '<button disabled>Block User</button>';
// LOGIC FOR FRIEND BUTTON
if($isFriend == true){
$friend_button = '<button onclick="friendToggle(\'unfriend\',\''.$u.'\',\'friendBtn\')">Unfriend</button>';
}
else if($user_ok == true && $u != $log_username &&
$ownerBlockViewer == false){
$friend_button = '<button onclick="friendToggle(\'friend\',\''.$u.'\',\'friendBtn\')">Request As Friend</button>';
}
// LOGIC FOR BLOCK BUTTON
if($viewerBlockOwner == true){
$block_button = '<button onclick="blockToggle(\'unblock\',\''.$u.'\',\'blockBtn\')">Unblock User</button>';
} else if($user_ok == true && $u != $log_username){
$block_button = '<button onclick="blockToggle(\'block\',\''.$u.'\',\'blockBtn\')">Block User</button>';
}
?>
Opening up the console i see "Uncaught SyntaxError: Invalid or unexpected token"
The console issue is with lines 2 & 3 of your JavaScript code;
var conf = confirm("Press OK to confirm the '"+type+"' action for user
<?php echo $u; ?>.");
You have a multi-line String which the console is not interpreting as one String value. In order to resolve, ECMAScript 6 (ES6) introduced template literals which can be utilized like below to handle multi-line Strings;
var conf = confirm(`Press OK to confirm the '"+type+"' action for user
<?php echo $u; ?>.`);
(i.e. use back-ticks rather than double quotes to start & end the multi-line String)
Or, if ES6 isn't supported you can use good old String concatenation like below;
var conf = confirm("Press OK to confirm the '"+type+"' action for user" +
"<?php echo $u; ?>.");
I've got myself a little script that checks the validity of a link supplied by the user, making it safe to store in the database (safer at least) and to confirm it's a link to facebook.
Now I want to roll this code out for another links, changing parameters as and when needed so that links to people user profile on these sites work, bit I dont want to copy and paste the code another 5 times and then try and adapt the Ajax to work with it, if theres a better way to approach this.
This is my code, it can been seen working at www.vwrx_project.co.uk/test.php. It hopefully only accepts facebook.com/(something here) .
link_checker.php
<?php
function check_url($dirty_url) {
//remove anything before facebook.com using strstr()
//clean url leaving alphanumerics : / . only - required to remove facebook link format with /#!/
$clean_url = strstr(preg_replace('#[^a-z0-9:/.?=]#i', '', $dirty_url), 'facebook.com');
$parsed_url = parse_url("http://www.".$clean_url); //parse url to get brakedown of components
$safe_host = $parsed_url['host']; // safe host direct from parse_url
// str_replace to switch any // to a / inside the returned path - required due to preg_replace process above
$safe_path = str_replace("//", "/", ($parsed_url['path']));
if ($parsed_url['host'] == 'www.facebook.com' && $parsed_url['path'] != '' && $parsed_url['path'] != '/') {
echo "Facebook";
} else if ($parsed_url['host'] == 'www.facebook.com' && $parsed_url['path'] == '') {
echo "missing_profile1";
} else if ($parsed_url['host'] == 'www.facebook.com' && $parsed_url['path'] == '/') {
echo "missing_profile2";
} else {
echo "invalid_url";
}
}
?>
Test.php
<?php
include_once ("includes/check_login_status.php");
include_once ("includes/link_checker.php");
// AJAX CALLS THIS LOGIN CODE TO EXECUTE
if(isset($_POST["L"])){
$dirty_url = $_POST["L"]; //user supplied link
//$dirty_url = "http://www.facebook.com/profile.php?id=4";
// if $dirty_url is blank
if($dirty_url == ""){
echo "no link supplied";
exit();
} else {
check_url($dirty_url);
}
exit();
}
?>
<html>
<head>
<title>testing</title>
<script type="text/javascript" src="js/main.js"></script>
<script src="js/main.js"></script>
<script src="js/ajax.js"></script>
<script>
function emptyElement(x){
_(x).innerHTML = "";
}
function cleanURL(){
var user_url = _("user_link").value;
var func = _("hidden").value;
if(user_url == ""){
_("status").innerHTML = "Please provide a link before clicking submit";
} else {
_("submitbtn").style.display = "none";
