Use single request for both data and file submission to server - php

A dropzone js need to create a new form but I want to use the same form to post both data and image, how can I achieve this, any idea.
<form method="POST" enctype="multipart/form-data">
<input type="text" name="name" id="name">
<!-- how to replace this field with dropzone but in this form in order to use the same ajax as below -->
<input type="file" name="photo" id="photo">
<button type="submit">send</button>
</form>
$("form").on('submit', function(e) {
$.ajax({
url: 'add.php',
type: 'POST',
data: new FormData(this),
dataType: 'JSON',
contentType: false,
cache: false,
processData: false,
}).done(function(data) {
if (data.success == false) {
if (data.errors.name) {
$('#name').append('<span class="text-danger">' + data.errors.name + '</span>');
}
if (data.errors.photo) {
$('#photo').append('<span class="text-danger">' + data.errors.photo + '</span>');
}
}
});
e.preventDefault();
});

You need to append dropzone files separately to FormData. Here is my solution,
$(document).ready(function () {
// get a reference to photo dropzone
var photoDropzone = Dropzone.forElement('#photo-dropzone');
$("form").submit(function (e) {
e.preventDefault();
// create the complete FormData here
var fd = new FormData(this);
// append dropzone files into the form data
for (var i = 0; i < photoDropzone.files.length; i++) {
fd.append('file[]', photoDropzone.files[i]);
}
$.ajax({
url: 'add.php',
type: 'POST',
data: fd,
dataType: 'JSON',
contentType: false,
cache: false,
processData: false,
}).done(function (data) {
console.log('done');
if (data.success == false) {
if (data.errors.name) {
$('#name').append('<span class="text-danger">' + data.errors.name + '</span>');
}
if (data.errors.photo) {
$('#photo').append('<span class="text-danger">' + data.errors.photo + '</span>');
}
}
});
});
})
<link href="https://cdnjs.cloudflare.com/ajax/libs/dropzone/5.9.2/dropzone.min.css" rel="stylesheet"/>
<link href="https://cdnjs.cloudflare.com/ajax/libs/dropzone/5.9.2/basic.min.css" rel="stylesheet"/>
<script src="https://cdnjs.cloudflare.com/ajax/libs/dropzone/5.9.2/min/dropzone.min.js"></script>
<script src="https://cdnjs.cloudflare.com/ajax/libs/jquery/3.3.1/jquery.min.js"></script>
<script>
// prevent auto processing in dropzone configuration
Dropzone.options.photoDropzone = {
autoProcessQueue: false
};
</script>
<form method="POST" enctype="multipart/form-data">
<input type="text" name="name" id="name">
<button type="submit">send</button>
</form>
<!-- add dropzone form in the same page -->
<form action="add.php" class="dropzone" id="photo-dropzone">

Related

Why aren't the Attachments in my Contact Form coming through? [duplicate]

