$caseid is (usually) a 5-digit number (it could be lower). I want a leading 0 so that the number is 6 digits long:
<?php
$caseid=12345;
echo str_pad(strval($caseid), 6-strlen(strval($caseid)), '0', STR_PAD_LEFT); ?>
This doesn't work as expected (displays the same number). Instead if I add 5 to the second argument of str_pad, it works.
<?php echo str_pad(strval($caseid), 11-strlen(strval($caseid)), '0', STR_PAD_LEFT); ?>
It works. What is the error here?
You don't need to compute the difference you just put the total characters you want it to be.
str_pad(strval($caseid), 6, '0', STR_PAD_LEFT);
I was once bothered by str_pad()s behavior too. I got tired of it, and returned to old stable sprintf().
<?php
header('Content-Type: text/plain');
$test = [
1,
12,
123,
1234,
12345,
123456
];
foreach($test as $n){
echo sprintf('%06d' . PHP_EOL, $n);
}
?>
Result:
000001
000012
000123
001234
012345
123456
Maybe, it is not an answer, but I hope it might help somebody.
See the function prototype:
string str_pad (
string $input ,
int $pad_length
[, string $pad_string = " "
[, int $pad_type = STR_PAD_RIGHT ]]
)
Pad a string to a certain length with another string, $pad_length means the length you want.
str_pad in php.net
Related
I have variables of bitcoin values all rounded to 8 decimal places. eg
1.00645600
I need a way in jQuery or php to get the whole number [1], The decimal values [006456], and trailing zeros [00]. I have already tried php substr but it messed up with the results since im dealing with variables.
Simple and general solution in PHP without involving regular expressions (that is an option also):
$number = '1.00645600';
$flooredNumber = floor($number); // 1
$decimalPart = (string) (floatval($number) - $flooredNumber); // 0.006456
$decimals = str_replace('0.', '', $decimalPart); // 006456
$trailingZeros = str_replace(rtrim($number, '0'), '', $number); // 00
substr
Returns the portion of string specified by the start and length parameters.
http://php.net/manual/en/function.substr.php
If the numbers in your string are always in the same position you can use substr() to get the desired values:
$str = '1.00645600';
echo substr($str, 0, 1)."\r\n";
echo substr($str, 2, 2)."\r\n";
echo substr($str, 2, 6)."\r\n";
Output:
1
00
006456
Perhaps, this way?
<?php
$i = '1.00645600';
echo rtrim(rtrim($i, '0'), '.');
?>
I was wondering if it is possible to always force a minimum of triple digits from an SQL statement to PHP, I am resonably new to PHP/SQL.
$count = $con->num_rows #num_rows currently shows 1
echo "Number of Rows: " .$count #shows "Number of Rows: 1"
How would I force it to output "Number of Rows: 001".
But then once it goes into natural four digit numbers, 1000, then it doesn't force triple digits.
Examples: 001 010 100 1000
Thanks for the help!
str_pad ( $count, 3, "0", STR_PAD_LEFT)
$newstring = str_pad($string,3,"0",STR_PAD_LEFT);
str_pad — Pad a string to a certain length with another string
string str_pad ( string $input , int $pad_length [, string $pad_string = " " [, int $pad_type = STR_PAD_RIGHT ]] )
and more
http://php.net/manual/en/function.str-pad.php is what you need.
The number is 13911392101301011 and regardless of using sprintf or number_format i get the same strange result.
sprintf('%017.0f', "13911392101301011"); // Result is 13911392101301012
number_format(13911392101301011, 0, '', ''); // Result is 13911392101301012
sprintf('%017.0f', "13911392101301013"); // Result is 13911392101301012
number_format(13911392101301013, 0, '', ''); // Result is 13911392101301012
As you actually have the number as a string, use the %s modifier:
sprintf('%s', "13911392101301011"); // 13911392101301011
Note that PHP is using a signed integer internally. The size depends on your system.
32bit system:
2^(32-1) = 2147483648
64bit system:
2^(64-1) = 9223372036854775808
-1 because 1 bit is reserved for the signage flag.
