i am coding a page for the attendance of students and in the page all the students name are retrieved dynamically from database using while loop and inside the while loop i have used a radio button.
my problem is the radio button work's correctly but i am unable to insert the value of radio buttons into database.here is my code :
include'connection.php';
#$id = mysql_real_escape_string($_GET['id']);
$res=mysql_query("SELECT * FROM `std_register` AS p1 ,`sims-register-course` AS p2 WHERE p2.semester=p1.std_semester and p2.department=p1.std_department and p2.id = '".$id."'");
if ($res==FALSE) {
echo die(mysql_error());
}
while ($row=mysql_fetch_assoc($res)) { ?>
<input type="hidden" id="dept_0" name="dept[]" value="<?php echo $row["department"] ?>">
<input type="hidden" id="course_name_1" name="course_name[]" value="<?php echo $row["course_name"] ?>">
<input type="hidden" id="std_semester_2" name="std_semester[]" value="<?php echo $row["semester"] ?>">
<input type="hidden" id="std_id_3" name="std_id[]" value="<?php echo $row["id"] ?>">
<input type="hidden" id="std_name_4" name="std_name[]" value="<?php echo $row["std_name"] ?>">
<tr>
<td class =info><?php echo $row["std_name"];?></td>
<td><input type="radio" name="<?php echo "status['".$row["std_name"]."']" ?>" value="1"></td>
<td><input type="radio" name="<?php echo "status['".$row["std_name"]."']" ?>" value="2"></td>
</tr>
<?php }?>
</table><br>
<div class="form-group">
<div class="col-sm-offset-2 col-sm-3">
<input type="submit" name="submit" value="Assign" class="btn btn-large btn-block btn-primary"></div></div>
</form>
<?php
for ($i=0; $i < 4; $i++) {
if(isset($_POST["submit"])) {
$stdid = mysql_real_escape_string($_POST['std_id'][$i]);
$dptname = mysql_real_escape_string($_POST['dept'][$i]);
$courseName = mysql_real_escape_string($_POST['course_name'][$i]);
$stdSemester = mysql_real_escape_string($_POST['std_semester'][$i]);
$std_name = mysql_real_escape_string($_POST['std_name'][$i]);
$present = mysql_real_escape_string($_POST['status'][$i]);
$totalClasses = $present;
$insrt = mysql_query("INSERT INTO `attendence_student` (department_name,courseName,semester,present,absent,total_classes) VALUES('$dptname','$courseName','$stdSemester','$present',0,0)") or die(mysql_error());
}
}
and is it possible to insert values from this radio buttons to two columns of database?
I am not sure but try to add 'checked' property in radio input
<input type="radio" name="<?php echo "status[".$row["std_name"]."]" ?>" value="1" checked></td>
Or
use Select tag instead of radio button
EDIT
use this code to insert in present column or absent column
$value = mysql_real_escape_string($_POST['status'][$i]);
$totalClasses = $value;
if($value == 1) //check if present
{
$sql="INSERT INTO `attendence_student` (department_name,courseName,semester,present,absent,total_classes) VALUES('$dptname','$courseName','$stdSemester','$value',0,0)";
}
else //if absent
{
$sql="INSERT INTO `attendence_student` (department_name,courseName,semester,present,absent,total_classes) VALUES('$dptname','$courseName','$stdSemester',0,'$value',0)";
}
$insrt = mysql_query($sql) or die(mysql_error());
Related
I'm trying to call the old values to be edited. What part am I wrong at?
<?php
if (isset($_GET['edit'])) {
$id = $_GET['edit'];
$update = true;
$record = mysqli_query($db, "SELECT * FROM bookinfo WHERE BookNo='$BookNo'");
if (mysqli_num_rows($record) == 1 ) {
$n = mysqli_fetch_array($record);
$BookNo = $n['BookNo'];
$ISBN = $n['ISBN'];
$title = $n['title'];
$author = $n['author'];
$publisher = $n['publisher'];
$status = $n['status'];
$cost = $n['cost'];
}
}
?>
<a href="viewBook.php?edit=<?php echo $row['BookNo']; ?>" class="edit_btn" >Edit</a>
</td>
<?php
if (isset($_GET['edit'])) { ?>
<form method="post" action = "viewBook.php">
<input type="hidden" name="BookNo" value="<?php echo $BookNo; ?>">
<input type="text" name="ISBN" value="<?php echo $ISBN; ?>">
<input type="text" name="title" value="<?php echo $title; ?>">
<input type="text" name="author" value="<?php echo $author; ?>">
<input type="text" name="publisher" value="<?php echo $publisher; ?>">
<input type="text" name="status" value="<?php echo $status; ?>">
<input type="text" name="cost" value="<?php echo $cost; ?>">
<?php if ($update == true): ?>
<button class="btn" type="submit" name="update" style="background: #556B2F;" >update</button>
<?php else: ?>
<button class="btn" type="submit" name="save" >Save</button>
<?php endif ?>
<?php } ?>
</form>
So far, what it does is, when the user clicks the edit button, it just shows 6 text fields. I thought by doing what I did, it was supposed to show the details already filled in the textbox.