This is my HTML which I'm generating dynamically using drag and drop functionality.
<form method="POST" id="contact" name="13" class="form-horizontal wpc_contact" novalidate="novalidate" enctype="multipart/form-data">
<fieldset>
<div id="legend" class="">
<legend class="">file demoe 1</legend>
<div id="alert-message" class="alert hidden"></div>
</div>
<div class="control-group">
<!-- Text input-->
<label class="control-label" for="input01">Text input</label>
<div class="controls">
<input type="text" placeholder="placeholder" class="input-xlarge" name="name">
<p class="help-block" style="display:none;">text_input</p>
</div>
<div class="control-group"> </div>
<label class="control-label">File Button</label>
<!-- File Upload -->
<div class="controls">
<input class="input-file" id="fileInput" type="file" name="file">
</div>
</div>
<div class="control-group">
<!-- Button -->
<div class="controls">
<button class="btn btn-success">Button</button>
</div>
</div>
</fieldset>
</form>
This is my JavaScript code:
<script>
$('.wpc_contact').submit(function(event){
var formname = $('.wpc_contact').attr('name');
var form = $('.wpc_contact').serialize();
var FormData = new FormData($(form)[1]);
$.ajax({
url : '<?php echo plugins_url(); ?>'+'/wpc-contact-form/resources/js/tinymce.php',
data : {form:form,formname:formname,ipadd:ipadd,FormData:FormData},
type : 'POST',
processData: false,
contentType: false,
success : function(data){
alert(data);
}
});
}
For correct form data usage you need to do 2 steps.
Preparations
You can give your whole form to FormData() for processing
var form = $('form')[0]; // You need to use standard javascript object here
var formData = new FormData(form);
or specify exact data for FormData()
var formData = new FormData();
formData.append('section', 'general');
formData.append('action', 'previewImg');
// Attach file
formData.append('image', $('input[type=file]')[0].files[0]);
Sending form
Ajax request with jquery will looks like this:
$.ajax({
url: 'Your url here',
data: formData,
type: 'POST',
contentType: false, // NEEDED, DON'T OMIT THIS (requires jQuery 1.6+)
processData: false, // NEEDED, DON'T OMIT THIS
// ... Other options like success and etc
});
After this it will send ajax request like you submit regular form with enctype="multipart/form-data"
Update: This request cannot work without type:"POST" in options since all files must be sent via POST request.
Note: contentType: false only available from jQuery 1.6 onwards
I can't add a comment above as I do not have enough reputation, but the above answer was nearly perfect for me, except I had to add
type: "POST"
to the .ajax call. I was scratching my head for a few minutes trying to figure out what I had done wrong, that's all it needed and works a treat. So this is the whole snippet:
Full credit to the answer above me, this is just a small tweak to that. This is just in case anyone else gets stuck and can't see the obvious.
$.ajax({
url: 'Your url here',
data: formData,
type: "POST", //ADDED THIS LINE
// THIS MUST BE DONE FOR FILE UPLOADING
contentType: false,
processData: false,
// ... Other options like success and etc
})
<form id="upload_form" enctype="multipart/form-data">
jQuery with CodeIgniter file upload:
var formData = new FormData($('#upload_form')[0]);
formData.append('tax_file', $('input[type=file]')[0].files[0]);
$.ajax({
type: "POST",
url: base_url + "member/upload/",
data: formData,
//use contentType, processData for sure.
contentType: false,
processData: false,
beforeSend: function() {
$('.modal .ajax_data').prepend('<img src="' +
base_url +
'"asset/images/ajax-loader.gif" />');
//$(".modal .ajax_data").html("<pre>Hold on...</pre>");
$(".modal").modal("show");
},
success: function(msg) {
$(".modal .ajax_data").html("<pre>" + msg +
"</pre>");
$('#close').hide();
},
error: function() {
$(".modal .ajax_data").html(
"<pre>Sorry! Couldn't process your request.</pre>"
); //
$('#done').hide();
}
});
you can use.
var form = $('form')[0];
var formData = new FormData(form);
formData.append('tax_file', $('input[type=file]')[0].files[0]);
or
var formData = new FormData($('#upload_form')[0]);
formData.append('tax_file', $('input[type=file]')[0].files[0]);
Both will work.
$(document).ready(function () {
$(".submit_btn").click(function (event) {
event.preventDefault();
var form = $('#fileUploadForm')[0];
var data = new FormData(form);
data.append("CustomField", "This is some extra data, testing");
$("#btnSubmit").prop("disabled", true);
$.ajax({
type: "POST",
enctype: 'multipart/form-data',
url: "upload.php",
data: data,
processData: false,
contentType: false,
cache: false,
timeout: 600000,
success: function (data) {
console.log();
},
});
});
});
Better to use the native javascript to find the element by id like: document.getElementById("yourFormElementID").
$.ajax( {
url: "http://yourlocationtopost/",
type: 'POST',
data: new FormData(document.getElementById("yourFormElementID")),
processData: false,
contentType: false
} ).done(function(d) {
console.log('done');
});
$('#form-withdraw').submit(function(event) {
//prevent the form from submitting by default
event.preventDefault();
var formData = new FormData($(this)[0]);
$.ajax({
url: 'function/ajax/topup.php',
type: 'POST',
data: formData,
async: false,
cache: false,
contentType: false,
processData: false,
success: function (returndata) {
if(returndata == 'success')
{
swal({
title: "Great",
text: "Your Form has Been Transfer, We will comfirm the amount you reload in 3 hours",
type: "success",
showCancelButton: false,
confirmButtonColor: "#DD6B55",
confirmButtonText: "OK",
closeOnConfirm: false
},
function(){
window.location.href = '/transaction.php';
});
}
else if(returndata == 'Offline')
{
sweetAlert("Offline", "Please use other payment method", "error");
}
}
});
});
Actually The documentation shows that you can use XMLHttpRequest().send()
to simply send multiform data
in case jquery sucks
View:
<label class="btn btn-info btn-file">
Import <input type="file" style="display: none;">
</label>
<Script>
$(document).ready(function () {
$(document).on('change', ':file', function () {
var fileUpload = $(this).get(0);
var files = fileUpload.files;
var bid = 0;
if (files.length != 0) {
var data = new FormData();
for (var i = 0; i < files.length ; i++) {
data.append(files[i].name, files[i]);
}
$.ajax({
xhr: function () {
var xhr = $.ajaxSettings.xhr();
xhr.upload.onprogress = function (e) {
console.log(Math.floor(e.loaded / e.total * 100) + '%');
};
return xhr;
},
contentType: false,
processData: false,
type: 'POST',
data: data,
url: '/ControllerX/' + bid,
success: function (response) {
location.href = 'xxx/Index/';
}
});
}
});
});
</Script>
Controller:
[HttpPost]
public ActionResult ControllerX(string id)
{
var files = Request.Form.Files;
...
Good morning.
I was have the same problem with upload of multiple images. Solution was more simple than I had imagined: include [] in the name field.
<input type="file" name="files[]" multiple>
I did not make any modification on FormData.

