I am trying to do a query that filters on 2 columns on one table OR 2 columns on another. This is what I have so far:
// In my controller
return $registry = Registry::search($first_name, $last_name)->get();
// In my model
public function user()
{
return $this->belongsTo('User');
}
public function scopeSearch($query, $first_name, $last_name)
{
$search = $query->where('coregistrant_first_name', 'LIKE', "%$first_name%")
->where('coregistrant_last_name', 'LIKE', "%$last_name%")
->orWhere(function($query) use ($first_name, $last_name)
{
$query->$this->user()->where('first_name', 'LIKE', "%$first_name%");
});
return $search;
}
I have tried a lot of different things and now I'm stuck on the $query->$this->user() line with this error:
Undefined property: Illuminate\Database\Query\Builder::$[]
Anyone know how I can fix this problem?
#Keith, In Laravel, you can not use relationship for selecting data dynamically.
AS far as i know, Laravel support the following rules to retrieve data using relationship:
$registers = Registry::with('user')->get();
$registers = Registry::where('xyz', '1')->get();
// then you can load the relationship if you needed
$registers->load('user');
In your model
public function user()
{
return $this->belongsTo('User')->where('first_name', 'LIKE', "%xyz%");
}
Then From your controller:
$registers = Registry::with('user')->get();
If you have one to many relationship,
Say you have licenses relationship
// You can specify an operator and a count:
$registers = Registry::has('licenses', '>=', 3)->get();
Reference: http://laravel.com/docs/eloquent#querying-relations
I ended up using query builder to do it.
Related
I have implemented eloquent relationship in my code but Laravel unable to read the function that I created to map the eloquent relationship in the model.
User Model
public function products(){
return $this->hasMany(Product::class,'userid');
}
Product Model
public function users(){
return $this->belongsTo(User::class);
}
Product Controller
$products = Product::with('Users')->Users()->where('users.isActive',1)->get();
return view('product',compact('products'));
I keep getting error from the product controller, I also attached the error that I current encountered as below.
How can I get all the product and user data with the where condition such as "Users.isActive = 1".
Thanks.
You can use whereHas to filter from a relationship.
$products = Product::with('users')
->whereHas('users', function ($query) {
$query->where('isActive', 1);
})
->get();
Also it is generally a good idea to use singular noun for belongsTo relationship because it returns an object, not a collection.
public function user() {
return $this->belongsTo(User::class);
}
$products = Product::with('user')
->whereHas('user', function ($query) {
$query->where('isActive', 1);
})
->get();
EDIT
If you want to retrieve users with products you should query with User model.
$users = User::with('products')
->where('isActive', 1)
->get();
Then you can retrieve both users and products by
foreach($users as $user) {
$user->products;
// or
foreach($users->products as $product) {
$product;
}
}
You can use whereHas() method for this purpose. Here is the doc
$products = Product::with('users')->whereHas('users', function (Illuminate\Database\Eloquent\Builder $query) {
$query->where('isActive', 1);
})->get();
$users = $products->pluck('users');
return view('product',compact('products'));
You have a typo after the with, is users instead of Users and you're redundant about the Query Builder, remove the ->Users():
Before:
$products = Product::with('Users')->Users()->where('users.isActive',1)->get();
return view('product',compact('products'));
After:
$products = Product::with('users')->where('users.isActive',1)->get();
return view('product',compact('products'));
Fix that and all should work.
i have this code in my controller
if (request('tag')) {
$Posts = Tags::where('name' ,request('tag'))->firstOrFail()->Posts;
} else {
$Posts = Blog::paginate(10);
}
return view('Panel.Posts',['Posts' => $Posts]);
and this is my model function
public function tag(){
return $this->belongsToMany(Tags::class,'Post_tag','Post_id');
}
It's a web application I am creating and it's a blog.
I'm trying to create a category.
I want to paginate my search method but I can't do it.
If I use paginate method it says posts relation is not found in paginate.
I tried this:
$Posts = Tags::where('name' ,request('tag'))->firstOrFail()->paginate(10)->Posts;
and this
$Posts = Tags::where('name' ,request('tag'))->firstOrFail()->Posts->paginate(10);
Can any one help me to fix this?
try my code
$Posts = Blog::whereHas('tag', function (Builder $query) {
$query->where('name', request('tag'));
})->paginate(25);
you can yse where ha and query builder instans a relation in models
Make sure Tags has relation relation in model. Also use ->posts instead ->Posts, but anyway:
There is no point of using separate query if relation is defined or not. Instead you need combination of when and whereHas.
