Passing javascript var to php [duplicate] - php

Question

This question already has answers here:
How do I pass JavaScript variables to PHP?
(16 answers)
Closed 8 years ago.
I have a php function that simply get me the value of an array given the key.
Example:
<?=__('mykey')?>
Return the value of my array.
I would to call this function after an ajax jQuery call, with a param.
The POST give me a json array, and I need to use the previous funct like this
$.ajax({
url: myfile.php',
type: 'POST',
data: $('#contact_form').serialize(),
dataType: 'json',
}).done(function(data) {
str = '';
$.each(data, function(index) {
$('#message').html(" <?=__('"+index+"')?> ");
});
})
The problem is that the index value inside the $.each function is not passed to php...there is a way to solve it or i have to do something like this?
$.each(data, function(index) {
switch(index):{
case 1: $('#message').html(" <?=__('1')?> "); break;
case 2: $('#message').html(" <?=__('2')?> "); break;
case 3: $('#message').html(" <?=__('3')?> "); break;
...
}
});

Answer 1

I've had to do something similar and actually used jQuery to set the value on a hidden input for me to grab later.
$('#some-hidden-input').val(yourvalue)
Make sure this hidden field exists and is in the rendered HTML
Then the PHP can simply grab that input value on POST.
$myVar = $_POST['some-hidden-input'];

Answer 2

To pass variables to PHP via Javascript, the only reasonable way is to use AJAX, but you do it only when you are posting something. If not, the best way is to have a hidden input field.
Based on different conditions you define, you can set the hidden input field to carry the value you want to apply it to.
To assign the value to <input name="A" id="B">
$("Input[name='A']").val(data);
or
$('#B').val(data);
Both will assign the value of data to the input field