Why Getting only 1 array instead of many arrays? - php

I am a completely newbie in programming php I would like to make this code below return many arrays(to flash as3), however I only receive one array.Can anyone please pinpoint what is my mistake here? thanks.
$data_array = "";
$i = 0;
//if(isset($_POST['myrequest']) && $_POST['myrequest'] == "get_characters")
//{
$sql = mysqli_query($conn, "SELECT * FROM ns_users ORDER BY Char_id");
while($row = mysqli_fetch_array($sql))
{
$i++;
$fb_name = $row["Username"];
$fb_id = $row["Fb_id"];
$fb_at = $row["Access_token"];
$fb_sig = $row["Fb_sig"];
$char_id = $row["Char_id"];
if($i == 1)
{
$data_array .= "$fb_name|$fb_id|$fb_at|$fb_sig|$char_id";
}
else
{
$data_array .= "(||)$fb_name|$fb_id|$fb_at|$fb_sig|$char_id";
}
echo "returnStr=$data_array";
exit();
}

When you write your exit insight your loop you stop executing your program and you get only one record. You should set the echo and exit after your while loop.
$data_array = "";
$i = 0;
$sql = mysqli_query($conn, "SELECT * FROM ns_users ORDER BY Char_id");
while($row = mysqli_fetch_array($sql)) {
$i++;
$fb_name = $row["Username"];
$fb_id = $row["Fb_id"];
$fb_at = $row["Access_token"];
$fb_sig = $row["Fb_sig"];
$char_id = $row["Char_id"];
if($i == 1) {
$data_array .= "$fb_name|$fb_id|$fb_at|$fb_sig|$char_id";
} else {
$data_array .= "(||)$fb_name|$fb_id|$fb_at|$fb_sig|$char_id";
}
}
echo "returnStr=$data_array";
exit();

Those two last line of your should be outside of your loop:
$data_array = "";
$i = 0;
//if(isset($_POST['myrequest']) && $_POST['myrequest'] == "get_characters")
//{
$sql = mysqli_query($conn, "SELECT * FROM ns_users ORDER BY Char_id");
while($row = mysqli_fetch_array($sql))
{
$i++;
$fb_name = $row["Username"];
$fb_id = $row["Fb_id"];
$fb_at = $row["Access_token"];
$fb_sig = $row["Fb_sig"];
$char_id = $row["Char_id"];
if($i == 1)
{
$data_array .= "$fb_name|$fb_id|$fb_at|$fb_sig|$char_id";
}
else
{
$data_array .= "(||)$fb_name|$fb_id|$fb_at|$fb_sig|$char_id";
}
}
echo "returnStr=$data_array";
exit();

If you would name the columns that you want in the SELECT then it's much simpler. Make sure to use MYSQLI_ASSOC in the fetch:
$sql = mysqli_query($conn, "SELECT Username, Fb_id, Access_token, Fb_sig, Char_id FROM ns_users ORDER BY Char_id");
while($row = mysqli_fetch_array($sql, MYSQLI_ASSOC))
{
$data_array[] = implode('|', $row);
}
echo "returnStr=" . implode('(||)', $data_array);
exit();

Related

Query Debugging.

