I have implemented eloquent relationship in my code but Laravel unable to read the function that I created to map the eloquent relationship in the model.
User Model
public function products(){
return $this->hasMany(Product::class,'userid');
}
Product Model
public function users(){
return $this->belongsTo(User::class);
}
Product Controller
$products = Product::with('Users')->Users()->where('users.isActive',1)->get();
return view('product',compact('products'));
I keep getting error from the product controller, I also attached the error that I current encountered as below.
How can I get all the product and user data with the where condition such as "Users.isActive = 1".
Thanks.
You can use whereHas to filter from a relationship.
$products = Product::with('users')
->whereHas('users', function ($query) {
$query->where('isActive', 1);
})
->get();
Also it is generally a good idea to use singular noun for belongsTo relationship because it returns an object, not a collection.
public function user() {
return $this->belongsTo(User::class);
}
$products = Product::with('user')
->whereHas('user', function ($query) {
$query->where('isActive', 1);
})
->get();
EDIT
If you want to retrieve users with products you should query with User model.
$users = User::with('products')
->where('isActive', 1)
->get();
Then you can retrieve both users and products by
foreach($users as $user) {
$user->products;
// or
foreach($users->products as $product) {
$product;
}
}
You can use whereHas() method for this purpose. Here is the doc
$products = Product::with('users')->whereHas('users', function (Illuminate\Database\Eloquent\Builder $query) {
$query->where('isActive', 1);
})->get();
$users = $products->pluck('users');
return view('product',compact('products'));
You have a typo after the with, is users instead of Users and you're redundant about the Query Builder, remove the ->Users():
Before:
$products = Product::with('Users')->Users()->where('users.isActive',1)->get();
return view('product',compact('products'));
After:
$products = Product::with('users')->where('users.isActive',1)->get();
return view('product',compact('products'));
Fix that and all should work.
Related
Hellow guys,
so I have 2 tables
is Listings
is Users
in Listings I have some columns, one is user_id, and is related to users tables.
I want to display the user name related to the user table.
in the index blade, I use some tags.
But when I use ->rightjoin("users", "users.id", "=", "listings.user_id") it's works but,
the join broke my tags make them default, same with others posts.
public function index(Request $request)
{
$listings = Listing::where('is_active', true)->with('tags')
//->rightjoin("users", "users.id", "=", "listings.user_id") //don't show tags of the posts
->orderBy('listings.created_at', 'desc')
->get();
//check if posts ar listing by last date or something
$tags = Tag::orderBy('name') // variable displayed in view
->get();
You could just use the with method to get the related user like this
public function index(Request $request) {
$listings = Listing::where('is_active', true)->with(['user', 'tags'])
->orderBy('listings.created_at', 'desc')
->get();
}
but make sure that you add to your Listing model the correct relation like this
Listing Model
public function user() {
return $this->belongsTo(User::class);
}
I recommend this code for controller:
public function index(Request $request) {
return $listings = Listing::query()
->where('is_active', true)->with(['user', 'tags'])
->orderBy('listings.created_at', 'desc')
->get();
}
In the models section, I suggest you put this code:
public function user() {
return $this->belongsTo(User::class);
}
I suggest you fill in the fields foreignKey, ownerkey in relation: as in the following example:
public function user()
{
return $this->belongsTo(User::class, 'user_id', 'id');
}
I have a model customer and it has many projects. I want to find projects count without including its object.
Customer model includes:
public function numberOfProjects()
{
return $this->hasMany(Project::class)->count();
}
Query in my controller:
$customers = Customer::where(['is_active'=>1])
->with(['customerContactInformation'=> function ($query) {
$query->where('is_active',1);
}, 'numberOfProjects'])
->skip($skip)->take(10)
->get();
Its giving me error:Call to a member function addEagerConstraints() on integer
Try this
Customer Model
public function numberOfProjects()
{
return $this->hasMany(Project::class);
}
Controller
$customers = Customer::where(['is_active'=>1])
->with(['customerContactInformation'=> function ($query) {
$query->where('is_active',1);
}])
->withCount('numberOfProjects') //you can get count using this
->skip($skip)
->take(10)
->get();
That should be work
$customers = Customer::withCount('numberOfProjects')->get();
WithCount on the particular status
$customers = Customer::withCount([
'numberOfProjects',
'numberOfProjects as approved_count' => function ($query) {
$query->where('approved', true);
}
])
->get();
class Tutorial extends Model
{
function chapters()
{
return $this->hasMany('App\Chapter');
}
function videos()
{
return $this->hasManyThrough('App\Video', 'App\Chapter');
}
}
And then you can do:
Tutorial::withCount(['chapters', 'videos'])
Counting Related Models
If you want to count the number of results from a relationship without actually loading them you may use the withCount method, which will place a {relation}_count column on your resulting models. For example:
$posts = App\Post::withCount('comments')->get();
foreach ($posts as $post) {
echo $post->comments_count;
}
You may add the "counts" for multiple relations as well as add constraints to the queries:
$posts = App\Post::withCount(['votes', 'comments' => function ($query) {
$query->where('content', 'like', 'foo%');
}])->get();
echo $posts[0]->votes_count;
echo $posts[0]->comments_count;
You may also alias the relationship count result, allowing multiple counts on the same relationship:
$posts = App\Post::withCount([
'comments',
'comments as pending_comments_count' => function ($query) {
$query->where('approved', false);
}
])->get();
echo $posts[0]->comments_count;
echo $posts[0]->pending_comments_count;
If you're combining withCount with a select statement, ensure that you call withCount after the select method:
$posts = App\Post::select(['title', 'body'])->withCount('comments');
echo $posts[0]->title;
echo $posts[0]->body;
echo $posts[0]->comments_count;
I'm still learning Laravel and I can't find the solution for this problem.
