I am trying to get all the values (numeric) of the column Bruel_ID from database mpctz_rsform_bruels to display them in a RSForm dropdown box. I'm using this code:
$db = JFactory::getDbo();
$db->setQuery("SELECT Bruel_ID FROM mpctz_rsform_bruels");
return $db->loadResult();
Howeve, I am only pulling the lowest value of the column. How can I get all the values?
Thanks,
Dani
Edit: I have been searching and I've found this code which was supposed to work:
//<code>
// Prepare the empty array
$items = array();
// Prepare the database connection
$db = JFactory::getDbo();
// Keep this if you'd like a "Please select" option, otherwise comment or remove it
$items[] = "|Selecciona un número[c]";
// Run the SQL query and store it in $results
$db->setQuery("SELECT Bruel_ID, Bruel_ID FROM #__rsform_bruels");
$results = $db->loadObjectList();
// Now, we need to convert the results into a readable RSForm! Pro format.
// The Items field will accept values in this format:
// value-to-be-stored|value-to-be-shown
// Eg. m|M-sized T-shirt
foreach ($results as $result) {
$value = $result->your_value;
$label = $result->your_label;
$items[] = $value.'|'.$label;
}
// Multiple values are separated by new lines, so we need to do this now
$items = implode("\n", $items);
// Now we need to return the value to the field
return $items;
//</code>
However, it displays nothing in the dropdown box, just the default value. Any help?
You can use loadColumn() to get an array of all the result in a single column. The below shows just that and a foreach loop so that each result displays on a new line:
$db = JFactory::getDbo();
$query = $db->getQuery(true);
$query->select($db->quoteName('Bruel_ID'))
->from($db->quoteName('#__rsform_bruels'))
->order($db->quoteName('Bruel_ID') . 'DESC');
$db->setQuery($query);
$results = $db->loadColumn();
$items[] = "|Selecciona un número[c]";
foreach ($results as $id) {
$items[] = $id.'|'.$id;
}
$items = implode("\n", $items);
return $items;
This uses the most up to date Joomla coding standards for a database query.
Also notice I have replaced mpctz_ with #__ which is a built in Joomla feature that will automatically get the table prefix. It saves you having to manually define it which is bad as in the future, you may decide to change the prefixx.
Hope this helps
Related
Good day! I am trying to get the user ids based on the names submitted on the input field. But the loop only returns the user id of the first selected user. Can somebody please help me?
Here's the code:
if(isset($_POST['proponent'])){
$proponent = mysqli_real_escape_string($con,$_POST['proponent']);
$myArray = explode(',', $proponent);
$posts = array();
foreach($myArray as $item) {
$query = "SELECT user_id FROM user WHERE CONCAT(fname, ' ', lname) = '$item'";
$get = mysqli_query($con, $query);
array_push($posts, mysqli_fetch_assoc($get));
print_r($posts);
}
}
Using mysqli_fetch_assoc only once will only get you the first row if it exists. So you will need to add this in a loop, say while loop like below in order for the mysqli_function to move it's pointer over the entire result set.
while($row = mysqli_fetch_assoc($get)){
$posts[] = $row;
}
I'm trying to run a MYSQL query inside a foreach loop.
here's the scenario:
I have a comma separated string with some names in it.
I use explode() and foreach() to get the separate values/names from this comma separated string.
Then I need to search mysql database for each of these values/names that I get from this string and if that value exists in the database, I then get its ID and create a new recrord in another table in the database.
However, when I run my code, I only get the ID of the first instance from the comma separated string.
my mysql database looks like this:
id category_name
3 Hotel
4 Restaurants
This is my code:
//My comma separated string///
$biz_cat = 'Hotel, Restaurants';
///i do the explode and foreach here///
$arrs = explode(',', $biz_cat);
foreach($arrs as $arr){
$sql99 = "SELECT * FROM categories WHERE category_name='$arr'";
$query99 = mysqli_query($db_conx, $sql99);
while($row99 = mysqli_fetch_array($query99, MYSQLI_ASSOC)){
$catIDS = $row99['id'];
}
//this is where i need to insert my new data in different tabel.
echo $catIDS.'<br>;
}
so when the i run my code, I get the ID of the Hotel twice like so:
3
3
I'm expecting it to be like below based on what I have in MYSQL:
3
4
Could someone please advice on this issue?
