$f = sprintf ("%.1f",$per);
echo "You hit".$f."
By this code i can show only one digit after floating point.But when my result is 100%,then it shows 100.0%. I want to show 100%. how could i do this????
The easiest way to do this is to cast resulting string into float again after formatting, i.e.:
$f=100.44;
$g=100;
var_dump((float)sprintf('%.1f', $f));//100.4
var_dump((float)sprintf('%.1f', $g));//100
$per = 100;
$f = sprintf ("%.1f",$per);
$rounded = round($f, 1);
echo $rounded;
Related
$quantity = 20;
$product_rate = 66.79;
$total = $quantity * $product_rate;
echo $total;
Output is showing 1335.8000000000002
is there possible to show 1335.8 using php..?
You can use the number_format() function like this:
$firstNum = 1335.8000000000002;
$number = number_format($firstNum, 1, '.', '');
echo $number;
outputs:
1335.8
more on number_format() here: http://php.net/number-format.
You can also multiply the number by 10, then use intval() to convert it to an integer (that way stripping out the decimals) and then divide by 10 like this:
$firstNum = 1335.8000000000002;
$number = 10 * intval($firstNum)/10;
echo $number;
outputs:
1335.8
Note: when using the methods above there will be no rounding, for rounding you would use something like this:
$number = round($firstNum, 1);
echo $number;
which in this case also outputs:
1335.8
Do you really use these variable values? I'm using PHP7 and the output for your given values is 1335.8. If you do a manual calculation it is the same result. It should be 1335.8. Anyway if you need to roundup the value you can use below.
round($total,1);
Please refer the below link and you will be able to grab more details.
http://php.net/manual/en/function.round.php
Because how floating point numbers work, they cannot represent every numbers exactly, so approximations are made.
The closest representation of 20 is 20, it can represent 20 exactly, but 66.79 for instance is approximated to 66.7900000000000062527760746889, that times 20 is 1335.800000000000125055521493778 that again cannot be represented and is approximated to 1335.80000000000018189894035459.
Depending on how you choose to print this number, it may round different ways, in your case for some reason you decided to print 13 decimal places so it rounded to 1335.8000000000002, but if you print only 1 or 2 decimal places it will print as 1335.8 or 1335.80. Just be mindful about that when printing floating point numbers, you may want to specify how many decimal places are relevant to you. For that, use number_format().
Example:
echo number_format($number, 2); // prints 2 decimal places
You can do this simply using echo echo round($total, 1) instead of doing round($total)
Is there any difference between floor() and intval()? Though both returns the same results, is there any issue with regard to performance? Which of the two is faster? Which is the right php function to use if I just want to return the whole value only of a decimal?
The goal here is to display 1999.99 to 1999, omitting the decimal value and only return the whole number.
$num = 1999.99;
$formattedNum = number_format($num)."<br>";
echo intval($num) . ' intval' . '<br />';
echo floor($num) . ' floor';
The functions give different results with negative fractions.
echo floor(-0.1); // -1
echo intval(-0.1); // 0
The fastest way is to use type casting: (int)$num.
Per the docs,
The return value of floor() is still of type float because the value range of float is usually bigger than that of integer.
Intval() returns an int, however.
$v = 1999.99;
var_dump(
intval($v),
floor($v)
);
Output:
int(1999)
float(1999)
Docs:
http://php.net/manual/en/function.intval.php
http://php.net/manual/en/function.floor.php
$ratio_x = (0.70/100);
$computation = $ratio_x * 8000;
$noDeci = floor(($ratio_x * 8000)*1)/1;
$intval = intval(($ratio_x * 8000)*1)/1;
$noDeci_hc = floor((int)56*1)/1;
echo $computation."|".$noDeci."|".$noDeci_hc."|".$intval;
OUTPUT:
56|55|56|55
$noDeci returns 55???
When I am using (int) with (double) some times it is not working correct.
Look At The PHP Code Example:
I Need To LEAVE 2 Decimals And REMOVE Other...
I Know number_format(); function But I Cannot Use It. Because It Is Rounding Number
number_format(24.299,2);
Output: 24.30
I Need: 24.29
<?php
$str="158.2";
echo (double)$str; // Output: 158.2
echo (double)$str*100; // Output: 15820
echo (int)((double)$str*100); // Output: 15819 <-WHY? It Must To Be 15820, Why 15819?
echo ((int)((double)$str*100)/100); // Output: 158.19
?>
I need To leave two decimals in the number and cut other WITHOUT rounding.
Because of floating point precision (see for example this question: PHP - Floating Number Precision), 158.2 * 100 is not exactly 15820 but something like 15819.99999999.
Now (int) is for type conversion, not for rounding, and any digits after the point are cut of.
I need To leave two decimals in the number and cut other WITHOUT rounding.
This is easy:
number_format($str, 2);
Update
number_format does round, so it is a bit more complicated:
bcmul($str,100,0)/100
bcmul multiplies with arbitrary precision, in this case 0. Results:
bcmul(158.2,100,0)/100 == 158.2
bcmul(24.299,100,0)/100 == 24.29
This doesn't answer the question of why that happens (it could be a precision bug), but to solve your problem, try using $foo = sprintf("%.2f", (float)$str);.
