I'm using a table to update a database, the table has 264 checkboxes which can be checked and unchecked then updated on the database.
I'm doing this by posting data on the form, using a while loop to set all fields to blank ( the value of the checkbox and the textarea value) for each respective field, then using a foreach loop to update each row in the database with the value of the checkbox.
Now, what I want to do is add the textarea value for each ticked checkbox into the database as well, what i cant figure out is how to do this?
This is my update code:
if (isset($_POST["update"])) {
$seolistRes2 = mysql_query($seolistQ) or die(mysql_error());
while ($seolistRow2 = mysql_fetch_array($seolistRes2)) {
$wsID1 = $seolistRow2["worksheetID"];
$updateWSQ2 = "UPDATE seo_work SET taskValue=0, taskInfo='' WHERE worksheetID=$wsID1 AND userID=$userID";
mysql_query($updateWSQ2) or die(mysql_error());
}
$item = $_POST;
foreach($item as $key => $value) {
$wsID = str_replace("checkbox","",$key);
if (is_numeric($wsID)) {
$updateWSQ = "UPDATE seo_work SET taskValue=$value taskInfo=$value WHERE worksheetID=$wsID AND userID=$userID";
mysql_query($updateWSQ) or die(mysql_error());
header("Location: worksheet.php?y=".$seoworkyear."&userID=$userID&action=success");
}
}
}
This is checkbox and textarea code: (please note this is within a form)
$currentTask = '';
echo "<tr class='tr'>";
while ($seolistRow = mysql_fetch_array($seolistRes)) {
$taskValue = $seolistRow["taskValue"];
$worksheetID = $seolistRow["worksheetID"];
$taskName = $seolistRow["taskName"];
$taskInfo = $seolistRow["taskInfo"];
if ($taskValue == 1) {
$taskDone = "<input type='checkbox' value='1' class='checkbox' name='checkbox".$worksheetID."' id=checkbox'".$worksheetID."' checked='checked' />".
"<textarea class='textarea' name='textarea".$worksheetID."' id=textarea'".$worksheetID."'>" . $taskInfo . "</textarea>";
}
else {
$taskDone = "<input type='checkbox' value='1' class='checkbox' name='checkbox".$worksheetID."' id='checkbox".$worksheetID."' />".
"<textarea class='textarea' name='textarea".$worksheetID."' id=textarea'".$worksheetID."'>" . $taskInfo . "</textarea>";
}
if ($currentTask != $taskName) {
echo "</tr>";
echo "<tr class='tr'>";
echo "<td class='task'>".$taskName."</td>";
}
echo "<td class='tick'>".$taskDone."</td>";
$currentTask = $taskName;
}
echo "</tr>";
Use your HTML form like shown below.
$currentTask = '';
echo "<tr class='tr'>";
while ($seolistRow = mysql_fetch_array($seolistRes)) {
$taskValue = $seolistRow["taskValue"];
$worksheetID = $seolistRow["worksheetID"];
$taskName = $seolistRow["taskName"];
$taskInfo = $seolistRow["taskInfo"];
if ($taskValue == 1) {
$taskDone = "<input type='checkbox' value='1' class='checkbox' name='checkbox[".$worksheetID."]' id='checkbox[".$worksheetID."]' checked='checked' />".
"<textarea class='textarea' name='textarea[".$worksheetID."]' id='textarea[".$worksheetID."]'>" . $taskInfo . "</textarea>";
}
else {
$taskDone = "<input type='checkbox' value='1' class='checkbox' name='checkbox[".$worksheetID."]' id='checkbox[".$worksheetID."]' />".
"<textarea class='textarea' name='textarea[".$worksheetID."]' id='textarea[".$worksheetID."]'>" . $taskInfo . "</textarea>";
}
if ($currentTask != $taskName) {
echo "</tr>";
echo "<tr class='tr'>";
echo "<td class='task'>".$taskName."</td>";
}
echo "<td class='tick'>".$taskDone."</td>";
$currentTask = $taskName;
}
echo "</tr>";
See the modified name and id of your textarea and checkbox. I have modified it to textarea[SOME_WORKSHEET_ID] and checkbox[SOME_WORKSHEET_ID] respectively.
So, when you submit the form, you will receive those checkbox and textarea value as an array, with worksheetId as an index. You can use this [] technique to retrieve the values of the textarea and checkbox, or as many field you want to add in form.
Use above HTML structure and check the $_POST array.