_("status").innerHTML = 'please wait ...';
var ajax = ajaxObj("POST", "test.php");
ajax.onreadystatechange = function() {
if(ajaxReturn(ajax) == true) {
if(ajax.responseText == "no link supplied"){
_("status").innerHTML = "Submitted blank form data.";
_("submitbtn").style.display = "block";
} else if(ajax.responseText == "invalid_url"){
_("status").innerHTML = "The url supplied is invalid";
_("submitbtn").style.display = "block";
} else if(ajax.responseText == "missing_profile1"){
_("status").innerHTML = "Please supply a link to your profile";
_("submitbtn").style.display = "block";
} else if(ajax.responseText == "missing_profile2"){
_("status").innerHTML = "Please supply a link to your profile";
_("submitbtn").style.display = "block";
} else{
_("status").innerHTML = ajax.responseText;
}
}
}
ajax.send("L="+user_url);
}
}
</script>
</head>
<body>
<p id="status"></p>
<form id="linkform" onSubmit="return false;">
<input type="text" id="user_link">
<input type="hidden" id="hidden" value="Facebook">
<button id="submitbtn" onClick="cleanURL()">Submit</button>
</form>
Why dont you add an additional parameter which is the website you want to allow?
function check_url($dirty_url, $websiteURL)
Then update your function to use the $websiteURL variable instead of the hardcoded 'facebook.com'
Then when you want to have several different urls you can do this
check_url($dirty_url, 'facebook.com');
or
check_url($dirty_url, 'twitter.com');
Or are you wanting to be able to check for multiple sites in the single function? such as facebook.com and twitter.com
I cannot get this script work. I try to warn if login that user entered is available. But I cannot manage this script to work:
$( "#myRegForm" ).submit(function( event ) {
var errors = false;
var userAvi = true;
var loginInput = $('#login').val();
if( loginInput == ""){
$("#errorArea").text('LOGIN CANNOT BE EMPTY!');
$("#errorArea").fadeOut('15000', function() { });
$("#errorArea").fadeIn('15000', function() { });
errors = true;
}
else if(loginInput.length < 5 ){
$("#errorArea").text('LOGIN MUST BE AT LEAST 5 CHARACTERS!');
$("#errorArea").fadeOut('15000', function() { });
$("#errorArea").fadeIn('15000', function() { });
errors = true;
}
else if (loginInput.length >=5) {
$.post('checkLogin.php', {login2: loginInput}, function(result) {
if(result == "0") {
alert("this");
}
else {
alert("that");
}
});
}
if (errors==true) {
return false;
}
});
Everything works fine until loginInput.length >=5 else block. So I assume there is a problem with getting answer from PHP file, but I cannot handle it, though I tried many different ways. Here is checkLogin.php's file (note that jQuery script and PHP file are in the same folder):
<?php
include ("bd.php");
$login2 = mysql_real_escape_string($_POST['login2']);
$result = mysql_query("SELECT login FROM users WHERE login='$login2'");
if(mysql_num_rows($result)>0){
//and we send 0 to the ajax request
echo 0;
}
else{
//else if it's not bigger then 0, then it's available '
//and we send 1 to the ajax request
echo 1;
}
?>
<?php
include ("bd.php");
$login2 = mysql_real_escape_string($_POST['login2']);
$result = mysql_query("SELECT login FROM users WHERE login='$login2'");
if(mysql_num_rows($result)>0){
//and we send 0 to the ajax request
echo "0"; // for you to use if(if(result == "0") you should send a string
} else {
//else if it's not bigger then 0, then it's available '
//and we send 1 to the ajax request
echo "1";
}
?>
You're literally sending the string 'loginInput'.
change
$.post('checkLogin.php', {login2: 'loginInput'}, function(result) {
to
$.post('checkLogin.php', {login2: loginInput}, function(result) {
Edit
I would just comment out everything except the following for now and see if that at least works
$.post('checkLogin.php', {login2: 'loginInput'}, function(result) { // put loginInput back in quotes
alert('#'+result+'#'); // # to check for whitespace
});
I have a problem where the values entered (email and password) into my login form are not being parsed to my server php script.
