I have a mysql query in which I group each post by the date is was posted. I want to be able to echo the amount of posts that happened each day, know a way?
Here is what I've written so far which does post a new <div> for each day it was posted.
$trendQuery = "
SELECT DATE(timestamp) AS ForDate,
COUNT(*) AS NumPosts
FROM trends
WHERE `trend` = '" . $_GET['graph'] . "'
GROUP BY DATE(timestamp)
ORDER BY ForDate
";
$result = mysql_query($trendQuery);
while ($row = mysql_fetch_array($result)) {
echo'
<div>
<p>Here is where I want to say how many posts that happened!</p>
</div>
';
}
You have your query pretty much set up. To echo the results, you simply need to refer the columns with the alias name, in your case ForDate and NumPosts
$trendQuery = "
SELECT timestamp AS ForDate,
COUNT(*) AS NumPosts
FROM trends
WHERE `trend` = '" . $_GET['graph'] . "'
GROUP BY timestamp
ORDER BY ForDate
";
$result = mysql_query($trendQuery);
while ($row = mysql_fetch_array($result)) {
echo'
<div>
Date: '.$row['ForDate'].' ---- Number of Posts: '.$row['NumPosts'].'<br />
</div>
';
Create a view of your trend query and inner join it with "Select (Id or day that you want to merge) From trend"
i hope that helps
Related
I am trying to make a members page. For the rank it shows numbers so I made another table that has the rank id (1,2,3 etc) and added a name to it also.
Here is my code.
<?php
$getCoB = mysql_query("SELECT * FROM `members`
WHERE `CoB` = '1' && `user_state` = '1' ORDER BY `id`");
$id = ($getCoB['rank']);
$rankInfo = mysql_query("SELECT * FROM `ranks` WHERE `id` = '".$id."'");?>
<h2 class="title">Council of Balance members</h2>
<style>tr:nth-of-type(odd) { background-color:#F0F0F0;}</style>
<div style='padding:5px;'>
<?php
if(mysql_num_rows($getCoB) == 0)
{
echo "There are no Council of Balance members.";
} else {
echo "<table cellpadding=20 width=100%>";
while($row = mysql_fetch_assoc($getCoB))
{
echo "<tr><td style='background-color:transparent;'><b>". $row['name']
. "</b></td><td>Rank: ".$rankInfo['name']." <br/> Role: ". $row['role']."</td>";
}
echo "</table>";
}
?>
The problem is rankInfo['name'] is not showing up. I tried to do something on this line while($row = mysql_fetch_assoc($getCoB)) and tried to make it something like this while($row = mysql_fetch_assoc($getCoB)) || while($rank = mysql_fetch_assoc($rankInfo) and changed this part <td>Rank: ". $rankInfo['name'] . " to this <td>Rank: ". $rank['name'] . " but I end up with an error. If I leave it like it is, it just shows Rank: without the name I added into my database.
You can combine your two queries into one using an inner join.
<?php
$getCoB = mysql_query("SELECT m.name as member_name, m.role, r.name as rank_name
FROM `members` as m INNER JOIN `ranks` as r ON m.rank = r.id
WHERE `CoB` = '1' && `user_state` = '1' ORDER BY m.id");
?>
Because of how INNER JOIN works, this will only display members who have corresponding records in the ranks table. If there are some members that you want to display that have no rank record, use LEFT JOIN instead.
Then when you echo out the data, be sure to refer to the item you have fetched ($row) each time. In your code, you are referring to $rankInfo['name'], where $rankInfo is not a variable, but a mysql query from which no rows have been fetched.
while($row = mysql_fetch_assoc($getCoB)) {
echo "<tr><td style='background-color:transparent;'><b>". $row['member_name']
. "</b></td><td>Rank: ". $row['rank_name'] . " <br/> Role: " . $row['role'] . "</td>";
}
Using legacy code which uses mysql instead of mysqli/pdo so don't worry about this, I'll update the queries for this later.
Even though my current method works, I'm positive there is a cleaner way of doing this rather than a query and 3 subqueries. I mainly want to learn how to better enhance my queries and minimizing the amount of them.
