i am going to create a live score board using php and mysql. But i want to create a json file which update automatically whenever i update my table on database. i mean new scores added in tables should be added in my json file. Really confused. sorry for not having any program. hope for some solutions. Thank you. i have some code which i have used to insert in database.
$data = array(
'name' => $name,
'score' => $score,
'comment' => $comment
);
$result=$this->db->insert('score', $data);
Do not quite understand what you want, I developed this code, see if it is what you need.
https://gist.github.com/juniorb2ss/7431040
Example:
public function __construct()
{
$this->load->helper('json');
}
public function index()
{
$data = array(
'name' => $name,
'score' => $score,
'comment' => $comment
);
save($data);
$result = $this->db->insert('score', $data);
}
File is created in folder application/cache/score.cache. Content is all scores the application.
You can enter a new score or update, the file will be updated.
Example cache content:
{"teste":{"name":"teste","score":"32","comment":"score comment"}}
The most direct solution would be to dump the whole of your score table as a JSON object on each insert. The problem with this approach is that if you have a large amount of data, on each insert you'll be selecting a lot of data.
function SelectScores()
{
$query = $this->db->query('SELECT * FROM score');
return $query->result();
}
You can then json_encode this result and save as file.
Related
I've an existing form which is passing the input data to the model in an array format. $postdata has all the data from the view and sending to model.
Controller:
$inquiry_id = $this->input->post('inquiry_id');
$postdata = $this->input->post();
$this->load->model('Design_model');
$this->Design_model->insertdata($postdata,$inquiry_id);
Model:
function insertdata($data = array(), $inquiry_id){
$sql = $this->db->query("select * from design where inquiry_id='".$inquiry_id."'");
if($sql->num_rows() == 0){
$sql_query = $this->db->insert('design', $data);
}
else{
$this->db->where('inquiry_id', $inquiry_id);
$this->db->update('design', $data);
}
}
Above is working fine. Now, I'd like to add few fields in the view and save in a different database table. Need to exclude the new field values from $postdata array getting saved. Need to find the best approach to do this. I can start with some name for all the new fields, so that we can add any filter if available to exclude from the $postdata.
You can use elements() function from Array helper.
$array = array(
'id' => 101,
'title' => 'example',
'desc' => 'something',
'unwanted' => 'bla bla'
);
$filtered_array = elements(array('id','title','desc'),$array); //you can use this directly to the post data
$this->Design_model->insertdata($filtered_array,$inquiry_id);
You can use array_merge() or array_push() functions to add new fields to the array.
Let's say you have following data
$postdata = array("name"=>"xyz",
"email"=>"xyz#gmail.com",
"age"=>"40",
"gender"=>"Male",
"occupation"=>"Engineer"
);
Of which first 3 records are from old fields and last 2 are from new fields as you saying.
You need to find last index of first set i.e. '3' Now you can do this.
$firstDb = array_splice($postdata,0,3); //here 3 is index we are using to get first 3 records from $postdata
$secondDb = array_slice($postdata,0,3); //here 3 is index we are using to get records from position 3 from $postdata
Output:
$firstDb = array("name"=>"xyz","email"=>"xyz#gmail.com","age"=>"40");
$secondDb = array("gender"=>"Male","occupation"=>"Engineer");
Now you can insert you records as you wish to. Happy coding
I am using the Firebase PHP Admin SDK: https://firebase-php.readthedocs.io/en/stable/realtime-database.html#update-specific-fields
Here is the example it gives to update specific fields:
$uid = 'some-user-id';
$postData = [
'title' => 'My awesome post title',
'body' => 'This text should be longer',
];
// Create a key for a new post
$newPostKey = $db->getReference('posts')->push()->getKey();
$updates = [
'posts/'.$newPostKey => $postData,
'user-posts/'.$uid.'/'.$newPostKey => $postData,
];
$db->getReference() // this is the root reference
->update($updates);
From that, I created a users class and in that I have an update function. Like so:
public function update() {
$data = array('users' => array('1' => 'David'));
$this->database->getReference()->update($data);
return true;
}
In my database I have this structure:
Now if I run that function $users->update();
It removes the other child and only leaves David. Like so:
How can I update only a specific value of a specified key without it overriding the other data?
There's nothing specific to PHP here. That's the way Realtime Database update operations work. If you want a minimal update, you have to target the deepest key that you want to update. In your case, since you're storing an array type object, the keys are the number indexes of the array items you've written. If you want to modify one of them, you need to build a reference that includes the child number you want update. In that case, none of the sibling values will be touched.
