Trouble with retrieving data from mysql with HTML select box - php

Question

Okay so I am developing a search engine for a non-profit group using MYSQL and PHP. The data appears fine from all the other fields. But when I try to get data from a drop down select box the data doesn't appear.
I know my code is pron to SQL injections however there isn't any important data kept on the server, it just info about treatments and research studies.
I would like to do it with a function. I was also wondering if there is anyway to retrieve data from multiple boxes. Like I have a keyword search and a drop down combo box both of them are set. How do I retrieve data from both columns in the database using the function I have? Thanks
Here is my code if you guys could help me that would be great thanks
The code for the html box
Broad Research Topic <select name="Treatment1">
<option value="Other">
Other
</option>
<option value="Treatment">
Treatment
</option>
<option value="PracticalCure">
Practical Cure
</option>
The php code to check if it is set
if (isset($_GET['Treatment1']) && in_array($_GET(['Treatment1']),
array('Treatment', 'PracticalCure', 'Other')) {
$state = $_GET['Treatment1'];
Investigator6($state); }
}
The Function Investigator6
function Investigator6($state)
{
$state = trim($state);
$state = preg_replace('/\s+/', ' ', $state);
//seperate multiple keywords into array space delimited
$keywords = explode(" ", $state);
//Clean empty arrays so they don't get every row as result
$keywords = array_diff($keywords, array(
""
));
//Set the MySQL query
if ($state == NULL or $state == '%') {
} else {
for ($i = 0; $i < count($keywords); $i++) {
$query = ("SELECT * FROM Studies1 WHERE BroadResearchTopic LIKE
' %$keywords[$i]%'");
}
//Store the results in a variable or die if query fails
$result = mysql_query($query) or die(mysql_error());
}
if ($state == NULL or $state == '%') {
} else {
//Count the rows retrived
$count = mysql_num_rows($result);
echo $count;
}
//If search variable is null do nothing, else print it.
if ($state == NULL) {
} else {
echo "You searched for <b><FONT COLOR=\"blue\">";
foreach ($keywords as $value) {
print "$value ";
}
echo "</font></b>";
}
echo "<p> </p><br />";
echo "</center>";
//If users doesn't enter anything into search box tell them to.
if ($state == NULL) {
echo "<center><b><FONT COLOR=\"red\">Please enter a search parameter to continue.
b</font></b><br /></center>";
} elseif ($state == '%') {
echo "<center><b><FONT COLOR=\"red\">Please enter a search parameter to continue.
</font></b><br /></center>";
//If no results are returned print it
} elseif ($count <= 0) {
echo "<center><b><FONT COLOR=\"red\">Your query returned no results from the
database.</font></b><br /></center>";
//ELSE print the data in a table
} else {
//Table header
echo "<center>";
echo "</center>";
//Colors for alternation of row color on results table
$color1 = "#d5d5d5";
$color2 = "#e5e5e5";
//While there are rows, print it.
while ($row = mysql_fetch_array($result)) {
//Row color alternates for each row
$row_color = ($row_count % 2) ? $color1 : $color2;
//table background color = row_color variable
echo "<td style = \"padding: 10px\">" . $row['BroadResearchTopic'] . "</td>";
$row_count++;
if ($state == NULL or $state == '%') {
} else {
//clear memory
mysql_free_result($result);
}
}