Example:
$str = "158.2";
$num = (double)$str;
print sprintf("%.2f", $num);
EDIT: Infact, yes, this is a precision issue. (in C++) by printing 158.2 to 20 decimal places, I get the output of "158.19999999999998863132". This is an inherent problem with floating point/double precision values. You can see the same effect by using echo sprintf("%.20f", $var); in PHP.
First off, PHP is a language that allows you to type juggle. Which means you do not need the (int) or the (double) to do what you're trying to do.
<?php
$str="158.2"; //could also do $str = 158.2
echo $str; // Ouput: 158.2
echo $str * 100; //Output: 15820
echo number_format($str, 2); //Output: 158.20
echo number_format(($str*100)/100, 2); //Output: 158.20
?>
Use the number_format command to format your numbers how you want.
More here
Never cast an unknown fraction to integers, see the manual on http://www.php.net/manual/en/language.types.integer.php.
(int) ( (0.1+0.7) * 10 ); will result in 7, not 8 as one might expect. Casting from float to integer will always round down - and you may also want to check the operator precedence http://php.net/manual/en/language.operators.precedence.php.
Solution: calculate your fraction before you cast it. $fStr = (float) $str; $iStr = (int) $fStr;
Fixed.
function cutDecimals($number,$decimal){
$_str=(string)$number;
if(strpos($_str,".")!==false){
$dotPosition=strpos($_str,".")+1;
$_numCount=strpos($_str,".");
$_decimal=strlen($_str)-$dotPosition;
if($_decimal<$decimal) return (double)$_str;
else return (double)substr($_str,0,$_numCount+$decimal+1);
}else return (double)$_str;
}
echo cutDecimals("158.099909865",2)."<br />";
echo cutDecimals("14.02",2)."<br />";
echo cutDecimals("41.12566",2)."<br />";
echo cutDecimals("1.981",2)."<br />";
echo cutDecimals("0.4111",2)."<br />";
echo cutDecimals("144.2",2)."<br />";
echo cutDecimals("55.000000",2)."<br />";
echo cutDecimals("1456115.499811445121",2)."<br />";
?>
I was just curious about this to see how this might work.
$number = "3/4";
echo $number;
and I get 3/4 as a string
$number = 3/4;
echo $number;
and I get 0.75 because it's doing the math
I am curious to see if there is a way to strip the "/" from the first one and have it divide number before the "/" by the number after the "/" so that it would come out as 0.75 instead of 3/4.
The reason I am building a form for a person who wants them to input the number in decimal form. However if a person inputs 3/4 I am going to kick an error that asks them to input it in decimal form and give them the decimal number.
A simple function would look like something below, you can throw more error handling in there if you want also.
function makeDecimal($string)
{
$parts = explode('/',$string);
if(count($parts) != 2)
//throw error here
return intval($parts[0]) / intval($parts[1]);
}
You can explode() the expression using the "/" as the delimited then just do the math on the numbers.
<?php
$number = "3/4";
$num = explode("/", $number);
$a = $num[0];
$b = $num[1];
$result = ((float)$a) / ((float)$b);
echo $result;
?>
Hope this helps
How do I output a value as a number in php? I suspect I have a php value but it is outputting as text and not as a number.
Thanks
Here is the code - Updated for David from question below
<?php
if (preg_match('/\-(\d+)\.asp$/', $pagename1, $a))
{
$pageNumber = $a[1];}
else
{ // failed to match number from URL}
}
?>
If I call it in: This code it does not seem to work.
$maxRows_rs_datareviews = 10;
$pageNum_rs_datareviews = $pagename1; <<<<<------ This is where I want to use it.
if (isset($_GET['pageNum_rs_datareviews'])) {
$pageNum_rs_datareviews = $_GET['pageNum_rs_datareviews'];
}
If I make page name a static number like 3 the code works, if I use $pagename1 it does not, this gives me the idea $pagename1 is not seen as a number?
My stupidity!!!! - I used $pagename1 instead of pageNumber
What kind of number? An integer, decimal, float, something else?
Probably the easiest method is to use printf(), eg
printf('The number %d is an integer', $number);
printf('The number %0.2f has two decimal places', $number);
This might be blindingly obvious but it looks like you want to use
$pageNum_rs_datareviews = $pageNumber;
and not
$pageNum_rs_datareviews = $pagename1;
echo (int)$number; // integer 123
echo (float)$number; // float 123.45
would be the easiest
I prefer to use number_format:
echo number_format(56.30124355436,2).'%'; // 56.30%
echo number_format(56.30124355436,0).'%'; // 56%
$num = 5;
echo $num;
Any output is text, since it's output. It doesn't matter what the type of what you're outputting is, since the human eye will see it as text. It's how you actually treat is in the code is what matters.
Converting (casting) a string to a number is different. You can do stuff like:
$num = (int) $string;
$num = intval($string);
Googling php string to number should give you a beautiful array of choices.
Edit: To scrape a number from something, you can use preg_match('/\d+/', $string, $number). $number will now contain all numbers in $string.