I have a string and some words, i want to highlight those words which match with string, and also i want to print only those words which are highlighted, like if apple matches, then only apple must be printed.
$string = "apple computer";
$keyword = "apple,orange,bike";
I am using the following function to highlight specific characters in a string.
$str = preg_replace("/($keyword)/i","<span style='color:orange;'>$0</span>",$string);
The problem is I want to show only those characters which are highlighted, currently it shows all the characters.
This would meet your need.
$string = " apple computer orange";
$keywords = "apple, orange";
$exp_kwd = explode(",", $keywords);
$res = "<span style='color:orange;'>";
foreach($exp_kwd as $val){
if(strpos($string, trim($val))){
$res .= $val." ";
}
}
$res = $res."</span>";
echo $res;
Hopefully this also will work
$string = "apple computer orange tested";
$keyword = "apple,orange,bike,tested";
$pattern="/".str_replace(",","/,/",$keyword)."/";
$pattern=explode(",",$pattern);
$string=explode(" ",$string);
$keyword =explode(",",$keyword);
$string=implode(",",(preg_filter($pattern, $keyword, $string)));
echo $string="<span style='color:orange;'>$string</span>";
$string = "Im On #Here";
$keyword = "#";
$var = strrchr($string,$keyword);
if(empty($var))
{
echo 'No Occerunce Found';
}
else
{
echo '<span style="color:orange;">'.$var.'</span>';
}
phpfiddle Preview
Related
I need help with writing a function for smart selection of fragments in the text.
Src text = "Regulation is mediated via many different mechanisms"
HightLight string = "mediate via"
Expected Result = "Regulation is mediated via many different mechanisms"
I found one solution in google, but it is not work correctly with strings with dynamic endings
<?php
$string = "The monkey hangs from the door";
$keyword = "the";
function highlightkeyword($str, $search) {
$occurrences = substr_count(strtolower($str), strtolower($search));
$newstring = $str;
$match = array();
for ($i=0;$i<$occurrences;$i++) {
$match[$i] = stripos($str, $search, $i);
$match[$i] = substr($str, $match[$i], strlen($search));
$newstring = str_replace($match[$i], '[#]'.$match[$i].'[#]', strip_tags($newstring));
}
$newstring = str_replace('[#]', '<b>', $newstring);
$newstring = str_replace('[#]', '</b>', $newstring);
return $newstring;
}
?>
Another examples:
Ex1:
src = is mediated via many
search = mediate via
result = is [b]mediated via[/b] many
Ex2:
src = are meddling in local affairs.
search = meddle in
result = are [b]meddling in[/b] local affairs.
Ex3:
src = who can not get married in France.
search = marry in
result = who can not get [b]married in[/b] France.
!! search string contain marry in, but source contain married in
To make patterns recognizable you can use the power of regex
function highlightkeyword($keyword, $string) {
return preg_replace("/{$keyword}/", '<strong>\\0</strong>', $string);
}
Examples
$string = "Regulation is mediated via many different mechanisms";
$keyword = "mediate.*? via";
echo highlightkeyword($keyword, $string), PHP_EOL;
Regulation is <strong>mediated via</strong> many different mechanisms
$string = "Who can not get married in France.";
$keyword = "marr(ied|y)";
echo highlightkeyword($keyword, $string), PHP_EOL;
Who can not get <strong>married</strong> in France.
$string = "Who can not marry in France.";
$keyword = "marr(ied|y)";
echo highlightkeyword($keyword, $string), PHP_EOL;
Who can not <strong>marry</strong> in France.
I have a search String: $str (Something like "test"), a wrap string: $wrap (Something like "|") and a text string: $text (Something like "This is a test Text").
$str is 1 Time in $text. What i want now is a function that will wrap $str with the wrap defined in $wrap and output the modified text (even if $str is more than one time in $text).
But it shall not output the whole text but just 1-2 of the words before $str and then 1-2 of the words after $str and "..." (Only if it isn`t the first or last word). Also it should be case insensitive.
