Dynamic Multi Dimensional Array - php

I have been trying to fureout how to create a dynamic multi dimensional array.
The reason for this is that I want to create a dropdown menu that will be created dynamically from the mysql
Sample database
|id|menu_name|menu_parent_id|
|1 |top menu1| 0 |
|2 |top menu2| 0 |
|3 |top menu3| 0 |
|4 |top menu4| 0 |
|5 |sub menu | 2 |
|6 |sub menu | 2 |
|7 |sub menu | 5 |
|8 |sub menu | 6 |
|9 |top menu | 0 |
I thought of starting from getting the menu with no parent then put it on an array
$parentIDs[0]=0;
$tempParentIDs = array();
$childIDs = array();
$menus = array();
$rows = 0;
$rows=0;
foreach($parentIDs AS $value){
$sql = mysql_query("SELECT * FROM service WHERE service_parent_id=$value");
while($temp = mysql_fetch_array($sql)){
//$tempParentIDs[] = $temp['service_id'];
//check if parent have child
$sql2 = mysql_query("SELECT * FROM service WHERE service_parent_id=$temp[service_id]") or die(mysql_error());
$rows = mysql_num_rows($sql2);
if($rows >= 1){
//This means there is a child
while($temp2 = mysql_fetch_array($sql2)){
$childIDs[] = $temp2['service_id'];
}
$tempParentIDs[$temp['service_id']] = $childIDs;
unset($childIDs);
} else {
//This means there is no child
}
}
}
echo "<pre>";
print_r($tempParentIDs);
echo "</pre>";
but after then I'm stuck.

I think you are looking for this:
$parentIDs[0]=0;
$tempParentIDs = array();
$childIDs = array();
$menus = array();
$rows = 0;
$multiDimensionalArray = NULL; //here I made change - vijay
$rows=0;
foreach($parentIDs AS $value){
$sql = mysql_query("SELECT * FROM service WHERE service_parent_id=$value");
while($temp = mysql_fetch_array($sql)){
$tempParentIDs = $temp['service_id']; //here I made change - vijay
//check if parent have child
$sql2 = mysql_query("SELECT * FROM service WHERE service_parent_id=$temp[service_id]") or die(mysql_error());
$rows = mysql_num_rows($sql2);
if($rows >= 1){
//This means there is a child
while($temp2 = mysql_fetch_array($sql2)){
$multiDimensionalArray[$tempParentIDs][] = $temp2['service_id']; //here I made change - vijay
}
// $tempParentIDs[$temp['service_id']] = $childIDs; //here I made change - vijay
// unset($childIDs); //here I made change - vijay
} else {
//This means there is no child
}
}
}
echo "<pre>";
print_r($multiDimensionalArray); //here I made change - vijay
echo "</pre>";

You should store array in php like this way :
This will maybe work for you
$next = 0;
$level = 0;
$sql = mysql_query("SELECT * FROM service WHERE service_parent_id=$next");
$temps = array();
while($temp = mysql_fetch_array($sql))
{
$temps[] = $temp;
}
foreach($temps as $temp)
{
echo $temp['service_id'];
}

Related

How to select and assign to a specific $key, a specific $value, among multiple choices?

