Match hyphen character from a string to make an array output - php

Question

I have a string that should contain a name and a date of registration:
Dipak Misra - 18 Nov 2018 10:20
I want to convert this string into array like this:
Array ( [0] => Dipak Misra [1] => 18 Nov 2018 [2] => 10:20 )
I am using preg_match_all() function:
$re = '/\w+(?:[-\s]\w+)*/';
$str = "Dipak Misra - 18 Nov 2018 10:20";
preg_match_all($re, $str, $matches);
print_r($matches[0]);
I am getting output Like this:
Array ( [0] => Dipak Misra [1] => 18 Nov 2018 10 [2] => 20 )
Please guide me.

Answer 1

If the format of that string does not change, you could split on either a space, hyphen space, or split on a space where on the left and the right side a digit is present instead of matching.
- |(?<=\d) (?=\d)
Regex demo
For example:
print_r(preg_split("/ - |(?<=\d) (?=\d)/", "Dipak Misra - 18 Nov 2018 10:20"));
Result:
Array
(
[0] => Dipak Misra
[1] => 18 Nov 2018
[2] => 10:20
)

Answer 2

Use preg_match() with ([^-]+)\s+-\s+(.*)\s(\d+:\d+) as pattern instead
$re = '/([^-]+)\s+-\s+(.*)\s(\d+:\d+)/';
$str = "Dipak Misra - 18 Nov 2018 10:20";
preg_match($re, $str, $matches);
unset($matches[0]);
print_r($matches);
Check result in demo

Answer 3

$pattern = "/(\w+\s\w+)\s-\s([0-9]{2}\s\w+\s[0-9]{4})\s([0-9]+:[0-9]+)/";
$chain = "Dipak Misra - 18 Nov 2018 10:20";
preg_match_all($pattern, $chain, $matches);
$data = [
'chain' => $chain,
'pattern' => $pattern,
'name' => $matches[1],
'date' => $matches[2],
'time' => $matches[3]
];
echo "<pre>";
print_r($data);
echo "<pre>";
the output