POST Value not Being Retrieved AJAX/JQUERY [duplicate]

This is my HTML which I'm generating dynamically using drag and drop functionality.
<form method="POST" id="contact" name="13" class="form-horizontal wpc_contact" novalidate="novalidate" enctype="multipart/form-data">
<fieldset>
<div id="legend" class="">
<legend class="">file demoe 1</legend>
<div id="alert-message" class="alert hidden"></div>
</div>
<div class="control-group">
<!-- Text input-->
<label class="control-label" for="input01">Text input</label>
<div class="controls">
<input type="text" placeholder="placeholder" class="input-xlarge" name="name">
<p class="help-block" style="display:none;">text_input</p>
</div>
<div class="control-group"> </div>
<label class="control-label">File Button</label>
<!-- File Upload -->
<div class="controls">
<input class="input-file" id="fileInput" type="file" name="file">
</div>
</div>
<div class="control-group">
<!-- Button -->
<div class="controls">
<button class="btn btn-success">Button</button>
</div>
</div>
</fieldset>
</form>
This is my JavaScript code:
<script>
$('.wpc_contact').submit(function(event){
var formname = $('.wpc_contact').attr('name');
var form = $('.wpc_contact').serialize();
var FormData = new FormData($(form)[1]);
$.ajax({
url : '<?php echo plugins_url(); ?>'+'/wpc-contact-form/resources/js/tinymce.php',
data : {form:form,formname:formname,ipadd:ipadd,FormData:FormData},
type : 'POST',
processData: false,
contentType: false,
success : function(data){
alert(data);
}
});
}
For correct form data usage you need to do 2 steps.
Preparations
You can give your whole form to FormData() for processing
var form = $('form')[0]; // You need to use standard javascript object here
var formData = new FormData(form);
or specify exact data for FormData()
var formData = new FormData();
formData.append('section', 'general');
formData.append('action', 'previewImg');
// Attach file
formData.append('image', $('input[type=file]')[0].files[0]);
Sending form
Ajax request with jquery will looks like this:
$.ajax({
url: 'Your url here',
data: formData,
type: 'POST',
contentType: false, // NEEDED, DON'T OMIT THIS (requires jQuery 1.6+)
processData: false, // NEEDED, DON'T OMIT THIS
// ... Other options like success and etc
});
After this it will send ajax request like you submit regular form with enctype="multipart/form-data"
Update: This request cannot work without type:"POST" in options since all files must be sent via POST request.
Note: contentType: false only available from jQuery 1.6 onwards
I can't add a comment above as I do not have enough reputation, but the above answer was nearly perfect for me, except I had to add
type: "POST"
to the .ajax call. I was scratching my head for a few minutes trying to figure out what I had done wrong, that's all it needed and works a treat. So this is the whole snippet:
Full credit to the answer above me, this is just a small tweak to that. This is just in case anyone else gets stuck and can't see the obvious.
$.ajax({
url: 'Your url here',
data: formData,
type: "POST", //ADDED THIS LINE
// THIS MUST BE DONE FOR FILE UPLOADING
contentType: false,
processData: false,
// ... Other options like success and etc
})
<form id="upload_form" enctype="multipart/form-data">
jQuery with CodeIgniter file upload:
var formData = new FormData($('#upload_form')[0]);
formData.append('tax_file', $('input[type=file]')[0].files[0]);
$.ajax({
type: "POST",
url: base_url + "member/upload/",
data: formData,
//use contentType, processData for sure.
contentType: false,
