PHP MySql Update else Insert Error "Warning: mysql_result()" - php

Question

I'm trying to go threw my table nonbulkmdu and look into r10database to find if there is a duplicate, if there is it will update 4 fields if its not it will insert a new row. I keep getting the error
Warning: mysql_result(): supplied argument is not a valid MySQL result resource in on line 19-23.
What am I doing wrong?
<?php
$username="";
$password="";
$database="";
$link = mysql_connect(localhost,$username,$password);
mysql_select_db($database) or die( "Unable to select database");
$query="SELECT * FROM nonbulkmdu";
if ($result=mysql_query($query, $link)) {
$num=mysql_numrows($result);
$i=0;
while ($i < $num) {
$address=strtoupper(mysql_result($result,$i,"address"));
$drops=mysql_result($result,$i,"drops");
$city=mysql_result($result,$i,"city");
$citycode=mysql_result($result,$i,"citycode");
$feature_type=mysql_result($result,$i,"Feature_Type");
$result = mysql_query("update r10_database
set drops=$drops, citycode=$citycode, city=$city, Feature_Type=$feature_type
where address=$address;");
if (mysql_affected_rows()==0) {
$result = mysql_query("insert into r10_database (address,
drops,
city,
citycode,
Feature_Type)
values ($address,
$drops,
$city,
$citycode,
$Feature_Type);");
}
$i++;
}
} else {
echo mysql_error();
}
mysql_close();
?>

Answer 1

You're missing quotes around the values in the UPDATE and INSERT call:
$result = mysql_query("update r10_database
set drops='$drops', citycode='$citycode', city='$city', Feature_Type='$feature_type'
where address='$address';");
if (mysql_affected_rows()==0) {
$result = mysql_query("insert into r10_database (address,
drops,
city,
citycode,
Feature_Type)
values ('$address',
'$drops',
'$city',
'$citycode',
'$Feature_Type');")
BTW, if address has a unique key in the table, you can do both queries at once, using INSERT ... ON DUPLICATE KEY UPDATE.