How to print one message from a loop within a condition? - php

Question

Let's say I have this loop:
for($i = 1; $i <= 10; $i++){
if($i > 4){
echo 'Greater Than 4.' . '<br/>';
}
}
The previous loop will output the following:
Greater Than 4.
Greater Than 4.
Greater Than 4.
Greater Than 4.
Greater Than 4.
Greater Than 4.
As the condition is true 6 times.
What I want to do is to print this message only once so the output from the same loop and condition will be :
Greater Than 4.
I think this could be achieved by using a variable and give it this value at a specific point , But I don't know how to do it.

Answer 1

Well, it will be like your code expect that you print the message once:
$msg = 'There is no greater than 4';
for($i = 1; $i <= 10; $i++){
if($i > 4){
$msg = 'Greater Than 4.' . '<br/>';
// Make any additional required code here...
}
}
echo $msg;
;

Answer 2

Have you tried this :)
for($i=1;$i<=10;$i++){
echo ($i>4 && !isset($rslt))?$rslt='Greater Than 4.':'';
}
Or, you can loop first
then print the result
like this
$bucket = '';
for($i=1;$i<=10;$i++){
$bucket = ($i>4)?'Greater Than 4.':$bucket;
}
echo $bucket;
Hmmmm, I guess you case like this :D
$bucket = $condition = '';
$flag = 1;
for($i=1;$i<=10;$i++){
if($i>4){
$bucket = 'Greater Than 4. <br>';
$condition .= "Proses :{$flag}<br>";
$flag++;
//more condition process 6 times
}
}
echo $condition;
echo $bucket;
Or like this :D
$j=1;
for($i=1;$i<=10;$i++){
if($i>4){
if($i<=5){
echo 'Greater Than 4. <br>';
}
echo 'Proses '.($j++).'<br>';
//more condition process 6 times
}
}
Or, using the short hand
for($i= $j =0;$i<=10;$i++){
if($i>4){
echo ($i<=5)?'TheGreater Than 4. <br>':false;
$j++;
echo "Process number : {$j} <br>";
}
}

Answer 3

$run_once = true;
for($i = 1; $i <= 10; $i++){
if($i > 4 AND $run_once){
echo 'Greater Than 4.' . '<br/>';
$run_once = false;
}
}
you could also use if ($i == 4)
EDIT:
for($i = 1; $i <= 10; $i++){
if($i > 4){
if($i == 4){
echo 'this runs only once';
}
echo 'this runs every time';
}
}