So i've been trying to get this bit of code to work all day and haven't been able to do it... I wnat to be able to replace letters with a number (or just a value) from an array. this is the code i've got:
$l2n =
array(
'a'=>'1',
'b'=>'2',
'c'=>'3',
'd'=>'4',
'e'=>'5',
'f'=>6,
'g'=>7,
'h'=>8,
'i'=>9,
'j'=>10,
'k'=>11,
'l'=>12,
'm'=>13,
'n'=>14,
'o'=>15,
'p'=>16,
'q'=>17,
'r'=>18,
's'=>19,
't'=>20,
'u'=>21,
'v'=>22,
'w'=>23,
'x'=>24,
'y'=>25,
'z'=>16
);
$string = str_split($string);
$explode = array_shift($string);
if($l2n[$explode] == $explode)
{
echo $l2n[$explode];
}
else
{
echo $l2n['a'];
}
I tried to use Preg_replace but i've never had a good expereince with that function. so If anybody could help me out, hint me in the correct direction, that'd be great.
You can just use str_replace once you've used array_keys and array_values to get each side of the array:
$keys = array_keys($l2n);
$values = array_values($l2n);
$yourstring = 'Hello world!';
echo str_replace($keys, $values, $yourstring);
// H5121215 231518124!
Demo: https://eval.in/77453
Docs:
http://php.net/str_replace
http://php.net/array_keys
http://php.net/array_values
You can simply do:
$string = preg_replace(array_keys($l2n), array_values($l2n), $string);
From the documentation:
If both pattern and replacement parameters are arrays, each pattern will be replaced by the replacement counterpart.
Why in the world would you use an array for this? Isn't ord() what you are looking for here?
$string = "ABCDE";
foreach ( str_split($string) as $chr ) {
echo ord($chr) - 64; // or 97 if they all are lowercase
echo PHP_EOL;
}
Related
I'm trying to get all numeric before space/alpha in PHP string.
Example:
<?php
//string
$firstStr = '12 Car';
$secondStr = '412 8all';
$thirdStr = '100Pen';
//result I need
firstStr = 12
SecondStr = 412
thirdStr = 100
How do I can get all the number of a string just like example above?
I've an idea to get the position of first Alpha, then get all numeric before that position.
I've successfully get the position using
preg_match('~[a-z]~i', $value, $match, PREG_OFFSET_CAPTURE);
But I'm not done yet to get the numeric before the posisition.
How do I can do that, or anybody know how to fix my idea?
Anyhelp will be appreciated.
You don't need to use regex for strings like the examples you've shown, or any functions at all for that matter. You can just cast them to ints.
$number = (int) $firstStr; // etc.
The PHP rules for string conversion to number will handle it for you.
However, because of those rules, there are some other types of strings that this won't work for. For example, '-12 Car' or '412e2 8all'.
If you do use a regex, be sure to anchor it to the beginning of the string with ^ or it will match digits anywhere in the string as the other regex answers here do.
preg_match('/^\d+/', $string, $match);
$number = $match[0] ?? '';
Here's an extremely hackish approach that will work in most situations:
$s = "1001BigHairyCamels";
$n = intval($s);
$my_number = str_replace($n, '', $s);
$input = '100Pen';
if (preg_match('~(\d+)[ a-zA-Z]~', $input, $m)) {
echo $m[1];
}
This function will do the job!
<?php
function getInt($str){
preg_match_all('!\d+!', $str, $matches);
return $matches[0][0];
}
$firstStr = '12 Car';
$secondStr = '412 8all';
$thirdStr = '100Pen';
echo 'firstStr = '.getInt($firstStr).'<br>';
echo 'secondStr = '.getInt($secondStr).'<br>';
echo 'thirdStr = '.getInt($thirdStr);
?>
I'm using PHP's preg_replace, and trying to transform the string
abcd
into
(a(b(c(d))))
This is the best I've got:
preg_replace('/.(?=(.*$))/', '$0($1)', 'abcd');
// a(bcd)b(cd)c(d)d()
Is it even possible with regex?
