Displaying a $result as a result for a Search - php

Question

I have recently completed my search engine but now I have a new challenge.
This following code I am using it to read out values from a callflow table in my DB and displaying them in a table letting u know wether the call was answered yes or no.
if(isset($res))
{
//creating table
echo '<table style="width:1500px; cell-padding:4px; cell-spacing:0; margin:auto;">';
echo'<th>Time</th><th>Answered Y/N</th></th><th>Naam</th><th>Caller ID</th>';
while($result = mysql_fetch_assoc($res))
{
echo '<tr>';
echo '<td>'.$result['statusCalling'].'</td>';
if ($result['statusAnswered'] =="NULL"||$result['statusAnswered'] =="Null" || $result['statusAnswered'] =="null" || $result['statusAnswered'] =="")
{
echo "<td>Not Answered!</td>";
}
else
{
echo "<td>Answered!</td>";
}
echo '<td>'.$result['calleridname'].'</td>'.'<td>'.$result['calleridnum'].'</td>' ;
echo '</tr>';
}
echo '</table>';
}
I need now to display these results in a search engine result!
I tried this but I doesnt work! No idea how else to go about this! Please help!
$output = '';
//collect
if(isset($_POST['asd'])) {
$searchq = $_POST['search'];
$searchq = preg_replace("#[^0-9a-z]#i","",$searchq);
$query = mysql_query('SELECT * FROM callflow WHERE statusCalling LIKE "%'.$searchq.'%" OR calleridname LIKE "%'.$searchq.'%" OR calleridnum LIKE "%'.$searchq.'%" OR $results LIKE "%'.$searchq'%"');
$count = mysql_num_rows($query);
if($count == 0) {
$output = 'There was no search results!';
}else{
while($row = mysql_fetch_array($query)) {
$statusCalling = $row['statusCalling'];
$calleridname = $row['calleridname'];
$calleridnum = $row['calleridnum'];
$results = $row['statusAnswered'];
$id = $row['ID'];
$output .= '<div>'.$statusCalling.' '.$calleridname.' '.$calleridnum.' '.$results.'</div>';
}
}
}
I know that mysql is deprecated, I am learning to program still and i figure if I don't know mysql I cant learn pdo because I don't understand what is what. Please help!

Answer 1

I've worked out the answer and I am posting it here so others can see a way of solving this when they researching for something similar.
<?php
mysql_connect("localhost","root","") or die("Could not connect");
mysql_select_db("voizxl_wachtrij") or die("Could not find Database");
$output = '';
//collect
if(isset($_POST['asd'])) {
$searchq = $_POST['search'];
$searchq = preg_replace("#[^0-9a-z]#i","",$searchq);
$query = mysql_query('SELECT * FROM callflow WHERE statusCalling LIKE "%'.$searchq.'%" OR calleridname LIKE "%'.$searchq.'%" OR calleridnum LIKE "%'.$searchq.'%"');
$count = mysql_num_rows($query);
if($count == 0) {
$output = 'There was no search results!';
}else{
while($row = mysql_fetch_array($query)) {
$statusCalling = $row['statusCalling'];
$calleridname = $row['calleridname'];
$calleridnum = $row['calleridnum'];
$id = $row['ID'];
$output[] = $row;
}
}
}
?>
<?php foreach($output as $o){;
if($o['statusAnswered']){
echo $o['statusCalling'].' Answered: '.$o['calleridname'].' '.$o['statusAnswered'].' '.$o['calleridnum'].'<br />';
}else{
echo $o['statusCalling'].' Not Answered: '.$o['calleridname'].' '.$o['calleridnum'].'<br/>';
}
}?>
<br/><br/><br/>
<?php
Cheers