Hope this will help..
Thanks!
Hussain.
You should be able to get the value in the textarea using $_POST['textarea' . $wsID] after your call to is_numeric.
Here is another approach, not completely tested, but hopefully you get the idea...
if (isset($_POST["update"]))
{
// All to blank
$seolistRes2 = mysql_query($seolistQ) or die(mysql_error());
while ($seolistRow2 = mysql_fetch_array($seolistRes2))
{
$wsID1 = $seolistRow2["worksheetID"];
$updateWSQ2 = "UPDATE seo_work SET taskValue=0, taskInfo='' WHERE worksheetID=$wsID1 AND userID=$userID";
mysql_query($updateWSQ2) or die(mysql_error());
}
// Re use your result from the select to go through all the known IDs
foreach($seolistRow2 as $i => $data)
{
// Obtain the ID
$id = $data['worksheetID'];
// Get the checkbox value for current ID
$checkbox_wsID = $_POST['checkbox' . $id];
// Get the textarea value for current ID
$textarea_wsID = $_POST['textarea' . $id];
// Update the Row using mysql_escape
$updateWSQ = "UPDATE seo_work " .
"SET taskValue = '" . mysql_escape_string($checkbox_wsID) ."' taskInfo = '" . mysql_escape_string($textarea_wsID) ."'" .
"WHERE worksheetID=$id AND userID=$userID";
mysql_query($updateWSQ)
or die(mysql_error());
header("Location: worksheet.php?y=".$seoworkyear."&userID=$userID&action=success");
}
}
Related
What I want to do is to display values from database on checkbox labels. I already did that part:
$acc = $truckerController->GetAccessory();
$acc_result = "<form action='' method='post'>";
foreach ($acc as $value) {
$id = $value->id;
$device = $value->device;
$acc_result .= "<input type='checkbox' name='$device' id='$device' value='$id'>"
. "<label for='$device'>$device</label> ";
}
$acc_result .= "<input type='submit' name='acc_submit' value='submit'><form/>";
echo $acc_result;
but what I want to accomplish is when submitting checked values I can't seem to get the checked values.
if (isset($_POST["acc_submit"])) {
echo $_POST["$device"];
}
Help please!
I'm having problems to find how to create an hyperlink in a table column result and then, on click, open another page with all fields (textboxes) filled. Imagine when a click an ID, i do a select * from table where column_id = ID... Is there a way to do it?
Thanks.
Best regards
I'm not completely sure what you are asking, but this may help you a bit.
First make a Javascript.
<script type="text/JavaScript">
function selectID() {
var ID = document.getElementById("ID").value;
document.location.href ="yoursite.php?ID="+ID;
}
</script>
Then connect to your database to query the table for a link ID (or more) for example by changing the variable $value.
<?php
//Connect to database
mysql_connect("host", "user", "pass");
mysql_select_db("db_name");
$value = 'something';
$ID = $_GET['ID'];
if (!$ID) {
$ID = 0;
}
if ($ID == 0) {
$query = "SELECT * FROM table WHERE `column_1` = '$value'";
$result = mysql_query($query);
echo "<table>";
while($myrow = mysql_fetch_array($result)) {
echo "<tr>";
echo "<td>";
echo "ID";
echo "</td>";
echo "</tr>";
}
echo "</table>";
}
elseif ($ID > 0) {
$query2 = "SELECT * FROM table WHERE `column_id` = '$ID'";
$result2 = mysql_query($query2);
while($myrow2 = mysql_fetch_array($result2)) {
$value1 = $myrow2['column_1'];
$value2 = $myrow2['column_2'];
}
echo "<form type=\"GET\" action=\"$PHP_SELF\">";
echo "<input type=\"text\" id=\"ID\" name=\"ID\" value=\"$ID\"><br>";
echo "<input type=\"text\" id=\"value1\" name=\"value1\" value=\"$value1\"><br>";
echo "<input type=\"text\" id=\"value2\" name=\"value2\" value=\"$value2\"><br>";
echo "<input type=\"hidden\" id=\"search\" name=\"search\" value=\"searching\">";
echo "<input type=\"submit\" id=\"submitbutton\" name=\"submitbutton\" value=\" Search \">";
echo "</form>";
}
?>
Am new to php... I have been battling on my dynamic checkboxes in such a way that if none is checked the form is return, also I need to retain what was checked when the form postback due to other invalid inputs.
