i am trying to send the value of text area into database but i am unable to get the values of text area. and also i want once data is saved to database i want to show that data in text area. kindly help me.
Thanks.
here is my code.
<script type="text/javascript" >
function save()
{
var mail = {
aboutus: $('textarea#area1').val(),
services: $("#area2").val(),
contact: $("#area3").val()
};
$.ajax({
url: "user_stall_add.php",
type: "POST",
enctype: "multipart/form-data",
data: mail,
success: function(data) {
alert("Content Added");
}
});
}
</script>
<script type="text/javascript" src="../nicEdit.js"></script>
<script type="text/javascript">
bkLib.onDomLoaded(function() { nicEditors.allTextAreas() });
</script>
<h4 style="margin-left:4em;">About Us Content</h4>
<textarea name="area1" id="area1" style="margin-left:4em;" cols="60" rows="10"></textarea>
<input type="button" style="margin-left:4em;" value="Save" onclick="save();"><br />
<h4 style="margin-left:4em;">Services Content</h4>
<textarea name="area2" id="area2" cols="60" rows="10">
Some Initial Content was in this textarea
</textarea>
<input type="button" style="margin-left:4em;" value="Save" onclick="save();"><br />
<h4 style="margin-left:4em;">Contact Content</h4>
<textarea style="margin-left:4em;" id="area3" name="area3" cols="60" rows="10">
HTML <b>content</b> <i>default</i> in textarea
</textarea>
<input style="margin-left:4em;" type="button" value="Save" onclick="save();"><br />
</div>
You have used nicEditors,
var aboutus = new nicEditors.findEditor('area1').getContent();
var services = new nicEditors.findEditor('area2').getContent();
var contact = new nicEditors.findEditor('area3').getContent();
var mail = {
aboutus: aboutus,
services: services,
contact: contact
};
REF: http://nicedit.com/demos.php
Doc: http://wiki.nicedit.com/w/page/521/Javascript%20API
Returns the current HTML of the nicInstance
For example:
nicEditors.findEditor('myArea2').getContent();
returns the HTML in the content editor that replaced the element on the page with ID 'myArea2'.
try
aboutus: $('textarea#area1').val(),
services: $('textarea#area2').val(),
contact: $('textarea#area3').val()
Please try $('#area1').val() to match your other textarea(s). Also, make sure there is a value in the textarea - or you'll get an undefined. Finally, your sample works fine when I just use
function test() {
// These both work for me.
console.log($("textarea#area1").val());
console.log($('#area1').val());
}
Related
I'm trying to create a search feature that searches a database based on the criteria a user has entered. Right now, I'm just trying to get the jQuery variable data into PHP. I've decided to use the shorthand AJAX $.post method because this is just a demo project. I know there are numerous similar questions like mine, but I have yet to find an answer to any of them that I can use.
So what I'm trying to do is, the user will click on a drop down menu and select an option. AJAX then sends the selected value to the PHP file and the PHP will eventually perform a database search based on what was selected. The issue is, in PHP, I'm getting a string of "Search" when the data is parsed and I echo it but when I do a console log on the variable that was sent, I'm getting the correct text. Can anyone tell me where I'm going wrong?
Here's what I have so far.
AJAX
$("#search_form").on("submit", function(ev){
ev.preventDefault();
$.post("../php/test.php", $(this).serialize(), function(data){
console.log(data);
})
})
PHP
ob_start();
require("../includes/header.php");
$criteria = $_POST["search"];
ob_clean();
echo $criteria;
HTML
<form id="search_form" method="post">
<fieldset id="search_by">
<div class="select" name="searchBy" id="searchBy">
<p>Search By...</p>
<div class="arrow"></div>
<div class="option-menu">
<div class="option">Airport Identifier</div>
<div class="option">Top Rated</div>
<div class="option">Instructor</div>
<div class="option">Malfunctions/Maneuvers</div>
</div>
</div>
<input type="text" name="search" id="search" />
<input type="submit" class="button" value="Search_Now" />
</fieldset>
As Requested
Here is a fiddle of the drop down menu to show how it works.
http://jsfiddle.net/xvmxc0zo/
Your form is being submitted via default form submission; the ajax call is misplaced, it should be within the submit handler, which should prevent default form submission.
Note that I have removed both name and id attributes from the submit button; you do not need them. Just let the submit button do it's job and listen for the submit event on the form where you would then use event.preventDefault(); to make sure the form does not submit, then you can make your ajax call.
