Populating select input field with value from mysql - php

My form has input fields with values populated from mysql table. In my select statement I am passing these values to the fields. The table is called person and has a unique id person_id and foreign key academy_id. Each person has a status active or inactive stored in field name person_status. I am having difficulties pulling the values from person_status for each person. How would I show the status for each person inside the select query? EXAMPLE
Select query to populate
<?php
$id = 15;
$db_select2 = $db_con->prepare("
SELECT a.name,
a.academy_id,
p.person_id,
p.person_status,
p.first_name
FROM academy a
LEFT JOIN person p ON a.academy_id = p.academy_id
WHERE a.academy_id = :id
");
if (!$db_select2) return false;
if (!$db_select2->execute(array(':id' => $id))) return false;
$results2 = $db_select2->fetchAll(\PDO::FETCH_ASSOC);
if (empty($results2)) return false;
$result2 = '';
$s = 1;
echo "<table>";
echo "<tbody>";
foreach ($results2 as $value2){
echo "<tr>";
echo "<td>Name #".$s."<input type=\"hidden\" name=\"person_id_".$s."\" value='". $person_id = $value2['person_id']."' readonly=\"readonly\"/><input id=\"person_fname_".$s."\" name=\"person_fname_".$s."\" placeholder=\"Person #".$s." First Name\" type=\"text\" value='" . $value2['first_name'] ."'/></td>";
echo "</tr>";
$s++;
}
echo "</tbody>";
echo "</table>";
?>
would like to integrate this to select statement:
<?php
$table_name2 = "person";
$column_name2 = "person_status";
echo "<select name=\"$column_name2\"><option>Select one</option>";
$sql1 = 'SHOW COLUMNS FROM '.$table_name2.' WHERE field="'.$column_name2.'"';
$row1 = $db_con->query($sql1)->fetch(PDO::FETCH_ASSOC);
$selected1 = '';
foreach(explode("','",substr($row1['Type'],6,-2)) as $option) {
if ($status == $option){
$selected1 = "selected=selected";
}else{
$selected1='';
}
echo "<option value='$option'" . $selected1. ">$option</option>";
}
echo "</select></br>";
?>

Get options only once (no need to repeat this for every person):
$sqlStatuses = 'SHOW COLUMNS FROM '.$table_name2.' WHERE field="'.$column_name2.'"';
$rowStatuses = $db_con->query($sql1)->fetch(PDO::FETCH_ASSOC);
$personStatuses = explode("','",substr($rowStatuses['Type'],6,-2));
Then, walk over the persons
foreach ($results2 as $value2) {
// Your code
echo "<tr>";
echo "<td>Name #".$s."<input type=\"hidden\" name=\"person_id_".$s."\" value='". $person_id = $value2['person_id']."' readonly=\"readonly\"/><input id=\"person_fname_".$s."\" name=\"person_fname_".$s."\" placeholder=\"Person #".$s." First Name\" type=\"text\" value='" . $value2['first_name'] ."'/></td>";
// Added
echo '<td><select name="person_status_'.$s.'">';
foreach($personStatuses as $option) {
echo '<option value="'.htmlspecialchars($option).'" ';
if ($value2['person_status'] == $option) {
echo 'selected="selected"';
}
echo '>' . htmlspecialchars($option) . '</option>';
}
echo '</select></td>';
// Your code again
echo "</tr>";
$s++;
}
Building this into one SELECT-query is unneccessary complex (although possible, but gives you unreadable code).
Oh, and take a look at htmlspecialchars(), if a name contains a "-character your HTML get screwed up

