Ajax Upload image - php

Question

Q.1 I would like to convert this form to ajax but it seems like my ajax code lacks something.
On submit doesn't do anything at all.
Q2. I also want the function to fire on change when the file has been selected not to wait for a submit.
Here is JS.
$('#imageUploadForm').on('submit',(function(e) {
e.preventDefault()
$.ajax({
type:'POST',
url: $(this).attr('action'),
data:$(this).serialize(),
cache:false
});
}));
and the HTMl with php.
<form name="photo" id="imageUploadForm" enctype="multipart/form-data" action="<?php echo $_SERVER["PHP_SELF"];?>" method="post">
<input type="file" style="widows:0; height:0" id="ImageBrowse" hidden="hidden" name="image" size="30"/>
<input type="submit" name="upload" value="Upload" />
<img width="100" style="border:#000; z-index:1;position: relative; border-width:2px; float:left" height="100px" src="<?php echo $upload_path.$large_image_name.$_SESSION['user_file_ext'];?>" id="thumbnail"/>
</form>

Answer 1

first in your ajax call include success & error function and then check if it gives you error or what?
your code should be like this
$(document).ready(function (e) {
$('#imageUploadForm').on('submit',(function(e) {
e.preventDefault();
var formData = new FormData(this);
$.ajax({
type:'POST',
url: $(this).attr('action'),
data:formData,
cache:false,
contentType: false,
processData: false,
success:function(data){
console.log("success");
console.log(data);
},
error: function(data){
console.log("error");
console.log(data);
}
});
}));
$("#ImageBrowse").on("change", function() {
$("#imageUploadForm").submit();
});
});

Answer 2

HTML Code
<div class="rCol">
<div id ="prv" style="height:auto; width:auto; float:left; margin-bottom: 28px; margin-left: 200px;"></div>
</div>
<div class="rCol" style="clear:both;">
<label > Upload Photo : </label>
<input type="file" id="file" name='file' onChange=" return submitForm();">
<input type="hidden" id="filecount" value='0'>
Here is Ajax Code:
function submitForm() {
var fcnt = $('#filecount').val();
var fname = $('#filename').val();
var imgclean = $('#file');
if(fcnt<=5)
{
data = new FormData();
data.append('file', $('#file')[0].files[0]);
var imgname = $('input[type=file]').val();
var size = $('#file')[0].files[0].size;
var ext = imgname.substr( (imgname.lastIndexOf('.') +1) );
if(ext=='jpg' || ext=='jpeg' || ext=='png' || ext=='gif' || ext=='PNG' || ext=='JPG' || ext=='JPEG')
{
if(size<=1000000)
{
$.ajax({
url: "<?php echo base_url() ?>/upload.php",
type: "POST",
data: data,
enctype: 'multipart/form-data',
processData: false, // tell jQuery not to process the data
contentType: false // tell jQuery not to set contentType
}).done(function(data) {
if(data!='FILE_SIZE_ERROR' || data!='FILE_TYPE_ERROR' )
{
fcnt = parseInt(fcnt)+1;
$('#filecount').val(fcnt);
var img = '<div class="dialog" id ="img_'+fcnt+'" ><img src="<?php echo base_url() ?>/local_cdn/'+data+'"></div><input type="hidden" id="name_'+fcnt+'" value="'+data+'">';
$('#prv').append(img);
if(fname!=='')
{
fname = fname+','+data;
}else
{
fname = data;
}
$('#filename').val(fname);
imgclean.replaceWith( imgclean = imgclean.clone( true ) );
}
else
{
imgclean.replaceWith( imgclean = imgclean.clone( true ) );
alert('SORRY SIZE AND TYPE ISSUE');
}
});
return false;
}//end size
else
{
imgclean.replaceWith( imgclean = imgclean.clone( true ) );//Its for reset the value of file type
alert('Sorry File size exceeding from 1 Mb');
}
}//end FILETYPE
else
{
imgclean.replaceWith( imgclean = imgclean.clone( true ) );
alert('Sorry Only you can uplaod JPEG|JPG|PNG|GIF file type ');
}
}//end filecount
else
{ imgclean.replaceWith( imgclean = imgclean.clone( true ) );
alert('You Can not Upload more than 6 Photos');
}
}
Here is PHP code :
$filetype = array('jpeg','jpg','png','gif','PNG','JPEG','JPG');
foreach ($_FILES as $key )
{
$name =time().$key['name'];
$path='local_cdn/'.$name;
$file_ext = pathinfo($name, PATHINFO_EXTENSION);
if(in_array(strtolower($file_ext), $filetype))
{
if($key['name']<1000000)
{
#move_uploaded_file($key['tmp_name'],$path);
echo $name;
}
else
{
echo "FILE_SIZE_ERROR";
}
}
else
{
echo "FILE_TYPE_ERROR";
}// Its simple code.Its not with proper validation.
Here upload and preview part done.Now if you want to delete and remove image from page and folder both then code is here for deletion.
Ajax Part:
function removeit (arg) {
var id = arg;
// GET FILE VALUE
var fname = $('#filename').val();
var fcnt = $('#filecount').val();
// GET FILE VALUE
$('#img_'+id).remove();
$('#rmv_'+id).remove();
$('#img_'+id).css('display','none');
var dname = $('#name_'+id).val();
fcnt = parseInt(fcnt)-1;
$('#filecount').val(fcnt);
var fname = fname.replace(dname, "");
var fname = fname.replace(",,", "");
$('#filename').val(fname);
$.ajax({
url: 'delete.php',
type: 'POST',
data:{'name':dname},
success:function(a){
console.log(a);
}
});
}
Here is PHP part(delete.php):
$path='local_cdn/'.$_POST['name'];
if(#unlink($path))
{
echo "Success";
}
else
{
echo "Failed";
}

