Application doesn't enter the loop - php

Question

I have that code :
<?php
error_reporting(E_ALL);
ini_set('display_errors',1);
$wynik = 0;
$licznik = 0;
wykonaj();
function wykonaj()
{
echo '1';
for($i = 1; $i == 404; $i++)
{
$temp = $i / 100;
echo $temp;
if(is_int($temp*1.5))
{
global $wynik, $licznik;
$wynik++;
//$liczba[$licznik] = $i + ($i/100)*1.5;
$licznik++;
}
}
}
echo "Ilosc wynikow : $wynik<br/>Liczby sa nastepujace :";
?>
My application returns :
1Ilosc wynikow : 0
Liczby sa nastepujace :
So I think there is an error (logical ?), because that line - echo $temp; isn't displayed yet, but 1 before a loop is displayed. I tried a lot of things, but I could not find any solution. Why are my errors ? Compiler doesn't tell anything.

Answer 1

It will only enter the loop if $i is equal to 404, which it's set to 1 right off so that won't happen.
Syntax in a for loop is something like:
for([Set Vars]; [Set Conditional]; [Set Increment])
The loop only runs when the conditional is true.

Answer 2

Try this code. Mising <= in the for condition
<?php
error_reporting(E_ALL);
ini_set('display_errors',1);
$wynik = 0;
$licznik = 0;
wykonaj();
function wykonaj()
{
echo '1';
for($i = 1; $i <= 404; $i++)
{
$temp = $i / 100;
echo $temp;
if(is_int($temp*1.5))
{
global $wynik, $licznik;
$wynik++;
//$liczba[$licznik] = $i + ($i/100)*1.5;
$licznik++;
}
}
}
echo "Ilosc wynikow : $wynik<br/>Liczby sa nastepujace :";
?>
demo here