First of all such things should be done using prepared statements. Not only it is easier and faster, but also more secure. Remember to always use prepared statements.
//My comma separated string///
$biz_cat = 'Hotel, Restaurants';
$stmt = $db_conx->prepare('SELECT * FROM categories WHERE category_name=?');
$stmt->bind_param('s', $cat);
foreach(explode(',', $biz_cat) as $cat){
$cat = trim($cat); // remove extra spaces at the beginning/end
$stmt->execute();
// we fetch a single row, but if you expect multiple rows for each category name, then you should loop on the $stmt->get_result()
$row99 = $stmt->get_result()->fetch_assoc();
// echo it in the loop or save it in the array for later use
echo $row99['id'];
}
In the example here I prepare a statement and bind a variable $cat. I then explode the string into an array on which I loop straight away. In each iteration I execute my statement, which in turn produces a result. Since you seem to be interested only in the first row returned, we do not need to loop on the result, we can ask for the array immediately. If you would like to loop just replace
$row99 = $stmt->get_result()->fetch_assoc();
with
foreach($stmt->get_result() as $row99) {
echo $row99['id'];
}
Once you get the id in the array, you can either print it out or save it into an array for later use.
As of now, you are re-assigning a new value to scalar variable $catIDS for each record returned by the query, then you echo it one you are done looping. You would need to put the echo/insert logic inside the loop (or maybe store the values in array).
Another thing to note is that you are splitting with , (a single comma), but you have a space between the two words. As a result, the second value (Restaurant) starts with a space, which will cause the query to return an empty resultset. You probably want to split with , (a comma followed by a space).
$biz_cat = 'Hotel, Restaurants';
$arrs = explode(', ', $biz_cat);
foreach($arrs as $arr){
$sql99 = "SELECT * FROM categories WHERE category_name='$arr'";
$query99 = mysqli_query($db_conx, $sql99);
while($row99 = mysqli_fetch_array($query99, MYSQLI_ASSOC)){
$catIDS = $row99['id'];
//this is where i need to insert my new data in different tabel.
echo $catIDS.'<br>';
}
}
The code below can do what you need.
Update INSERT YOUR NEW DATA HERE
$biz_cat = 'Hotel, Restaurants';
$arrs = explode(',', $biz_cat);
foreach ($arrs as $arr) {
$query99 = mysqli_query($db_conx, "SELECT * FROM categories WHERE category_name='$arr'");
while ($row99 = mysqli_fetch_array($query99, MYSQLI_ASSOC)) {
$catIDS = $row99['id'];
// INSERT YOUR NEW DATA HERE
echo $catIDS . '<br/>';
}
}
If I were to echo the result of this query:
//Find membertype from community builder
$db->setQuery('Select cb_membertype From #__comprofiler Where id='.$user->id);
$membertype = $db->loadResult(); //load the result from the query
I would use:
echo "Your member type is: $membertype";
I'd rather not use a new query for every variable thought since they are all in the same table.
I'd rather run a single query like this:
//Find all 3 from one query
$db->setQuery('Select cb_membertype, cb_2015vopac, cb_2015llf
From #__comprofiler Where id='.$user->id);
$result = $db->loadResult(); //load the result from the query
How do I echo the specific fields from that query when using the single $result variable?
First, let me just say that should should quote your values/columns/table names.
Secondly, if you want to get multiple values, you need to use loadObjectList instead of loadResult.
The following will do it for you:
$db = JFactory::getDbo();
$query = $db->getQuery(true);
$query->select($db->quoteName(array('cb_membertype', 'cb_2015vopac', 'cb_2015llf')))
->from($db->quoteName('#__comprofiler'))
->where($db->quoteName('id') . ' = '. $db->quote($user->id));
$db->setQuery($query);
$results = $db->loadObjectList();
foreach ($results as $result)
{
echo $result->cb_membertype;
echo $result->cb_2015vopac;
echo $result->cb_2015llf;
}
So loadObjectList give you an object, then you can loop though it using foreach loop.
