I want to know if it is possible to save a file to a different folder once it is opened. My current logic is -
$myfile = $_POST['file']; // gets path of (in this case an image)
$size = getimagesize($myfile); //for some reason I get an error message when this fails
// I'm assuming there is a better way of determining if the file is an image file or not.
if($size)
{
//save file to said file path
}
Try:
if($size)
{
copy($myfile, $newfile); //$newfile - with full path!
}
Related
I would to create a program that upload a file and whatever it is inside the file i would output it through the use of the textarea. But my problem is I can't get the full path of the uploaded file due to security of the browser. I tried using this How to get the path of a file before its uploaded? as a reference but it only show the fakepath. Main problem is I can't get the full path to store it in a variable. Any idea how to do this?
Im using this code to get the file name
<?php
if(isset($_POST['btnSubmit']))
{
$fileName = $_POST['file'];
$fullPath = (realpath).$fileName;
--here there must be a variable that will hold the fullpath but the $fullPath is wrong way to declare.
echo $fullPath."\n\n";
}
?>
I am having a problem with move_uploaded_file().
I am trying to upload a image path to a database, which is working perfectly and everything is being uploaded and stored into the database correctly.
However, for some reason the move_uploaded_file is not working at all, it does not produce the file in the directory where I want it to, in fact it doesn't produce any file at all.
The file uploaded in the form has a name of leftfileToUpload and this is the current code I am using.
$filetemp = $_FILES['leftfileToUpload']['tmp_name'];
$filename = $_FILES['leftfileToUpload']['name'];
$filetype = $_FILES['leftfileToUpload']['type'];
$filepath = "business-ads/".$filename;
This is the code for moving the uploaded file.
move_uploaded_file($filetemp, $filepath);
Thanks in advance
Try this
$target_dir = "business-ads/";
$filepath = $target_dir . basename($_FILES["leftfileToUpload"]["name"]);
move_uploaded_file($_FILES["leftfileToUpload"]["tmp_name"], $filepath)
Reference - click here
Try using the real path to the directory you wish to upload to.
For instance "/var/www/html/website/business-ads/".$filename
Also make sure the web server has write access to the folder.
You need to check following details :
1) Check your directory "business-ads" exist or not.
2) Check your directory "business-ads" has permission to write files.
You need to give permission to write in that folder.
make sure that your given path is correct in respect to your current file path.
you may use.
if (is_dir("business-ads"))
{
move_uploaded_file($filetemp, $filepath);
} else {
die('directory not found.');
}
I have a problem with saving PDF files to folders on my server. The code worked at one time and now it doesn't. What I want it to do is to check if someone is trying to upload a PDF when a form is submitted, and if there is a PDF in the file field it uploads it and then saves the path to the mysql database. Code is below:
if (!empty($_FILES['pdf'])){
$idir = "../files/PDF/"; //my directory file is supposed to be saved in
$randomd=rand(0000000,9999999); //creates a random number as filename
$domain = "http://".$_SERVER['HTTP_HOST'];
$file_ext = strrchr($_FILES['pdf']['name'], '.'); grabs file extension. my code checked if the file was a pdf a different way and neither seems to work.
$destination=$randomd.$file_ext; //new filename
if ($file_ext=='pdf') {
move_uploaded_file($_FILES['pdf']['tmp_name'], "$idir" . $destination);
$pdf= $domain."/files/PDF/".$destination; } else { echo("File type not supported.");
mysql_query("UPDATE tbl_listings SET pdf='$pdf' WHERE listing_id='$lid'");
}
The if not empty does not work and it always tries to upload a file, but when I check the folder nothing is in there and it doesnt update the mysql.
$_FILES['pdf'] will never be empty(when the form has been submitted), no matter if a file has been selected or not, it will always return an array.
Check $_FILES['pdf']['error'] , it will be 4 when no file has been uploaded.
I am sending image from android apps to server. The problem is image not moving to the correct path, but only at current directory (only in which that php script stored). I tested this codes on local server and webserver, getting same result. Any one can find out whats problems.
Local Server: XAMPP 1.7.7
My PHP Script :
<?php
$base=$_REQUEST['image'];
$Username=$_REQUEST['Username'];
$binary=base64_decode($base);
header('Content-Type: bitmap; charset=utf-8');
$file = fopen($Username.'.png', 'w');
fwrite($file, $binary);
$uploadFilename = '/htdocs/android/ProfileImage/';
$tr =move_uploaded_file($_FILES[$file]['tmp_name'], $uploadFilename);
if($tr)
echo 'true';
else
echo 'false';
echo 'Successfully Uploaded';
?>
Showing Output and Error in Local Server
Strict Standards: Resource ID#3 used as offset, casting to integer (3) in C:\xampp\htdocs\android\uploadSimage.php on line 12
Notice: Undefined offset: 3 in C:\xampp\htdocs\android\uploadSimage.php on line 12
falseSuccessfully Uploaded
Showing Output and Error in Webserver
Notice: Undefined offset: 3 in C:...\uploadSimage.php on line 12
falseSuccessfully Uploaded
move_uploaded_file() expects the second parameter to be a string representing the new path and filename of upload. Currently, you are passing only a path. I also question whether the path is correct. It must be a full path, or a relative path.