Answer 3

You can use jquery.form.js plugin to upload image via ajax to the server.
http://malsup.com/jquery/form/
Here is the sample jQuery ajax image upload script
(function() {
$('form').ajaxForm({
beforeSubmit: function() {
//do validation here
},
beforeSend:function(){
$('#loader').show();
$('#image_upload').hide();
},
success: function(msg) {
///on success do some here
}
}); })();
If you have any doubt, please refer following ajax image upload tutorial here
http://www.smarttutorials.net/ajax-image-upload-using-jquery-php-mysql/

Answer 4

Image upload using ajax and check image format and upload max size
<form class='form-horizontal' method="POST" id='document_form' enctype="multipart/form-data">
<div class='optionBox1'>
<div class='row inviteInputWrap1 block1'>
<div class='col-3'>
<label class='col-form-label'>Name</label>
<input type='text' class='form-control form-control-sm' name='name[]' id='name' Value=''>
</div>
<div class='col-3'>
<label class='col-form-label'>File</label>
<input type='file' class='form-control form-control-sm' name='file[]' id='file' Value=''>
</div>
<div class='col-3'>
<span class='deleteInviteWrap1 remove1 d-none'>
<i class='fas fa-trash'></i>
</span>
</div>
</div>
<div class='row'>
<div class='col-8 pl-3 pb-4 mt-4'>
<span class='btn btn-info add1 pr-3'>+ Add More</span>
<button class='btn btn-primary'>Submit</button>
</div>
</div>
</div>
</form>
</div>
$.validator.setDefaults({
submitHandler: function (form)
{
$.ajax({
url : "action1.php",
type : "POST",
data : new FormData(form),
mimeType: "multipart/form-data",
contentType: false,
cache: false,
dataType:'json',
processData: false,
success: function(data)
{
if(data.status =='success')
{
swal("Document has been successfully uploaded!", {
icon: "success",
});
setTimeout(function(){
window.location.reload();
},1200);
}
else
{
swal('Oh noes!', "Error in document upload. Please contact to administrator", "error");
}
},
error:function(data)
{
swal ( "Ops!" , "error in document upload." , "error" );
}
});
}
});
$('#document_form').validate({
rules: {
"name[]": {
required: true
},
"file[]": {
required: true,
extension: "jpg,jpeg,png,pdf,doc",
filesize :2000000
}
},
messages: {
"name[]": {
required: "Please enter name"
},
"file[]": {
required: "Please enter file",
extension :'Please upload only jpg,jpeg,png,pdf,doc'
}
},
errorElement: 'span',
errorPlacement: function (error, element) {
error.addClass('invalid-feedback');
element.closest('.col-3').append(error);
},
highlight: function (element, errorClass, validClass) {
$(element).addClass('is-invalid');
},
unhighlight: function (element, errorClass, validClass) {
$(element).removeClass('is-invalid');
}
});
$.validator.addMethod('filesize', function(value, element, param) {
return this.optional(element) || (element.files[0].size <= param)
}, 'File size must be less than 2 MB');

Answer 5

$(document).on('change', '#photo', function() {
var property = document.getElementById('photo').files[0];
var image_name = property.name;
var image_extension = image_name.split('.').pop().toLowerCase();
var url = './services/userProfile.php';
if (jQuery.inArray(image_extension, ['jpg', 'jpeg', 'png']) == -1) {
$('#msg').html('Invalid image file');
return false;
}
var form_data = new FormData();
form_data.append("file", property);
$.ajax({
url: url,
method: 'POST',
data: form_data,
contentType: false,
cache: false,
processData: false,
beforeSend: function() {
$('#msg').html('Loading......');
},
success: function(data) {
const obj = JSON.parse(data);
$('.image').attr('src', 'upload/' + obj['data']);
$('#msg').html(obj['msg']);
}
});
});
<script src="https://cdnjs.cloudflare.com/ajax/libs/jquery/3.3.1/jquery.min.js"></script>
<form id="form" action="" method="post" enctype="multipart/form-data">
<img src="upload/imag.jpg" class="mx-auto img-fluid img-circle d-block image" alt="avatar">
<h6 class="mt-2">Upload a different photo</h6>
<label class="custom-file">
<input type="file" id="photo" name="profilePicture" class="custom-file-input">
<span class="custom-file-control">Choose file</span>
</label>
<span id="msg" style="color:red"></span>
</form>

Answer 6

Here is simple way using HTML5 and jQuery:
1) include two JS file
<script src="jslibs/jquery.js" type="text/javascript"></script>
<script src="jslibs/ajaxupload-min.js" type="text/javascript"></script>
2) include CSS to have cool buttons
<link rel="stylesheet" href="css/baseTheme/style.css" type="text/css" media="all" />
3) create DIV or SPAN
<div class="demo" > </div>
4) write this code in your HTML page
$('.demo').ajaxupload({
url:'upload.php'
});
5) create you upload.php file to have PHP code to upload data.
You can download required JS file from here
Here is Example
Its too cool and too fast And easy too! :)