How to get affected rows using mysqli? - php

Question

I create function for make query in database:
function mysqli($query){
$mysqli = new mysqli('test','test','test','test');
if (mysqli_connect_errno()) {
printf("Bad connect: %s\n", mysqli_connect_error());
exit();
}
$result = $mysqli->query("SET NAMES utf8");
$result = $mysqli->query("set character_set_client='utf8'");
$result = $mysqli->query("set collation_connection='utf8_general_ci'");
$result = $mysqli->query($query);
$mysqli->close();
return $result;
};
In next step I want get count affected rows.
For this I make:
$res2 = mysqli("INSERT INTO Table (name, value) VALUES ('$name', '$value')");
echo $res2->affected_rows;
But I get Notice: Trying to get property of non-object on line echo $res2->affected_rows;
How to get count of affected_rows?

Answer 1

This function is pointless and harmful.
And should never be used.
All other answer told you to remove most useless parts. While what you really have to remove is connection part. Which makes whole function useless.
And even harmful, as you will kill your MySQL server by connecting every time you are going to run a query.
And even more harmful as it doesn't support prepared statements.

Answer 2

Remove $mysqli->close(); And make use of
$mysqli->query("INSERT INTO Table (name, value) VALUES ('$name', '$value')");
echo $mysqli->affected_rows;

Answer 3

change
$res2 = mysqli("INSERT INTO Table (name, value) VALUES ('$name', '$value')");
to
$res2 = mysqli_query("INSERT INTO Table (name, value) VALUES ('$name', '$value')");

Answer 4

Remove the line:
$mysqli->close();
from the function. and this will work.
function mysqli($query){
$mysqli = new mysqli('test','test','test','test');
if (mysqli_connect_errno()) {
printf("Bad connect: %s\n", mysqli_connect_error());
exit();
}
$result = $mysqli->query("SET NAMES utf8");
$result = $mysqli->query("set character_set_client='utf8'");
$result = $mysqli->query("set collation_connection='utf8_general_ci'");
$result = $mysqli->query($query);
$arr = array($result,$mysqli);
return $arr;
}
Amd the use like this:
$res2 = mysqli("INSERT INTO Table (name, value) VALUES ('$name', '$value')");
echo $res2[1]->affected_rows;
And your result will be in this variable: res2[0];
Read this answer: mysqli_affected_rows() expects parameter 1 to be mysqli, object given