When you do
$record = mysqli_query($db, "SELECT * FROM bookinfo WHERE BookNo='$BookNo'");
$BookNo is not defined.
maybe you wanted to do something like this:
$id = $_GET['edit'];
$update = true;
$record = mysqli_query($db, "SELECT * FROM bookinfo WHERE BookNo='$id'");
<form method="post" action = "viewBook.php">
your form method is "post" but you are checking $_GET You must check $_POST
if (isset($_GET['edit']))
you are passing value in $id And using $BookNo which not define.
only 6 input field will be show because first one is using hidden property.
<input type="hidden" name="BookNo" value="<?php echo $BookNo; ?>">
when you click on submit button data will be receive by $_POST
I'm trying to update multiple rows using a form and a foreach loop. I've tried solutions found on stackoverflow, but just can't seem to get it to work. I'm working on page project.php?id=13
My HTML form:
<form method="post" action="project.php?id=<?php echo $id; ?>">
<?php while($row = $shops->fetch_assoc()) : ?>
<input type="hidden" name="shop[]" value="<?php echo $row['id']; ?>">
<input type="text" name="boxposition[]" class="form-control" value="<?php echo $row['box_position']; ?>" style="width: 50px;">
<input type="submit" name="update" value="Update Order" class="btn btn-primary">
<?php endwhile; ?>
</form>
My PHP code (on the same page) which is executed on if(isset($_POST['update'])) :
$shopid = $_POST['shop'];
$boxorder = $_POST['boxposition'];
foreach ($shopid as $index => $value) {
$query = "UPDATE shops SET box_position = '".$boxorder[$index]."' WHERE id = '".$shopid[$index]."'";
$update_row = $db->update($query);
Unfortunately, it only updates the first row (lowest id). The very strange thing is that I get the correct values when I echo them using. E.g.:
echo $shopid[$index].'<br>';
echo $boxorder[$index].'<br>';
An example:
I update the $boxorder for 2 rows:
Row 1 (for shop 1): new value = 6 (old value was 7)
Row 2 (for shop 2): new value = 8 (old value was 5)
Using foreach to echo the result, it shows the correct values:
1 (shop id)
6 (new boxorder value)
2 (shop id)
8 (new boxorder value)
What am I missing? Thanks in advance for helping me out!
Try following
<?php while($row = $shops->fetch_assoc()) : ?>
<form method="post" action="project.php?id=<?php echo $id; ?>">
<input type="hidden" name="shop[]" value="<?php echo $row['id']; ?>">
<input type="text" name="boxposition[]" class="form-control" value="<?php echo $row['box_position']; ?>" style="width: 50px;">
<input type="submit" name="update" value="Update Order" class="btn btn-primary">
</form>
<?php endwhile; ?>
to
<form method="post" action="project.php?id=<?php echo $id; ?>">
<?php while($row = $shops->fetch_assoc()) : ?>
<input type="hidden" name="shop[]" value="<?php echo $row['id']; ?>">
<input type="text" name="boxposition[]" class="form-control" value="<?php echo $row['box_position']; ?>" style="width: 50px;">
<input type="submit" name="update" value="Update Order" class="btn btn-primary">
<?php endwhile; ?>
</form>
$shopid = $_POST['shop'];
$boxorder = $_POST['boxposition'];
$query = "UPDATE shops SET box_position =? WHERE id =?";
$db->prepare($query);
foreach ($shopid as $index => $value) {
$db->execute(array($boxorder[$index], $shopid[$index]));
}
This should do it. This way you prepare the statement with ? and fill it inside your for each.