Try this instead:
$this->database->getReference('users')->update(array('1' => 'David'));
Notice here that the update is rooted at "users", and you're updating just the immediate child "1" of that.
The example on docs is a little bit hard to grasp as a beginner. I have made it simpler for you to understand.
Once you get the newPostKey, prepare the url for child and run the code. It will only change the specific fields.
$ref = 'users/' . $newPostKey;
$updates = [
'title' => 'Updated title',
'body' => 'Updated body text',
];
$set = $db->getReference($ref)->update($updates);
I'm making a project where a user can publish/post their own stories and read others' stories. Very simple.
This is my controller method named publish:
public function published()
{
$story = array('author' => $this->session->userdata('username'),
'title' => $this->input->post('title'),
'synopsis' => $this->input->post('synopsis'));
$new_storyid = $this->story_model->new_story($story);
if($new_storyid != NULL)
{
$genre = $this->input->post('genre');
for($temp=0;$temp<count($genre);$temp++)
{
$genres[$temp] = array('story_id' => $new_storyid,
'story_genre_name' => $genre[$temp]);
}
$insert_genre = $this->story_model->new_story_genre($genres);
$tag = $this->input->post('tags');
for($temp=0;$temp<count($tag);$temp++)
{
$tags[$temp] = array('story_id' => $new_storyid,
'story_tag_name' => $tag[$temp]);
}
$content_warning = $this->input->post('content_warning');
for($temp=0;$temp<count($content_warning);$temp++)
{
$content_warnings[$temp] = array('story_id' => $new_storyid,
'story_content_warning_name' => $content_warning[$temp]);
}
//$chapter = array('story_id' => $new_storyid,
//'chapter_number' => 1, 'chapter_title' => $this->input->post('chapter_title'),
//'chapter_content' => $this->input->post('chapter_content'),
//'chapter_number' => 1, 'date_added' => mdate('%Y-%m-%d %h-%i-%s',time()));
//$result = $this->story_model->add_chapter($chapter);
//if($result){
//redirect('account/userprofile_published_stories');}
}
}
This is my model methods for the above controller method:
public function new_story($story)
{
$this->db->select('user_id');
$query = $this->db->get_where('users',array('username' => $story['author']))->result();
foreach($query as $row)
{ $userid = $row->user_id; }
$publish = array('user_id' => $userid,
'story_title' => $story['title'],
'synopsis' => $story['synopsis']);
$this->db->insert('story',$publish);
return $this->db->insert_id();
}
public function new_story_genre($genre)
{
foreach($genre as $row)
{
$this->db->insert('story_genre', $row);}
}
public function add_chapter($chapter){
$this->db->where('story_id', $chapter['story_id']);
return $this->db->insert('chapters', $chapter);
}
I haven't added the other 2 functions for my tags and content warning inserts because i am confused right now. It all works fine, my genre is inserted.
My tables looks like this:
Story tables
In inserting a story in my above method, the first thing i do is insert a new story row in my story table and returns the new_storyid variable.
after that with the new storyid i add the genre,tags,content warning then the chapters.
My question is, what should i return in my methods for inserting the genre,tags,contentwarning?
I forgot this part because every model method ive written so far always returns a variable i needed in my controller. My first thought was to return a TRUE/FALSE variable if insert is successful/fail but barring special circumstances since ive already processed the data its 100% sure to insert successfully. Should i be returning TRUE/FALSE and adding an if statement like:
if($insert_genre){
//insert tags here
if($insert_tags){
//insert content warning here
if($insert_content_warning){
//insert chapters here
//redirect to view here
}
}
}
Or can i just not return anything? and if so, is this a proper/right way?
EDIT: I forgot to mention i haven't yet added form_validation rules before all the inserts. So my function will be nested in multiple if statements.
I just edited my model method:
public function new_story_genre($genre){
$inserted = 0;
foreach($genre as $row){
$this->db->insert('story_genre', $row);
$inserted += $this->db->affected_rows();}
if($inserted == count($genre)){
return TRUE;}else{ return FALSE; }
}
Above compares the number of inserted rows with the number of rows passed into the method. Everytime a row is inserted it adds 1 to the inserted variable. So if my controller passes 3 rows into the method, the inserted variable should also be 3 for a successful insert.