I need to get invoices(with expenses) that are related to specific Partner Type.
I tried this:
$p = Project::with(['invoices.partner.partnerType' => function($query){
$query->where('partnerTypeName', 'Lieferant');
}, 'expenses'
])->where('id', $id)
->first();
I want to select invoices for Lieferant, but I get all invoices for one project.
Project Model:
public function invoices()
{
return $this->hasMany('App\Invoice');
}
Invoice Model
public function expenses()
{
return $this->hasMany('App\Expense');
}
public function partner()
{
return $this->belongsTo('App\Partner');
}
Partner Model
public function partnerType()
{
return $this->belongsTo('App\PartnerType');
}
Edit: PartnerType Model
public function partners()
{
return $this->hasMany('App\Partner');
}
Edit 2: Database
Partner(partnerID, name, partnerTypeId)
PartnerType(partnerTypeId, partnerTypeName)
Project(projectID, name)
Invoice(invoiceID, name, projectID, partnerID)
Expenses(expenseID, invoiceID)
If your models look like that.
Should be like :
$p = Project::with(['invoices' => function($query){
$query->where('partnerTypeName', 'Lieferant')
->with(['expenses','partner' => function($q){
$q->with('partnerType');
}]);
}])->where('id', $id)
->first();
return dd($p);
The solution to your problem is to update your query like this:
$p = Project::with(['invoices' => function($query){
$query->with('expenses')->whereHas('partner.partnerType', function($q){
$q->where('partnerTypeName', 'Lieferant');
});
}])
->where('id', $id)
->first();
But a cleaner solution would be using a scope for your problem.
In your Invoice model.
// Invoice.php
public function scopeByPartnerType($query, $partnerType)
{
$query->whereHas('partner.partnerType', function($q) use ($partnerType) {
$q->where('partnerTypeName', $partnerType);
});
}
And then in your Project model, add another relation that will just get Invoices with a particular partner type.
// Project.php
public function lieferantInvoices()
{
return $this->hasMany('App\Invoices')->byPartnerType('Lieferant');
}
Now you can do just this:
$project->find($id)->load('lieferantInvoices');
I've been looking at the newQuery eloquent model and best case uses and I can see the benefit in searching / filtering products based on a search page however is it possible to call the newQuery on only the Users related products?
For example, I have 2 models.
User
Product
User has many products and I have the relationship defined on the user model.
public function products() {
return $this->hasMany('App\Product');
};
Now, previously if I wanted to filter all the products and take user out of the scenario I could use:
$query = (new \App\Product)->newQuery();
if($request->get('category')){
$query->whereHas('category',function($q) use($request){
$q->where('category_id',$request->get('category'));
});
}
$products = $query->get();
This is great and I like this method and I now want to have a similar functionality on only users products.
For example, id like to:
$products = (Auth::user()->products)->newQuery();
if($request->get('category')){
$products->whereHas('category',function($q) use($request){
$q->where('category_id',$request->get('category'));
});
}
$products = $query->get();
But I can't do this I get newQuery() method is not available.
Is there a better way of performing optional queries based on parameters?