$("#searchBy").on("click", ".option", function(){
$('#search').val( $(this).text() );
});
$('form').on('submit', function(e) {
e.preventDefault();
$.post("../php/test.php", $(this).serialize(), function(data){
//jsonData = window.JSON.parse(data);
console.log( data);
})
});
<script src="https://ajax.googleapis.com/ajax/libs/jquery/1.11.1/jquery.min.js"></script>
<form>
<fieldset id="search_by">
<div class="select" name="searchBy" id="searchBy">
<p>Search By...</p>
<div class="arrow"></div>
<div class="option-menu">
<div class="option">Airport Identifier</div>
<div class="option">Top Rated</div>
<div class="option">Instructor</div>
<div class="option">Malfunctions/Maneuvers</div>
</div>
</div>
<input type="hidden" name="search" id="search" />
<input type="text" name="search_text" id="search_text" />
<input type="submit" class="button" value="Search" />
</fieldset>
</form>
In your PHP use echo $criteria; instead of echo json_encode($criteria);.
I'd suggest to use the way of jQuery documentation to check changes in your drop down.
$( "select" ).change(function () {
$( "select option:selected" ).each(function() {
$.post("../php/test.php", {search: $(this).text()}, function(data){
jsonData = window.JSON.parse(data);
});
});
})
You are getting "Search" on the PHP side because that is the value of your submit button.
You want the post to occur when you click on an option? Try adjusting your selector as follows:
$("#searchBy .option").on("click", function () {
var search = $(this).text().trim();
$.post("../php/test.php", { search: search }, function (data) {
jsonData = window.JSON.parse(data);
})
});
I think your header.php is provoking the error. I created a test file myself with your code and that works perfectly fine:
<?php
if($_POST)
{
ob_start();
//require("../includes/header.php");
$criteria = $_POST["search"];
ob_clean();
echo json_encode($criteria);
exit;
}
?>
<fieldset id="search_by">
<div class="select" name="searchBy" id="searchBy">
<p>Search By...</p>
<div class="arrow"></div>
<div class="option-menu">
<div class="option">Airport Identifier</div>
<div class="option">Top Rated</div>
<div class="option">Instructor</div>
<div class="option">Malfunctions/Maneuvers</div>
</div>
</div>
<input type="text" name="search_text" id="search_text" />
<input type="submit" name="search" id="search" class="button" value="Search" />
</fieldset>
<script src="http://code.jquery.com/jquery-1.11.1.min.js"></script>
<script>
$("#searchBy").on("click", ".option", function(){
var search = $(this).text();
$.post("<?=$_SERVER['PHP_SELF']?>", {search: search}, function(data){
jsonData = window.JSON.parse(data);
console.log(jsonData); //Prints the correct string
})
});
</script>
i have created a simple html form with one field and it post to the server side php and the value of the field is saved to a text file.
This is the parts of the code:
Html:
<form action="videorefresh.php" method="POST">
<input name="videolink" type="text" size="70" />
<input type="submit" name="submit" value="Save Data">
</form>
php:
<?php
$open = fopen("video.txt","w+");
$txt = "video.txt";
if (isset($_POST['videolink'])) { // check if both fields are set
$fh = fopen($txt, 'a');
$txt=$_POST['videolink'];
fwrite($fh,$txt); // Write information to the file
fclose($fh); // Close the file
}
?>
here everythink works fine!
I want to drive all this through Ajax so the main html form wont refresh.
so here is the html:
<!DOCTYPE html>
<html>
<head>
<script src="http://ajax.googleapis.com/ajax/libs/jquery/1.11.0/jquery.min.js"></script>
<script src="./JS/videolink.js"></script>
</head>
<body>
<div id="mainform">
<div id="form">
<div>
<input name="videolink" type="text" id="videolink" size="70">
<input id="submit" type="button" value="Submit">
</div>
</div>
</div>
</body>
</html>
And here is the js:
$(document).ready(function(){
$("#submit").click(function(){
var name = $("#videolink").val();
// Returns successful data submission message when the entered information is stored in database.
var dataString = 'videolink1='+ videolink ;
if(videolink=='')
{
alert("Please Fill All Fields");
}
else
{
// AJAX Code To Submit Form.
$.ajax({
type: "POST",
url: "./videorefresh.php",
data: dataString,
cache: false,
success: function(result){
alert(result);
}
});
}
return false;
});
});
What i do wrong here and it doesnt work?
Please help
I think you want to do is:
var dataString = '?videolink='+ name;//typo videolink
// or better put an id on the form and use serialize()
// var dataString = $('#myform).serialize();
NOT
var dataString = 'videolink1='+ videolink ;
You have the value of the input in name, videolink is undefined
I'm following the following tutorial to place a form on my website using PHP, AJAX, and JQUERY that will send the form information to my email:
http://www.spruce.it/noise/simple-ajax-contact-form/
The problem is, when I have the jquery outside the document ready I get no message at all, and when I place it in the document ready i get the error text, but when there is information in the fields nothing happens at all. Please, can someone look and see what might be the problem with my html, jquery, php, or AJAX? I'm about to pull out all of my hair. I'm testing it in Wampserver.
