PHP Update multiple rows in MySQL - php

Question

I have this PHP/HTML Code that is selecting data from a MySQL Database:
<?php
$sql3="SELECT * from property_images where property_seq = '".$property["sequence"]."' ";
$rs3=mysql_query($sql3,$conn);
while($property_img=mysql_fetch_array($rs3))
{
?><tr>
<td colspan="2"><img src="http://domain.co.uk/img/property-images/<?php echo $property_img["image"]; ?>" width="80px" height="80px" /></td>
<td colspan="2"><input type="checkbox" name="image1" value="Y" <?php if($property_img["image1"] == 'Y') { echo 'checked="checked"'; } ?> />
<input type="checkbox" name="image2" value="Y" <?php if($property_img["image2"] == 'Y') { echo 'checked="checked"'; } ?> />
<input type="checkbox" name="image3" value="Y" <?php if($property_img["image3"] == 'Y') { echo 'checked="checked"'; } ?> />
<input type="checkbox" name="image4" value="Y" <?php if($property_img["image4"] == 'Y') { echo 'checked="checked"'; } ?> />
<input type="checkbox" name="image5" value="Y" <?php if($property_img["image5"] == 'Y') { echo 'checked="checked"'; } ?> />
<input type="checkbox" name="image6" value="Y" <?php if($property_img["image6"] == 'Y') { echo 'checked="checked"'; } ?> />
<input type="checkbox" name="image7" value="Y" <?php if($property_img["image7"] == 'Y') { echo 'checked="checked"'; } ?> />
<input type="checkbox" name="image8" value="Y" <?php if($property_img["image8"] == 'Y') { echo 'checked="checked"'; } ?> />
<input type="checkbox" name="image9" value="Y" <?php if($property_img["image9"] == 'Y') { echo 'checked="checked"'; } ?> />
<input type="checkbox" name="image10" value="Y" <?php if($property_img["image10"] == 'Y') { echo 'checked="checked"'; } ?> />
<input type="checkbox" name="image11" value="Y" <?php if($property_img["image11"] == 'Y') { echo 'checked="checked"'; } ?> />
<input type="checkbox" name="image12" value="Y" <?php if($property_img["image12"] == 'Y') { echo 'checked="checked"'; } ?> />
<input type="checkbox" name="image13" value="Y" <?php if($property_img["image13"] == 'Y') { echo 'checked="checked"'; } ?> /></td>
</tr><?php
}
?>
each row, has its own image with the columns image1 - image13
i want to update the table with the checkboxes that are checked and unchecked on the form update
how is this possible?
Thanks

Answer 1

If you mean that you want to update the $property_img["imagexx"] val on db depending on the user click on the checkbox you must use ajax.
Fire an event on triggering each checkbox and send the value to a php page that update the php.
Jquery Ajax function can help you on this task.
L

Answer 2

name all your checkboxes images[]
<input type="checkbox" name="images[]" value="1" />
<input type="checkbox" name="images[]" value="2" />
<input type="checkbox" name="images[]" value="3" />
<input type="checkbox" name="images[]" value="4" />
You can then update with PHP :
<?php
$q = "UPDATE property_images SET";
foreach($_POST["images"] as $image) {
$q .= " image" . $image ." = 'Y', ";
}
$q .= " property_seq = '".$property["sequence"]."' WHERE property_seq = '".$property["sequence"]."'";
mysql_query($q);
?>

Answer 3

First of all, mysql_ functions are deprecated, please google mysqli_ or PDO, mysql_ won't be supported on future versions, and is unsafe, etc
Your html output could be much simpler with a loop, also have an eye on putting the sequence number on a hidden field or something first:
<?php
$sql3="SELECT * from property_images where property_seq = '".$property["sequence"]."' ";
$rs3=mysql_query($sql3,$conn);
while($property_img=mysql_fetch_array($rs3)){
?>
<tr>
<td colspan="2"><img src="http://domain.co.uk/img/property-images/<?php echo $property_img["image"]; ?>" width="80px" height="80px" /></td>
<!-- THIS IS VERY IMPORTANT: send the sequence or ID through a hidden field, to know which row you are gonna update later-->
<input type="hidden" name="sequence" value="<?php echo $property_img['sequence']; ?>"/>
<td colspan="2">
<?php for($i = 1; $i <= 13; $i++): ?>
<input type="checkbox" name="images[]>" value="<?php echo $i; ?>" <?php if($property_img["image$i"] == 'Y') { echo 'checked="checked"'; } ?> />
<?php endfor ?>
</td>
</tr>
<?php
}
?>
Then this is the next page where the update is done, have a good look at the comments:
<?php
//Handle as you want the situation when there are no images selected instead of using an exit(), I used it here just for the quickness;
if(count($_POST['images'] < 1) exit('no images where selected to update');
$images = array();
for($i = 1; $i <= 13; $i++){
$string = "image$i = ";
if(in_array($i, $_POST['images'])){
$string .= "'Y'"; //notice the double quoting here, it's important
} else {
//This updates the table so if it was checked when loaded, but unchecked by the user, this makes the change!
$string .= "'N'";
}
}
//This creates a string like: image1 = 'Y', images2 = 'N', etc...
$images = implode(', ', $images );
//try to sanitize the query first ... I won't cos am just showing you your question xD
$sql = "UPDATE property_images SET $images WHERE property_seq = " . mysql_real_escape_string($_POST[sequence]) . ";
mysql_query($sql,$conn);
?>