you can do it with also as the following :
$query = "UPDATE shops SET box_position = :position WHERE id = :id ";
$db->prepare($query);
foreach ($shopid as $index => $value) {
$db->execute(
array(
':position' => $boxorder[$index],
':id' => $shopid[$index]
)
);
}
this is radio button code
now what if radio button does not have a constant name how would i store the data in database because to store the data in database we will need a name of form attribute
$sql1="select * from questions where email='". $_SESSION['email'] ."'";
$row=mysqli_query($conn,$sql1);
while ($result = mysqli_fetch_array($row))
{
?>
<h2 id="question_<?php echo $result['qid'];?>"><?php echo $result['qid'].".".$result['question'];?></h2>
<input type="radio" value="<?php echo $result['answer1'];?>" name="<?php echo $result['qid'];?>"><?php echo $result['answer1'];?>
<input type="radio" value="<?php echo $result['answer2'];?>" name="<?php echo $result['qid'];?>"><?php echo $result['answer2'];?>
<input type="radio" value="<?php echo $result['answer3'];?>" name="<?php echo $result['qid'];?>"><?php echo $result['answer3'];?>
<input type="radio" value="<?php echo $result['answer4'];?>" name="<?php echo $result['qid'];?>"><?php echo $result['answer4'];?>
if we know the name of radio button we can access it using
<input type="radio" value="<?php echo $result['answer4'];?>" name="name"><?php echo $result['answer4'];?>
$name=$_POST['name'];
but in the above code name of radio button is not fixed.questions is the table which consists of qid and questions with multiple options that is answer1,answer2 etc
i want to store the option select by user into database.for which i need to know the name of radio button
how should i use post in this case
$name=$_POST['what should go in here'];
You can get the radio button value along with question ID as:
Basic Example:
<?php
$array = array(1,2); // your Question ID array
?>
Your Form:
<form method="post" action="">
<?php
foreach ($array as $key => $qid) {
?>
<input type="radio" value="1" name="radio[<?=$qid?>]">
Answer 1
<input type="radio" value="2" name="radio[<?=$qid?>]">
Answer 2
<input type="radio" value="3" name="radio[<?=$qid?>]">
Answer 3
<input type="radio" value="4" name="radio[<?=$qid?>]">
Answer 4
<?php
echo "<br/>";
}
?>
<input type="submit" name="submit">
</form>
In PHP:
<?php
if(isset($_POST['submit'])) {
$query = array();
foreach ($_POST['radio'] as $key => $value) {
$query[] = "('$value','$key')";
}
$sql = "INSERT INTO table (answer,questionID) VALUES ";
$sql .= implode(",", $query);
echo $sql;
}
?>
In this example query look like:
INSERT INTO table (answer,questionID) VALUES ('2','1'),('3','2')
Few Suggestions:
- Your code is open for SQL Injection, you must need to prevent your code with SQL Attack and this reference will help you to understand: How can I prevent SQL injection in PHP?
- Make sure your column name and table name not having any conflict, currently, you are using same name for both.
Update with Your Code:
<?php
while ($result = mysqli_fetch_array($row))
{
?>
<h2 id="question_<?php echo $result['qid'];?>"><?php echo $result['qid'].".".$result['question'];?></h2>
<input type="radio" value="<?php echo $result['answer1'];?>" name="radio[<?php echo $result['qid'];?>]">
<?php echo $result['answer1'];?>
<input type="radio" value="<?php echo $result['answer2'];?>" name="radio[<?php echo $result['qid'];?>]">
<?php echo $result['answer2'];?>
<input type="radio" value="<?php echo $result['answer3'];?>" name="radio[<?php echo $result['qid'];?>]">
<?php echo $result['answer3'];?>
<input type="radio" value="<?php echo $result['answer4'];?>" name="radio[<?php echo $result['qid'];?>]">
<?php echo $result['answer4'];?>
<?
}
?>
In PHP:
<?php
if(isset($_POST['submit'])) {
$query = array();
foreach ($_POST['radio'] as $key => $value) {
$query[] = "('$value','$key')";
}
$sql = "INSERT INTO table (answer,questionID) VALUES ";
$sql .= implode(",", $query);
echo $sql; // run this query in mysqli_query()
}
?>
Few More Instructions:
- Change the table name as per your table name
- Change the column name according to your column.
- Use INSERT query at once, no need to use it inside the loop.