Example:
$str = "Text"
$wrap = "<span>|</span>"
$text = "This is a really long Text where the word Text appears about 3 times Text"
Output would be:
"...long <span>Text</span> where...word <span>Text</span> appears...times <span>Text</span>"
My Code (Obviusly doesnt works):
$tempar = preg_split("/$str/i", $text);
if (count($tempar) <= 2) {
$result = "... ".substr($tempar[0], -7).$wrap.substr($tempar[1], 7)." ...";
} else {
$amount = substr_count($text, $str);
for ($i = 0; $i < $amount; $i++) {
$result = $result.".. ".substr($tempar[$i], -7).$wrap.substr($tempar[$i+1], 0, 7)." ..";
}
}
If you have a tipp or a solution dont hesitate to let me know.
I have taken your approach and made it more flexible. If $str or $wrap changes you could have escaping issues within the regex pattern so I have used preg_quote.
Note that I added $placeholder to make it clearer, but you can use $placeholder = "|" if you don't like [placeholder].
function wrapInString($str, $text, $element = 'span') {
$placeholder = "[placeholder]"; // The string that will be replaced by $str
$wrap = "<{$element}>{$placeholder}</{$element}>"; // Dynamic string that can handle more than just span
$strExp = preg_quote($str, '/');
$matches = [];
$matchCount = preg_match_all("/(\w+\s+)?(\w+\s+)?({$strExp})(\s+\w+)?(\s+\w+)?/i", $text, $matches);
$response = '';
for ($i = 0; $i < $matchCount; $i++) {
if (strlen($matches[1][$i])) {
$response .= '...';
}
if (strlen($matches[2][$i])) {
$response .= $matches[2][$i];
}
$response .= str_replace($placeholder, $matches[3][$i], $wrap);
if (strlen($matches[4][$i])) {
$response .= $matches[4][$i];
}
if (strlen($matches[5][$i]) && $i == $matchCount - 1) {
$response .= '...';
}
}
return $response;
}
$text = "text This is a really long Text where the word Text appears about 3 times Text";
string(107) "<span>text</span> This...long <span>text</span> where...<span>text</span> appears...times <span>text</span>"
To make the replacement case insensitive you can use the i regex option.
If I understand your question correct, just a little bit of implode and explode magic needed
$text = "This is a really long Text where the word Text appears about 3 times Text";
$arr = explode("Text", $text);
print_r(implode('<span>Text</span>', $arr));
If you specifically need to render the span tags using HTML, just write it that way
$arr = explode("Text", $text);
print_r(implode('<span>Text</span>', $arr));
Use patern below to get your word and 1-2 words before and after
/((\w+\s+){1,2}|^)text((\s+\w+){1,2}|$)/i
demo
In PHP code it can be:
$str = "Text";
$wrap = "<span>|</span>";
$text = "This is a really long Text where the word Text appears about 3 times Text";
$temp = str_replace('|', $str, $wrap); // <span>Text</span>
// find patern and 1-2 words before and after
// (to make it casesensitive, delete 'i' from patern)
if(preg_match_all('/((\w+\s+){1,2}|^)text((\s+\w+){1,2}|$)/i', $text, $match)) {
$res = array_map(function($x) use($str, $temp) { return '... '.str_replace($str, $temp, $x) . ' ...';}, $match[0]);
echo implode(' ', $res);
}
Objective: strings with ' should match the string without it.
Example:
$first_string = "alex ern o'brian";
$second_string = "alex-ern o brian";
$pattern = array("/(-|\.| )/", "/(')/");
$replace = array(' ', '(\s|)');
$first_string = preg_replace($pattern, $replace, $first_string);
$second_string = preg_replace($pattern, $replace, $second_string);
$first_string_split = preg_split("/(-|\.| )/", $first_string);
$first_string_split[] = $first_string;
$second_string_split = preg_split("/(-|\.| )/", $second_string);
$second_string_split[] = $second_string;
$first_string = array_slice($first_string_split, -1)[0];
$second_string = array_slice($second_string_split, -1)[0];
if(in_array($first_string, $second_string_split) || in_array($second_string, $first_string_split))
{
echo 'true';
} else {
echo 'false';
}
I think you are expecting this.