processData: false,
beforeSend: function() {
$('.modal .ajax_data').prepend('<img src="' +
base_url +
'"asset/images/ajax-loader.gif" />');
//$(".modal .ajax_data").html("<pre>Hold on...</pre>");
$(".modal").modal("show");
},
success: function(msg) {
$(".modal .ajax_data").html("<pre>" + msg +
"</pre>");
$('#close').hide();
},
error: function() {
$(".modal .ajax_data").html(
"<pre>Sorry! Couldn't process your request.</pre>"
); //
$('#done').hide();
}
});
you can use.
var form = $('form')[0];
var formData = new FormData(form);
formData.append('tax_file', $('input[type=file]')[0].files[0]);
or
var formData = new FormData($('#upload_form')[0]);
formData.append('tax_file', $('input[type=file]')[0].files[0]);
Both will work.
$(document).ready(function () {
$(".submit_btn").click(function (event) {
event.preventDefault();
var form = $('#fileUploadForm')[0];
var data = new FormData(form);
data.append("CustomField", "This is some extra data, testing");
$("#btnSubmit").prop("disabled", true);
$.ajax({
type: "POST",
enctype: 'multipart/form-data',
url: "upload.php",
data: data,
processData: false,
contentType: false,
cache: false,
timeout: 600000,
success: function (data) {
console.log();
},
});
});
});
Better to use the native javascript to find the element by id like: document.getElementById("yourFormElementID").
$.ajax( {
url: "http://yourlocationtopost/",
type: 'POST',
data: new FormData(document.getElementById("yourFormElementID")),
processData: false,
contentType: false
} ).done(function(d) {
console.log('done');
});
$('#form-withdraw').submit(function(event) {
//prevent the form from submitting by default
event.preventDefault();
var formData = new FormData($(this)[0]);
$.ajax({
url: 'function/ajax/topup.php',
type: 'POST',
data: formData,
async: false,
cache: false,
contentType: false,
processData: false,
success: function (returndata) {
if(returndata == 'success')
{
swal({
title: "Great",
text: "Your Form has Been Transfer, We will comfirm the amount you reload in 3 hours",
type: "success",
showCancelButton: false,
confirmButtonColor: "#DD6B55",
confirmButtonText: "OK",
closeOnConfirm: false
},
function(){
window.location.href = '/transaction.php';
});
}
else if(returndata == 'Offline')
{
sweetAlert("Offline", "Please use other payment method", "error");
}
}
});
});
Actually The documentation shows that you can use XMLHttpRequest().send()
to simply send multiform data
in case jquery sucks
View:
<label class="btn btn-info btn-file">
Import <input type="file" style="display: none;">
</label>
<Script>
$(document).ready(function () {
$(document).on('change', ':file', function () {
var fileUpload = $(this).get(0);
var files = fileUpload.files;
var bid = 0;
if (files.length != 0) {
var data = new FormData();
for (var i = 0; i < files.length ; i++) {
data.append(files[i].name, files[i]);
}
$.ajax({
xhr: function () {
var xhr = $.ajaxSettings.xhr();
xhr.upload.onprogress = function (e) {
console.log(Math.floor(e.loaded / e.total * 100) + '%');
};
return xhr;
},
contentType: false,
processData: false,
type: 'POST',
data: data,
url: '/ControllerX/' + bid,
success: function (response) {
location.href = 'xxx/Index/';
}
});
}
});
});
</Script>
Controller:
[HttpPost]
public ActionResult ControllerX(string id)
{
var files = Request.Form.Files;
...
Good morning.
I was have the same problem with upload of multiple images. Solution was more simple than I had imagined: include [] in the name field.
<input type="file" name="files[]" multiple>
I did not make any modification on FormData.