I have a MySQL table with multiple columns, from which I need to select all of them of each record, and to create a specific $key=>$value from it.
for example
TABLE
ID | group_cat | group_sec | group_name | enabled | sent
-------------------------------------------------------------------------------------
1 | C | sct_a | Project_A | 1 | no
2 | C | sct_b | Project_B | 1 | no
3 | P | sct_c | Moderators | 1 | no
4 | C | sct_d | Ambassad | 1 | no
5 | P | sct_e | PMP | 0 | no
The MySQL query I need is "SELECT * FROM groups WHERE sent = 'no' "
By PHP is
PHP Code
$query = "SELECT * FROM `groups` WHERE `sent`= 'no' ";
$sth = $sql->prepare($query);
$sth->execute();
while($row = $sth->fetch(PDO::FETCH_ASSOC)) {
foreach($row as $key => $value) { $$key = $value; }
...
...
...
}
Here my question:
I need that the $key is from the column 'group_sec' and the related $value is from the column 'group_name'. So that the couple $$key=>$value can return this result (for instance)
echo $sec_b;
returns: Project_B
Could you help me to get this done please?
Thank you in advance
This will do the job for you:
${$row['group_sec']} = $row['group_name'];
echo $sct_b;
Output:
Project_B
You would use this in your while loop (the foreach can probably be deleted):
while($row = $sth->fetch(PDO::FETCH_ASSOC)) {
${$row['group_sec']} = $row['group_name'];
...
// do something with $sct_b
...
}
Alternatively, if your column names might change, but the positions will stay the same, you can use
while($row = $sth->fetch(PDO::FETCH_NUM)) {
${$row[2]} = $row[3];
...
// do something with $sct_b
...
}
You can build an array based on key and value you prefer using $row['group_sec'] for key and $row['group_name'] eg:
$query = "SELECT * FROM `groups` WHERE `sent`= 'no' ";
$sth = $sql->prepare($query);
$sth->execute();
while($row = $sth->fetch(PDO::FETCH_ASSOC)) {
$myArray[$row['group_sec']] = $row['group_name'];
}
and you can see the result
foreach($myArray as $key => $value){
echo $key . ' - ' . $value . '<br>';
}
$sql = "SELECT * FROM groups WHERE sent= 'no'";
$result = $conn->query($sql);
if ($result->num_rows > 0) {
// output data of each row
$list=[];
while($row = $result->fetch_assoc()) {
$list{$row['group_sec']} = $row['group_name'];
}
}

Fetch Mysql Results into serialized data

I have this table:
| id | related_id |
| 1 | 100 |
| 1 | 200 |
| 1 | 300 |
| 2 | 400 |
| 2 | 500 |
| 2 | 600 |
I need to retrieve serialized data as:
a:3:{i:1;s:3:"100";i:2;s:3:"200";i:3;s:3:"300";}
Query
SELECT id, related_id from mytable where id = 1;
I'm trying to get this using 'while'
$result = $link->query($query);
$item = array();
while($f = $result->fetch_assoc()){
$id = $f['id'];
if ($id == $f['id']){
$item[] = $f['related_id'];
}
print serialize($item);
break; // for test
}
SOLUTION that works for me (provided by Erwin - Thanks!)
$item = array();
while($f = $result->fetch_assoc()) {
$id = $f['id'];
if (!array_key_exists($id, $item)) {
$item[$id] = [1 => $f['related_id']];
} else {
$item[$id][] = $f['related_id'];
}
}
foreach ($item as $value) {
print serialize($value) . PHP_EOL;
}
Collect first each related_id and store to id array with your while loop. Then print each using foreach.
$item = array();
while($f = $result->fetch_assoc()) {
$id = $f['id'];
if (!array_key_exists($id, $item)) { // create id array if not exist
$item[$id] = [1 => $f['related_id']]; // To start with index 1
} else {
$item[$id][] = $f['related_id']; // Push each new related_id
}
}
foreach ($item as $value) {
print serialize($value); // Print each serialized
echo '<br>'; // New line
}
What you are trying to do is something like this:
$result = $link->query($query);
$items = array();
while($f = $result->fetch_assoc()){
$id = $f['id'];
if(!isset($items[$id])) {
$items[$id] = array();
}
$items[$id][] = $f['related_id'];
}
foreach($items as $item) {
print serialize($item);
}
For your serialized string, you have to work with an array with related_id in the second layer. The first layer is to save all related_id in an array with the same id.
You have 6 rows, 3 have id 1 and 3 have id 2. You are specifying that you want to use these ids as array keys so you will end up with 2 arrays, each holding 3 values.
If you want each row in its own array you do this:
while($f = $result->fetch_assoc()){
$item[] = array($f['id'] => $f['related_id']);
}