Edit I've just discovered this in the PCRE spec: Replacements are not subject to re-matching, so my original approach isn't going to work. I wanted to keep it all regex because there's some more complicated matching logic in my actual use case.
How about:
preg_replace('/./s', '($0', 'abcd') . str_repeat(')', strlen('abcd'));
?
(Does that count as "with regex"?)
You can use preg_match_all. Not sure what kind of characters you want, though. So I'll give an example for all characters:
$val = 'abcd1234';
$out = '';
if(preg_match_all('#.#', $val, $matches))
{
$i = 0; // we'll use this to keep track of how many open paranthesis' we have
foreach($matches[0] as &$v)
{
$out .= '('.$v;
$i++;
}
$out .= str_repeat(")", $i);
}
else
{
// no matches found or error occured
}
echo $out; // (a(b(c(d(1(2(3(4))))))))
Will be easy to customise further, as well.
This is my way to do it =) :
<?php
$arr = str_split("abcd");
$new_arr = array_reverse($arr);
foreach ($new_arr as $a) {
$str = sprintf('(%s%s)', $a, $str);
}
echo "$str\n";
?>
KISS isn't it ? (few lines : 6)
I went with something along the lines of a combination of the above answers:
preg_match_all('/./ui', 'abcd', $matches);
$matches = $matches[0];
$string = '('.implode('(', $matches).str_repeat(')', count($matches));
I've got this string, but I need to remove specific things out of it...
Original String: hr-165-34.sh-290-92.ch-215-84.hd-180-1.lg-280-64.
The string I need: sh-290-92.ch-215-84.lg-280-64.
I need to remove hr-165-34. and hd-180-1.
!
EDIT: Ahh ive hit a snag!
the string always changes, so the bits i need to remove like "hr-165-34." always change, it will always be "hr-SOMETHING-SOMETHING."
So the methods im using wont work!
Thanks
Depends on why you want to remove exactly those Substrigs...
If you always want to remove exactly those substrings, you can use str_replace
If you always want to remove the characters at the same position, you can use substr
If you always want to remove substrings between two dots, that match certain criteria, you can use preg_replace
$str = 'hr-165-34.sh-290-92.ch-215-84.hd-180-1.lg-280-64';
$new_str = str_replace(array('hr-165-34.', 'hd-180-1.'), '', $str);
Info on str_replace.
The easiest and quickest way of doing this is to use str_replace
$ostr = "hr-165-34.sh-290-92.ch-215-84.hd-180-1.lg-280-64";
$nstr = str_replace("hr-165-34.","",$ostr);
$nstr = str_replace("hd-180-1.","",$nstr);
<?php
$string = 'hr-165-34.sh-290-92.ch-215-84.hd-180-1.lg-280-64';
// define all strings to delete is easier by using an array
$delete_substrings = array('hr-165-34.', 'hd-180-1.');
$string = str_replace($delete_substrings, '', $string);
assert('$string == "sh-290-92.ch-215-84.lg-280-64" /* Expected result: string = "sh-290-92.ch-215-84.lg-280-64" */');
?>
Ive figured it out!
$figure = $q['figure']; // hr-165-34.sh-290-92.ch-215-84.hd-180-1.lg-280-64
$s = $figure;
$matches = array();
$t = preg_match('/hr(.*?)\./s', $s, $matches);
$s = $figure;
$matches2 = array();
$t = preg_match('/hd(.*?)\./s', $s, $matches2);
$s = $figure;
$matches3 = array();
$t = preg_match('/ea(.*?)\./s', $s, $matches3);
$str = $figure;
$new_str = str_replace(array($matches[0], $matches2[0], $matches3[0]), '', $str);
echo($new_str);
Thanks guys!
$string = 'test check one two test3';
$result = mb_eregi_replace ( 'test|test2|test3' , '<$1>' ,$string ,'i');
echo $result;
This should deliver: <test> check one two <test3>
Is it possible to get, that test and test3 was found, without using another match function ?