Since you are dealing with large numbers here, you may want to keep them as strings and perform numerical operation on the string values using BCMath functions.
$val = "13911392101301011";
echo $val; // 13911392101301011
echo bcadd($val, '4'); // 13911392101301015
echo bcmul($val, '2'); // 27822784202602022
You can do easily this way :-
ini_set("precision",25); // change 25 to whatever number you want or need
$num = 13911392101301011;
print $num;
Documentation states that $number in number_format is float so there is explicit typecast. Equivalent would look like this:
sprintf('%017.0f', (float) "13911392101301011");
Float is precise to around 14 digits and your number has 17 digits.
Your number_format call is setting the . and , to blank
string number_format ( float $number , int $decimals = 0 , string $dec_point = '.' , string $thousands_sep = ',' )
try this:
number_format(13911392101301011, 0, '.', ',');
I have a string, its content is "24896". Now I want to add some zeros to the left, so I tried:
$test = str_pad($myString, 4, "0", STR_PAD_LEFT);
The result is "24896" again, no zeros added to the left. Am I missing something here?
Thanks!
The second argument to str_pad() takes the full length of the final string; because you're passing 4 and the length of $myString is 5, nothing will happen.
You should choose a width that's at least one bigger than your example value, e.g.:
str_pad($myString, 9, '0', STR_PAD_LEFT);
// "000024896"
Update
This might be obvious, but if you always want 4 zeros in front of whatever $myString is:
'0000' . $myString;
Because you're padding it to length 4, and your string 24896 is 5 characters long, hence it doesn't need to pad anything as it's already more than 4 characters long.
The second parameter in the str_pad function is the new length of the string.
Try
$myString = "24896" ;
$test = str_pad($myString, strlen($myString) + 4, "0", STR_PAD_LEFT);
echo $test;
Output
000024896
Just make the pad first and attach it, presuming you don't know how long it is. No need to calculate the length of the original string:
$x = 4;
$pad = str_pad('', $x, '0');
$test = $pad.$myString;
Or better
$x = 4;
$test = str_pad('', $x, '0').$myString;
The length you specified in the str_function is less than the input string read documentation properly
try this it will work for you
Your String is 5 character
e.g $myString=24896;
Now you want to add 5 zero to the left
then your length will be you string + 5 the actual is 5+5=10;
Now pass this to the function your function will be like this
$test = str_pad($myString, 10, "0", STR_PAD_LEFT);
echo $test;
OUTPUT:
0000024896
how many no zero you want to add? no zeros added because padding length is smaller than your given $myString length.
Please try this one
$number = 24896;
$number = sprintf('%06d', $number);
echo $number;
or use this one
$number = 24896;
$number = str_pad($number, 6, '0', STR_PAD_LEFT);//here 6 is padding length
echo $number;
output
024896
If I have a variable in PHP containing 0001 and I add 1 to it, the result is 2 instead of 0002.
How do I solve this problem?
$foo = sprintf('%04d', $foo + 1);
It would probably help you to understand the PHP data types and how they're affected when you do operations to variables of various types. You say you have "a variable in PHP say 0001", but what type is that variable? Probably a string, "0001", since an integer can't have that value (it's just 1). So when you do this:
echo ("0001" + 1);
...the + operator says, "Hm, that's a string and an integer. I don't know how to add a string and an int. But I DO know how to convert a string INTO an int, and then add two ints together, so let me do that," and then it converts "0001" to 1. Why? Because the PHP rules for converting a string to an integer say that any number of leading zeroes in the string are discarded. Which means that the string "0001" becomes 1.
Then the + says, "Hey, I know how to add 1 and 1. It's 2!" and the output of that statement is 2.
Another option is the str_pad() function.
$text = str_pad($text, 4, '0', STR_PAD_LEFT);
<?php
#how many chars will be in the string
$fill = 6;
#the number
$number = 56;
#with str_pad function the zeros will be added
echo str_pad($number, $fill, '0', STR_PAD_LEFT);
// The result: 000056
?>