Create an array at the end of while loop like this :
while ($result = mysqli_fetch_array($row))
{
?>
<h2 id="question_<?php echo $result['qid'];?>"><?php echo $result['qid'].".".$result['question'];?></h2>
<input type="radio" value="<?php echo $result['answer1'];?>" name="<?php echo $result['qid'];?>"><?php echo $result['answer1'];?>
<input type="radio" value="<?php echo $result['answer2'];?>" name="<?php echo $result['qid'];?>"><?php echo $result['answer2'];?>
<input type="radio" value="<?php echo $result['answer3'];?>" name="<?php echo $result['qid'];?>"><?php echo $result['answer3'];?>
<input type="radio" value="<?php echo $result['answer4'];?>" name="<?php echo $result['qid'];?>"><?php echo $result['answer4'];?>
<? $names[] = $result['qid'];
}
if(isset($_POST['submit'])) {
for ($i=0; $i<count($names); $i++) {
if(isset($_POST[$names[$i]]) {
$rate = $_POST[$names[$i]];
$sql ="INSERT INTO answer (answer, qid) VALUES (".$rate.", ".$names[$i] .")";
mysqli_query($con, $sql);
}
}
}
?>
I have an issue where I need to loop the number of check boxes on a form submit. Foreach check box that is looped I need to then insert data into the database.
How Would I go about looping over the amount of check boxes that have being passed via form submit?
My code is as follows:
Form:
<form action="createChallenge.php" method="post" name="chalCreate">
Challenge Name:<input type="text" name="chalName" />
<br />
Challenge Target:<input type="text" name="chalTarget"/>
<br />
End Date:<input type="text" name="chalDate">
<br />
<!-- Needs a jquery datepicker -->
Select Friends: <br />
<?php
$selFriend = $conn->prepare("SELECT * FROM Friends WHERE UserID = '$userID' AND Friend = 'y' ORDER BY FriendName ASC");
$selFriend->execute();
foreach($selFriend as $row){
?>
<input type="checkbox" name="test" value="<?php echo $row['FriendID'] ?>"><?php echo $row['FriendName'] ?><br>
<?php
}
?>
<br />
<button type="submit">Create Challenge</button>
</form>
PHP to handle the form:
<?php
if(isset($_POST['test']))
{
$i = 0;
foreach($_POST['test'] as $checked)
{
echo $friend = $checked;
$i++;
}
echo $name = $_POST['chalName'];
echo $target = $_POST['chalTarget'];
echo $date = $_POST['chalDate'];
echo $friend = $_POST['test'];
echo $setby = $_COOKIE['userID'];
$create = $conn->prepare("INSERT INTO Challenge ( chalSetBy, chalName, chalTarget, chalDate ) VALUES ('$setby', '$name', '$target', '$date') ");
$create->execute();
if($create)
{
echo "Challenge made successfully";
}
else
{
echo "There was a problem";
}
}
?>
I thought doing the following would echo out data, but it didn't, it only selected the last check box:
$i = 0;
foreach($_POST['test'] as $checked)
{
echo $friend = $checked;
$i++;
}
Make an array of your checkbox in HTML page like as below,
<form name="frm" method="post">
<input type="checkbox" value="1" name="test[]">
<input type="checkbox" value="2" name="test[]">
<input type="checkbox" value="3" name="test[]">
<input type="checkbox" value="4" name="test[]">
<input type="checkbox" value="5" name="test[]">
<input type="checkbox" value="6" name="test[]">
<input type="submit">
</form>
<?php
foreach($_POST['test'] as $key=>$value)
{
echo $value."<br>";
}
I have this PHP/HTML Code that is selecting data from a MySQL Database:
<?php
$sql3="SELECT * from property_images where property_seq = '".$property["sequence"]."' ";
$rs3=mysql_query($sql3,$conn);
while($property_img=mysql_fetch_array($rs3))
{
?><tr>
<td colspan="2"><img src="http://domain.co.uk/img/property-images/<?php echo $property_img["image"]; ?>" width="80px" height="80px" /></td>
<td colspan="2"><input type="checkbox" name="image1" value="Y" <?php if($property_img["image1"] == 'Y') { echo 'checked="checked"'; } ?> />
<input type="checkbox" name="image2" value="Y" <?php if($property_img["image2"] == 'Y') { echo 'checked="checked"'; } ?> />
<input type="checkbox" name="image3" value="Y" <?php if($property_img["image3"] == 'Y') { echo 'checked="checked"'; } ?> />
<input type="checkbox" name="image4" value="Y" <?php if($property_img["image4"] == 'Y') { echo 'checked="checked"'; } ?> />