What I'm trying to do is
echo out all the data for each date with the date displayed on top
Display the count of entries for each user on that particular day next to the user
For each date, at the bottom of the above 2 bits of data, display the user/s with the highest number of entries
$query = mysql_query('SELECT * FROM entries GROUP BY DATE(dt)');
$g = 0;
while ($row = #mysql_fetch_array($query))
{
$group[$g] = date('y-m-d', strtotime($row['dt']));
echo $group[$g] . "<br />";
//display the person's name for today with their count
$dayquery = mysql_query('SELECT *, COUNT(username) as total FROM entries WHERE DATE(dt) = "'.$group[$g].'" GROUP BY username ORDER BY COUNT(username) DESC');
while ($today = #mysql_fetch_array($dayquery))
{
echo $today['first_name'] . " | " . $today['total'] . "<br />";
}
//display the highest count for today
$topquery = mysql_query('SELECT COUNT(username) as highest FROM entries WHERE DATE(dt) = "'.$group[$g].'" GROUP BY username ORDER BY COUNT(username) DESC LIMIT 1');
while ($toptoday = #mysql_fetch_array($topquery))
{
echo "Highest today: " . $toptoday['highest'] . "<br /><br />" ;
}
//display the users with the highest count for today
echo "Highest users: ";
$userstopquery = mysql_query('SELECT *, COUNT(username) as total FROM entries WHERE DATE(dt) = "'.$group[$g].'" AND COUNT(username) = "' . $toptoday['highest'] . '" AND GROUP BY username');
while ($topusers = #mysql_fetch_array($userstopquery))
{
echo $topusers['first_name'] . "<br />" ;
}
$g++;
}
The trouble I'm having is that when I try and reduce these subqueries and use MAX it will only output the highest count but not all the data for each date, which is what I need, including output of the user/s with the most amount of entries for that given day.
You could start with something like this. Note that I'm not using PHP's mysql_ API as it was deprecated 3 or 4 years ago...
require('path/to/mysqli/connection/stateme.nts');
$array = array();
$query = "
SELECT e.dt
, e.username
, COUNT(*) ttl
FROM entries e
GROUP
BY e.dt
, e.username
ORDER
BY e.dt, ttl DESC;
";
$result = mysqli_query($conn,$query);
while ($row = mysqli_fetch_assoc($result))
{
$array[] = $row;
}
print_r($array);
I have a left join, code shown below that takes,
id
referrer
search term
client_id
From table 1 and then takes the following columns from table 2 using the left join query underneath.
client_id
visit_id
timedate
url1
$query = "SELECT table1.id, table1.search_term, table1.referrer, table1.client_id, table2.client_id, table2.url1, table2.visit_id, table2.timedate ".
"FROM table1 LEFT JOIN table2 "
"ON table1.id = table2.visit_id WHERE table1.ip_address = '$ip_address' AND table1.client_id='$client_id' Group BY visit_id, timedate";
$result = mysql_query($query) or die(mysql_error());
while($row = mysql_fetch_array($result)){ ?>
<div id=''>
<?php "<br />";
echo $row['referrer']. " - ". $row['search_term'];
echo $row['timedate']. " - ". $row['url1']. " - ". $row['visit_id'];
echo "<br />"; ?>
</div>
<?php
}
What I am trying to do is format the rows so the referrer and search term only shows once and not on every line so that the results would look like this.
Referrer Search term
timedate url1 1
timedate Url1 1
timedate url1 1
referrer Search Term
timedate Url1 2
timedate Url1 2
timedate Url1 2
the numbers 1 and 2 are to represent different visit id's by which the results are grouped. At the moment i get the referrer and search term after every row because it is in the loop and understand that. Just don't know if i can show the referrer and searc term just once per group of results.
You have to save the current pending referrer-searchterm combination and check if it changes, if yes, print out the referrer-searchterm line:
$query = "SELECT table1.id, table1.search_term, table1.referrer, table1.client_id, table2.client_id, table2.url1, table2.visit_id, table2.timedate ".
"FROM table1 LEFT JOIN table2 "
"ON table1.id = table2.visit_id WHERE table1.ip_address = '$ip_address' AND table1.client_id='$client_id' Group BY visit_id, timedate" .
"ORDER BY referrer, search_term";
$result = mysql_query($query) or die(mysql_error());
$currentReferrerSeatchTerm = null;
while($row = mysql_fetch_array($result)){
$newReferrerSearchTerm = $row['referrer']. " - ". $row['search_term'];
echo '<div id=""><br>';
if($currentReferrerSeatchTerm != $newReferrerSearchTerm){
echo $newReferrerSearchTerm . '<br>';
$currentReferrerSeatchTerm = $newReferrerSearchTerm
}
echo $row['timedate']. " - ". $row['url1']. " - ". $row['visit_id'];
echo '<br></div>';
}
I usually set a var to store the referrer then check that on each loop through. If it's the same as the previous, do nothing. If it's different, display the new header info (referrer & search_term in your case) and then update the var.
$query = "SELECT table1.id, table1.search_term, table1.referrer, table1.client_id, table2.client_id, table2.url1, table2.visit_id, table2.timedate ".