Related

showing results obtained after $_POST in a new page

I have been trying to work this out for a while.
I have created a form with a dropdown box that gets results from a database. from this i then $_POST that from to another page. From that second page i wish to get the ID number and then get the records and display them on screen.
I will then put them in a table to organise the results better.
can anyone help me in achieving this.
Here is the code for the form (which works and sends the $PlantID)
$sql = "SELECT DISTINCT * FROM PLANTS";
$result = mysqli_query($mysqli,$sql)or die(mysqli_error());
//********************* Botannical name drop down box
echo "<form name='selection' id='selection' action='profile.php' method='post'>";
echo "<select name='flower'>";
while($row = mysqli_fetch_array($result)) {
$plantid = $row['FlowerID'];
$plantname = $row['Botannical_Name'];
$plantcommon = $row['Common_Name'];
/* $plantheight = $row['Height'];
$plantav = $row['AV'];
$plantcolours = $row['Colours'];
$plantflowering = $row['Flower_Time'];
$plantspecial = $row['Special_Conditions'];
$plantfrost = $row['Frost_Hardy'];
$plantaspect = $row['Aspect'];
$plantspeed = $row['Growth_Speed'];*/
echo "<option value=".$plantid.">".$plantname." -> AKA -> ".$plantcommon."</option>";
}
echo "</select>";
echo "<br />";
//********************* End of form
echo "<input type='submit' name='submit' value='Submit'/>";
echo "</form>";
I have created this page to get the ID and display that ID on screen. AS you can tell i have probably doubled up on ways to try work this out.
$sql = "SELECT * FROM PLANTS";
$result = mysqli_query($mysqli,$sql)or die(mysqli_error());
if(isset($_POST['submit'])){
$selected_val = $_POST['Botannical_Name']; // Storing Selected Value In Variable
echo "You have selected :" .$selected_val; // Displaying Selected Value
}
echo "<br />";
echo "well:".$_POST["Botannical_Name"]."<br/>";
echo "now:".$plantquery."<br />";
echo $_POST;
echo "<table>";
foreach ($_POST as $key => $value) {
echo "<tr>";
echo "<td>";
echo $key;
echo "</td>";
echo "<td>";
echo $value;
echo "</td>";
echo "</tr>";
}
echo "</table>";
Any help would be greatly appreciated.
you should use following to get the selected value,
$selected_val = $_POST['flower'];
if(isset($_POST['submit'])){
$selected_val = $_POST['flower']; // Storing Selected Value In Variable
echo "You have selected :" .$selected_val; // Displaying Selected Value
$sql = "SELECT * FROM PLANTS WHERE FlowerID='.$selected_val.'";
$result = mysqli_query($mysqli,$sql)or die(mysqli_error());
while ($row=mysqli_fetch_assoc($result))
{
echo $row['Botannical_Name'];
}
}
echo "<br />";
print_r($_POST);
if(!empty(_POST)) {
echo "<table>";
foreach ($_POST as $key => $value) {
echo "<tr>";
echo "<td>";
echo $key;
echo "</td>";
echo "<td>";
echo $value;
echo "</td>";
echo "</tr>";
}
echo "</table>";
}

How to use MySQL query results as options in HTML forms

<?php
$con = new mysqli('localhost', 'root' ,'', 'world');
$query = 'SELECT * FROM city ORDER BY Name';
if ($result = mysqli_query($con, $query)) {
echo "<table>";
while ($row = mysqli_fetch_assoc($result)) {
echo "<tr>"
echo "<td>" . $row['Name'] . "</td>";
echo "<td>" . $row['CountryCode'] . "</td>";
echo "</tr>";
}
echo "</table>";
mysqli_free_result($result);
}
mysqli_close($con);
?>
This simple code will display every entries in this database. Now I would like to add a selective display option by choosing the CountryCode.
$query2 = 'SELECT DISTINCT CountryCode FROM city ORDER BY CountryCode';
How do I use the result I got from the query above and make it become radio buttons to choose what to display?
Similar to what you are doing already: Something like
while ($row = mysqli_fetch_assoc($result)) {
echo "<input type='radio' name='whatever' value='".$row['Name']."'>". $row['Name'];
}
Ofcourse the field names can be whatever you like them to be, as long as you select them in the query

Retrieve data from sql database and display in tables - Display certain data according to checkboxes checked

