Append data and display html table - php

Question

I have some data set. I want to arrange data like this:
My code displays result like this:
.
How can I fix this. This is my code:
<?php
echo "<tr><th></th><th>Control</th><th>Sub 1</th><th>Sub2</th></tr>";
$i=0;
$PrevIssoff=0;
$sql="SELECT `code`, `name`,`type`
FROM `testdate`
WHERE `code`='11111'
ORDER BY `code` ASC, `type` ASC ";
$result=mysql_query($sql);
while($row=mysql_fetch_array($result)){
$frm=$row['code'];
if ($frm != $PrevIssoff && $row['type']==0)
{
$i=$i+1;
$PrevIssoff=$frm;
echo "<tr><td>$i</td><td>$row[name]</td><td></td><td></td></tr>";
}
else if($row['type']==1 )
{
echo "<tr><td></td><td></td><td>$row[name]</td><td></td></tr>";
}
else if ($row['type']==2)
{
echo "<tr><td></td><td></td><td></td><td>$row[name]</td></tr>";
}
}
echo"</table>";
?>
Database table structure - testdate
databasetable

Answer 1

First, your data needs to be normalized. There should be a way to write a database query to skip this step if you look hard enough.
Walkthrough each row in the while loop, building a close representation for it an array.
$dataTable = [];
while ($row = mysqli_fetch_array($result)) {
$numRows = count($dataTable);
$lastRowIndex = $numRows == 0 ? 0 : $numRows-1;
if($numRows == 0) {
$dataTable[] = [];
}
if(count($dataTable[$lastRowIndex]) == 3) {
$dataTable[] = [];
$lastRowIndex += 1;
}
$type = $row['type'];
$dataTable[$lastRowIndex][$type] = $row['name'];
}
Then make your $rowsMarkup which can be readily concatenated with the table heading.
$rowsMarkup = array_map(function($row) {
return '<tr>'.
'<td>'.$row[0] .'</td>'.
'<td>'.$row[1] .'</td>'.
'<td>'.$row[2] .'</td>'.
'</tr>';
},
$dataTable
);