Can't upload multiple files with different extension?

Multiple file upload is not working if all files are not the same extension !! If I chose two png files , it works . But choosing two different file extensions (png,pdf) got empty array in $_FILES !
index.php
<html>
<head>
<script src="https://ajax.googleapis.com/ajax/libs/jquery/1.9.0/jquery.min.js" > </script>
</head>
<body>
<form>
<input name="file[]" type="file" multiple/>
<input type="button" value="Upload" />
</form>
<progress></progress>
<script>
$(':button').on('click', function() {
$.ajax({
// Your server script to process the upload
url: 'upload.php',
type: 'POST',
// Form data
data: new FormData($('form')[0]),
// Tell jQuery not to process data or worry about content-type
// You *must* include these options!
cache: false,
contentType: false,
processData: false,
// Custom XMLHttpRequest
xhr: function() {
var myXhr = $.ajaxSettings.xhr();
if (myXhr.upload) {
// For handling the progress of the upload
myXhr.upload.addEventListener('progress', function(e) {
if (e.lengthComputable) {
$('progress').attr({
value: e.loaded,
max: e.total,
});
}
} , false);
}
return myXhr;
},
});
});
</script>
</body>
</html>
upload.php
<?php var_dump($_FILES); ?>
Result image
Hope to help you.
demo.php
<?php
if(isset($_FILES)&&!empty($_FILES)){
for($i=0;$i<count($_FILES);$i++){
echo "File ".($i+1)." is ".$_FILES["file-".$i]['name']."\n";
}
die;
}
?>
<!DOCTYPE html>
<html>
<head>
<script src="https://ajax.googleapis.com/ajax/libs/jquery/3.3.1/jquery.min.js"></script>
<script>
$(document).ready(function(){
// Updated part
jQuery.each(jQuery('#file')[0].files, function(i, file) {
data.append('file-'+i, file);
});
// Full Ajax request
$(".update").click(function(e) {
// Stops the form from reloading
e.preventDefault();
$.ajax({
url: 'demo.php',
type: 'POST',
contentType:false,
processData: false,
data: function(){
var data = new FormData();
jQuery.each(jQuery('#file')[0].files, function(i, file) {
data.append('file-'+i, file);
});
return data;
}(),
success: function(result) {
alert(result);
},
error: function(xhr, result, errorThrown){
alert('Request failed.');
}
});
});
});
</script>
</head>
<body>
<form enctype="multipart/form-data" method="post">
<input id="file" name="file[]" type="file" multiple/>
<input class="update" type="submit" />
</form>
<body>
</html>
I think you can use following code :-
<button id="upload">Upload</button>
<script type="text/javascript">
$(document).ready(function (e) {
$('#upload').on('click', function () {
var form_data = new FormData();
var ins = document.getElementById('multiFiles').files.length;
for (var x = 0; x < ins; x++) {
form_data.append("files[]", document.getElementById('multiFiles').files[x]);
}
$.ajax({
url: 'uploads.php', // point to server-side PHP script
dataType: 'text', // what to expect back from the PHP script
cache: false,
contentType: false,
processData: false,
data: form_data,
type: 'post',
success: function (response) {
$('#msg').html(response); // display success response from the PHP script
},
error: function (response) {
$('#msg').html(response); // display error response from the PHP script
}
});
});
});
</script>