$result = mysql_query("SELECT * FROM course") or die(mysql_error());
if ($result)
{
while ($row = mysql_fetch_array($result)){
if (isset($_POST['courses']) and $_POST['courses'] == $row['cid']) {echo $row['cid'];}
print "<input type=\"checkbox\" name=\"courses[]\" value=\"$row[cid]\">$row[cname]\n";
}
}
Help needed purely on php codes. Thanks in advance
Do this where the checkbox appears in the HTML on your php page:
<?php
$checked = isset($_POST["checkboxname"]) ? " checked" : '' ;
echo "<input type='checkbox' name='checkboxname' value='yes'" . $checked . ">";
?>
This will retain the checkbox state after the form has been posted.
UPDATE:
For your code, just do it like this, I think:
$result = mysql_query("SELECT * FROM course") or die(mysql_error());
if ($result) {
while ($row = mysql_fetch_array($result)) {
$checked = '';
/* ERROR: if (isset($_POST['courses']) and $_POST['courses'] == $row['cid']) { */
if (isset($_POST['courses']) {
if (in_array($row['cid'], $_POST['courses']) {
echo $row['cid'];
$checked = " checked";
}
}
echo "<input type=\"checkbox\" name=\"courses[]\" value=\"$row[cid]\"" . $checked . ">$row['cname']\n";
}
}
EDIT: The condition needs to change too, I think, as I show in the code above.
i try to make checkboxes. When i click checkbox it makes isPremium = 1 if i click a checked checkbox it makes isPremium = 0
However: when i click a checked checkbox it does not work..
<meta http-equiv="Content-Type" content="text/html; charset=utf-8" />
<?php
require 'connectDB.php';
$mysql = new mysql();
$mysql->connect();
$dbResult = mysql_query("select * from profiles");
echo "<form action='#' method='post'>";
$dbResult = mysql_query("select * from profiles");
while ($info = mysql_fetch_array($dbResult)) {
if ($info['isPremium'] == 0)
echo "<input type=checkbox name='check2[]' id='check2' value=" . $info['id'] . ">";
else
echo "<input type=checkbox name='check1[]' id='check1' value=" . $info['id'] . " checked>";
echo $info['profileName'] . "<br />";
}
echo "<p><input type='submit' name='btnPremium' /></p>";
echo "</form>";
if (isset($_POST['btnPremium'])) {
if (isset($_POST['check2'])) {
$arrPremium = $_POST['check2'];
foreach ($arrPremium as $result) {
mysql_query("UPDATE profiles set isPremium=1 where id=" . $result . "");
}
}
else
{
$arrPremium = $_POST['check1'];
foreach ($arrPremium as $result2) {
mysql_query("UPDATE profiles set isPremium=0 where id=" . $result2 . "");
}
}
}
?>
when i click a checked checkbox it makes another checkbox unclick.
This is the checkbox page
I have refactored your code into this:
<meta http-equiv="Content-Type" content="text/html; charset=utf-8" />
<?php
require 'connectDB.php';
$mysql = new mysql();
$mysql->connect();
$update = (isset($_POST['check']) && is_array($_POST['check']));
$dbResult = mysql_query("select * from profiles");
echo "<form action='#' method='post'>";
while ($info = mysql_fetch_array($dbResult))
{
if ($update)
{
$info['isPremium'] = (in_array($info['id'], $_POST['check']) ? 1 : 0);
mysql_query("UPDATE profiles SET isPremium = " . $info['isPremium'] . " WHERE id = " . $info['id']);
}
echo "<input type=checkbox name='check[]' value=" . $info['id'] . ($info['isPremium'] == 0 ? "" : "checked") . " />";
echo htmlspecialchars($info['profileName']) . "<br />";
}
echo "<p><input type='submit' name='btnPremium' /></p>";
echo "</form>";
?>
There were several problems with your original code:
Several HTML input elements with the same ID. This is wrong. We can have several elements with the same name attribute, but the id attribute should be unique for each element.
The database UPDATE code runs after displaying the form. This is wrong. In this case, we should update the database prior to generating the HTML output.
IMPORTANT: There is no need of two different POST arrays (check1 and check2). We only need one array. The checked boxes will be posted by the browser. The unchecked boxes will not be posted by the browser. As the id is the value, we can use the in_array function to verify if the checkbox for an item was checked or not.
It is a good idea to escape things you will output as HTML from the database. Otherwise, the application is vulnerable for some kinds of attack. The function htmlspecialchars is useful for this purpose.