I have created an sql database(with phpmyadmin) filled with measurements from which I want to call data between two dates( the user selects the DATE by entering in the HTML forms the "FROM" and "TO" date) and display them in a table.
Additionally I have put, under my html forms, some checkboxes and by checking them you can restrict the amount of data displayed.
Each checkbox represent a column of my database; so along with the date and hour column, anything that is checked is displayed(if none is checked then everything is displayed).
So far I managed to write a php script that connects to the database, display everything when none of my checkboxes is checked and also managed to put in order one of my checkboxes.
Problem: The data that I call for are been displayed twice.
Question: I want to have four checkboxes.
Do I need to write an sql query for every possible combination or there is an easier way?
<?php
# FileName="Connection_php_mysql.htm"
# Type="MYSQL"
# HTTP="true"
$hostname_Database_Test = "localhost";
$database_Database_Test = "database_test";
$table_name = "solar_irradiance";
$username_Database_Test = "root";
$password_Database_Test = "";
$Database_Test = mysql_pconnect($hostname_Database_Test, $username_Database_Test, $password_Database_Test) or trigger_error(mysql_error(),E_USER_ERROR);
//HTML forms -> variables
$fromdate = $_POST['fyear'];
$todate = $_POST['toyear'];
//DNI CHECKBOX + ALL
$dna="SELECT DATE, Local_Time_Decimal, DNI FROM $database_Database_Test.$table_name where DATE>=\"$fromdate\" AND DATE<=\"$todate\"";
$tmp ="SELECT * FROM $database_Database_Test.$table_name where DATE>=\"$fromdate\" AND DATE<=\"$todate\"";
$entry=$_POST['dni'];
if (empty($entry))
{
$result = mysql_query($tmp);
echo
"<table border='1' style='width:300px'>
<tr>
<th>DATE</th>
<th>Local_Time_Decimal</th>
<th>Solar_time_decimal</th>
<th>GHI</th>
<th>DiffuseHI</th>
<th>zenith_angle</th>
<th>DNI</th>
";
while( $row = mysql_fetch_assoc($result))
{
echo "<tr>";
echo "<td>" . $row['DATE'] . "</td>";
echo "<td>" . $row['Local_Time_Decimal'] . "</td>";
echo "<td>" . $row['Solar_Time_Decimal'] . "</td>";
echo "<td>" . $row['GHI'] . "</td>";
echo "<td>" . $row['DiffuseHI'] . "</td>";
echo "<td>" . $row['Zenith_Angle'] . "</td>";
echo "<td>" . $row['DNI'] . "</td>";
echo "</tr>";
}
echo '</table>';}
else
{
$result= mysql_query($dna);
echo
"<table border='1' style='width:300px'>
<tr>
<th>DATE</th>
<th>Local_Time_Decimal</th>
<th>DNI</th>
";
while($row = mysql_fetch_assoc($result))
{
echo "<tr>";
echo "<td>" . $row['DATE'] . "</td>";
echo "<td>" . $row['Local_Time_Decimal']."</td>";
echo "<td>" . $row['DNI'] . "</td>";
echo "</tr>";
}
echo '</table>';
}
if($result){
echo "Successful";
}
else{
echo "Enter correct dates";
}
?>
<?php
mysql_close();
?>
Try to create your checkbox like below:
Solar_Time_Decimal<checkbox name='columns[]' value='1'>
GHI<checkbox name='columns[]' value='2'>
DiffuseHI<checkbox name='columns[]' value='3'>
Zenith_Angle<checkbox name='columns[]' value='4'>
DNI<checkbox name='columns[]' value='5'>
And try to hange your PHP code to this:
<?php
//HTML forms -> variables
$fromdate = isset($_POST['fyear']) ? $_POST['fyear'] : data("d/m/Y");
$todate = isset($_POST['toyear']) ? $_POST['toyear'] : data("d/m/Y");
$all = false;
$column_names = array('1' => 'Solar_Time_Decimal', '2'=>'GHI', '3'=>'DiffuseHI', '4'=>'Zenith_Angle','5'=>'DNI');
$column_entries = isset($_POST['columns']) ? $_POST['columns'] : array();
$sql_columns = array();
foreach($column_entries as $i) {
if(array_key_exists($i, $column_names)) {
$sql_columns[] = $column_names[$i];
}
}
if (empty($sql_columns)) {
$all = true;
$sql_columns[] = "*";
} else {
$sql_columns[] = "DATE,Local_Time_Decimal";
}
//DNI CHECKBOX + ALL
$tmp ="SELECT ".implode(",", $sql_columns)." FROM $database_Database_Test.$table_name where DATE>=\"$fromdate\" AND DATE<=\"$todate\"";
$result = mysql_query($tmp);
echo "<table border='1' style='width:300px'>
<tr>
<th>DATE</th>
<th>Local_Time_Decimal</th>";
foreach($column_names as $k => $v) {
if($all || (is_array($column_entries) && in_array($k, $column_entries)))
echo "<th>$v</th>";
}
echo "</tr>";
while( $row = mysql_fetch_assoc($result))
{
echo "<tr>";
echo "<td>" . $row['DATE'] . "</td>";
echo "<td>" . $row['Local_Time_Decimal'] . "</td>";
foreach($column_names as $k => $v) {
if($all || (is_array($column_entries) && in_array($k, $column_entries))) {
echo "<th>".$row[$v]."</th>";
}
}
echo "</tr>";
}
echo '</table>';
if($result){
echo "Successful";
}
else{
echo "Enter correct dates";
}
?>
<?php
mysql_close();?>
This solution consider your particular table columns but if your wish a generic solution you can try to use this SQL too:
$sql_names = "SELECT COLUMN_NAME FROM INFORMATION_SCHEMA.COLUMNS WHERE TABLE_SCHEMA = '$database_Database_Test' AND TABLE_NAME = '$table_name'";
and use the result to construct the $column_names array.
Solution for your problem : Change the mysql_fetch_assoc with mysql_fetch_array
If you have the same problem try to print your result with print_r
Answer : Use the bit datatype in mysql for store and read your checkboxes.
When you're receiving thr value from the database then you can use
in the parameter checked you can use the php code as exist :
$value = ...get the value from db ( 1 or 0 )
echo '<input type="checkbox" name="thename" value="thevalue" '.($value==1?'checked=checked'.'').'/>';