"FROM table1 LEFT JOIN table2 "
"ON table1.id = table2.visit_id WHERE table1.ip_address = '$ip_address' AND table1.client_id='$client_id' Group BY visit_id, timedate";
$result = mysql_query($query) or die(mysql_error());
$prevRef = '';
while($row = mysql_fetch_array($result)){ ?>
<div id=''>
<?php "<br />";
if($prevRef != $row['referrer']) {
echo $row['referrer']. " - ". $row['search_term'];
$prevRef = $row['referrer'];
}
echo $row['timedate']. " - ". $row['url1']. " - ". $row['visit_id'];
echo "<br />"; ?>
</div>
<?php
}
The following query works, but for some reason the first select statement is the only URL being displayed. Items from other tables are displayed, however, their URL is wrong.
$sql = "(SELECT postsID as postsID, postsSubject AS postsSubject, postsTimestamp AS timestamp
FROM posts
WHERE postsCategory = '$id')
UNION
(SELECT eventID as eventID, eventTitle as eventTitle, eventsTimestamp as timestamp
FROM events
WHERE eventLocation = '$id')
ORDER BY timestamp DESC";
The information is being correctly displayed from both the events and posts table, but the results are appearing to ONLY come from the posts table.
For example, say I have the following info
postsID | postsSubject | postsTimestamp
1 post 123
eventID | eventTitle | eventsTimestamp
2 event 456
I have the following to display my results
while($row = mysql_fetch_assoc($result)){
?>
<tr><td><? echo '' . $row['eventTitle'] . '' ; ?></td>
<tr><td><? echo '' . $row['postsSubject'] . '' ; ?></td>
<?
if(preg_match('/[0-9]/',$row['timestamp'])){
list($yyyy,$dd,$mm) = explode('-',$row['timestamp']);
$newDate = $dd."-".$mm."-".$yyyy;
}
?>
<td><center><? echo $newDate; ?></center></td></tr>
<?
}
echo '</table>';
}
The output appears to be correct
post 123
event 456
However, both results link to the following (respectively)
viewpost.php?id = 1
viewpost.php?id = 2 //this should be viewevent.php
sql as below:
$sql = "(SELECT postsID as ids, postsSubject AS description, postsTimestamp AS timestamp,'p' as status
FROM posts
WHERE postsCategory = '$id')
UNION
(SELECT eventID as ids, eventTitle as description, eventsTimestamp as timestamp, 'e' as status
FROM events
WHERE eventLocation = '$id')
ORDER BY timestamp DESC";
when retrieving data,
while($row = mysql_fetch_assoc($result)){
if ($row['status']=="e"){
?>
<tr><td><? echo '' . $row['description'] . '' ; ?></td>
<? }else{?>
<tr><td><? echo '' . $row['description'] . '' ; ?></td>
<? } ?>
<?
if(preg_match('/[0-9]/',$row['timestamp'])){
list($yyyy,$dd,$mm) = explode('-',$row['timestamp']);
$newDate = $dd."-".$mm."-".$yyyy;
}
?>
<td><center><? echo $newDate; ?></center></td></tr>
<?
}
echo '</table>';
}
A union/union all brings the rows together in one table, using the columns from the first table. So, the result set has a PostsId, but no EventsId.
Perhaps you want a join, which will put the columns side-by-side. Perhaps you want to run this as two separate queries.
Here is the example:
$sql = "select *
from (SELECT postsID as postsID, postsSubject AS postsSubject, postsTimestamp AS timestamp
FROM posts
WHERE postsCategory = '$id') p
cross join
(SELECT eventID as eventID, eventTitle as eventTitle, eventsTimestamp as timestamp
FROM events
WHERE eventLocation = '$id') e
ORDER BY postsTimeStamp DESC"
Do note that this is producing a cartesian product. So, if there are more rows from one of the tables, then you will get a proliferation of rows.
I have a MySQL database called "bookfeather" with several tables that contain list books. Under each table, each book has a given number of votes. The PHP code below allows the user to enter in a book title ($entry), and then returns the total number of votes that book has in all tables ($sum).
How could I use PHP to make a 2-column, 25-row table that lists the 25 books in the database with the highest value for $sum (in descending order)?