I think you are correct in always returning something. Errors can and do happen for whatever reason, and its a good idea to account for them even if you already validated your data (you never know). Coding practices suggest that more than a couple of nested ifs is bad practice. A personal preference of mine is to check for failure rather than success all the way down the chain until the last lines of the function (if it got that far than everything is good to go).
A scheme like this I usually use:
public function something() {
if (!$insert_genre) {
// add flash error message
// redirect to controller
}
if (!$insert_tags) {
// add flash error message
// redirect to controller
}
if (!$insert_content_warning) {
// add flash error message
// redirect to controller
}
// yay, something went right!
}
In this kindof circumstance it is very procedural. The most important conditions should be first, and if C depends on A, then A should be the first condition.
Unrelated:
It is hard to follow some of your text here, but it also seems like you should look into how you are doing the genres. If the entered genre already exists in the database do you really need to add it? Shouldn't you just use a relationship there storing the id in the main table and joining when displaying?
I’m trying to display two columns in my table view, one being a title of the document, the next being a description of the document. I have a column in the particular table which I am selecting named “filename” that stores the name of the uploaded document which is associated with it’s title and description.
I’m curious as to how I would manage to display only the title and description, while setting the data contained in the “filename” column as the hyperlink value of the title? (Basically, I’m wanting them to be able to download a document once they click on it’s name)
I’m fairly certain that I can pull this off by manually by skipping the table generator and doing a “foreach” in the view to print out all the data from the resultset, but I’m open to suggestions, as this would make for sloppy code. Here’s a snippet of my controller below.
<?php
class blah extends CI_Controller {
public function troubleshooting() {
$this->load->library('pagination');
$this->load->library('table');
$config['base_url'] = 'http://somewebsite.com/troubleshooting';
$config['total_rows'] = $this->db->get('document')->num_rows();
$config['per_page'] = 10;
$config['num_links'] = 10;
$this->pagination->initialize($config);
$data['records'] = $this->db->get('document', $config['per_page'],$this->uri->segment(3));
$this->db->select('doc_title, filename, description, category_id, product_id');
$this->db->where('category_id = 1');
$this->db->where('product_id = 1');
$this->db->order_by('doc_title', 'asc');
$this->load->view('blah/troubleshooting.php', $data);
}
}
You can create the link in your query with a select->(CONCAT(...), FALSE) query.
http://codeigniter.com/forums/viewthread/105687/#531878
** UPDATE **
Well, your table helper is going to receive an array - and your db query is going to return an array. So, you have to create your query in a way that will create your array the way you need it for the table helper.
You need something like this:
$records = [
'doc_title' => 'My Title',
'filename' => 'filename.php',
'description' => 'My description text here.',
'category_id' => 5,
'product_id' => 56
]
Your query might look like this:
$this->db->select('doc_title');
$this->db->select('CONCAT("<a href=path/to/'.filename.'>".'filename'."</a>")', FALSE);
$this->db->select('description, category_id, product_id');
$this->db->where('category_id = 1');
$this->db->where('product_id = 1');
$this->db->order_by('doc_title', 'asc');
$records = $this->db->get('document', $config['per_page'],$this->uri->segment(3));
The trick is your CONCAT function will have some 'quote' issues. Without actually testing this myself, I'm not sure I've got the quotes right. Take a look at some docs there and that should help: http://dev.mysql.com/doc/refman/5.0/en/string-functions.html#function_concat
I'm starting out using the Zend Framework and have created a suitable model which saves data back to a database table. The issue I am having is that the sql statement is trying to insert '?' as the value for each column in the database. I have created the following save function which passes an array of data to the DBtable adapter functions:
public function save() {
$data = $this->getData();
if ($data['pageId']==0) {
$this->getDbTable()->insert($data);
} else {
$this->getDbTable()->update($data, array('pageId = ?' => $data['pageId']));
}
}
This seems to go through the appropriate motions but the item is not added to the database and the sql statement within MySql logs looks something like:
insert into DB_Table ('pageId','title','body') values ('?', '?', '?');
Not quite sure where this is falling down, any pointers would be gratefully received.
Thanks
Data should be in next format:
$data = array(
'pageId' => 1,
'title' => 'title',
'body' => 'body'
);
Are you sure that $this->getDbTable() returns your db adapter?
Try to use:
$db = new Zend_Db_Table('table_name');
$db->insert($data);