Create hyperlink on table result and fill editable form in other page

I'm having problems to find how to create an hyperlink in a table column result and then, on click, open another page with all fields (textboxes) filled. Imagine when a click an ID, i do a select * from table where column_id = ID... Is there a way to do it?
Thanks.
Best regards
I'm not completely sure what you are asking, but this may help you a bit.
First make a Javascript.
<script type="text/JavaScript">
function selectID() {
var ID = document.getElementById("ID").value;
document.location.href ="yoursite.php?ID="+ID;
}
</script>
Then connect to your database to query the table for a link ID (or more) for example by changing the variable $value.
<?php
//Connect to database
mysql_connect("host", "user", "pass");
mysql_select_db("db_name");
$value = 'something';
$ID = $_GET['ID'];
if (!$ID) {
$ID = 0;
}
if ($ID == 0) {
$query = "SELECT * FROM table WHERE `column_1` = '$value'";
$result = mysql_query($query);
echo "<table>";
while($myrow = mysql_fetch_array($result)) {
echo "<tr>";
echo "<td>";
echo "ID";
echo "</td>";
echo "</tr>";
}
echo "</table>";
}
elseif ($ID > 0) {
$query2 = "SELECT * FROM table WHERE `column_id` = '$ID'";
$result2 = mysql_query($query2);
while($myrow2 = mysql_fetch_array($result2)) {
$value1 = $myrow2['column_1'];
$value2 = $myrow2['column_2'];
}
echo "<form type=\"GET\" action=\"$PHP_SELF\">";
echo "<input type=\"text\" id=\"ID\" name=\"ID\" value=\"$ID\"><br>";
echo "<input type=\"text\" id=\"value1\" name=\"value1\" value=\"$value1\"><br>";
echo "<input type=\"text\" id=\"value2\" name=\"value2\" value=\"$value2\"><br>";
echo "<input type=\"hidden\" id=\"search\" name=\"search\" value=\"searching\">";
echo "<input type=\"submit\" id=\"submitbutton\" name=\"submitbutton\" value=\" Search \">";
echo "</form>";
}
?>

Updating MYSQL DB with checkbox and textarea data (in PHP)