I have two tables i am using two quires to fetch data from them separately.
$query = mysql_query("SELECT * FROM offers");
$query1 = mysql_query("SELECT * FROM Offers_Dalia ") or die(mysql_error());
I am printing the result on one html-table.
.... the problem is that i want to know that why the loop is running for 11 times both.
1). I am using two while loops. 2). each loop is running for row->mysql_fetch_object times. please help me to find error why my both loops are running for 11 times. total 22 rows are present in html table output. but my both table have so many rows. 100 of rows in both table.
please check the code.
$query = mysql_query("SELECT * FROM offers");
$query1 = mysql_query("SELECT * FROM Offers_Dalia ") or die(mysql_error());
$x = 1;
$n = 0;
while($row = mysql_fetch_object($query))
{
$oid = $row->id;
$name = stripslashes($row->name);
$reward = stripslashes($row->credits);
$network = stripslashes($row->network);
$hits = $row->hits; //clicks; $epc = $row->epc;
$campid = stripslashes($row->campaign_id);
$country = $row->countries;
$url2=$row->link;
$desc=$row->description;
if($x%2 == 0)
{
$trColor = "f1f0f0";
}else
{
$trColor = "ffffff";
}
if(stristr($country, ","))
{
$country_arrs = explode(",", $country);
$country = implode(", ", $country_arrs);
}
?>
<tr style="background:#<?=$trColor?>" ><td><input type="checkbox" value="<?=$oid?>" name="ids[]" onclick="uncheckCheckAllbox(this)" /></td><td><?=$campid?>- campId</td><td><?=$name?></td><td><?=$reward?><td><?=$network?><td><?=$desc?></td><td>Click Here</td></td><td><?=$country?></td></tr>
$n++;
while($row1 = mysql_fetch_object($query1))
{
$uuid = $row1->offers_uuid;
$title1 = stripslashes($row1->title);
$info1 = stripslashes($row1->info_short);
$device_kind1 = stripslashes($row1->device_kinds);
$country1 = stripslashes($row1->target_groups_values);
// $status = toggleStatus($row->active);
$reward_dollar1 = $row1->reward_dollar; //clicks;
$url1 = $row1->url;
$network1 = 'Dalia';
$url1 = urldecode($url1);
if($x%2 == 0)
{
$trColor = "f1f0f0";
}else
{
$trColor = "ffffff";
}
if(stristr($country, ","))
{
$country_arrs = explode(",", $country);
$country = implode(", ", $country_arrs);
}
?>
<tr style="background:#<?=$trColor?>" ><td><input type="checkbox" value="" onclick="uncheckCheckAllbox(this)" /></td><td><?=$uuid?></td><td><?=$title1?></td><td><?=$reward_dollar1?></td><td><?=$network1?></td><td><?=$info1?></td><td>Click Here</td><td><?=$country1?></td></tr>
$n++;
$x++;
goto n;
}
n:
$x++;
}

PHP: Array to string conversion when retrieving outside function

Good day!
I have a problem here that I can't solve (last 5hrs).
here's my codes:
include 'assets\function\retrieveFunction.php';
$loadGradProgram = array();
$x = count(getCourseInfo());
for($i=0;$i<=$x;$i++){
$loadGradProgram[$i] = getCourseInfo();
}
echo $loadGradProgram[0];
getCourseInfo function
Solution 1:
function getCourseInfo(){
$getInfo = array();
include 'assets\database\connect.php';
$i = 0;
$x = 0;
$sql = "SELECT c.courseID, c.courseCode, c.courseTitle, m.description";
$sql .=" FROM tblcourse as c INNER JOIN tblcoursemajor as m ON c.courseid=m.courseID ORDER BY c.courseID";
$result = $conn->query($sql);
if ($result->num_rows > 0) {
while($row = $result->fetch_assoc()) {
$getInfo[$i] = $row;
$i++;
}
return $getInfo;
}
}
Result: Array to string conversion
Solution 2:
function getCourseInfo(){
$getInfo = array();
$loadInfo = array();
include 'assets\database\connect.php';
$i = 0;
$x = 0;
$sql = "SELECT c.courseID, c.courseCode, c.courseTitle, m.description";
$sql .=" FROM tblcourse as c INNER JOIN tblcoursemajor as m ON c.courseid=m.courseID ORDER BY c.courseID";
$result = $conn->query($sql);
if ($result->num_rows > 0) {
while($row = $result->fetch_assoc()) {
$getInfo[$i] = $row;
$i++;
}
$conn->close();
for($x,$x<=$i;$x++;){
$loadInfo[] = implode(',', $getInfo[$x]);
}
return $loadInfo;
}
}
Result: Still the same
and this line causing error: echo $loadGradProgram[0];
I use echo just to see if the query is working.
if you want a multi-dimmentional array like in w3c documentation, you do it like this :
if ($result->num_rows > 0) {
while($row = $result->fetch_assoc()) {
$getInfo[$i][] = $row['courseID'];
$getInfo[$i][] = $row['courseCode'];
...
$i++;
}
return $getInfo;
then, if you want to diplay an information in the array you can do a foreach loop or a for loop like :
foreach($loadGradProgram as $key => $value) // here the key is useless
{
echo $value[0];
echo $value[1];
}
or directly like this :
echo $loadGradProgram[0][0];
echo $loadGradProgram[0][1];
echo $loadGradProgram[1][0];

