php output display on a greybox - php

Question

I have a form that calls a php script on submit to insert data into a MySQL database. I would like the output of the php script return to a greybox. I haven't been able to make it work so I appreciate any help you guys can provide.
I have the greybox call on the form definition see below but is not doing the trick.
Here is a subset of the code:
<script type="text/javascript" src="greybox/AJS.js"></script>
<script type="text/javascript" src="greybox/AJX_fx.js"></script>
<script type="text/javascript" src="greybox/gb_scripts.js"></script>
<div id="content">
<form id="contact_us" name="contact_us" action="contact-greybox.php" method="POST" onSubmit="return GB_showCenter('Testing', this.action, 500, 500)">
<fieldset>
<label for="employee_id">Employee ID:</label>
<input id="employee_id" name="employee_id" type="number" size="10" /><P />
<label for="employee_name">Employee Name:<strong><br /> (as it should appear on
email) </strong></label>
<input id="employee_name" name="employee_name" type="text" /><P />
</fieldlist>
<p class="submit"><input type="image" name="submit" value="Submit Form" src="icons/ambas_submit.jpg" boder="0">
</form>
</div>
The php is a simple insert statement into MySQL.
Appreciate any help

Answer 1

greybox doesn't support POST submits, but the general pattern is to use ajax to submit the form- otherwise your page will refresh.
You need to set an onclick( $.submit ) to the form input then return false at the end of your ajax call:
$('#contact_us').submit(function(){
//get your inputs here
var e_id = $.('#employee_id').val();
//...etc....
$.post( ...
//set your data/input fields here:
data: { id: e_id },
success: function(response){
//display the response: this is what you get back from: contact-greybox.php
}
})
return false;
});
fancybox is an overlay box that supports being called with pure html as a parameter, so that you can just put this in your success function:
$.fancybox(response);
...or
$.fancybox(response.html)... etc.