how to retrieve data in multiple selected list - php

Question

i need to retrive data in mutiple selected list from database
in my database value is
Marathi,Arunachali,Assamese,Awadhi,Marathi,Arunachali,Assamese,Awadhi
i used the below code to retrive
<select id="spokenlanguages" name="known_languages[]" multiple="multiple" size="5">
<option value="" >Select</option>
<?php
$langs = $editdatapersonaltbl[0]['known_languages'] ;
$known_languages = explode(",",$langs);
//print_r($known_languages); exit();
for($i=0;$i < count($known_languages);$i++)
{
?>
<option value="<?php echo $known_languages[$i] ;?>" selected="selected"><?php echo $known_languages[$i] ;?></option>
<?php } ?>
<option value="Marathi" >Marathi</option>
<option value="Arunachali" >Arunachali</option>
<option value="Assamese" >Assamese</option>
<option value="Awadhi" >Awadhi</option>
<option value="Bengali" >Bengali</option>
<option value="Bhojpuri" >Bhojpuri</option>
<option value="Brij" >Brij</option>
<option value="Bihari" >Bihari</option>
</select>
but my problem is if marathi is previously selected than it displayed in selected and
not selected also
not selected because of <option value="Marathi" >Marathi</option> option is there if i will remove this option <option value="Marathi" >Marathi</option> than if marathi is not in database than what if user want to select marathi
please provide me some solutions....

Answer 1

Try this:
<select id="spokenlanguages" name="known_languages[]" multiple="multiple" size="5">
<option value="" >Select</option>
<?php
$langs = $editdatapersonaltbl[0]['known_languages'] ;
$known_languages = explode(",",$langs);
$known_languages = array_filter( $known_languages ); #remove the blank values if any
//print_r($known_languages); exit();
?>
<option value="Marathi" <?php if(in_array('Marathi', $known_languages)){echo 'selected="selected"';}?> >Marathi</option>
<option value="Arunachali" <?php if(in_array('Arunachali', $known_languages)){echo 'selected="selected"';}?>>Arunachali</option>
<option value="Assamese" <?php if(in_array('Assamese', $known_languages)){echo 'selected="selected"';}?>>Assamese</option>
<option value="Awadhi" <?php if(in_array('Awadhi', $known_languages)){echo 'selected="selected"';}?>>Awadhi</option>
<option value="Bengali" <?php if(in_array('Bengali', $known_languages)){echo 'selected="selected"';}?>>Bengali</option>
<option value="Bhojpuri" <?php if(in_array('Bhojpuri', $known_languages)){echo 'selected="selected"';}?>>Bhojpuri</option>
<option value="Brij" <?php if(in_array('Brij', $known_languages)){echo 'selected="selected"';}?>>Brij</option>
<option value="Bihari" <?php if(in_array('Bihari', $known_languages)){echo 'selected="selected"';}?>>Bihari</option>
</select>

Answer 2

first u must put html options in array as html_aarray , then cho database array . after that in another while eho html option if the node of html_aarray not exists in database array.
i wrote it 4 u , use this :http://codepad.org/gjWW9UGg

Answer 3

<?php
//$lang_array is ur language array
$lang_array = array('Marathi','Hindi','Gujrati','Bengali');
//this array ehich u fetching from DB
$known_languages = array('Marathi', 'Gujrati');
?>
<select id="spokenlanguages" name="known_languages[]" multiple="multiple" size="5">
<option value="" >Select</option>
<?php
for($i=0;$i < count($lang_array); $i++)
{
if(in_array($lang_array[$i], $known_languages))
{
$str = 'selected="selected"';
}
else
{
$str ='';
}
echo
'<option value="'.$lang_array[$i].'" '.$str.'> '.$lang_array[$i].'</option>';
}
?>