I would like to find the date in a string after a particular word (key).
My string is dynamic and the date format also not same from one string to another string.
$data = "Balance- 0.30,Val-Aug 29 2013, Free Bal- 0.00";
or
$data = "Bal: 96.27.Valid Sep 26 2013.Toll Free Dial 578785";
or
$data = "BalanceRs.0.00,Expiry date: Apr 04 20141 Live Scores";
or
$data = "Your current balance is 0.20.Your account expires on 2013-11-23 23:59:59.";
or
$data = "Main Bal Rs.87.850 Val 09-07-2014,More";
$key = array('Val-','Val','Valid','Expiry date:','expires on');
$result=preg_match_all("/(?<=(".$key."))(\s\w*)/i",$data,$networkID);
$myanswer = #$networkID[0][0];
Here I am getting the output of only the first word.
Anyone please guide me to get the date. Thanks.
How about:
$data = "Balance- 0.30,Val-Aug 29 2013, Free Bal- 0.00";
$data .= "Bal: 96.27.Valid Sep 26 2013.Toll Free Dial 578785";
$data .= "BalanceRs.0.00,Expiry date: Apr 04 20141 Live Scores";
$data .= "Your current balance is 0.20.Your account expires on 2013-11-23 23:59:59.";
$data .= "Main Bal Rs.87.850 Val 09-07-2014,More";
$key = array('Valid','Val-','Val','Expiry date:','expires on');
$key_str = implode('|', $key);
preg_match_all("/(?<=$key_str)\s*((?:\w{3} \d\d \d{4})|(?:\d{4}-\d\d-\d\d)|(?:\d\d-\d\d-\d{4}))/i", $data, $networkID);
print_r($networkID);
output:
Array
(
[0] => Array
(
[0] => Aug 29 2013
[1] => Sep 26 2013
[2] => Apr 04 2014
[3] => 2013-11-23
[4] => 09-07-2014
)
[1] => Array
(
[0] => Aug 29 2013
[1] => Sep 26 2013
[2] => Apr 04 2014
[3] => 2013-11-23
[4] => 09-07-2014
)
)
Related
I have a string that should contain a name and a date of registration:
Dipak Misra - 18 Nov 2018 10:20
I want to convert this string into array like this:
Array ( [0] => Dipak Misra [1] => 18 Nov 2018 [2] => 10:20 )
I am using preg_match_all() function:
$re = '/\w+(?:[-\s]\w+)*/';
$str = "Dipak Misra - 18 Nov 2018 10:20";
preg_match_all($re, $str, $matches);
print_r($matches[0]);
I am getting output Like this:
Array ( [0] => Dipak Misra [1] => 18 Nov 2018 10 [2] => 20 )
Please guide me.
If the format of that string does not change, you could split on either a space, hyphen space, or split on a space where on the left and the right side a digit is present instead of matching.
- |(?<=\d) (?=\d)
Regex demo
For example:
print_r(preg_split("/ - |(?<=\d) (?=\d)/", "Dipak Misra - 18 Nov 2018 10:20"));
Result:
Array
(
[0] => Dipak Misra
[1] => 18 Nov 2018
[2] => 10:20
)
Use preg_match() with ([^-]+)\s+-\s+(.*)\s(\d+:\d+) as pattern instead
$re = '/([^-]+)\s+-\s+(.*)\s(\d+:\d+)/';
$str = "Dipak Misra - 18 Nov 2018 10:20";
preg_match($re, $str, $matches);
unset($matches[0]);
print_r($matches);
Check result in demo
$pattern = "/(\w+\s\w+)\s-\s([0-9]{2}\s\w+\s[0-9]{4})\s([0-9]+:[0-9]+)/";
$chain = "Dipak Misra - 18 Nov 2018 10:20";
preg_match_all($pattern, $chain, $matches);
$data = [
'chain' => $chain,
'pattern' => $pattern,
'name' => $matches[1],
'date' => $matches[2],
'time' => $matches[3]
];
echo "<pre>";
print_r($data);
echo "<pre>";
the output
I have read a standard RSS feed into simpleXML and get the following after converting to an array:
[0] => SimpleXMLElement Object (
[guid] => https://www.zazzle.com/scissors_by_any_other_name_dreadful_pun_t_shirt-235586301981812394
[pubDate] => Wed, 23 Aug 2017 13:41:08 GMT
[title] => SimpleXMLElement Object ( )
[link] => https://www.zazzle.com/scissors_by_any_other_name_dreadful_pun_t_shirt-235586301981812394
[author] => HightonRidley
[description] => SimpleXMLElement Object ( )
[price] => $30.15
)
[1] => SimpleXMLElement Object (
[guid] => {not enough reputation points to show link}
[pubDate] => Sat, 19 Aug 2017 15:53:19 GMT
[title] => SimpleXMLElement Object ( )