I'm using a table to update a database, the table has 264 checkboxes which can be checked and unchecked then updated on the database.
I'm doing this by posting data on the form, using a while loop to set all fields to blank ( the value of the checkbox and the textarea value) for each respective field, then using a foreach loop to update each row in the database with the value of the checkbox.
Now, what I want to do is add the textarea value for each ticked checkbox into the database as well, what i cant figure out is how to do this?
This is my update code:
if (isset($_POST["update"])) {
$seolistRes2 = mysql_query($seolistQ) or die(mysql_error());
while ($seolistRow2 = mysql_fetch_array($seolistRes2)) {
$wsID1 = $seolistRow2["worksheetID"];
$updateWSQ2 = "UPDATE seo_work SET taskValue=0, taskInfo='' WHERE worksheetID=$wsID1 AND userID=$userID";
mysql_query($updateWSQ2) or die(mysql_error());
}
$item = $_POST;
foreach($item as $key => $value) {
$wsID = str_replace("checkbox","",$key);
if (is_numeric($wsID)) {
$updateWSQ = "UPDATE seo_work SET taskValue=$value taskInfo=$value WHERE worksheetID=$wsID AND userID=$userID";
mysql_query($updateWSQ) or die(mysql_error());
header("Location: worksheet.php?y=".$seoworkyear."&userID=$userID&action=success");
}
}
}
This is checkbox and textarea code: (please note this is within a form)
$currentTask = '';
echo "<tr class='tr'>";
while ($seolistRow = mysql_fetch_array($seolistRes)) {
$taskValue = $seolistRow["taskValue"];
$worksheetID = $seolistRow["worksheetID"];
$taskName = $seolistRow["taskName"];
$taskInfo = $seolistRow["taskInfo"];
if ($taskValue == 1) {
$taskDone = "<input type='checkbox' value='1' class='checkbox' name='checkbox".$worksheetID."' id=checkbox'".$worksheetID."' checked='checked' />".
"<textarea class='textarea' name='textarea".$worksheetID."' id=textarea'".$worksheetID."'>" . $taskInfo . "</textarea>";
}
else {
$taskDone = "<input type='checkbox' value='1' class='checkbox' name='checkbox".$worksheetID."' id='checkbox".$worksheetID."' />".
"<textarea class='textarea' name='textarea".$worksheetID."' id=textarea'".$worksheetID."'>" . $taskInfo . "</textarea>";
}
if ($currentTask != $taskName) {
echo "</tr>";
echo "<tr class='tr'>";
echo "<td class='task'>".$taskName."</td>";
}
echo "<td class='tick'>".$taskDone."</td>";
$currentTask = $taskName;
}
echo "</tr>";
Use your HTML form like shown below.
$currentTask = '';
echo "<tr class='tr'>";
while ($seolistRow = mysql_fetch_array($seolistRes)) {
$taskValue = $seolistRow["taskValue"];
$worksheetID = $seolistRow["worksheetID"];
$taskName = $seolistRow["taskName"];
$taskInfo = $seolistRow["taskInfo"];
if ($taskValue == 1) {
$taskDone = "<input type='checkbox' value='1' class='checkbox' name='checkbox[".$worksheetID."]' id='checkbox[".$worksheetID."]' checked='checked' />".
"<textarea class='textarea' name='textarea[".$worksheetID."]' id='textarea[".$worksheetID."]'>" . $taskInfo . "</textarea>";
}
else {
$taskDone = "<input type='checkbox' value='1' class='checkbox' name='checkbox[".$worksheetID."]' id='checkbox[".$worksheetID."]' />".
"<textarea class='textarea' name='textarea[".$worksheetID."]' id='textarea[".$worksheetID."]'>" . $taskInfo . "</textarea>";
}
if ($currentTask != $taskName) {
echo "</tr>";
echo "<tr class='tr'>";
echo "<td class='task'>".$taskName."</td>";
}
echo "<td class='tick'>".$taskDone."</td>";
$currentTask = $taskName;
}
echo "</tr>";
See the modified name and id of your textarea and checkbox. I have modified it to textarea[SOME_WORKSHEET_ID] and checkbox[SOME_WORKSHEET_ID] respectively.
So, when you submit the form, you will receive those checkbox and textarea value as an array, with worksheetId as an index. You can use this [] technique to retrieve the values of the textarea and checkbox, or as many field you want to add in form.
Use above HTML structure and check the $_POST array.
Hope this will help..
Thanks!
Hussain.
You should be able to get the value in the textarea using $_POST['textarea' . $wsID] after your call to is_numeric.
Here is another approach, not completely tested, but hopefully you get the idea...
if (isset($_POST["update"]))
{
// All to blank
$seolistRes2 = mysql_query($seolistQ) or die(mysql_error());
while ($seolistRow2 = mysql_fetch_array($seolistRes2))
{
$wsID1 = $seolistRow2["worksheetID"];
$updateWSQ2 = "UPDATE seo_work SET taskValue=0, taskInfo='' WHERE worksheetID=$wsID1 AND userID=$userID";
mysql_query($updateWSQ2) or die(mysql_error());
}
// Re use your result from the select to go through all the known IDs
foreach($seolistRow2 as $i => $data)
{
// Obtain the ID
$id = $data['worksheetID'];
// Get the checkbox value for current ID
$checkbox_wsID = $_POST['checkbox' . $id];
// Get the textarea value for current ID
$textarea_wsID = $_POST['textarea' . $id];
// Update the Row using mysql_escape
$updateWSQ = "UPDATE seo_work " .
"SET taskValue = '" . mysql_escape_string($checkbox_wsID) ."' taskInfo = '" . mysql_escape_string($textarea_wsID) ."'" .
"WHERE worksheetID=$id AND userID=$userID";
mysql_query($updateWSQ)
or die(mysql_error());
header("Location: worksheet.php?y=".$seoworkyear."&userID=$userID&action=success");
}
}

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