You are also using the $_FILES array incorrectly. Are you uploading the image by encoding it in base64 and passing it via the URL's query string? Or are you actually uploading it using a multipart/form-data file upload field?
If you uploaded a file belonging to the upload field called image then you would get access to the file like this:
$origname = $_FILES['image']['name']; // the name from the client device
$temppath = $_FILES['image']['tmp_name']; // the temp location on the PHP server
$error = $_FILES['image']['error']; // > 0 if there was an error
$size = $_FILES['image']['size']; // size of the file
$type = $_FILES['image']['type']; // mime type, cannot be trusted though
You would then move it like this:
// Be careful using the original file name.
// If the user uploads a file with a .php extension, they may be
// able to run PHP code on your server if they can access the upload folder
// You should either generate a random file name or remove the extension
// IF THE DESTINATION FILE EXISTS, IT WILL BE OVERWRITTEN
$newPath = '/home/yoursite/htdocs/uploads/' . $origname;
$moved = move_uploaded_file($_FILES['image']['tmp_name'], $newPath);
if ($moved) {
echo "File was moved successfully.";
} else {
echo "Failed to move file.";
}
EDIT:
If you are in fact uploading the image by encoding it in base64 and sending it over the URL, then you don't need move_uploaded_file at all; in that case you can just write the decoded contents to a file anywhere you like. Keep in mind, the length of the URL may be limited so sending the image in the URL via base64 may not be a good idea.
EDIT 2:
To comment on the questions in your subsequent answer: The php function move_uploaded_file() should only be used when the file you are trying to move was uploaded to PHP using an HTTP POST method upload. It does an internal check to see if the file you are trying to move was uploaded to PHP. If it was not, then it won't move the file. Therefore you shouldn't be using move_uploaded_file() since you confirmed you were uploading the image through the URL.
Since your PHP script's path is C:\xampp\htdocs\android, this means the root path is C:\. The server root is different from your web root or document root which are both relative to your public directory. Any time you are dealing with reading/writing files in PHP, you use the full server path (relative to C:\ or /).
Given the new facts, try some code like this to "upload" the image:
<?php
$base = (isset($_REQUEST['image'])) ? $_REQUEST['image'] : '';
$Username = (isset($_REQUEST['Username'])) ? trim($_REQUEST['Username']) : '';
$binary = #base64_decode($base);
if (empty($Username)) {
die('no username specified');
}
if (!$binary) {
// data was not in base64 or resulted in an empty string
die('invalid image uploaded');
}
$basePath = 'C:\\xampp\\htdocs\\android\\ProfileImage\\';
$imagePath = $basePath . $Username . '.png';
$file = #fopen($imagePath, 'w+');
if (!$file) {
die('failed to open ' . $imagePath . ' for writing');
}
fwrite($file, $binary);
fclose($file);
echo 'Successfully Uploaded';
Make sure to take the necessary precautions so I can't upload an image for another user.
per to this document http://php.net/manual/en/function.move-uploaded-file.php another reason for this problem is invalid File name if your file Name in
move_uploaded_file ( string $filename , string $destination ) be invalid
this function return false
I accessed my server using file zilla and give write Group permissions to the target folder and then it worked.
If you're using XAMPP:
sudo chmod 777 -R /opt/lampp/htdocs/
I have searched far and wide on this one, but haven't really found a solution.
Got a client that wants music on their site (yea yea, I know..). The flash player grabs the single file called song.mp3 and plays it.
Well, I am trying to get functionality as to be able to have the client upload their own new song if they ever want to change it.
So basically, the script needs to allow them to upload the file, THEN overwrite the old file with the new one. Basically, making sure the filename of song.mp3 stays intact.
I am thinking I will need to use PHP to
1) upload the file
2) delete the original song.mp3
3) rename the new file upload to song.mp3
Does that seem right? Or is there a simpler way of doing this? Thanks in advance!
EDIT: I impimented UPLOADIFY and am able to use
'onAllComplete' : function(event,data) {
alert(data.filesUploaded + ' files uploaded successfully!');
}
I am just not sure how to point THAT to a PHP file....
'onAllComplete' : function() {
'aphpfile.php'
}
???? lol
a standard form will suffice for the upload just remember to include the mime in the form. then you can use $_FILES[''] to reference the file.
then you can check for the filename provided and see if it exists in the file system using file_exists() check for the file name OR if you don't need to keep the old file, you can use perform the file move and overwrite the old one with the new from the temporary directory
<?PHP
// this assumes that the upload form calls the form file field "myupload"
$name = $_FILES['myupload']['name'];
$type = $_FILES['myupload']['type'];
$size = $_FILES['myupload']['size'];
$tmp = $_FILES['myupload']['tmp_name'];
$error = $_FILES['myupload']['error'];
$savepath = '/yourserverpath/';
$filelocation = $svaepath.$name.".".$type;
// This won't upload if there was an error or if the file exists, hence the check
if (!file_exists($filelocation) && $error == 0) {
// echo "The file $filename exists";
// This will overwrite even if the file exists
move_uploaded_file($tmp, $filelocation);
}
// OR just leave out the "file_exists()" and check for the error,
// an if statement either way
?>
try this piece of code for upload and replace file
if(file_exists($newfilename)){
unlink($newfilename);
}
move_uploaded_file($_FILES["fileToUpload"]["tmp_name"], $newfilename);