Change your code to this to make it work:
$products = Product::where('user_id', auth()->id());
if (request('category')) {
$products = $products->whereHas('category', function($q) {
$q->where('category_id', request('category'));
});
}
$products = $products->get();
Alternatively, you could just load related products using lazy eager loading:
auth()->user()->load(['products' => function($q) {
if (request('category')) {
$q->whereHas('category', function($q) {
$q->where('category_id', request('category'));
});
}
}]);
Just for a bit of neatness you can use the when() method on the builder class too
auth()->user()->products()
->when($request->category, function ($query) use ($request) {
$query->whereCategoryId($request->category);
})->get();
or
Product::whereUserId(auth()->id())
->when($request->category, function ($query) use ($request) {
$query->whereCategoryId($request->category);
})->get();
I'm developing a web API with Laravel 5.0 but I'm not sure about a specific query I'm trying to build.
My classes are as follows:
class Event extends Model {
protected $table = 'events';
public $timestamps = false;
public function participants()
{
return $this->hasMany('App\Participant', 'IDEvent', 'ID');
}
public function owner()
{
return $this->hasOne('App\User', 'ID', 'IDOwner');
}
}
and
class Participant extends Model {
protected $table = 'participants';
public $timestamps = false;
public function user()
{
return $this->belongTo('App\User', 'IDUser', 'ID');
}
public function event()
{
return $this->belongTo('App\Event', 'IDEvent', 'ID');
}
}
Now, I want to get all the events with a specific participant.
I tried with:
Event::with('participants')->where('IDUser', 1)->get();
but the where condition is applied on the Event and not on its Participants. The following gives me an exception:
Participant::where('IDUser', 1)->event()->get();
I know that I can write this:
$list = Participant::where('IDUser', 1)->get();
for($item in $list) {
$event = $item->event;
// ... other code ...
}
but it doesn't seem very efficient to send so many queries to the server.
What is the best way to perform a where through a model relationship using Laravel 5 and Eloquent?
The correct syntax to do this on your relations is:
Event::whereHas('participants', function ($query) {
return $query->where('IDUser', '=', 1);
})->get();
This will return Events where Participants have a user ID of 1. If the Participant doesn't have a user ID of 1, the Event will NOT be returned.
Read more at https://laravel.com/docs/5.8/eloquent-relationships#eager-loading
#Cermbo's answer is not related to this question. In that answer, Laravel will give you all Events if each Event has 'participants' with IdUser of 1.
But if you want to get all Events with all 'participants' provided that all 'participants' have a IdUser of 1, then you should do something like this :
Event::with(["participants" => function($q){
$q->where('participants.IdUser', '=', 1);
}])
N.B:
In where use your table name, not Model name.
for laravel 8.57+
Event::whereRelation('participants', 'IDUser', '=', 1)->get();
With multiple joins, use something like this code:
$userId = 44;
Event::with(["owner", "participants" => function($q) use($userId ){
$q->where('participants.IdUser', '=', 1);
//$q->where('some other field', $userId );
}])
Use this code:
return Deal::with(["redeem" => function($q){
$q->where('user_id', '=', 1);
}])->get();
for laravel 8 use this instead
Event::whereHas('participants', function ($query) {
$query->where('user_id', '=', 1);
})->get();
this will return events that only with partcipats with user id 1 with that event relastionship,
I created a custom query scope in BaseModel (my all models extends this class):
/**
* Add a relationship exists condition (BelongsTo).
*
* #param Builder $query
* #param string|Model $relation Relation string name or you can try pass directly model and method will try guess relationship
* #param mixed $modelOrKey
* #return Builder|static
*/
public function scopeWhereHasRelated(Builder $query, $relation, $modelOrKey = null)
{
if ($relation instanceof Model && $modelOrKey === null) {
$modelOrKey = $relation;
$relation = Str::camel(class_basename($relation));
}
return $query->whereHas($relation, static function (Builder $query) use ($modelOrKey) {
return $query->whereKey($modelOrKey instanceof Model ? $modelOrKey->getKey() : $modelOrKey);
});
}
You can use it in many contexts for example:
Event::whereHasRelated('participants', 1)->isNotEmpty(); // where has participant with id = 1
Furthermore, you can try to omit relationship name and pass just model:
$participant = Participant::find(1);
Event::whereHasRelated($participant)->first(); // guess relationship based on class name and get id from model instance
[OOT]
A bit OOT, but this question is the most closest topic with my question.
Here is an example if you want to show Event where ALL participant meet certain requirement. Let's say, event where ALL the participant has fully paid. So, it WILL NOT return events which having one or more participants that haven't fully paid .
Simply use the whereDoesntHave of the others 2 statuses.
Let's say the statuses are haven't paid at all [eq:1], paid some of it [eq:2], and fully paid [eq:3]
Event::whereDoesntHave('participants', function ($query) {
return $query->whereRaw('payment = 1 or payment = 2');
})->get();
Tested on Laravel 5.8 - 7.x