<input type="checkbox" name="image5" value="Y" <?php if($property_img["image5"] == 'Y') { echo 'checked="checked"'; } ?> />
<input type="checkbox" name="image6" value="Y" <?php if($property_img["image6"] == 'Y') { echo 'checked="checked"'; } ?> />
<input type="checkbox" name="image7" value="Y" <?php if($property_img["image7"] == 'Y') { echo 'checked="checked"'; } ?> />
<input type="checkbox" name="image8" value="Y" <?php if($property_img["image8"] == 'Y') { echo 'checked="checked"'; } ?> />
<input type="checkbox" name="image9" value="Y" <?php if($property_img["image9"] == 'Y') { echo 'checked="checked"'; } ?> />
<input type="checkbox" name="image10" value="Y" <?php if($property_img["image10"] == 'Y') { echo 'checked="checked"'; } ?> />
<input type="checkbox" name="image11" value="Y" <?php if($property_img["image11"] == 'Y') { echo 'checked="checked"'; } ?> />
<input type="checkbox" name="image12" value="Y" <?php if($property_img["image12"] == 'Y') { echo 'checked="checked"'; } ?> />
<input type="checkbox" name="image13" value="Y" <?php if($property_img["image13"] == 'Y') { echo 'checked="checked"'; } ?> /></td>
</tr><?php
}
?>
each row, has its own image with the columns image1 - image13
i want to update the table with the checkboxes that are checked and unchecked on the form update
how is this possible?
Thanks
If you mean that you want to update the $property_img["imagexx"] val on db depending on the user click on the checkbox you must use ajax.
Fire an event on triggering each checkbox and send the value to a php page that update the php.
Jquery Ajax function can help you on this task.
L
name all your checkboxes images[]
<input type="checkbox" name="images[]" value="1" />
<input type="checkbox" name="images[]" value="2" />
<input type="checkbox" name="images[]" value="3" />
<input type="checkbox" name="images[]" value="4" />
You can then update with PHP :
<?php
$q = "UPDATE property_images SET";
foreach($_POST["images"] as $image) {
$q .= " image" . $image ." = 'Y', ";
}
$q .= " property_seq = '".$property["sequence"]."' WHERE property_seq = '".$property["sequence"]."'";
mysql_query($q);
?>
First of all, mysql_ functions are deprecated, please google mysqli_ or PDO, mysql_ won't be supported on future versions, and is unsafe, etc
Your html output could be much simpler with a loop, also have an eye on putting the sequence number on a hidden field or something first:
<?php
$sql3="SELECT * from property_images where property_seq = '".$property["sequence"]."' ";
$rs3=mysql_query($sql3,$conn);
while($property_img=mysql_fetch_array($rs3)){
?>
<tr>
<td colspan="2"><img src="http://domain.co.uk/img/property-images/<?php echo $property_img["image"]; ?>" width="80px" height="80px" /></td>
<!-- THIS IS VERY IMPORTANT: send the sequence or ID through a hidden field, to know which row you are gonna update later-->
<input type="hidden" name="sequence" value="<?php echo $property_img['sequence']; ?>"/>
<td colspan="2">
<?php for($i = 1; $i <= 13; $i++): ?>
<input type="checkbox" name="images[]>" value="<?php echo $i; ?>" <?php if($property_img["image$i"] == 'Y') { echo 'checked="checked"'; } ?> />
<?php endfor ?>
</td>
</tr>
<?php
}
?>
Then this is the next page where the update is done, have a good look at the comments:
<?php
//Handle as you want the situation when there are no images selected instead of using an exit(), I used it here just for the quickness;
if(count($_POST['images'] < 1) exit('no images where selected to update');
$images = array();
for($i = 1; $i <= 13; $i++){
$string = "image$i = ";
if(in_array($i, $_POST['images'])){
$string .= "'Y'"; //notice the double quoting here, it's important
} else {
//This updates the table so if it was checked when loaded, but unchecked by the user, this makes the change!
$string .= "'N'";
}
}
//This creates a string like: image1 = 'Y', images2 = 'N', etc...
$images = implode(', ', $images );
//try to sanitize the query first ... I won't cos am just showing you your question xD
$sql = "UPDATE property_images SET $images WHERE property_seq = " . mysql_real_escape_string($_POST[sequence]) . ";
mysql_query($sql,$conn);
?>