Removing duplicated options from select box in PHP - php

Question

I want to generate select boxes based on the number of elements in the $chosen array and each of them will have the default selected options. The first one is A, and the second one is D. The following code is almost okay except I want to remove the duplicated options. Here's the output:
<select>
<option>Select</option>
<option value="A" selected="selected">A</option>
<option value="A">A</option>
<option value="B">B</option>
<option value="C">C</option>
<option value="D">D</option>
<option value="E">E</option>
</select>
<select>
<option>Select</option>
<option value="D" selected="selected">D</option>
<option value="A">A</option>
<option value="B">B</option>
<option value="C">C</option>
<option value="D">D</option>
<option value="E">E</option>
</select>
I tried array_merge with array_unique to merge $options and $chosen before foreach($options as $option) but it isn't working. Can anyone suggest a solution?
<?php
$options = array("A","B","C","D","E");
$chosens = array("A","D");
foreach($chosens as $chosen)
{
print "<select><option>Select</option>";
if(in_array($chosen,$options))
{
print "<option value='".$chosen."' selected='selected'>$chosen</option>";
}
/* $options = array_unique(array_merge($chosen,$options)); */
foreach($options as $option)
{
print "<option value='".$option."'>$option</option>";
}
print "</select>";
}
?>*

Answer 1

Actually, just a simple if condition is enough. Like this:
<?php
$options = array("A","B","C","D","E");
$chosens = array("A","D");
?>
<?php foreach($chosens as $chosen): ?>
<select name="">
<?php foreach($options as $option): ?>
<option value="<?php echo $option; ?>" <?php echo ($option == $chosen) ? 'selected' : ''; ?>><?php echo $option; ?></option>
<?php endforeach; ?>
</select><br/>
<?php endforeach; ?>