How find Row Number of Value within Array? - php

Question

I've saved all my data to an array, and I want to get the 'name' of a supplied 'code'.
How to I get the array row of that code?
Also, is this the most efficient process?
id | code | name |
__________________________
1 | KNTY | Kentucky |
2 | PURD | Purdue |
3 | TEXS | Texas |
// Move data to array
$search = "SELECT * FROM table";
$query = mysqli_query($conn, $search);
while($row = mysqli_fetch_assoc($query)) {
$array[] = $row;
}
// Code I want a name for
$code = "KNTY";
// MYSTERY STEP I NEED HELP WITH
$name = $array[$id]['name'];

Answer 1

I edit with the hint of the comment of itachi. You can use the code as the key of the $array:
$search = "SELECT * FROM table";
$query = mysqli_query($conn, $search);
$array = array();
while($row = mysqli_fetch_assoc($query)) {
$array[$row['code']] = $row['name'];
}
// Code I want a name for
$code = "KNTY";
$name = $array[$code];

Answer 2

Yes you could do something like that, while inside the fetch loop, assign the code as key. This must be unique though:
$search = 'SELECT * FROM table_name';
$query = mysqli_query($conn, $search);
while($row = mysqli_fetch_assoc($query)) {
// assign `$row['code']` as key to this rowset
$array[$row['code']] = $row;
}
$code = 'KNTY';
if(isset($array[$code])) { // add some checking, you wouldn't want undefined index errors
$name = $array[$code]['name'];
echo $name;
} else {
echo 'Sorry not found';
}