My ajax request:
function signin(){
var loginEmail = gebi("loginEmail").value;
var loginPass = gebi("loginPass").value;
if(loginEmail == "" || loginPass == ""){
gebi("loginEmail").style.borderColor = "red";
gebi("loginPass").style.borderColor = "red";
} else {
gebi("signinBtn").style.display = "none";
//Declare ajax request variables
hr = new XMLHttpRequest();
url = "main.php";
vars = "email="+loginEmail+"&pass="+loginPass;
//Open the PHP file that is receiving the request
hr.open("POST", url, true);
//Set content type header info for sending url ecncoded variable in the request
hr.setRequestHeader("Content-type", "application/x-www-form-urlencoded");
//Trim string data before sending it
if (!String.prototype.trim) {
String.prototype.trim = function () {
return this.replace(/^\s+|\s+$/g, '');
};
}
//Access the onreadystatechange event for the XMLHttpRequest
hr.onreadystatechange = function() {
if (hr.readyState == 4 && hr.status == 200) {
var responseText = hr.responseText.trim();
if (responseText != "signin_failed") {
console.log(responseText);
} else {
console.log(responseText);
gebi("signinBtn").style.display = "block";
gebi("loginEmail").style.borderColor = "red";
gebi("loginPass").style.borderColor = "red";
}
}
}
//Send the data to the PHP file for processing and wait for responseText
hr.send(vars);
}
}
and when the php script returns a value using this code:
if (isset($_POST["email"])) {
echo 'email = '+$_POST["email"];
}
the return value that is logged to the console is '0' even tho there is data present in the forms fields.
What is going wrong?
The problem is in your PHP script. If you are trying to concatenate string in PHP use dot .. + is used to concatenate string in languages like javascript.
echo 'email = ' . $_POST["email"];
this is changepassword.php file
<?php
include 'core/init.php';
if (empty($_POST) === false) {
if (md5($_POST['current_password']) === $user_data['password']) {
} else {
$errors[] = 'Your current psasword is incorrect';
}
}
if (empty($_POST) === false && empty($errors) === true) {
change_password($session_user_id, $_POST['password']);
} else if (empty($errors) === false) {
$error = output_errors($errors);
this variable
}
?>
this is the jQuery file
$('#save_pass').click(function(){
var current_password = $('#current').val();
var password = $('#new').val();
var password_again = $('#confirm').val();
if ((password == password_again) && (password.length >= 8)) {
$.post('changepassword.php', {current_password: current_password, password: password, password_again: password_again });
$('#show').html('password changed').fadeIn(500).delay(2000).fadeOut(500);
} else if ((current_password ==0) || (password_again.length == 0) || (password.length == 8)) {
$('#show').html('all fields are required').fadeIn(500).delay(2000).fadeOut(500);
} else {
$('#show').html('your password must be at least 8 characters').fadeIn(500).delay(2000).fadeOut(500); }
$('#current').val(null);
$('#new').val(null);
$('#confirm').val(null);
});
i want to echo out $error variable when a user enters an incorrect password and click on the change password button with id="#save_pass"
You cannot echo php variables within a javascript file. Instead, put the javascript in your php file and echo it there - eg:
<script>
function something() {
alert('<?php echo $error; ?>');
}
</script>
In order to get back the errors from your $.post() ajax call, you need to echo $errors in your php script. Then add a success/done function to your $.post():
$.post('changepassword.php', {current_password: current_password ...})
.done(function (data) {
alert(data);
}
This should be the basics for getting back the raw echo data, but look at $.post documentation for more guidance on how to refine this.