Assign variables from array

I created a settings table in my database and I would like to assign value to a variable based on the setting and I'm not sure how to go about doing it.
table: settings
id | setting | value
1 | setting_one | value_one
2 | setting_two | value_two
3 | setting_three | value_three
Query
if ($result = $db->query("SELECT * FROM settings")) {
while($row = mysqli_fetch_assoc($result)) {
$SettingOne = $row['setting_one'];
$SettingTwo = $row['setting_two'];
$SettingThree = $row['setting_three'];
}
}
The select will return you 3 rows, assuming your table has only 3 rows in it
that is why you process the result in a while lop.
Each $row will contain an Assoc array in the form of the columns that you selected in your query.
In this case as you use SELECT * the $row array will contain 3 occurances
id, setting, value
So your loop should look like
if ($result = $db->query("SELECT * FROM settings")) {
while($row = mysqli_fetch_assoc($result)) {
$id = $row['id'];
$setting = $row['setting'];
$value = $row['value'];
echo "The id = $id, the setting = $setting, the value is $value <br>";
}
}
This will produce you 3 lines of output, assuming you only have 3 rows in your table
I got it figured out and just echo the row['setting'] as $setting for each :)
if ($result = $db->query("SELECT * FROM settings")) {
while($row = mysqli_fetch_assoc($result)) {
$key = $row['setting'];
$$key = $row['value'];
}
$result->free();
$result->close();
}

How to create a JSON from table PHP

How to create a json like this in php;
[{"idorder":"34",
"totalOrder":"55",
"products":[{"idproduct":"5","price":"10"},{"idproduct":"4","price":"45"}]
}]
from table mysql;
+---------+-----------+--------------+
| idorder | idproduct | priceproduct |
+---------+-----------+--------------+
| 1 | 4 | 45 |
| 1 | 5 | 10 |
+---------+-----------+--------------+
my current code something.php;
...
$result = $conn->query($pendientesq);
$return_arr = array();
$productos = array();
$r1=$result->fetch_array();
$return_arr['idorder'] = $r1['idorder'];
$return_arr['totalOrder'] = '55';
//But now????How to create sub array with multiples products.
echo json_encode($return_arr);
you need to try something like this:
$r1=$result->fetch_array();
$return_arr['idorder'] = $r1['idorder'];
$return_arr['totalOrder'] = '55';
// suposse total products are 10
$product=10;
for($i=0;$i<product;$i++){
$return_arr['product'][] = array("idproduct"=>$i,"price"=>$i);//use your price and idproduct.
}
echo json_encode($return_arr);
I don't know how Your table looks like because You've not described it.
But I got for example "orders" table with idorder,idproduct,priceproduct fields.
And wrote this code:
// $q = "SELECT * FROM orders WHERE idorder = 5"; // for single order
$q = "SELECT * FROM orders";
$result = $conn->query($q);
$orders = [];
while($record=$result->fetch_array()) {
if(!isset($orders[$record['idorder']])) {
$orders[$record['idorder']] = [];
$orders[$record['idorder']]['idorder'] = $record['idorder'];
$orders[$record['idorder']]['totalOrder'] = 0;
$orders[$record['idorder']]['products'] = [];
}
$orders[$record['idorder']]['products'][] = ['idproduct' => $recrod['idproduct'],
'price' => $record['priceproduct']];
$orders[$record['idorder']]['totalOrder'] += $record['priceproduct'];
}
$orders = array_values($orders);
echo json_encode($orders);

How find Row Number of Value within Array?

I've saved all my data to an array, and I want to get the 'name' of a supplied 'code'.
How to I get the array row of that code?
Also, is this the most efficient process?
id | code | name |
__________________________
1 | KNTY | Kentucky |
2 | PURD | Purdue |
3 | TEXS | Texas |
// Move data to array
$search = "SELECT * FROM table";
$query = mysqli_query($conn, $search);
while($row = mysqli_fetch_assoc($query)) {
$array[] = $row;
}
// Code I want a name for
$code = "KNTY";
// MYSTERY STEP I NEED HELP WITH
$name = $array[$id]['name'];
I edit with the hint of the comment of itachi. You can use the code as the key of the $array:
$search = "SELECT * FROM table";
$query = mysqli_query($conn, $search);
$array = array();
while($row = mysqli_fetch_assoc($query)) {
$array[$row['code']] = $row['name'];
}
// Code I want a name for
$code = "KNTY";
$name = $array[$code];
Yes you could do something like that, while inside the fetch loop, assign the code as key. This must be unique though:
$search = 'SELECT * FROM table_name';
$query = mysqli_query($conn, $search);
while($row = mysqli_fetch_assoc($query)) {
// assign `$row['code']` as key to this rowset
$array[$row['code']] = $row;
}
$code = 'KNTY';
if(isset($array[$code])) { // add some checking, you wouldn't want undefined index errors
$name = $array[$code]['name'];
echo $name;
} else {
echo 'Sorry not found';
}

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