If I understand correctly what you're trying to achieve, your code is needlessly complicated. You should use isset to check whether the value of a checkbox was included in the $_POST array. If yes, the checkbox was checked.
<meta http-equiv="Content-Type" content="text/html; charset=utf-8" />
<?php
require 'connectDB.php';
$mysql = new mysql();
$mysql->connect();
echo "<form action='#' method='post'>";
$dbResult = mysql_query("SELECT * FROM profiles");
$profileid = array();
while ($info = mysql_fetch_array($dbResult)) {
echo "<input type=\"checkbox\" name=\"" . $info['id'] . "\" " . ($info['isPremium'] != 0 ? "checked " : "") . "/>";
echo $info['profileName'] . "<br />";
$profileid[] = $info['id'];
}
echo "<p><input type='submit' name='btnPremium' /></p>";
echo "</form>";
if (isset($_POST['btnPremium'])) {
foreach ($profileid as $id) {
if (isset($_POST[$id])) {
mysql_query("UPDATE profiles SET isPremium=1 WHERE id=" . $id);
} else {
mysql_query("UPDATE profiles SET isPremium=0 WHERE id=" . $id);
}
}
}
?>
Checkboxes typically send the value "on" to the server, regardless of what value attribute is set. If you can, try to use radio buttons instead, as these send the proper value to the server. If that's not an option, have the name of the checkbox be check1[".$info['id']." and access array_keys($_POST['check1']).
I've been trying think of a way to do this. I want it to where users can check off items, hit submit and it goes to the code on the next page and deletes all of the checked items from the database. Problem one is that in the post its only sending over the last checked item. Here is how I have it set up right now.
echo "<form name='fm1' METHOD ='POST' ACTION ='displaydelete.php' > ";
//Draws up the table headers
echo "";
echo "";
echo "Fund Number ";
echo "Hours ";
echo "Percentage";
echo "Delete";
echo "";
//While there are query results data is pushed into table cells
while ($row = mysql_fetch_array($queryResult2))
{
$hours = $row['hours'];
$percentage = $hours / 160 * 100;
echo "<tr>";
echo "<td>";
echo $row['funnumber'];
echo "</td>";
echo "<td>";
echo $hours;
echo "</td>";
echo "<td>";
echo $percentage ."%";
echo "</td>";
echo "<td>";
echo "<input type='checkbox' name='id' value='$row[id]'/>";
echo "</td>";
echo "</tr>";
}
//End of tabel
echo "</table>";
echo" ";
echo "";
What I would like to do is push all of the items into a variable and maybe delete them that way. I'm not really sure how you would handle multiple deletes. I'm doing my delete like this for something else if this helps any.
$query = "DELETE FROM users
WHERE ninenumber = '$ninenumber'";
$result = mysql_query($query)
or die("Query Failed: " .mysql_error());
mysql_close($conn);
In your form:
<input type='checkbox' name='id[]' value='$row[id]'/>
Then, in the file you post to:
if(is_array($_POST['id'])){
foreach($_POST['id'] as $id){
...do something to $id;
}
}
Instead of this:
echo "<input type='checkbox' name='id' value='$row[id]'/>";
You need this:
echo "<input type='checkbox' name='id[]' value='$row[id]'/>";
Note the difference. I added [] after the input name. This tells the client and server that there are multiple inputs with that name. $_POST['id'] will be an array you can loop through on the next page.
foreach ($_POST['id'] as $checkbox) {
// DELETE FROM users WHERE ninenumber = $checkbox
}
isset, is_array, and mysql_real_escape_string omitted for brevity.
In the form-generating code, make the name in the html have" []" after it:
...
echo "<input type='checkbox' name='id[]' value='$row[id]'/>";
...
Then, in the form-reading code, your post'ed id will be an array.
$id_array = isset($_POST['id']) && is_array($_POST['id']) ? $_POST['id'] : array();
foreach( $id_array as $id ) {
$query = "DELETE FROM users WHERE ninenumber = '" . mysql_real_escape_string($id) . "'";
// execute the delete query
}
Putting [] after the name of a control will turn it into an array in the superglobal that you can then iterate over to get all the values from.
You need to have the same name for all of your checkboxes, then all values are passed as array POST variable.
<input type='checkbox' name='id[]' value='$row[id]'/>
Change
name=id
to
name=id[]
this will then give you an array.