[link] => {not enough reputation points to show link}
[author] => HightonRidley
[description] => SimpleXMLElement Object ( )
[price] => $15.65 )
)
This is the code used to create and display the above
$sortable = array();
foreach($product_grid->channel->item as $node) {
$sortable[] = $node;
}
print_r($sortable);
To prove to myself it's working and accessible as intended I used this
foreach ($sortable as $rssitem) {
echo "<br>" . $rssitem->pubDate;
}
echo "<br>".$sortable[0]->pubDate;
echo "<br>".$sortable[1]->pubDate;
and got this output
Wed, 23 Aug 2017 13:41:08 GMT
Sat, 19 Aug 2017 15:53:19 GMT
Wed, 23 Aug 2017 13:41:08 GMT
Sat, 19 Aug 2017 15:53:19 GMT
...but when I try to sort using usort, I get no output and Firefox console tells me I have a server error 500
Here's how I'm using usort
usort($sortable, function($a, $b)
{
return strtotime($a->pubDate) > strtotime($b->pubDate);
});
I've checked various questions/answers on using usort here and as many other places as I can find online but to no avail.
Can someone please tell me how to reference the various elements of $sortable from within that anonymous function. I will be doing other sorts using other elements once I get this first one cracked.
Thanks!
Please tell how to make regex code to find all occurrence of date from the string, in the format listed below :
26 jan 2016
26th jan 2016
26 january 2016
26th january 2016
26 feb 15
26th feb 15
ie :
$string = "Test 26 jan 2016 test test test 12 Feb 15 test test test 17 January 2013 nice testing 123 6 12 2016";
I want the result as an array where i will get :
$res = array (
'2016-01-26',
'2015-02-12',
'2013-01-27'
)
Please tell how to make the same using PHP regex.
The solution using preg_match_all, array_map, date and strtotime functions (I've modified the initial string a bit to get a complex case):
$string = "Test 26th jan 2016 test test test 12 Feb 15 test test test 17 January 2013 nice testing 123 6 12 2016";
preg_match_all("/\b\d{2}(?:\w{2})? \w+? \d{2,4}\b/i", $string, $matches);
$dates = array_map(function($d) {
return date('Y-m-d', strtotime($d));
}, $matches[0]);
print_r($dates);
The output:
Array
(
[0] => 2016-01-26
[1] => 2015-02-12
[2] => 2013-01-17
)
I have a bunch of strings like this, for example:
Time: 22:30 (25) | Date: 19 March 2011 | Contributor: Salesman
Now, I want to extract the date and the string after Contributor, i.e, Salesman.
Currently, I am using explode() function in PHP.
But the problem is, the string has many variations like:
Time: 22:30 (25) | Date: 19 March 2011
Time: 22:30 (25) | Date: 2011 | Contributor: Salesman
Time: 22:30 (25) | Contributor: Salesman
Time: 22:30 (25) | Date: 2011
I want something that works perfect for all the variations. Where a field is unavailable, I shall consider it as NULL. For full date I need to store the date in database, and for only year I shall save the year.
Suggest me some code for this problem, or a regular expression in PHP if this problem can be solved through it.
Time:.*?\|\s*(?:Date:\s*([0-9a-zA-Z ]+))?\|?\s*(?:Contributor:\s*([a-zA-Z0-9 ]+))?
Try this.This will only give groups available.
See demo.
http://regex101.com/r/nG1gU7/18
You could try something like this:
$string = 'Time: 22:30 (25) | Date: 19 March 2011';
function str_func($string, $key, $remove_key = FALSE)
{
$string = trim($string);
if ($string[strlen($string) - 1] !== '|') {
$string .= '|';
}
$pos = strpos(strtolower($string), strtolower($key) . ':');
if ($pos !== FALSE) {
$return = strstr(substr($string, $pos), '|', true);
return ($remove_key) ? trim(substr($return, strlen($key) + 1)) : $return;
} else {
return NULL;
}
}
So just pass it the string and 'Time' or 'Contributor' (and optionally whether you'd like the key to be removed) e.g.