How to pass file object with multiple attribute via jQuery ajax

I am trying to pass a file object with multiple attribute via AJAX in my WordPress application but not being able to capture them in the process function.
HTML:
<form enctype="multipart/form-data" method="post">
<input type="text" id="album_title" name="album_title" />
<input type="file" multiple" id="photo_upload" name="photo_upload[]" class="files-data" />
<input type="button" value="Submit" onclick="uploadPhoto();" />
</form>
JS:
var formData = new FormData();
formData.append('album_title', jQuery('#album_title').val());
formData.append('security', mbAlbumUploader.ajax_nonce);
jQuery.each(jQuery('.files-data'), function(i, obj) {
jQuery.each(obj.files, function(j, file){
formData.append('files[' + j + ']', file);
});
});
jQuery.ajax({
url: 'mbAlbumUploader.ajax_url,'
type: 'post',
data: formData,
dataType: 'json',
processData: false,
contentType: false,
success: function(response) {
alert(response.files);
}
});
PHP function:
function uploadPhoto() {
$fileName_str = '';
foreach($_FILES['photo_upload']['name'] as $f=>$name) {
$extension = pathinfo($name, PATHINFO_EXTENSION);
$fileName_str .= $name . ', ';
}
die(wp_json_encode(array(
'files' => $fileName_str;
)));
}
What I am doing wrong?
Try to run ajax request by click event or submit event. I made few changes this is script below. Assuming your button has update class.
HTML
<form enctype="multipart/form-data" method="post">
<input type="text" id="album_title" name="album_title" />
<input id="file" name="file[]" type="file" multiple/>
<input class="update" type="submit" />
</form>
JavaScript
$(".update").click(function(e) {
// Stops the form from reloading
e.preventDefault();
$.ajax({
url: 'upload.php',
type: 'POST',
contentType:false,
processData: false,
data: function(){
var data = new FormData();
data.append('album_title', jQuery('#album_title').val());
data.append('security', mbAlbumUploader.ajax_nonce);
jQuery.each(jQuery('#file')[0].files, function(i, file) {
data.append('file-'+i, file);
});
data.append('body' , $('#body').val());
data.append('uid', $('#uid').val());
return data;
}(),
success: function(result) {
alert(result);
},
error: function(xhr, result, errorThrown){
alert('Request failed.');
}
});
$('#picture').val('');
$('#body').val('');
});
PHP (upload.php)
You can Access your files from $_FILES global.

why I can't post to laravel rout using jquery?

I'm trying to submit a single value as following?
HTML:
<form class="form-horizontal" role="form" method="POST" enctype="multipart/form-data" name="frmanalyse" id="frmanalyse">
{{ csrf_field() }}
<label for="marginsource" style="float: left; width:150px; text-align:left;">Margin Source</label>
<input type="file" name="marginsource" id="marginsource" >
<br />
</form>
script:
<script type="text/javascript">
$( "#frmanalyse" ).submit(function(event) {
$.post( "marginanalyser", {username: "medo ampir"}, function( data ) {
alert(data);
});
event.preventDefault();
});
in laravel routes:
Route::post('marginanalyser',function(Request $request){
echo $request->input('username');
$file = $request->file('marginsource');
echo 'File Name: '.$file->getClientOriginalName();
});
nothing shows in the message at all.
Change your JavaScript to use FormData as you aren't submitting the file
$( "#frmanalyse" ).submit(function(event) {
event.preventDefault();
var formData = new FormData();
formData.append('marginsource', $('#marginsource')[0].files[0]);
formData.append('username', "medo ampir");
$.ajax({
url : window.location.origin + "/marginanalyser",
type: "POST",
data : formData,
headers: {
'X-CSRF-TOKEN': $('meta[name="csrf-token"]').attr('content')
},
processData: false,
contentType: false,
success:function(data, textStatus, jqXHR) {
console.log(data);
},
error: function(jqXHR, textStatus, errorThrown){
//if fails
}
});
});

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