how to get data from virtuemart categories tables? - php

hi i need to make a drop down list field in a form (RSForm joomla 2.5), that will drew its values from virtuemart categories names.
i have this block of code that i need to customize to my needs but since i dont know php all my improvisations ended up in fatal error and need to reinstall the form again:(
the name of my table in mysql is xxx_virtuemart_categories_he_il
the names of the categories are listed here category_names
their id's are here virtuemart_category_id
this is the block of code how do i change it?
//<code>
// Prepare the empty array
$items = array();
// Prepare the database connection
$db = JFactory::getDbo();
// Run the SQL query and store it in $results
$db->setQuery("SELECT your_value, your_label FROM #__your_table");
$results = $db->loadObjectList();
// Now, we need to convert the results into a readable RSForm! Pro format.
// The Items field will accept values in this format:
// value-to-be-stored|value-to-be-shown
foreach ($results as $result) {
$value = $result->your_value;
$label = $result->your_label;
$items[] = $value.'|'.$label;
}
// Multiple values are separated by new lines, so we need to do this now
$items = implode("\n", $items);
// Now we need to return the value to the field
return $items;
//</code>

Add:
$db->query();
before:
$results = $db->loadObjectList();

The fast and simple solution to connect to a bd in virtuemart is:
$db = JFactory::getDbo();
$db->setQuery("SELECT * FROM ... WHERE ...");
$db->query();
$results = $db->loadObjectList();
echo var_dump($results);

Related

Why PHP Mysql query inside a foreach loop always returns the first result from database?

I'm trying to run a MYSQL query inside a foreach loop.
here's the scenario:
I have a comma separated string with some names in it.
I use explode() and foreach() to get the separate values/names from this comma separated string.
Then I need to search mysql database for each of these values/names that I get from this string and if that value exists in the database, I then get its ID and create a new recrord in another table in the database.
However, when I run my code, I only get the ID of the first instance from the comma separated string.
my mysql database looks like this:
id category_name
3 Hotel
4 Restaurants
This is my code:
//My comma separated string///
$biz_cat = 'Hotel, Restaurants';
///i do the explode and foreach here///
$arrs = explode(',', $biz_cat);
foreach($arrs as $arr){
$sql99 = "SELECT * FROM categories WHERE category_name='$arr'";
$query99 = mysqli_query($db_conx, $sql99);
while($row99 = mysqli_fetch_array($query99, MYSQLI_ASSOC)){
$catIDS = $row99['id'];
}
//this is where i need to insert my new data in different tabel.
echo $catIDS.'<br>;
}
so when the i run my code, I get the ID of the Hotel twice like so:
3
3
I'm expecting it to be like below based on what I have in MYSQL:
3
4
Could someone please advice on this issue?
First of all such things should be done using prepared statements. Not only it is easier and faster, but also more secure. Remember to always use prepared statements.
//My comma separated string///
$biz_cat = 'Hotel, Restaurants';
$stmt = $db_conx->prepare('SELECT * FROM categories WHERE category_name=?');
$stmt->bind_param('s', $cat);
foreach(explode(',', $biz_cat) as $cat){
$cat = trim($cat); // remove extra spaces at the beginning/end
$stmt->execute();
// we fetch a single row, but if you expect multiple rows for each category name, then you should loop on the $stmt->get_result()
$row99 = $stmt->get_result()->fetch_assoc();
// echo it in the loop or save it in the array for later use
echo $row99['id'];
}
In the example here I prepare a statement and bind a variable $cat. I then explode the string into an array on which I loop straight away. In each iteration I execute my statement, which in turn produces a result. Since you seem to be interested only in the first row returned, we do not need to loop on the result, we can ask for the array immediately. If you would like to loop just replace
$row99 = $stmt->get_result()->fetch_assoc();
with
foreach($stmt->get_result() as $row99) {
echo $row99['id'];
}
Once you get the id in the array, you can either print it out or save it into an array for later use.
As of now, you are re-assigning a new value to scalar variable $catIDS for each record returned by the query, then you echo it one you are done looping. You would need to put the echo/insert logic inside the loop (or maybe store the values in array).
Another thing to note is that you are splitting with , (a single comma), but you have a space between the two words. As a result, the second value (Restaurant) starts with a space, which will cause the query to return an empty resultset. You probably want to split with , (a comma followed by a space).
$biz_cat = 'Hotel, Restaurants';
$arrs = explode(', ', $biz_cat);
foreach($arrs as $arr){
$sql99 = "SELECT * FROM categories WHERE category_name='$arr'";
$query99 = mysqli_query($db_conx, $sql99);
while($row99 = mysqli_fetch_array($query99, MYSQLI_ASSOC)){
$catIDS = $row99['id'];
//this is where i need to insert my new data in different tabel.
echo $catIDS.'<br>';
}
}
The code below can do what you need.
Update INSERT YOUR NEW DATA HERE
$biz_cat = 'Hotel, Restaurants';
$arrs = explode(',', $biz_cat);
foreach ($arrs as $arr) {
$query99 = mysqli_query($db_conx, "SELECT * FROM categories WHERE category_name='$arr'");
while ($row99 = mysqli_fetch_array($query99, MYSQLI_ASSOC)) {
$catIDS = $row99['id'];
// INSERT YOUR NEW DATA HERE
echo $catIDS . '<br/>';
}
}