Solution 1: Try this code snippet here
Regex: (\s|) this will match either space or null.
<?php
ini_set('display_errors', 1);
$string = "o'brian";
$string=str_replace("'", "(\s|)",$string);
$list = array("o'neal", "o brian", "obrian");
$result=array();
foreach($list as $value)
{
if(preg_match("/$string/", $value))
{
$result[]=$value;
}
}
print_r($result);
Solution 2:
Regex: [a-z]+ will match character from a to z.
$string1="o brian";
$string2="obrian";
if(preg_match("/".implode(" ", $matches[0])."/", $string1))
{
echo "matched";
}
if( preg_match("/".implode("", $matches[0])."/", $string2))
{
echo "matched";
}
I'm not sure if I got your question right, but this should do it:
(?<=\w)'(?=\w)
It matches every ' character, which is followed and preceded by a word character. The word character \w is equal to [a-zA-Z0-9_].
Here is a live example to test the regex
Here is a live PHP example
I have the following :
Sentence :
"This is a red apple"
pattern to check :
red & apple.
Both sentence and pattern to check are user generated.
$sentence = "This is a red apple";
$words = array('red','apple');
$ch = implode("|",$words);
$pattern = '/[$ch]/';
if(preg_match($pattern, $sentence))
{
// Do something if the sentence contains red & apple
}
When i execute that code, i get nothing (nothing is displayed). When i do echo on $pattern it returns it as a whole string instead.
How can i fix this ? What am i missing ?
change $pattern = '/[$ch]/';
to
$pattern = '/('.$ch.')/'; or $pattern = '/['.$ch.']';
<?php
$sentence = "This is a red apple";
$words = array('apple','red');
$ch = implode("|",$words);
echo $pattern = '/('.$ch.')/';
if(preg_match($pattern, $sentence))
{
echo ' Do something if the sentence contains red & apple';
}else
{
echo 'nothing happpen';
}
?>
check if both word match
<?php
$sentence = "This is a red apple";
$words = array('red','apple');
$ch = implode("|",$words);
echo $pattern = '['.$ch.']';
if(preg_match_all($pattern, $sentence,$matches) == 2)
{
echo ' Do something if the sentence contains red & apple';
}else
{
echo 'nothing happpen';
}
?>
You also check how many word matched using
echo count($matches[0]);
$matches is array contain word are matched
You need to take care about quotes while using variables within quotes you need to update
$pattern = '/[$ch]/';
into
$pattern = "/($ch)/";
^^ ^^ ^^ ^^
You need to update your regex pattern also, so your code looks like as
$sentence = "This is a red apple";
$words = array('red','apple');
$ch = implode("|",$words);
$pattern = "/($ch)/";
if(preg_match_all($pattern, $sentence,$m))
{
echo "yes \n";
print_r($m);
}
Instead of regex I'll use array_intersect along with str_word_count like as
$sentence = "This is a red apple";
$words = array('red','apple','blue');
$var = count(array_intersect(str_word_count($sentence,1),$words));
if(count($words == $var)){
echo "Yes got it";
}
Demo
Demo2
how write the script, which menchion the whole word, if it contain the keyword? example: keyword "fun", string - the bird is funny, result - the bird is * funny*. i do the following
$str = "my bird is funny";
$keyword = "fun";
$str = preg_replace("/($keyword)/i","<b>$1</b>",$str);
but it menshions only keyword. my bird is funny
Try this:
preg_replace("/\w*?$keyword\w*/i", "<b>$0</b>", $str)
\w*? matches any word characters before the keyword (as least as possible) and \w* any word characters after the keyword.