Thanks in advance,
John
mysql_connect("mysqlv10", "username", "password") or die(mysql_error());
mysql_select_db("bookfeather") or die(mysql_error());
// We preform a bit of filtering
$entry = strip_tags($entry);
$entry = trim ($entry);
$entry = mysql_real_escape_string($entry);
$result = mysql_query("SHOW TABLES FROM bookfeather")
or die(mysql_error());
$table_list = array();
while(list($table)= mysql_fetch_row($result))
{
$sqlA = "SELECT COUNT(*) FROM `$table` WHERE `site` LIKE '$entry'";
$resA = mysql_query($sqlA) or die("$sqlA:".mysql_error());
list($isThere) = mysql_fetch_row($resA);
$isThere = intval($isThere);
if ($isThere)
{
$table_list[] = $table;
}
}
//$r=mysql_query("SELECT * , votes_up - votes_down AS effective_vote FROM `$table[0]` ORDER BY effective_vote DESC");
if(mysql_num_rows($resA)>0){
foreach ($table_list as $table) {
$sql = "SELECT votes_up FROM `$table` WHERE `site` LIKE '$entry'";
$sql1 = mysql_query($sql) or die("$sql:".mysql_error());
while ($row = mysql_fetch_assoc($sql1)) {
$votes[$table] = $row['votes_up'];
$sum += $row['votes_up'];
//echo $table . ': "' . $row['votes_up'] . " for $entry from $table\"<br />";
}
}
}
else{
print "<p class=\"topic2\">the book \"$entry\" has not been added to any category</p>\n";
}
//within your loop over the DB rows
//$votes[$table] = $row['votes_up'];
//afterwards
if($sum>0){
print "<table class=\"navbarb\">\n";
print "<tr>";
print "<td class='sitenameb'>".'<a type="amzn" category="books" class="links2b">'.$entry.'</a>'."</td>";
print "</tr>\n";
print "</table>\n";
//echo "<p class=\"topic3\">".''.$entry.''. "</p>\n";
echo "<p class=\"topic4\">". number_format($sum) . ' votes in total.'."</p>\n";
Try something like this. All of this hasn't been tested so please add comments for changes. I'll work with you to get the code right.
// After getting your array of tables formated like
$tableArray = array("`tableA`", "`tableB`", "`tableC`");
// create a table statement
$tableStatement = implode(", ", $tableArray);
// create a join statement
$joinStatement = "";
for ($i = 1; $i < count($tableArray); $i++) {
if ($joinStatement != "")
$joinStatement .= " AND ";
$joinStatement .= $tableArray[0] . ".site = " . $tableArray[$i] . ".site"
}
$firstTable = $tableArray[0];
$sql = "SELECT SUM(votes_up) FROM " . $tableStatement . " WHERE " . $joinStatement . " AND " . $firstTable . ".site LIKE '" . $entry . "' GROUP BY " . $firstTable . ".site ORDER BY SUM(votes_up) DESC";
Edit --------
I now realize that the query above won't work perfectly because votes_up will be ambiguous. Also because you probably want to be doing joins that grab records that are only in one table. I think the concept is the right direction even though the query may not be perfect.
You can do something like
$selectStatement = "SUM(tableA.votes_up) + SUM(tableB.votes_up) as total_votes_up"
I did something like this recently. In your database, you'll have to rename each field to a corresponding book name.php like (TaleofTwoCities.php). Now on your page that will display the vote results, you'll need to include some php files that will drive the database query on each load. I called mine "engine1.php" and "engine2.php." These will do all your sorting for you.
$query1 = mysql_fetch_row(mysql_query("SELECT url FROM pages ORDER BY counter DESC
LIMIT 0,1"));
$query2 = mysql_fetch_row(mysql_query("SELECT url FROM pages ORDER BY counter DESC
LIMIT 1,1"));
$query3 = mysql_fetch_row(mysql_query("SELECT url FROM pages ORDER BY counter DESC
LIMIT 2,1"));
and so on.. then..
$num1 = "$query1[0]";
$num2 = "$query2[0]";
$num3 = "$query3[0]";
That part sorts your listings by the number of votes from highest to lowest, with url, in your case, being the name of the books(remember you want it to end in .php - you'll see why in a second), and counter being the field that logs your votes.
Make your second engine.php file and add something like this:
$vquery1 = mysql_fetch_row(mysql_query("SELECT counter FROM pages WHERE
url='book1.php'"));
$vquery2 = mysql_fetch_row(mysql_query("SELECT counter FROM pages WHERE
url='book2.php'"));
$vnum1 = "$vquery1[0]";
$vnum2 = "$vquery2[0]";
and so on... Until you get to 25 for both this and engine 1.
Now, in your results page, after you put in the require_once(engine.php) and require_once(engine2.php) at the start of your body, start an HTML table. You only want two columns, so it'll be something like..
<table border=1 cellspacing=0 cellpadding=0>
<tr>
<?php include $num1; ?>
</tr>
<tr>
<?php include $num2; ?>
</tr>
And so on... By naming your field with "book1.php" and including the engines, $num1 will change to a different .php file depending on votes from high to low. Now all you have to do is make small php files for each book like so - no headers or anything because you're inserting it into the middle of html code already:
<td style="width:650px;"><center><img src="images/book1.jpg" alt="" border="none"
/></a></center></td>
<td style="width:150px;">Votes: <?php echo $vnum1;?></td>
And there you have it. A code that will dynamically give you results from high to low depending on the number of votes each book has.