Search database using array and then echo/print result in foreach loop using PHP

I need to get variable code from URL so I $codes = $_GET['code']; (url example website.com/update?code[]=7291&code[]=9274&code[]=8264&) then I SELECT firstname FROM guests WHERE invitecode = $codes" then I output data and set as $relatives = $row["firstname"] and then later on in the file I need to echo/print print $relative.
Why is this not working for me?
... connection made ...
$codes = $_GET['code'];
$sql = "SELECT firstname FROM guests WHERE invitecode = $codes";
$result = mysqli_query($conn, $sql);
if (mysqli_num_rows($result) > 0) {
// output data of each row
while($row = mysqli_fetch_assoc($result)) {
$relatives[] = $row["firstname"];
}
}
foreach ($relatives as $relative) {
print $relative;
}
Update:
So now using:
<?php
$codes = $_GET['code'];
$thecodes = "";
foreach($codes as $vals)
$thecodes .= (int)$vals . ",";
if($thecodes != "")
{
$thecodes = trim($thecodes, ",");
$sql = "SELECT firstname FROM guests WHERE invitecode IN ($thecodes)";
$result = mysqli_query($conn, $sql);
$result = mysqli_query($conn, $sql);
if (mysqli_num_rows($result) > 0) {
while($row = mysqli_fetch_assoc($result)) {
$relatives[] = $row["firstname"];
}
}
foreach ($relatives as $relative) {
print $relative;
}
}
else
{
}
?>
It works but I would like to enter the foreach ($relatives as $relative) { echo $relative; }; into a value like this $message = $firstname . " " . $lastname . " will be coming to your event. " . ;.
In the end it would turn out something like this: $message = $firstname . " " . $lastname . " will be coming to your event. " . foreach ($relatives as $relative) { echo $relative . " "; };.
For some reason it won't work when I combine them.
Use the IN operator for this.
<?php
$codes = $_GET['code'];
$thecodes = "";
foreach($codes as $vals)
$thecodes .= (int)$vals . ","; //Loop through making sure each is an int for security reasons (No sqli)
if($thecodes != "") //There is at least one code
{
$thecodes = trim($thecodes, ","); //Remove any additional commas
$sql = "SELECT firstname, lastname FROM guests WHERE invitecode IN ($thecodes)"; //Use the IN operator
$result = mysqli_query($conn, $sql);
if (mysqli_num_rows($result) > 0) {
while($row = mysqli_fetch_assoc($result)) {
echo $row["firstname"] . " " . $row["lastname"] . "is coming to your event";
}
}
}
else //No codes to be queried
{
}
?>
Can this be a solution for you?
$relatives = array(); // declare array
$codes = $_GET['code'];
$sql = "SELECT firstname FROM guests WHERE ";
foreach ($codes as $code) $sql .= "invitecode = " . intval($code) . " OR ";
$sql .= "1=2"; // simple way to remove last OR or to make sql valid if there are no codes
$result = mysqli_query($conn, $sql);
if (mysqli_num_rows($result) > 0) {
// output data of each row
while($row = mysqli_fetch_assoc($result)) {
array_push($relatives, $row["firstname"]);
}
}
foreach ($relatives as $relative) {
print $relative;
}
I think this will work...
... connection made ...
$codes = $_GET['code'];
$sql = "SELECT firstname FROM guests WHERE invitecode = '$codes'";
$result = mysqli_query($conn, $sql) or die('-1' . mysqli_error());
if (mysqli_num_rows($result) > 0) {
// output data of each row
while($row = mysqli_fetch_assoc($result)) {
echo ($row['firstname']);
}
}