And I recommend you to use preg_quote to escape the keyword:
preg_replace("/\w*?".preg_quote($keyword)."\w*/i", "<b>$0</b>", $str)
For Unicode support, use the u flag and \p{L} instead of \w:
preg_replace("/\p{L}*?".preg_quote($keyword)."\p{L}*/ui", "<b>$0</b>", $str)
You can do the following:
$str = preg_replace("/\b([a-z]*${keyword}[a-z]*)\b/i","<b>$1</b>",$str);
Example:
$str = "Its fun to be funny and unfunny";
$keyword = 'fun';
$str = preg_replace("/\b([a-z]*${keyword}[a-z]*)\b/i","<b>$1</b>",$str);
echo "$str"; // prints 'Its <b>fun</b> to be <b>funny</b> and <b>unfunny</b>'
<?php
$str = "my bird is funny";
$keyword = "fun";
$look = explode(' ',$str);
foreach($look as $find){
if(strpos($find, $keyword) !== false) {
if(!isset($highlight)){
$highlight[] = $find;
} else {
if(!in_array($find,$highlight)){
$highlight[] = $find;
}
}
}
}
if(isset($highlight)){
foreach($highlight as $replace){
$str = str_replace($replace,'<b>'.$replace.'</b>',$str);
}
}
echo $str;
?>
Here by am added multi search in a string for your reference
$keyword = ".in#.com#dot.com#1#2#3#4#5#6#7#8#9#one#two#three#four#five#Six#seven#eight#nine#ten#dot.in#dot in#";
$keyword = implode('|',explode('#',preg_quote($keyword)));
$str = "PHP is dot .com the amazon.in 123455454546 dot in scripting language of choice.";
$str = preg_replace("/($keyword)/i","<b>$0</b>",$str);
echo $str;
Basically, since this is HTML, what you have to do is iterate over text nodes and split those containing the search string into up to three nodes (before match, after match and the highlighted match). If "after match" node exist, it must be processed too. Here is a PHP7 example using PHP DOM extension. The following function accepts preg_quoted UTF-8 search string (or regex-conpatible expression like apple|orange). It will enclose every match in a given tag with a given class.
function highlightTextInHTML($regex_compatible_text, $html, $replacement_tag = 'span', $replacement_class = 'highlight') {
$d = new DOMDocument('1.0','utf-8');
$d->loadHTML('<head><meta http-equiv="Content-Type" content="text/html; charset=utf-8"/></head>' . $html);
$xpath = new DOMXPath($d);
$process_node = function(&$node) use($regex_compatible_text, $replacement_tag, $replacement_class, &$d, &$process_node) {
$i = preg_match("~(?<before>.*?)(?<search>($regex_compatible_text)+)(?<after>.*)~ui", $node->textContent, $m);
if($i) {
$x = $d->createElement($replacement_tag);
$x->setAttribute('class', $replacement_class);
$x->textContent = $m['search'];
$parent_node = $node->parentNode;
$before = null;
$after = null;
if(!empty($m['after'])) {
$after = $d->createTextNode($m['after']);
$parent_node->replaceChild($after, $node);
$parent_node->insertBefore($x, $after);
} else {
$parent_node->replaceChild($x, $node);
}
if(!empty($m['before'])) {
$before = $d->createTextNode($m['before']);
$parent_node->insertBefore($before, $x);
}
if($after) {
$process_node($after);
}
}
};
$node_list = $xpath->query('//text()');
foreach ($node_list as $node) {
$process_node($node);
}
return preg_replace('~(^.*<body>)|(</body>.*$)~mis', '', $d->saveHTML());
}
Search and highlight the word in your string, text, body and paragraph:
<?php $body_text='This is simple code for highligh the word in a given body or text'; //this is the body of your page
$searh_letter = 'this'; //this is the string you want to search for
$result_body = do_Highlight($body_text,$searh_letter); // this is the result with highlight of your search word
echo $result_body; //for displaying the result
function do_Highlight($body_text,$searh_letter){ //function for highlight the word in body of your page or paragraph or string
$length= strlen($body_text); //this is length of your body
$pos = strpos($body_text, $searh_letter); // this will find the first occurance of your search text and give the position so that you can split text and highlight it
$lword = strlen($searh_letter); // this is the length of your search string so that you can add it to $pos and start with rest of your string
$split_search = $pos+$lword;
$string0 = substr($body_text, 0, $pos);
$string1 = substr($body_text,$pos,$lword);
$string2 = substr($body_text,$split_search,$length);
$body = $string0."<font style='color:#FF0000; background-color:white;'>".$string1." </font> ".$string2;
return $body;
} ?>