how to echo multiple DB results with one query

If I were to echo the result of this query:
//Find membertype from community builder
$db->setQuery('Select cb_membertype From #__comprofiler Where id='.$user->id);
$membertype = $db->loadResult(); //load the result from the query
I would use:
echo "Your member type is: $membertype";
I'd rather not use a new query for every variable thought since they are all in the same table.
I'd rather run a single query like this:
//Find all 3 from one query
$db->setQuery('Select cb_membertype, cb_2015vopac, cb_2015llf
From #__comprofiler Where id='.$user->id);
$result = $db->loadResult(); //load the result from the query
How do I echo the specific fields from that query when using the single $result variable?
First, let me just say that should should quote your values/columns/table names.
Secondly, if you want to get multiple values, you need to use loadObjectList instead of loadResult.
The following will do it for you:
$db = JFactory::getDbo();
$query = $db->getQuery(true);
$query->select($db->quoteName(array('cb_membertype', 'cb_2015vopac', 'cb_2015llf')))
->from($db->quoteName('#__comprofiler'))
->where($db->quoteName('id') . ' = '. $db->quote($user->id));
$db->setQuery($query);
$results = $db->loadObjectList();
foreach ($results as $result)
{
echo $result->cb_membertype;
echo $result->cb_2015vopac;
echo $result->cb_2015llf;
}
So loadObjectList give you an object, then you can loop though it using foreach loop.
Hope this helps

Pulling column values from MySQL with PHP

I am trying to get all the values (numeric) of the column Bruel_ID from database mpctz_rsform_bruels to display them in a RSForm dropdown box. I'm using this code:
$db = JFactory::getDbo();
$db->setQuery("SELECT Bruel_ID FROM mpctz_rsform_bruels");
return $db->loadResult();
Howeve, I am only pulling the lowest value of the column. How can I get all the values?
Thanks,
Dani
Edit: I have been searching and I've found this code which was supposed to work:
//<code>
// Prepare the empty array
$items = array();
// Prepare the database connection
$db = JFactory::getDbo();
// Keep this if you'd like a "Please select" option, otherwise comment or remove it
$items[] = "|Selecciona un número[c]";
// Run the SQL query and store it in $results
$db->setQuery("SELECT Bruel_ID, Bruel_ID FROM #__rsform_bruels");
$results = $db->loadObjectList();
// Now, we need to convert the results into a readable RSForm! Pro format.
// The Items field will accept values in this format:
// value-to-be-stored|value-to-be-shown
// Eg. m|M-sized T-shirt
foreach ($results as $result) {
$value = $result->your_value;
$label = $result->your_label;
$items[] = $value.'|'.$label;
}
// Multiple values are separated by new lines, so we need to do this now
$items = implode("\n", $items);
// Now we need to return the value to the field
return $items;
//</code>
However, it displays nothing in the dropdown box, just the default value. Any help?
You can use loadColumn() to get an array of all the result in a single column. The below shows just that and a foreach loop so that each result displays on a new line:
$db = JFactory::getDbo();
$query = $db->getQuery(true);
$query->select($db->quoteName('Bruel_ID'))
->from($db->quoteName('#__rsform_bruels'))
->order($db->quoteName('Bruel_ID') . 'DESC');
$db->setQuery($query);
$results = $db->loadColumn();
$items[] = "|Selecciona un número[c]";
foreach ($results as $id) {
$items[] = $id.'|'.$id;
}
$items = implode("\n", $items);
return $items;
This uses the most up to date Joomla coding standards for a database query.
Also notice I have replaced mpctz_ with #__ which is a built in Joomla feature that will automatically get the table prefix. It saves you having to manually define it which is bad as in the future, you may decide to change the prefixx.
Hope this helps