$posts = Blog::when(request('tag'), function ($q, $tagName) {
return $q->whereHas('tag', function ($q) use ($tagName) {
return $q->where('name', $tagName);
});
})->paginate(10);
When fill apply what is inside it if condifion will match. So it is just replace for "if". Docs https://laravel.com/docs/7.x/queries#conditional-clauses
WhereHas will check if relation model exists and allow you to use "where" (or other queries) on that relation. Docs https://laravel.com/docs/7.x/eloquent-relationships#querying-relationship-existence
If you wanna still use "if" nad not "when":
$posts = Blog::query();
if (request('tag')) {
$posts = $posts->whereHas('tag', function ($q) {
return $q->where('name', request('tag'));
});
}
$posts = $posts->paginate(10);
I am experimenting with creating a Restful API in Laravel and I am making use of the resources feature designed for API output. I have created the following models:
Book, Author and Category. I also created a resource for each of these models.
There is a one to many relationship between author and book and a many to many between category and book which has a pivot table.
I can return a collection of all books easily with the following:
return BookResource::collection(Book::with(['author', 'categories'])->paginate(10));
But I want to easily filter by author and category so I have implemented it in the following way inside my controller:
public function index(request $request)
{
//if no filer params are passed in return all books with author and categories
if (!$request->has('author') && !$request->has('category')) {
return BookResource::collection(Book::with(['author', 'categories'])->paginate(10));
}
//author param is passed in
if($request->has('author') && !$request->has('category')){
$authorName = $request->author;
return BookResource::collection(Book::whereHas('author', function ($query) use ($authorName) {
$query->where('name', $authorName);
})->get());
}
//category param is passed in
if(!$request->has('author') && $request->has('category')){
$categoryName = $request->category;
return BookResource::collection(Book::whereHas('categories', function ($query) use ($categoryName) {
$query->where('name', $categoryName);
})->get());
}
}
Is there a better more efficient way of returning the BookResource collection filtered by author and category?
Please try to implement this way. Hope this helps. Thanks.
public function index(){
$author = request ('author', null);
$category = request ('category', null);
$books = Book::with(['author', 'categories'])->when($author, function ($query) use ($author) {
return $query->whereHas('author', function ($query) use ($author){
$query->where('name', $author);
});
})->when($category, function ($query) use ($category) {
return $query->whereHas('categories', function ($query) use ($category) {
$query->where('name', $category);
});
})->paginate(10);
return BookResource::collection($books);
}
I have two models, App\Song (belongsTo App\Host) and App\Host (hasMany App\Song).
I have the following query in my Controller:
$songs = Song::whereHas('host', function($query) {
$query->where('skip_threshold', '>', \DB::raw('songs.attempts'))
->where('active', 1);
})
->whereNull('downloaded')
->get();
For reusability I would like to turn into a query scope(s).
I'm quite new to Eloquent so I'm not sure this is the correct way to do this being that its two Models as its not returning any results (where there should be).
Song.php
public function scopeEligable($query)
{
$query->where('skip_threshold', '>', \DB::raw('songs.attempts'));
}
public function scopeActiveHost($query)
{
$query->where('active', 1);
}
public function scopeInDownloadQueue($query)
{
$query->whereNull('downloaded');
}
You should put scopes into Models they belong to. Looking at your initial query scopes scopeEligable and scopeActiveHost belongs to Host model, so you should move them into Host model and then you'll be able to use your query using scopes like this:
$songs = Song::whereHas('host', function($query) {
$query->eligable()->activeHost();
})->inDownloadedQueue()->get();
and as already pointed in comment you should add return to each scope so they could be used as they intended.
EDIT
If you would like to make using it shorter, you could create new relationship in Song model:
public function activeHost()
{
return $this->belongsTo(Host:class)->eligable()->activeHost();
}
so now, you could write:
$songs = Song::whereHas('activeHost')->inDownloadedQueue()->get();
I think you're mistaken about 2 models. I think this should work
Song.php
public function scopeEligable($query, $active) {
return $query->whereHas('host', function($q) {
$q->where('skip_threshold', '>', \DB::raw('songs.attempts'))->where('active', $active);
})
}
public function scopeInDownloadQueue($query)
{
$query->whereNull('downloaded');
}
Usage
$songs = Song::eligable(true)->inDownloadQueue()->get();
I want to keyword search from a table and its all related table using Elequent in Laravel5.
My controller is
$clients = Client::with('contacts', 'paymentTerm', 'addressInfo');
if ($q = Request::input("q")) {
$clients->where("clients.name", 'LIKE', "%$q%");
$clients->where("address_info.email", 'LIKE', "%$q%");//This is not working,I want to search from both client and client address_info
}
return $clients->paginate(10);
Client Model ,
public function addressInfo() {
return $this->hasOne('App\Model\ClientAddressInfo');
}
Client Address info,
public function client() {
return $this->belongsTo('App\Model\Client');
}
how can I apply keyword search here?
You can use whereHas to filter by a related model:
$clients->whereHas('addressInfo', function($query) use ($q){
$query->where("email", 'LIKE', "%$q%");
});