Hope this helps
hi i need to make a drop down list field in a form (RSForm joomla 2.5), that will drew its values from virtuemart categories names.
i have this block of code that i need to customize to my needs but since i dont know php all my improvisations ended up in fatal error and need to reinstall the form again:(
the name of my table in mysql is xxx_virtuemart_categories_he_il
the names of the categories are listed here category_names
their id's are here virtuemart_category_id
this is the block of code how do i change it?
//<code>
// Prepare the empty array
$items = array();
// Prepare the database connection
$db = JFactory::getDbo();
// Run the SQL query and store it in $results
$db->setQuery("SELECT your_value, your_label FROM #__your_table");
$results = $db->loadObjectList();
// Now, we need to convert the results into a readable RSForm! Pro format.
// The Items field will accept values in this format:
// value-to-be-stored|value-to-be-shown
foreach ($results as $result) {
$value = $result->your_value;
$label = $result->your_label;
$items[] = $value.'|'.$label;
}
// Multiple values are separated by new lines, so we need to do this now
$items = implode("\n", $items);
// Now we need to return the value to the field
return $items;
//</code>
Add:
$db->query();
before:
$results = $db->loadObjectList();
The fast and simple solution to connect to a bd in virtuemart is:
$db = JFactory::getDbo();
$db->setQuery("SELECT * FROM ... WHERE ...");
$db->query();
$results = $db->loadObjectList();
echo var_dump($results);
I have a mysql table with columns id, f1, f2, f3, ..., f20 where id is productID and f1,...f20 are product features. Depending on each product, some might have all, none or only some columns filled.
Each column holds a delimited string like a#b#c#d where a,b,c,d are values in different languages (a=english, b=french etc)
I need to select a row by it's id, explode each column's value (f1,f2...) with '#' in order to get the language part I need and then pass the values to an array in order to use in my product spec page.
How do I loop through the fetched row (i'm using $row = my_fetch_array) and put the exploded value into a one dimension array like $specs=('green', 'M', '100', 'kids'...) etc?
PS:I know, is complicated but I cant come up with a better idea right now.
Try this:
$result = mysql_query("...");
while ($row = mysql_fetch_array($result, MYSQL_NUM)) {
$arr = array();
foreach ($row as $k=>$v)
{
$features = explode("#", $v);
$value = $features[1]; // get the specific language feature
$arr[] = $value;
}
$specs = join(", " , $arr);
}
Not sure this is the best way togo but you could define an array with your langs, then access the result by lang
<?php
$langs=array('eng'=>0,'fr'=>1,'ger'=>2,'geek'=>3);
while ($row=mysql_fetch_assoc($result)) {
$specs=explode('#',$row['f1']);
$other=explode('#',$row['f2']);
...
}
//Get lang from cookie that you could set elsewhere
$lang=(isset($_COOKIE['lang']))?$_COOKIE['lang']:'eng';
echo $specs[$langs[$lang]];
?>
My solution for how I understand you question:
// Make a MySQL Connection
$sQuery = "SELECT f1,f2,... FROM table WHERE id = ...";
$oResult = mysql_query($sQuery) or die(mysql_error());
//Fetch assoc to use the column names.
$aRow = mysql_fetch_assoc($oResult);
//Prepare the product properties array
$aProductProperties = array("English"=>array(),"French"=>array(),"Dutch"=>array());
//Loop over all the columns in the row
foreach($aRow as $sColName=>$sColVal){
//Explde the column value
$aExplodedCol = explode("#",$sColVal);
//The code below could be nicer when turned into a looped that looped over every language,
//But that would make the code less readable
$aProductProperties['English'][$sColName] = $aExplodedCol[0];
$aProductProperties['French'][$sColName] = $aExplodedCol[1];
$aProductProperties['Dutch'][$sColName] = $aExplodedCol[2];
}
//Done, you should now have an array with all the product properties in every language