The HTML file is in the root directory with the PHP file. In the root directory there is a folder called "includes" that the Javascript is in. Here is the relevant code for each:
HTML:
<form id="repairform" method="post">
<p id="p1">Name:</p>
<input id="one" type="text" name="name" />
<p id="p2">How would you prefer to be reached?: </p>
<select id="two" name="Contact methods">
<option value="Phone">Email</option>
<option value="Email">Phone</option>
</select>
<p id="p3">What kind of computer are you having trouble with?</p>
<p id="p3-2">Give as much or as little info. as you'd like.</p>
<p id="p3-3">(Laptop PC, desktop Macintosh, etc)</p>
<textarea id="four" name="pc type" rows="3" cols="30"></textarea>
<p id="p4">What problems are you having with your computer/ what needs to be fixed?</p>
<textarea id="five" name="problem" rows="5" cols="30"></textarea>
<input id="three" type="submit" value="Submit Request" />
<p id="p5">What is your Email?</p>
<input id="six" type="text" name="Email/Phone" />
<p id="p7">What is your Phone Number?</p>
<input id="eight" type="text" name="Email/Phone2" />
<p id="p6">What time of day would you prefer to be reached?</p>
<input id="seven" type="text" name="Preferred Contact Time" />
</form>
JQuery:
$(document).ready(function () {
$("#repairform").submit(function (e) {
e.preventDefault();
if (!$("#six").val()) {
$("#six").val("shanew#ufl.edu");
}
var name = $("#one").val();
var email = $("#six").val();
var text = $("#five").val();
var reachpreference = $("#two").val();
var computertype = $("#four").val();
var phonenumber = $("#eight").val();
var timeofday = $("#seven").val();
var dataString = 'name=' + name + '&email=' + email + '&text=' + text
+ '&reachpreference=' + reachpreference + '&computertype=' + computertype
+ '&phonenumber=' + phonenumber + '&timeofday=' + timeofday;
function isValidEmail(emailAddress) {
var pattern = new RegExp(/^((([a-z]|\d|[!#\$%&'\*\+\-\/=\?\^_`{\|}~]|[\u00A0-\uD7FF\uF900-\uFDCF\uFDF0-\uFFEF])+(\.([a-z]|\d|[!#\$%&'\*\+\-\/=\?\^_`{\|}~]|[\u00A0-\uD7FF\uF900-\uFDCF\uFDF0-\uFFEF])+)*)|((\x22)((((\x20|\x09)*(\x0d\x0a))?(\x20|\x09)+)?(([\x01-\x08\x0b\x0c\x0e-\x1f\x7f]|\x21|[\x23-\x5b]|[\x5d-\x7e]|[\u00A0-\uD7FF\uF900-\uFDCF\uFDF0-\uFFEF])|(\\([\x01-\x09\x0b\x0c\x0d-\x7f]|[\u00A0-\uD7FF\uF900-\uFDCF\uFDF0-\uFFEF]))))*(((\x20|\x09)*(\x0d\x0a))?(\x20|\x09)+)?(\x22)))#((([a-z]|\d|[\u00A0-\uD7FF\uF900-\uFDCF\uFDF0-\uFFEF])|(([a-z]|\d|[\u00A0-\uD7FF\uF900-\uFDCF\uFDF0-\uFFEF])([a-z]|\d|-|\.|_|~|[\u00A0-\uD7FF\uF900-\uFDCF\uFDF0-\uFFEF])*([a-z]|\d|[\u00A0-\uD7FF\uF900-\uFDCF\uFDF0-\uFFEF])))\.)+(([a-z]|[\u00A0-\uD7FF\uF900-\uFDCF\uFDF0-\uFFEF])|(([a-z]|[\u00A0-\uD7FF\uF900-\uFDCF\uFDF0-\uFFEF])([a-z]|\d|-|\.|_|~|[\u00A0-\uD7FF\uF900-\uFDCF\uFDF0-\uFFEF])*([a-z]|[\u00A0-\uD7FF\uF900-\uFDCF\uFDF0-\uFFEF])))\.?$/i);
return pattern.test(emailAddress);
};
if (isValidEmail(email) && (text.length > 2) && (name.length > 1)) {
$.ajax({
type: "POST",
url: "../functions.php",
data: dataString,
success: function () {
alert("Thank you! Your message has been delivered. I will be back with you shortly");
}
});
} else {
alert("Some of the form information was not filled out correctly. Ensure all of the correct fields are filled out.");
}
return false;
});
PHP:
<?php
// Email Submit
if (isset($_POST['email']) && isset($_POST['name']) && isset($_POST['text'])){
//send email
mail("shanew#ufl.edu", "Contact Form: ".$_POST['name'],
$_POST['text'], $_POST['reachpreference'], $_POST['computertype']
$_POST['phonenumber'], $_POST['timeofday'], "From:" . $_POST['email']);
}
?>
Use
data: $('#repairform').serializeArray()
instead of the datastring object you're creating.