Read from database, single rows (Joomla framework)

I use this code to read from data base:
$db = JFactory::getDbo();
$query = $db->getQuery(true);
$query->select(array('category_name', 'category_short_description'));
$query->from('#__redshop_category');
$query->where('category_id = 1');
$db->setQuery($query);
$results = $db->loadObjectList();
How can i read once element, for example extra *category_name* and extra *category_short_description*
Here is also offical joomla wiki, but without single output: http://docs.joomla.org/J2.5:Accessing_the_database_using_JDatabase
Here what i have doing, but that's not work:
echo $results; ->output:ARRAY
echo $results['category_name']; -> without output, empty (In database rows are not empty)
How can i do this?
You can use loadObject() instead of loadObjectList() to retrieve just the first row:
$results = $db->loadObject();
echo $results->category_name;
If you want an associative array instead of an object, there is loadAssoc():
$results = $db->loadAssoc();
echo $results['category_name'];
To fetch single row you can use
$result = $db->loadObject()
instead of
$results = $db->loadObjectList()
and then you can access data by
$result->category_name;
$result->category_short_description;

Return a multidimensional array from MySQL result php

I have a PHP function that extract dat of an invoice from DB.
The invoice may have more then one line (one product).
function getInvoiceLines($id)
{
$res = mysql_query("select * from invoice_lines where id = $id ");
while ($row = mysql_fetch_array($res))
{
$res_retun['ref']=$row['ref'];
$res_retun['label']=$row['label'];
$res_retun['price']=$row['label'];
$res_retun['qty']=$row['qty'];
}
return $res_retun ;
}
I found this link Create a Multidimensional Array with PHP and MySQL and I made this code using that concept.
Now, how can I move something like a cursor to the next line and add more lines if there's more in MySQL result??
If it's possible, how can I do to show data in HTML with for ??
A little modification should get what you want, below the [] operator is a shorthand notation to add elements to an array, the problem with your code is that you are overwriting the same keys on each iteration
// fetch only what you need;
$res = mysql_query("select ref, label, price, qty from invoice_lines where id = $id ");
while ($row = mysql_fetch_array($res))
{
$res_return[] = $row;
}
return $res_return;
Note, I fixed some of your typos (you were using $rw instead of $row in the loop of your original code)
If you used PDO with fetchAll() you would be returned with the array your expecting, also be safe from nastys:
<?php //Cut down
$db = new PDO("mysql:host=localhost;dbname=dbName", 'root', 'pass');
$sql = "SELECT * FROM invoice_lines WHERE id = :id ";
$stmt = $db->prepare($sql);
$stmt->bindParam(':id', $id);
$stmt->execute();
$res_return = $stmt->fetchAll(PDO::FETCH_ASSOC);
?>
Then you just loop through the array like with any other array:
<?php
foreach($res_return as $row){
echo $row['ref'];
...
...
}
?>
Also id should not have more then 1 row it should be unique IF its your primary key.
If you were using PDO like you should be it would be super easy and you would solve your sql injection issues
$db = new PDO(...);
function getInvoiceLines( $db, $id )
{
$stmnt = $db->prepare("select ref, label, price, qty from invoice_lines where id=?");
$stmnt->execute( array( $id ) );
return $stmnt->fetchAll( PDO::FETCH_ASSOC );
}
Make variable global first Then access it in function. For exp.
$return_arr = array(); // outside function
$i = 0;
cal_recursive(); // call function first time
function cal_recursive(){
global $return_arr;
global $i;
$return_arr[$i] = // here push value to array variable
$i++;
// do code for recursive function
return $return_arr // after end
}

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