//Will return Time: 22:30 (25)
echo str_func($string, 'time');
//Will remove 'date: ' from the returned string
echo str_func($string, 'date', TRUE);
Hope this helps!
I think you want something like this,
^.*?\|\s*\K(?:Date:\s*((?:\d{2}\s*\S+)?\s*\d{4})\s*\|?)?\s*(?:Contributor:\s*(\S+))?
DEMO
Group index 1 contains the value of Date: field and group index 2 contains the value of Contributor: field.
Code:
<?php
$data = <<< EOT
Time: 22:30 (25) | Date: 19 March 2011
Time: 22:30 (25) | Date: 2011 | Contributor: Salesman
Time: 22:30 (25) | Contributor: Salesman
Time: 22:30 (25) | Date: 2011
EOT;
$regex = '~^(?:.*?\|\s*)(Date:\s*((?:\d{2} \S+ )?\d{4}))?(?:\s\|\s*)?(Contributor:\s*(\S+))?\s*$~m';
preg_match_all($regex, $data, $matches);
print_r($matches);
?>
Output:
Array
(
[0] => Array
(
[0] => Time: 22:30 (25) | Date: 19 March 2011
[1] => Time: 22:30 (25) | Date: 2011 | Contributor: Salesman
[2] => Time: 22:30 (25) | Contributor: Salesman
[3] => Time: 22:30 (25) | Date: 2011
)
[1] => Array
(
[0] => Date: 19 March 2011
[1] => Date: 2011
[2] =>
[3] => Date: 2011
)
[2] => Array
(
[0] => 19 March 2011
[1] => 2011
[2] =>
[3] => 2011
)
[3] => Array
(
[0] =>
[1] => Contributor: Salesman
[2] => Contributor: Salesman
[3] =>
)
[4] => Array
(
[0] =>
[1] => Salesman
[2] => Salesman
[3] =>
)
)
All values of array $A are string the same length.
$A = Array
(
[0] => 03
[1] => 04
[2] => 05
[3] => 06
// [4] => 07 // "07" before "04" position
[4] => 04
[5] => 05
[6] => 06
// [8] => 07 // "07" before "08" position
[7] => 08
[8] => 03
[9] => 04
[10] => 05
[11] => 06
[12] => 07 // it is existing
[13] => 08
) ;
I want to Insert the "07" element if it is not existing before "04" or "08" position.start from position 1
So It will be after changed
$A = Array
(
[0] => 03
[1] => 04
[2] => 05
[3] => 06
[4] => 07 // just appended
[5] => 04
[6] => 05
[7] => 06
[8] => 07 // just append
[9] => 08
[10] => 03
[11] => 04
[12] => 05
[13] => 06
[14] => 07
[15] => 08
) ;
Anybody know how to do this ,help me please?
There would be "prettier" ways to do this but, as intended...
iterate the array
if the current value is equal to 7 minus 1 you will insert a new value there
create a function "insert_into_array" that:
a) Splits your array in two (look at array_chunk)
b) POPs your element to the end of the first array (array_pop)
c) merges your two arrays back (array_merge)
I've abstained from writing any code as this is probably homework and, writing code, even if you're not really deep thinking the problem will push you a long way to passing the exam...
not the most beautiful solution, but should do the job:
$b = array();
for($i=0;$i<count($A);$i++){
$b[] = $A[$i];
if(($i<count($A) - 1) && ($A[$i+1]<$A[$i] || ($A[$i+1] == '08')) && $A[$i] < '07')
$b[] = '07';
}
var_dump($b);
First, find the gaps in your array, that is the positions where there's 06 but not a following 07:
$positions = array();
foreach ($A as $k => $v) {
if (isset($last) && $last != $v - 1 && $last == '06') {
$positions[] = $k;
}
$last = $v;
}
Then, insert them:
$count = 0;
foreach ($positions as $pos) {
array_splice($A, $pos + ($count++), 0, '07');
}
That's it.
//make sure the array is numeric:
$A = array_values($A);
foreach(array('04','08') as $search){
$positions = array_keys($A,$search);
rsort($positions);
foreach($positions as $key){
if($key==0 || $A[$key-1] != '07'){
array_splice($A,$key,0,'O7');
}
}
}
In 2017, I've found 2 beautiful methods that is part of nette\utils package.
Arrays::insertBefore()
Arrays::insertAfter()
They do job perfectly!
Just run:
composer require nette/utils
and use Arrays class or inspire in their code.