The datastring will be treated as a String, and you'll never be able to access it using $_POST['text'] and all. You may try using using $_GET instead. The datastring will be accessible that way only.
I think you miss some of closing branch });
And I think you should use name attribute for variable name that will be used in php..
<form id="theForm">
<input type="text" name="email" />
</form>
and in javascript you can use serialize so less line and easier to read.
$.ajax({
type:'POST'
url:'../functions.php'
data:$('#theForm').serialize();
})
and in php
echo $_POST['email']
I have a contact form which performs a PHP action. The contact form is connected with validation engine in jQuery. If messege is sent correctly I simply include PHP file with thanks message - require_once('success.php');. After sending message I would like to replace contact form with thanks message without reloading the whole page. Please give me some advices how to do it.
Here is my html:
<div id="contactForm">
<form id="expertForm" class="formular" method="post" action="send.php">
<fieldset>
<label>
<input name="email"
id="email"
class="required email"
type="text"
size="40"/>
</label>
<p>
<textarea name="body" id="body" rows="5" cols="50" class="required"></textarea>
</p>
</fieldset>
<input class="submit"
type="image"
src="../images/btn-send.png"/>
</form>
</div>
<script type="text/javascript">
$("#expertForm").validate();
</script>
In send.php I have:
if(!$mail->Send()) {
echo "Mailer Error: " . $mail->ErrorInfo;
} else {
require_once('success.php');
}
You can see an almost working demo here http://jsfiddle.net/v7MJA/1/
$(function(){
$("#expertForm").submit(function(e){
e.preventDefault();
if(!$(this).validate().form()) return false;
$.ajax({
url:$(this).attr('action'),
data:$(this).serialize(),
type:'post',
success:function(msg){
$("#expertForm").replaceWith(msg);
}
});
});
});
You'd better give us some code so that we could help.
Here is the theorical way: use the success event of the jquery ajax[ref] call:
$.ajax({
url: "test.html",
context: document.body,
success: function(){
$("#myformdiv").html("Thanks!");
}
});
assuming that your HTML markup is something like:
<div id="myformdiv">
<form>
<!-- form code here -->
</form>
</div>
Assuming I've understood your question correctly, you can use the replaceWith method to replace the matched elements with the specified content:
$("#yourForm").replaceWith("<p>Thanks!</p>");
I'm assuming that you're doing something asynchronously to send the form data to the server, so you can just run the above code in the callback:
$.post("yourScript.php", function() {
$("#yourForm").replaceWith("<p>Thanks!</p>");
});
I have a form that calls a php script on submit to insert data into a MySQL database. I would like the output of the php script return to a greybox. I haven't been able to make it work so I appreciate any help you guys can provide.
I have the greybox call on the form definition see below but is not doing the trick.
Here is a subset of the code:
<script type="text/javascript" src="greybox/AJS.js"></script>
<script type="text/javascript" src="greybox/AJX_fx.js"></script>
<script type="text/javascript" src="greybox/gb_scripts.js"></script>
<div id="content">
<form id="contact_us" name="contact_us" action="contact-greybox.php" method="POST" onSubmit="return GB_showCenter('Testing', this.action, 500, 500)">
<fieldset>
<label for="employee_id">Employee ID:</label>
<input id="employee_id" name="employee_id" type="number" size="10" /><P />
<label for="employee_name">Employee Name:<strong><br /> (as it should appear on
email) </strong></label>
<input id="employee_name" name="employee_name" type="text" /><P />
</fieldlist>
<p class="submit"><input type="image" name="submit" value="Submit Form" src="icons/ambas_submit.jpg" boder="0">
</form>
</div>
The php is a simple insert statement into MySQL.
Appreciate any help
greybox doesn't support POST submits, but the general pattern is to use ajax to submit the form- otherwise your page will refresh.
You need to set an onclick( $.submit ) to the form input then return false at the end of your ajax call:
$('#contact_us').submit(function(){
//get your inputs here
var e_id = $.('#employee_id').val();
//...etc....
$.post( ...
//set your data/input fields here:
data: { id: e_id },
success: function(response){
//display the response: this is what you get back from: contact-greybox.php
}
})
return false;
});
fancybox is an overlay box that supports being called with pure html as a parameter, so that you can just put this in your success function:
$.fancybox(response);
...or
$.fancybox(response.html)... etc.