php get first and second word after (at) - php

Question

I need some help with a php code which torment me 2-3 hours. Ny methods tried but no result. I want to take the first and second word after the #, eg #John Doe and php result took me John and Doe
I thing something that:
(Edited)
$q = 'Hi #Stefan Simeonov kak si? #Krasi avramov';
if (preg_match_all("(#[^ ]+[ ][^ ]+)", $q, $match)) {
foreach ($match[0] as $singleMatch) {
$finded[] = $singleMatch;
$success = 1;
}
} elseif (preg_match_all("(#[^ ]+)", $q, $match)) {
foreach ($match[0] as $singleMatch) {
$finded[] = $singleMatch;
$success = 1;
}
} else {
$success = 0;
}
if($success = 1) {
$replace = $q;
foreach ($finded as $user) {
$expl = explode("#",$user);
$rep = ''.$expl[1].'';
$replace = str_replace($user,$rep,$replace);
}
echo $replace;
} else {
echo $q;
}

Answer 1

Using a regular expression for example:
<?php
$q = 'Hi #John Doe kak si?';
if (preg_match('/#(\w+)\s(\w+)/', $q, $matches)) {
var_dump($matches);
}
This will look for a word after a #, followed by a space, followed by another word.

Answer 2

You can do something like this:
<?
$q = 'Hi #John Doe kak si?';
$explodeTab = explode("#",$q);
$words = explode(" ",$explodeTab[1]);
print_r($words);
?>
WORKING CODE

Answer 3

You can use a regex of (#[^ ]+[ ][^ ]+) for this:
<?php
$q = 'Hi #Stefan Simeonov kak si?';
if (preg_match_all("(#[^ ]+[ ][^ ]+)", $q, $match)) {
foreach ($match[0] as $singleMatch) {
echo 'Found match: ' . $singleMatch . PHP_EOL;
}
}
?>
Will output:
Found match: #Stefan Simeonov

Answer 4

Assuming that words are always separated by spaces, you can achieve this by first splitting the input string on the # character and then taking the 1th item and splitting that on the space character and reducing that result to the words that you need.
<?php
$q = 'Hi #John Doe kak si?';
$atSplitResult = explode('#', $q);
$spaceSplitResult = explode(' ', $atSplitResult[1]);
$firstTwoWords = array_slice($spaceSplitResult, 0, 2);
var_dump($firstTwoWords);

Answer 5

Let's say, we have a sentence
Let's see, #mike, how are you doing?
now:
$atExploded = explode('#', $str); //where $str is our string
if(count($atExploded)){
foreach($atExploded as $at){
$spaceExplode = explode(' ', $at);
echo $spaceExplode[0].' '.$spaceExplode[1]; //after checking that [0] and [1] are reachable
}
}
of course you should cut any unwanted characters (like braces, colons and so on) but I hope you get the idea.

Answer 6

PHP
$string = 'Hi #John Doe kak si?';
$regex = preg_match("/#(.+?)\s(.+?)\s/", $string, $matches);
var_dump($matches);
Returns
array(3) { [0]=> string(10) "#John Doe " [1]=> string(4) "John" [2]=> string(3) "Doe" }

Answer 7

You can write something like this. This will output #John Doe
<?php
$q = 'Hi #John Doe kak si?';
$q = preg_match('/#[A-Za-z]+\s[A-Za-z]+/', $q, $match);
print_r($match);
?>