Form json using php json_encode failed

By using below code
$data = array();
$sql = "SELECT * FROM list";
$result = $db->query($sql);
if ($result->num_rows > 0) {
while($row = $result->fetch_assoc()) {
$data['title'] = $row['title'];
$data['name'] = $row['name'];
}
}
echo json_encode($data);
I got 1 result, I can get full result if I do $data[] = $row['title'], but I want to make the result like this
{'title' : ['title 1','title 2'], 'name':['John','Amy']}
You are overwriting the title in each loop iteration. You need to accumulate all the titles and then set it in your data array.
$data = array();
$sql = "SELECT title FROM mainlist";
$result = $db->query($sql);
$titles = array();
if ($result->num_rows > 0) {
while($row = $result->fetch_assoc()) {
$titles[] = $row['title'];
}
}
$data['title'] = $titles;
echo json_encode($data);
The easiest away is probably this:
$rows = array();
$sql = "SELECT * FROM list";
$result = $db->query($sql);
if ($result->num_rows > 0) {
while($row = $result->fetch_assoc()) {
$rows[] = $row;
}
}
echo json_encode($rows);
you could achieve by using group_concat on each of the columns in your query. That way you do not need to loop the result again and add column etc...
$sql = "SELECT group_concat(title) as title,group_concat(name) as name FROM list";
$result = $db->fetch(PDO::FETCH_ASSOC);
echo json_encode($result);
Try this:
$titles = array();
$names = array();
$sql = "SELECT title,name FROM mainlist";
$result = $db->query($sql);
if ($result->num_rows > 0) {
while($row = $result->fetch_assoc()) {
$titles[] = $row['title'];
$names[] = $row['name'];
}
}
echo json_encode(array("title" => $titles, "name" => $names));
UPDATE
Updated my code to let you manage an undefined number of columns as result
$out = array();
$sql = "SELECT * FROM wp_cineteca";
$result = $db->query($sql);
if ($result->num_rows > 0) {
while($row = $result->fetch_array()) {
$keys = array_keys($row);
for ($i = 0; $i < count($row); $i++) {
$out[$keys[$i]][] = $row[$i];
}
}
}
echo json_encode($out);

php oci_fetch_array and pass value to function issue

1) I want to save case 1 value to an array. Return this array and pass it to a function. The code become case 2, but no result come out, where is the problem?
2) In function display_urls, i want to echo both $url and $category. What should i do in IF condition or add another line of code?
function display_urls($url_array)
{
echo "";
if (is_array($url_array) && count($url_array)>0)
{
foreach ($url_array as $url)
{
echo "".$url."";
echo "".$category."";
}
}
echo "";
}
case 1: work fine
$result = oci_parse($conn, "select * from bookmark where username ='$username'");
if (!$result){ $err = oci_error(); exit; }
$r = oci_execute($result);
$i=0;
echo "";
while( $row = oci_fetch_array($result) ){
$i++;
echo "";
echo "".$row['USERNAME']."";
echo "".$row['BM_URL']."";
echo "".$row['CATEGORY']."";
echo "";
}
echo "";
case 2:
$url_array = array();
while( $row2 = oci_fetch_array($result, OCI_BOTH)){
$i++;
$url_array[$count] = $row[0];
}
return $url_array;
I think you probably want something like this:
function display_urls($url_array)
{
echo "";
if (is_array($url_array) && count($url_array)>0)
{
foreach ($url_array as $url)
{
echo "".$url['BM_URL']."";
echo "".$url['CATEGORY']."";
}
}
echo "";
}
$result = oci_parse($conn, "select * from bookmark where username ='$username'");
if (!$result){ $err = oci_error(); exit; }
$r = oci_execute($result);
$url_array = array();
while( $row = oci_fetch_array($result, OCI_ASSOC)){
$url_array[] = $row;
}
display_urls($url_array);
This will store all the information on the URLs in $url_array with a lookup by column name.

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