You can use preg_replace_callback instead:
$string = 'test check one two test3';
$matches = array();
$result = preg_replace_callback('/test|test2|test3/i' , function($match) use ($matches) {
$matches[] = $match;
return '<'.$match[0].'>';
}, $string);
echo $result;
Here preg_replace_callback will call the passed callback function for each match of the pattern (note that its syntax differs from POSIX). In this case the callback function is an anonymous function that adds the match to the $matches array and returns the substitution string that the matches are to be replaced by.
Another approach would be to use preg_split to split the string at the matched delimiters while also capturing the delimiters:
$parts = preg_split('/test|test2|test3/i', $string, null, PREG_SPLIT_DELIM_CAPTURE);
The result is an array of alternating non-matching and matching parts.
As far as I know, eregi is deprecated.
You could do something like this:
<?php
$str = 'test check one two test3';
$to_match = array("test", "test2", "test3");
$rep = array();
foreach($to_match as $val){
$rep[$val] = "<$val>";
}
echo strtr($str, $rep);
?>
This too allows you to easily add more strings to replace.
Hi following function used to found the any word from string
<?php
function searchword($string, $words)
{
$matchFound = count($words);// use tha no of word you want to search
$tempMatch = 0;
foreach ( $words as $word )
{
preg_match('/'.$word.'/',$string,$matches);
//print_r($matches);
if(!empty($matches))
{
$tempMatch++;
}
}
if($tempMatch==$matchFound)
{
return "found";
}
else
{
return "notFound";
}
}
$string = "test check one two test3";
/*** an array of words to highlight ***/
$words = array('test', 'test3');
$string = searchword($string, $words);
echo $string;
?>
If your string is utf-8, you could use preg_replace instead
$string = 'test check one two test3';
$result = preg_replace('/(test3)|(test2)|(test)/ui' , '<$1>' ,$string);
echo $result;
Oviously with this kind of data to match the result will be suboptimal
<test> check one two <test>3
You'll need a longer approach than a direct search and replace with regular expressions (surely if your patterns are prefixes of other patterns)
To begin with, the code you want to enhance does not seem to comply with its initial purpose (not at least in my computer). You can try something like this:
$string = 'test check one two test3';
$result = mb_eregi_replace('(test|test2|test3)', '<\1>', $string);
echo $result;
I've removed the i flag (which of course makes little sense here). Still, you'd still need to make the expression greedy.
As for the original question, here's a little proof of concept:
function replace($match){
$GLOBALS['matches'][] = $match;
return "<$match>";
}
$string = 'test check one two test3';
$matches = array();
$result = mb_eregi_replace('(test|test2|test3)', 'replace(\'\1\')', $string, 'e');
var_dump($result, $matches);
Please note this code is horrible and potentially insecure. I'd honestly go with the preg_replace_callback() solution proposed by Gumbo.
Say this is my string
$string = 'product[0][1][0]';
How could I use that string alone to actually get the value from an array as if I had used this:
echo $array['product'][0][1][0]
I've messed around with preg_match_all with this regex (/\[([0-9]+)\]/), but I am unable to come up with something satisfactory.
Any ideas? Thanks in advance.
You could use preg_split to get the individual array indices, then a loop to apply those indices one by one. Here's an example using a crude /[][]+/ regex to split the string up wherever it finds one or more square brackets.
(Read the [][] construct as [\]\[], i.e. a character class that matches right or left square brackets. The backslashes are optional.)
function getvalue($array, $string)
{
$indices = preg_split('/[][]+/', $string, -1, PREG_SPLIT_NO_EMPTY);
foreach ($indices as $index)
$array = $array[$index];
return $array;
}
This is prettttty hacky, but this will work. Don't know how much your array structure is going to change, either, this won't work if you get too dynamic.
$array = array();
$array['product'][0][1][0] = "lol";
$string = 'product[0][1][0]';
$firstBrace = strpos( $string, "[" );
$arrayExp = substr($string, $firstBrace );
$key = substr( $string, 0, $firstBrace );
echo $arrayExp, "<br>";
echo $key, "<br>";
$exec = "\$val = \$array['".$key."']".$arrayExp.";";
eval($exec);
echo $val;
What about using eval()?
<?php
$product[0][1][0] = "test";
eval ("\$string = \$product[0][1][0];");
echo $string . "\n";
die();
?>